Name: ______________________________ Test on Chapter 1: Driving the Roads (Part 3) Period _____ CP Physics Date: _________ E. Burns For each of the problems below, be sure to show all work, including a labeled sketch, the equation used, numbers plugged in, and answers with correct units. You may encounter unfamiliar situations in which you need to apply concepts that you have learned. Just think it through and show your work! PROBLEM #1: A car is traveling down a road traveling at a constant velocity. A deer jumps into the middle of the road. The driver first reacts and then after reaction time hits the brakes and slows down to a complete stop. The graph on the left represents the car’s motion while reacting. The graph on the right represents the car’s motion while braking. Each shows the distance traveled for different velocities that car could be going. Car's reaction distance with constant reaction time Car's braking distance with an constant braking acceleration 200 braking distance [m] reaction distance [m] 40 30 20 10 0 150 100 50 0 0 20 40 60 0 average velocity [m/s] 20 40 60 initial velocity [m/s] A] Look at the graph on the left. What is the relationship between reaction distance and average velocity? How do you know? B] Look at the graph on the right. What is the relationship between braking distance and average velocity? How do you know? vf2= vo2 + 2a飦刣 vf= vo + at 饾懀饾憥饾懀 = 饾憽饾憸饾憽饾憥饾憴 饾憫饾憱饾憼饾憽饾憥饾憶饾憪饾憭⁄饾憽饾憸饾憽饾憥饾憴 饾憽饾憱饾憵饾憭 饾憥饾憪 = 饾懀2 饾憛 飦刣 = vot + ½ at2 饾惞饾憪 = 饾憵饾憥饾憪 C] What is the total stopping distance for the driver who is going 30 m/s? Justify your answer! Show your work! Distance (m) D] Draw a d-t graph and a v-t graph of the motion of the car from first sight of the deer to a complete stop. The dashed vertical line represents the end of the driver’s reaction time and the beginning of braking. Velocity (m/s) Time (s) Time (s) vf2= vo2 + 2a飦刣 vf= vo + at 饾懀饾憥饾懀 = 饾憽饾憸饾憽饾憥饾憴 饾憫饾憱饾憼饾憽饾憥饾憶饾憪饾憭⁄饾憽饾憸饾憽饾憥饾憴 饾憽饾憱饾憵饾憭 饾憥饾憪 = 饾懀2 饾憛 飦刣 = vot + ½ at2 饾惞饾憪 = 饾憵饾憥饾憪 Problem #2: A car approaches a 7-m wide intersection. A] Design a safe 7-m wide intersection. Use reasonable estimates for the variables, and include your reasoning. Variable Your Value Your Reasoning vi a w 7-m ty tr B] Use your values to calculate the GO Zone and the STOP Zone. C] Sketch the intersection, showing the GO and STOP zones and either the Overlap or Dilemma Zone. Label all distances clearly. vf2= vo2 + 2a飦刣 vf= vo + at 饾懀饾憥饾懀 = 饾憽饾憸饾憽饾憥饾憴 饾憫饾憱饾憼饾憽饾憥饾憶饾憪饾憭⁄饾憽饾憸饾憽饾憥饾憴 饾憽饾憱饾憵饾憭 饾憥饾憪 = 饾懀2 饾憛 飦刣 = vot + ½ at2 饾惞饾憪 = 饾憵饾憥饾憪 Let’s change the yellow light model so that, instead of maintaining constant speed through the intersection, you accelerate through the GO Zone. Therefore, instead of calculating the GO ZONE using a = 0 in the distance equation, you must use the car’s positive acceleration as you hit the gas to make it through the yellow light. D] Explain what effect this change has on each of the following, and explain why. (i) GO Zone (ii) STOP Zone (iii) Overall safety of your intersection. E] Given your response to [D], why shouldn’t you accelerate every time you encounter a yellow light? vf2= vo2 + 2a飦刣 vf= vo + at 饾懀饾憥饾懀 = 饾憽饾憸饾憽饾憥饾憴 饾憫饾憱饾憼饾憽饾憥饾憶饾憪饾憭⁄饾憽饾憸饾憽饾憥饾憴 饾憽饾憱饾憵饾憭 饾憥饾憪 = 饾懀2 饾憛 飦刣 = vot + ½ at2 饾惞饾憪 = 饾憵饾憥饾憪 PROBLEM #3: A 615-kg racing car is moving at its maximum speed of 42 m/s around a circular racetrack that has a 50 m radius. a) What is the centripetal acceleration of the car? b) What is the friction force required to keep the car on the road? c) If 8800 Newtons of friction between the tires and the road are available, what will happen to the car? d) Name two things that can be done to the racetrack and/or the car in order to increase the maximum speed at which the car can make the turn. e) In the diagram to the right, the circle represents the track, and the box represents the car. If the car was traveling clockwise when it hits an icy patch on which there wasn’t enough friction, which way would the car move? EXPLAIN. Also, draw an arrow to show what you mean. vf2= vo2 + 2a飦刣 vf= vo + at 饾懀饾憥饾懀 = 饾憽饾憸饾憽饾憥饾憴 饾憫饾憱饾憼饾憽饾憥饾憶饾憪饾憭⁄饾憽饾憸饾憽饾憥饾憴 饾憽饾憱饾憵饾憭 饾憥饾憪 = 饾懀2 饾憛 飦刣 = vot + ½ at2 饾惞饾憪 = 饾憵饾憥饾憪