Physics 30 Finding Resultant Vectors Using Law of Cosines and Law of Sines We know from previous lessons that we can find the resultant vector of a right triangle using Pythagorean’s theorem. The problem is that not all motion will be moving in perpendicular motion or from right triangles. We need to have solutions for solving for resultant vectors that are not right triangles. We will use the law of cosines and the law of sines. Law of Cosines: The Law of Cosines is a general equation relating three sides and one angle in a triangle. There are no restrictions on the triangle's shape. Three elements determine a triangle. If any three of the four elements in the law-of-cosines equation are given, the equation allows you to calculate the fourth one. There are three law-of-cosines equations, depending on which angle is included: c2 = a2 + b2 - 2ab cos g (1) a2 = b2 + c2 - 2bc cos a (2) b2 = c2 + a2 - 2ca cos b (3) Physics 30 Law of Sines: The Law of Sines is a set of equations true for any triangle. It states that the ratio "sine of an angle divided by the length of the opposite side" is the same for any pair of angle and opposite side. The law-of-sines equations are A triangle is determined by three of its elements. Given two sides and an angle opposite to one of the sides, the Law of Sines lets you determine the angle opposite to the other side. Let’s try an example: Vector 1 is 100m, while vector 2 is 130m. Find vector r. The Law of Cosines can be used to calculate the magnitude r of the resultant vector. Physics 30 The Law of Sines can then be used to calculate the direction (q) of the resultant vector. Components of Vectors Vectors can be described in terms of their scalar components. A vector in two dimensions has two scalar components, one along the x-axis and one along the y-axis. For a vector , these components are denoted ax and ay, respectively. Physics 30 The vector in Figure 7 has a magnitude of 8 and an angle q with the positive x-axis equal to 30o. Its scalar components have the values ax = 6.93, ay = 4.00 The definition of the sine and cosine imply that ax = a cos θ, ay = a sin θ Substituting a = 8.00 and q = 30.0o into these equations gives the answers 6.93 and 4.00 Let’s try an example! The magnitude and direction of are: v1 = 100, θ1 = 60o v2 = 130, θ2 = 140o 1 and 2 Physics 30 The components of each vector are calculated using the appropriate trigonometric functions. Vector Diagram x - component y - component To add the two vectors is to add the respective components. If the components of the resultant are denoted (rx,ry), we get: Physics 30 rx = v1x + v2x rx = (+50.00) + (-99.59) rx = -49.59 ry = v1y + v2y ry = (+86.60) + (+83.56) ry = +170.16 You could specify the resultant in terms of the components and stop the calculation at this point. However, if the magnitude and direction angle of the resultant are required, these can be calculated from the components as follows: The direction can be calculated using the definition of the tangent of an angle This implies for the direction angle of the value 180 73.75 = 106.24o Physics 30 In summary, if two vectors 1 and 2 are given in terms of magnitude and direction, a resultant can be calculated by doing the following: Use a vector diagram and trigonometric functions to convert the vectors to component form. Add the components (xtotal = x1 + x2) and (ytotal = y1 + y2). Remember to include positive or negative directions. Draw the resultant vector using the xtotal component and the ytotal component. Remember to include positive or negative directions. Calculate the resultant magnitude using the Pythagorean theorem (c2 = a2 + b2). Calculate the direction using the appropriate trigonometric function (tangent function). Practice 1. Using the component method, calculate the resultant (sum) of the following two vectors. Show all required calculations and diagrams below and identify the direction = 175, 70o o 2 = 200, 200 1 a) Vector diagram and calculation of the components for 1. b) Vector diagram and calculation of the components for 2. Physics 30 c) Addition of the components and drawing of the resultant vector. d) Calculation of the resultant magnitude using the Pythagorean theorem. e) Calculation of the resultant direction using the tangent function. Express the direction. 2. = 185, 45o o 2 = 95, 320 1 a) Vector diagram and calculation of the components for 1. b) Vector diagram and calculation of the components for 2. Physics 30 c) Addition of the components and drawing of the resultant vector. d) Calculation of the resultant magnitude using the Pythagorean theorem. e) Calculation of the resultant direction using the tangent function. Express the direction.