Honors Algebra Order of Operations
Please show ALL work on a separate sheet of paper.
For questions # 1 – 6, evaluate each expression.
1) 50 ÷ 52 + 25
2) 2*42 + [(4 + 2*3) – 3]
3) 7{4[6(3) – 5]} – 2
4) {14 – [(9 + 16) ÷ 52 ]} – 13
5)
6)
For questions 7 and 8, place quantity symbols to make each equation true.
7) 2 + 3 * 4 – 4 * 4 = 64
8) 4 + 6 * 5 – 32 = 40
For questions 9 & 10, evaluate each expression when m = 8, n = 10 and p = 6.5.
9)
10) [m + n *(p + 1)]m
–
11) A math class is given the following order of operations problem: 5 – 12 ÷ 2 * 5 + 8. The work of three different students is
shown below. Two of the students have made an error, determine which student has the correct solution and explain the mistakes
of the other two students.
Student #1
Student # 2
Student #3
5 – 12 ÷ 2 * 5 + 8
5 – 12 ÷ 2 * 5 + 8
5 – 12 ÷ 2 * 5 + 8
5 – 12 ÷ 10 + 8
5–6*5+8
5–6*5+8
5 – 1.2 + 8
5 – 30 + 8
5 – 30 + 8
3.8 + 8 = 11.8
5 – 38 = – 33
– 25 + 8 = – 17
Key
1) 27 2) 53 3) 362 4) 0 5) – 544 6) 6
7) [(2+3)*4 – 4] * 4
8) (4+6)*(5 – 3)2 9) 9 10) 664
11) Student #1 is incorrect, their mistake occurs on the first line…they did 2*5 first, according to the order of
operations, when considering only multiplication and division; you go from left to right. This student did the
multiplication first even though the division appears first in the problem.
Student #2 is incorrect, their mistake occurs on the third line…they did 30 + 8 first according to the order of
operations, when considering addition and subtraction you go from left to right, they did the addition first when the
subtraction sign is to the left of the addition sign
Student #3 is correct
Parenthesis
Parentheses