Name: Date: Period: Protein Synthesis 13.3A Use the chart of the genetic code given at the right and the notes given to you below to answer the questions that follow. You may also have to refer to your textbook or notes for help. Reading the Chart: •The first base in a codon is the largest most center letter in the chart. •The second base in a codon is the medium size letter just outside the first bases. •The third base in a codon is the smallest size letter next to the words of the amino acids. ***Translation begins at the first “start” codon (AUG or Met) and ends when a “stop” codon is reached. Ex: Methionine (located towards the bottom of the wheel) is AUG. 1. Transcribe the entire section of DNA below into mRNA. Use the top strand for transcription. DNA mRNA T A C-A T A-C C A-T T A-G C T-T G C-C A T-A C T-A A A T G-T A T-G G T-A A T-C G A-A C G-G TA-T G A-T T ___________________________________________________________________________ 2. Translate the mRNA sequence above into the appropriate amino acid sequence (protein/polypeptide). Remember to start on Met and stop on the right codon. Amino Acid Sequence ___________________________________________________________________________ 3. Go through transcription and translation to give the appropriate amino acid sequence for the DNA molecules below. Like before, use the top strand for translation. Transcribe the entire sequence but only translate the sequence after the “start” codon. DNA A C C-T A C-A T G-A C A-T T G-A A A-A T T-T C T G G-A T G-T A C-T G T-A A C-T T T- T A A-A G mRNA ___________________________________________________________________________ Amino Acid Sequence ___________________________________________________________________________ 4. Now work backwards from the amino acid sequence below to generate the appropriate mRNA molecule. There will be several different possible answers because more than one codon can stand for a single amino acid. Amino Acid Sequence mRNA Met - Pro - Lys - Thr - stop ___________________________________________________________________________ 5. Use the mRNA sequence you generated above to determine the corresponding DNA molecule. Hint: Generate the corresponding single strand first from mRNA and then fill in the complimentary strand to make the DNA double helix. Remember, DNA has thymine and RNA has uracil. DNA First Strand DNA Complimentary Strand ___________________________________________________________________________ ___________________________________________________________________________ Protein Synthesis – More Transcription and Translation Transcription (DNA → mRNA) Use the summary of transcription below as well as information gathered in your notes to answer the questions that follow. Transcription: DNA double helix unwinds. RNA copy made from DNA template. RNA is edited before exiting the nucleus. Questions: 6. Summarize in your own words transcription. ______________________________________ _________________________________________________________________________________ _________________________________________________________________________________ 7. Where does transcription occur? Why must it occur in this location? ___________________ _________________________________________________________________________________ _________________________________________________________________________________ 8. Fill in the correct base for the complimentary RNA strand. DNA strand RNA strand Guanine (G) ______________ Adenine (A) ______________ Thymine (T) ______________ Cytosine (C) ______________ 9. Give the appropriate mRNA strand that would be transcribed from the DNA strand below. DNA strand: T A T A A T A C T C G A C A A T T mRNA strand: _______________________________________________________________ Translation (mRNA AA chain/Polypeptide chain/Protein) Use the summary of translation below as well as information gathered in your notes to answer the questions that follow. Translation: mRNA start codon binds to ribosome. tRNA picks up AA in cytoplasm and carries it to ribosome. tRNA anticodon binds to complimentary mRNA codon. AA attaches to end of growing polypeptide chain. tRNA leaves to find another AA. Translation ends when stop codon is reached. Polypeptide released for folding. Questions: 10. Describe, in your own words, translation: _________________________________________ ___________________________________________________________________________ ___________________________________________________________________________ 11. Where does translation occur? Why must it occur in this location? ____________________ ___________________________________________________________________________ ___________________________________________________________________________ 12. Describe, in your own words, genetic code: _______________________________________ ___________________________________________________________________________ ___________________________________________________________________________ 13. What is a codon? What is an anticodon? _________________________________________ ___________________________________________________________________________ ___________________________________________________________________________ 14. Use the AA chart from page 1 (front page) to answer this question. A. Match the following codons with the AA they code. The first one is done for you. GCU Alanine_____ AAG ___________ CAA ___________ UUU ___________ UGG ___________ AUG ___________ 15. What codon(s) code for the Amino Acid lysine (Lys)? For valine (Val)? ___________________________________________________________________________ 16. What are the 3 stop codons? What do stop codons do? What is the start codon? ___________________________________________________________________________ ___________________________________________________________________________ ___________________________________________________________________________ ___________________________________________________________________________ Below are two partial sequences of DNA bases (shown for only one strand of DNA) Sequence 1 is from a human and sequence 2 is from a cow. In both humans and cows, this sequence is part of a set of instructions for controlling a bodily function. In this case, the sequence contains the gene to make the protein insulin. Insulin is necessary for the uptake of sugar from blood. Without insulin, a person cannot digest sugars the same way others can, and they have a disease called diabetes. Instructions: For both the human and the cow sequences, make complimentary RNA strands for the DNA shown. Remember to substitute U’s for T’s when transcribing RNA. Use the codon table on the front page to translate the amino acid sequences to make the insulin proteins. 17. Sequence 1 – Human DNA : T A C C C A T A G C A C G T T A C A A C G T G A A G G A T T mRNA : _______________________________________________________________________ Amino Acids: __________________________________________________________________ 18. Sequence 2 – Cow DNA : T A C C C G T A G C A T G T T A C A A C G C G A A G G A T T mRNA: _______________________________________________________________________ Amino Acids: __________________________________________________________________ 19. The DNA sequence is different for the cow and the human, but the amino acid chain produced by the sequence is almost the same. How can humans and cows have amino acid chains that are similar? ___________________________________________________________________________ ___________________________________________________________________________ 20. Could two humans (or two cows) have some differences in the DNA sequence for insulin, yet still make exactly the same insulin proteins? Explain. ___________________________________________________________________________ ___________________________________________________________________________