Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 Lecture 11: Extensions of Mendelian Inheritance Inheritance of coat color in Labrador Retrievers is under the control of two genes. If both dominant alleles are present, the dog has a black coat. If the dog lacks “E”, its coat will be yellow, regardless of its genotype at the other locus. If “E” is present in the absence of “B”, then the dog has a chocolate coat. http://www.labbies.com/genetics.htm Page 1 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 I. Extensions Involving the Inheritance of Single Genes Unlike what Mendel observed, there are many different ways that two alleles can interact to govern the inheritance of a trait governed by a single gene. See Table 4.1, Brooker These extensions of Mendel’s findings will be examined with two things in mind: Understanding the relationship between the molecular expression of a gene and the trait itself Understanding how the extension alters the expected outcome of genetic crosses A. Wild-Type versus Mutant Alleles Prevalent alleles in a population are called wild-type alleles. These typically encode proteins that are made in the right amount and function normally. Alleles that are present at less than 1% in the population and have been altered by mutation are called mutant alleles. Such alleles usually result in a reduction in the amount or function of the wild-type protein and are most often inherited in a recessive fashion. For Mendel’s traits: Wild-type (dominant) allele Mutant (recessive) allele Purple flowers White flowers Axial flowers Terminal flowers Yellow seeds Green seeds Round seeds Wrinkled seeds Smooth pods Constricted pods Green pods Yellow pods Tall plants plants Page 2 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 Human diseases are also caused by mutations, and are also most often inherited in a recessive fashion because the mutant protein is either non-functional or greatly reduced compared to the protein coded by the wild-type allele. See Table 4.2, Brooker Mendel always chose traits where one of the alleles was completely recessive. At the molecular level, the most usual explanation for this is that 50% of the normal level of protein is sufficient to accomplish the protein’s task in the cell. Therefore, heterozygotes have a normal phenotype. B. Extension 1: Lethal Alleles Sometimes, a gene is absolutely essential for survival. The alleles created by mutations in these genes are called lethal alleles. Although they are usually recessive (only homozygotes are affected), they are occasionally dominant as well. Lethal alleles fall into four categories: 1. Early onset. The gene is necessary for basic cellular functions and mutants die during embryogenesis. 2. Late onset. The gene is necessary for life, but not until the individual is older. Homozygotes for lethal alleles of this kind are born and may survive for many years but will eventually succumb to the disease. Page 3 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 3. Conditional. The mutation only kills the organism when certain environmental conditions prevail. -In Drosophila, a temperature-sensitive lethal allele kills larvae at 30 degrees but not at 22 degrees. 4. Semi-lethal. Kills some mutant individuals in the population, but not all. This may be due to an unknown environmental influence or other genes that also influence the phenotype. -The allele for long-necks in mice is an example (Homework 1) Lethal alleles may cause a departure from Mendelian ratios, particularly if they are early onset. See Brooker, page 78 for an example. C. Extension 2: Incomplete Dominance of Alleles In incomplete dominance, the heterozygote exhibits a phenotype that is intermediate between the two pure-breeding parents. Thus, it appears to be “blending inheritance” in the F1s. However, in the F2s. both of the original traits reappear in the homozygotes. Incomplete dominance is seen in flower color in the four o’clock plant. Two alleles o CR = wild-type allele for red flower color o CW = allele for white flower color See Figure 4.2, Brooker Whether a trait is completely or incompletely dominant can depend on how closely the trait is examined. Take, for example, the characteristic of pea shape o Mendel visually concluded that RR and Rr genotypes produced round peas rr genotypes produced wrinkled peas o However, a microscopic examination of round peas reveals that not all round peas are “created equal” – the heterozygotes have less starch than the homozygotes (while the wrinkled peas have very little starch) Page 4 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 See Figure 4.3, Brooker D. Extension 3: Multiple Alleles Genes can be mutated all along their length (nucleotide sequence), and different mutations can give rise to subtly different phenotypes. When this happens, the gene is said to have multiple alleles. An interesting example is coat color in rabbits o Four different alleles C (full coat color) cch (chinchilla pattern of coat color) Partial defect in pigmentation ch (himalayan pattern of coat color) Pigmentation in only certain parts of the body c (albino) Lack of pigmentation o The dominance hierarchy is as follows: C > cch > ch > c See Figure 4.4, Brooker The ABO blood group provides another example of multiple alleles It is determined by the type of antigen present on the surface of red blood cells o Antigens are substances that are recognized by antibodies produced by the immune system As shown in in the diagram at the top of the next page, there are three different types of antigens found on red blood o Antigen A, which is controlled by allele IA o Antigen B, which is controlled by allele IB o Antigen O, which is controlled by allele i Allele i is recessive to both IA and IB Alleles IA and IB are codominant o They are both expressed in a heterozygous individual Page 5 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 N-acetylgalactosamin e The carbohydrate tree on the surface of RBCs is composed of three sugars A fourth can be added by the enzyme glycosyl transferase o The i allele encodes a defective enzyme The carbohydrate tree is unchanged o IA encodes a form of the enzyme that can add the sugar Nacetylgalactosamine to the carbohydrate tree o IB encodes a form of the enzyme that can add the sugar galactose to the carbohydrate tree Thus, the A and B antigens are different enough to be recognized by different antibodies For safe blood transfusions to occur, the donor’s blood must be an appropriate match with the recipient’s blood For example, if a type O individual received blood from a type A, type B or type AB blood o Antibodies in the recipient blood will react with antigens in the donated blood cells o This causes the donated blood to agglutinate o A life-threatening situation may result because of clogging of blood vessels E. Extension 4: Overdominance Overdominance is the phenomenon in which a heterozygote is more vigorous than both of the corresponding homozygotes o It is also called heterozygote advantage Example = Sickle-cell anemia o Autosomal recessive disorder o Affected individuals produce abnormal form of hemoglobin o Two alleles Page 6 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 HbA Encodes the normal hemoglobin, hemoglobin A HbS Encodes the abnormal hemoglobin, hemoglobin S HbSHbS individuals have red blood cells that deform into a sickle shape under conditions of low oxygen tension o Refer to Figure 4.9 o This has two major ramifications 1. Sickling phenomenon greatly shortens the life span of the red blood cells Anemia results 2. Odd-shaped cells clump Partial or complete blocks in capillary circulation o Thus, affected individuals tend to have a shorter life span than unaffected ones The sickle cell allele has been found at a fairly high frequency in parts of Africa where malaria is found o How come? Malaria is caused by a protozoan, Plasmodium o This parasite undergoes its life cycle in two main parts One inside the Anopheles mosquito The other inside red blood cells o Red blood cells of heterozygotes, are likely to rupture when infected by Pasmodium sp. This prevents the propagation of the parasite Therefore, HbAHbS individuals are “better” than o HbSHbS, because they do not suffer from sickle cell anemia o HbAHbA, because they are more resistant to malaria At the molecular level, overdominance is due to two alleles that produce slightly different proteins But how can these two protein variants produce a favorable phenotype in the heterozygote Well, there are three possible explanations for overdominance at the molecular/cellular level o 1. Disease resistance Page 7 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 2. Homodimer formation 3. Variation in functional activity See Figure 4.10, Brooker F. Extension 5: Incomplete Penetrance In some instances, a dominant allele is not expressed in a heterozygote individual Example = Polydactyly o Autosomal dominant trait o Affected individuals have additional fingers and/or toes See Figure 4.11 and 4.12, Brooker o A single copy of the polydactyly allele is usually sufficient to cause this condition o In some cases, however, individuals carry the dominant allele but do not exhibit the trait The term indicates that a dominant allele does not always “penetrate” into the phenotype of the individual The measure of penetrance is described at the population level o If 60% of heterozygotes carrying a dominant allele exhibit the trait allele, the trait is 60% penetrant NOTE: o In any particular individual, the trait is either penetrant or not G. Extension 6: Expressivity Expressivity is the degree to which a trait is expressed In the case of polydactyly, the number of digits can vary o A person with several extra digits has high expressivity of this trait o A person with a single extra digit has low expressivity The molecular explanation of expressivity and incomplete penetrance may not always be understood In most cases, the range of phenotypes is thought to be due to influences of the Page 8 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 Environment, and/or Other genes Environmental conditions may have a great impact on the phenotype of the individual. Example: Snapdragon flower color vs. Temperature and degree of sunlight H. Extension 7: Sex-Limited and Sex-Influenced Traits Sex-influenced traits are ones in which an allele is dominant in one sex but recessive in the opposite sex. Thus, sex influence is a phenomenon of heterozygotes. Example: Pattern baldness in humans o Caused by an autosomal gene Page 9 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 Allele B behaves as dominant in males, but recessive in females Genotype Phenotype in Females Phenotype in Males BB bald bald Bb nonbald bald bb nonbald nonbald Pattern baldness appears to be related to the level of male sex hormones In females, a rare tumor of the adrenal gland can cause the secretion of large amounts of male sex hormones o If this case a heterozygous Bb female will become bald o When the tumor is removed surgically, her hair returns to its normal condition The autosomal nature of pattern baldness has been revealed by analysis of human pedigrees Bald fathers can pass the trait to their sons Sex-limited traits occur in only one of the two sexes For example in humans, breast development is normally limited to females and beard growth is normally limited to males Page 10 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 II. Extensions Involving the Inheritance of More than One Gene Gene interactions occur when two or more different genes influence the outcome of a single trait. Indeed, morphological traits such as height weight and pigmentation are affected by many different genes in combination with environmental factors We will next examine two different cases, both involving two genes that two alternative alleles The two crosses we will perform can be illustrated in this general pattern o AaBb X AaBb Where A is dominant to a and B is dominant to b If these two genes govern two different traits o A 9:3:3:1 ratio is predicted among the offspring However, the two genes in this section do affect the same trait o In the first case, the 9:3:3:1 ratio is not affected, but in the second case, it is altered. A. Situation in Which the 9:3:3:1 Ratio is Not Affected Example: Inheritance of comb morphology in chicken o First example of gene interaction o Discovered by William Bateson and Reginald Punnett in 1906 o Comb types come in four different morphologies See Figure 14.7b in Brooker Thus, the F2 generation consisted of chickens with four types of combs o 9 walnut : 3 rose : 3 pea : 1 single Bateson and Punnett reasoned that comb morphology is determined by two different genes o R (rose comb) is dominant to r Page 11 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 o P (pea comb) is dominant to o R and P are codominant (walnut comb) o rrpp produces single comb Note: o Mendel’s laws of segregation and independent assortment still hold! B. A Cross Involving a Two-Gene Interaction Can Produce a 9:7 ratio Inheritance of flower color in the sweet pea o Also discovered by Bateson and Punnett o Lathyrus odoratus normally has purple flowers o Bateson and Punnett obtained several true-breeding varieties with white flowers o They carried out the following cross P: True-breeding purple X true-breeding white F1: Purple flowered plants F2: Purple- and white-flowered in a 3:1 ratio These results were not surprising, but the results shown in Figure 4.18 (Brooker) were. Thus, the F2 generation contained purple and white flowers in a ratio of 9 purple : 7 white o Bateson and Punnett reasoned that flower color is determined by two different genes C (one purple-color-producing) allele is dominant to c (white) P (another purple-color-producing) allele is dominant to p (white) cc or pp masks P or C alleles, producing white color Thus, a plant that is homozygous for either recessive white allele, would develop a white flower, regardless whether of not the other gene contains a purple-producing allele The term epistasis describes the situation in which a gene can mask the phenotypic effects of another gene. Page 12 Modified from http://www.mhhe.com/brooker BIO 184 Fall 2006 LECTURE 11 Epistatic interactions often arise because two (or more) different proteins participate in a common cellular function For example, an enzymatic pathway Colorless precursor Enzyme C Colorless intermediate The recessive c allele encodes an inactive enzyme Enzyme P Purple pigment The recessive p allele encodes an inactive enzyme If an individual is homozygous for either recessive allele o It will lack one of the enzymes required to make purple pigment o Therefore, the flowers remain white Thus, there is an alteration in the phenotypes seen by Mendel: 9 3 3 1 C_P_ C_pp ccP_ ccpp purple white white white Page 13 7 white