Chp. 4 review game answers:
CPCTC category
10.) m<A=m<D, m<B=m<E, m<C=m<F and AB=DE, AC=DF, EF=BC
20.) ∆𝑄𝐵𝐶 ≅ ∆𝑋𝐴𝑅
30.) Corresponding Parts of Congruent Triangles are Congruent.
40.) PQ
50.) <A, <B <BCD, <ADC <ACD, <BDC
AC, BD CD, CD BC,AD
“I saw celese” category
10.) y=84
20.) the base angles of the triangle on the left are 56 degrees. The vertical angles makes one base angle of the other triangle 56 as well. We solve the equation 56+56+x=180 and get x=68
30.) The base angles of the triangle on the left are 65 degrees. The supplementary angle on the right side of 65 must be 115. Since this is the vertex angle of the triangle on the right, we solve the equation 115+x+x=180 and get 32.5 for <1.
40.)Since the circumference of the circle is 31.4 in. we need to set the circumference formula=to
31.4. We now have that 2rπ=31.4. 2r=diameter, which is one of the legs of the isosceles triangles. By dividing by 3.14 on both sides we end up getting 2r=10. Since the leg then must be
10 in, y=5 in.
50) The exterior angle could be on the outside of the vertex or one of the base angles. This is going to provide us with two different answers. If it’s outside the vertex, the vertex angle is 50 which means the base angles are 65 each. The other option would be the base angles are both 50 and the vertex is 80 degrees.
Congruency Thms. Category
10.) ASA

20.) AAS
30.)ASA
40.)SSS
50.) Not congruent, the angles are not corresponding. Need m<W=m<A
Missing steps category
10) 1.) Given statement)
2.) def. bisect 3.) WZ=WZ
20) 1.) Given 2.) TQ=QR 3.) v. <’s 4.) AAS
4.)(copy down congruence
30) 1.) Defn. bisect what asked to prove
2.)CM=MD
3.) reflexive 40) 1.) given 4.) HL
3.) m<AMD=m<CMB
50) 1.) P is center 2.) AW=WX=BW=WL 3.) m<AWX=m<BWL
AWX and BWL are congruent (use statement format)
4.) copy down
4. Triangles