MODULE IV FOR THE FINAL PERIOD Learning Objectives At the end of Module III, the students are expected to be able to: 1. Explain and determine the roots of real numbers; 2. Recognize the principal nth root of a real number; 3. Simplify expressions containing rational exponents; 4. Define Radicals and name parts of a radical; 5. Explain the laws of radicals; 6. Operate on radical expressions; 7. Define algebraic equation; 8. Explain the different types of equations; 9. Define linear equation in one variable; 10. Solve for the solution set of a linear equation; 11. Translate worded problems into mathematical statements; and, 12. Solve mathematical problems involving linear equation. ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV MODULE IV 4.1 ROOTS AND RADICAL EXPRESSION Definition: If a and b are real numbers and n is a positive integer greater than 1 such that bn = a, then b is called an nth root of a. Illustrations: 1. Since 22 = 4 and (-2)2 = 4, then 2 and -2 are square roots of 4. 2. (-4)3 = - 64, hence – 4 is the cube root of – 64. 3. 3 and – 3 are fourth roots of 81 since 34 = 81 and (- 3)4 = 81. In the above illustrations, 1 and 3 have more than one root. To identify which root is needed in a problem, the concept of principal nth root is defined herewith. π Definition: Let the principal nth root of a be denoted by √π . π If a is a positive real number, then √π is the positive nth root of a. If a is a π negative number and n is a positive odd integer, then √π is the negative nth root of a. If π a is equal to zero, then √0 = 0. Illustrations: 1. The principal square root of 4 is 2, thus √4 = 2. However, - 2 is also a square root but not the principal square root of 4. This root is written as - √4 = - 2. 2. The principal cube root of – 64 is – 4. 4 3. 3 is the principal fourth root of 81 so √81 = 3. Although – 3 is also a fourth π root but this is written as - √81 = - 3. 1 The principal nth root of a real number a may also be denoted by ππ . That is, if b 1 is the principal nth root of a real number a, then ππ = b. Hence, from the above 1 1 1 illustration: 42 = 2, (−64)3 = - 4 and 814 = 3. ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV π A more general expression containing a rationalexponent isπ π . For relatively π 1 prime integers m and n, that is, they have no common factor except 1, π π = ( ππ )α΅ or π 1 π π =(πα΅)π , provided each expression is defined, that is the expression will result to a real number since the variables satisfy the conditions in the definition. Examples: Simplify the following expressions containing rational exponents. 2 1 1. 83 = (83 )² = 22 = 4 2. ( 32 243 4 4 5 ) = 325 4 2435 1 = ( 325 )β΄ 1 (2435 )β΄ 2β΄ = 3β΄ = 16 81 3. Assume that x and y are both positive. 1 3 (π₯ π¦‾¹) − 1 3 3 − 2 = (π₯ ) 3 2 (π¦‾¹) 3 2 − 1 2 − 3 2 = π₯ π¦ = 3 π¦2 1 π₯2 4. Assume that x is positive. 1 3 1 1 3 1 1 π₯ 2 (3π₯ 2 + 2π₯ −2 ) = 3π₯ 2+2 + 2π₯ 2−2 4 = 3π₯ 2 + 2π₯ 0 = 3π₯ 2 + 2 1 1 2 1 1 5. (π₯ 3 − π¦ 3 ) (π₯ 3 + π₯ 3 π¦ 3 ) = x – y 4.2 RADICALS π 1 If a is a real number and n is a positive integer greater than 1, then √π = ππ π provided a is positive whenever n is even.The expression √π is called a radical, a is π called the radicand and n the index. √π is the radical form of the principal nth root of a 1 while ππ is the exponential form. The two notations may be used interchangeably. ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV Illustrations: 1 1. 42 = √4 = 2 1 2. − 42 = − √4 = - 2 1 3 3. (−27)3 = √−27= - 3 1 4 4. 6254 = √625 = 5 3 1 5. 492 = (492 )³ = (√49) ³ = 7³ = 343 Simplify the following expressions. 1. √. 0081 1 2. 362 1 3. 643 2 1 4 4. π₯ 2 (π₯ 3 − π₯ 3 ) 7 5 5. π₯ 2 π₯ 2 π₯ 3 2 − 2 6. 325 7. ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 1 2 1 2 1 2 1 2 ( π₯ + π¦ )(π₯ − π¦ ) Laws of Radicals 1 π Where: √π = ππ , if a and are real numbers and n is a positive integer. Theorem 1. Raising to the Index π π ( √π)n = a or ππ = a This theorem states that when a radical is being raised to a power equal to its index, and assuming the radicand is positive and the index, the index and the exponent cancel off. 5 Example: ( √−6 )5 = - 6 Theorem 2.Root of a Product π π 1 π 1 1 π √π • √π = √ππ or ππ • π π = (ππ)π = √ππ This theorem states that when radicals with the same index are being multiplied, only the radicands are multiplied while the index remains the same for the product. 3 3 3 3 3 Examples: 1. √8 • √2 = √16= √8 • 2= 2 √2 2. √9 • √π₯ = √9π₯ = 3√π₯ 3 3 3 3. √−6π’²π£β΄ • √9π’β΅π£² = √−54π’β·π£βΆ 3 3 3 3 = √−27 • √2π’ • √π’βΆ • √π£βΆ 6 6 3 3 = - 3(π’3 )(π£ 3 ) √2π’= - 3u2v2 √2π’ Theorem 3. Root of a Quotient π √π π √π ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV π π = √ from: π 1 π √π π √π = ππ 1 ππ π π π = ( )π1 = √ b ≠ 0 π π 3 Examples: 1. √π₯β΅ 3 √π₯² 3 = √ π₯β΅ π₯² 3 = √π₯³ = x Theorem 4. Root of a root π π ππ √ √π = √π 3 6 6 Examples: 1. √ √64π§ = √64π§ = 2 √π§ 3 4 2. √ √π₯𦲠= 12 √π₯𦲠Simplify the following radical expressions and equations: 5 5 5 5 5 1. √64 = √32 • 2 = √32 • √2 = 2√2 2. √π₯² + 2π₯π¦ + 𦲠= √(π₯ + π¦)² = x + y 3 3 3 3 3. √81π₯β΅π¦β· = √(27π₯ 3 π¦ 6 )(3π₯ 2 π¦) = √27π₯³π¦βΆ • √3π₯²π¦ 3 = 3xy²√3π₯²π¦ 4. √54 4 1 2 4 2 = ( 5β΄) = 5 = 52 = 25 1 1 5. √(32)² = (32²)4 = 322 = √32 = √16 • 2 = √16 • √2 = 4√2 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV Addition and subtraction of Radicals Similar radicals are radicals of the same radicand and index. For 3 example, 4√3 and 3√3 are similar radicals while √2 and √2 are not similar radicals since they have different indices although their radicands are the same. In adding or subtracting similar radicals, we only add or subtract the integral factors. Examples: 1. √3 + 2√3 = (1 + 2)√3 = 3√3 2. 10√6 + 5√6 - 7√6 = (10 +5 - 7)√6 = 8√6 3. √9 + √45 - √320 = 3 + √9 • 5 - √64 • 5 = 3 + 3 – 8 √5 = 3 - 5√5 1 1 1 4. √2 + √2 = 2√2 5. √π + √π = √π + √π 3 3 3 3 6. √π₯³π¦ + √π₯π¦³= x √π¦ + π¦ √π₯ ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV Solve the following: 1. 3 3 3 √4 + 2 √4 - 5√4 3 5 2. (√2)βΆ + √25 - √64 + √−32 3. √8π₯β΄π¦β· + √32π₯²π¦ 4. 8√7 - 7π₯ √7 + √875 5. √π²π₯ − π² + √π4 π₯ − πβ΄ 6. √8π₯² − 8 + √2π₯² − 2 7. √16π₯ − 16 - √π₯³ − π₯² 8. 3√50 + 4√18 - 36√32 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 3 3 3 Multiplication and division of Radicals The second theorem of radicals is very useful in this operation. Multiplying and dividing radicals follow from the properties of radicals, that is, π π π √π π √π • √π = √ππ and π √π π = √ π π (b ≠ 0) If the radicals to be multiplied or divided have different indices, derive the least common multiple (LCM) of the indices. Then multiply or divide the radicals having the same index. Examples: 3 1. √18π₯ • √4π₯ = 6 6 √18π₯ = √9 • 2π₯ = √3² • 2π₯ = √3βΆ • 2³π₯³ = 3 √2³π₯³ 3 3 6 √4π₯ = √2²π₯ = √2β΄π₯² 6 6 6 3 therefore: √18π₯ • √4π₯ = 3 √2³π₯³ • √2β΄π₯² = 3 √2β·π₯β΅ 6 6 3 • 2 √2π₯β΅ = 6 √2π₯β΅ 2. 3 4 12 12 √π₯𦲠÷ √π₯²π¦ = √π₯β΄π¦βΈ ÷ √π₯βΆπ¦³ = 12 √π₯β΄π¦βΈ 12 √π₯βΆπ¦³ 12 √π₯βΆπ¦³ • 12 √π₯βΆπ¦³ 12 = √π₯¹β°π¦¹¹ π₯π¦ 3. √4π₯ • √12π₯³ = √(4π₯)(12π₯ 3 ) = √48π₯β΄ = √16π₯β΄3 = 4x√3 4. (√π¦ − 1)(√π¦ − 1) = √(π¦ − 1)(π¦ − 1) = √(π¦ − 1)² = y–1 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 5. (√π₯ + √π¦)(√π₯ − √π¦) = (√π₯ )2 – (√π¦ )2 = x - y 3 6. √64π₯β΅ 3 = √ 3 √4π₯² 64π₯β΅ 4π₯² 3 3 3 = √16π₯³ = π₯ √8 • 2 = 2x√2 Solve the following: 3 4 1. √π • √π • √π 2. 3. √128π₯β΅π¦βΆ √2π₯β΄π¦² 2 √3 + √4 4. (√3 + √4)² 3 3 5. ( √π₯ + 1)(√π₯ 2 + 2π₯ + 1) 3 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 3 6. √3 • √3 7. √5 • √9 3 WORK PROJECT / LEARNING ACTIVITY NO.1, MODULE IV Name: ___________________________________ Yr/Sec: ____________ Date: ____________ A. Simplify the following: 3 3 1. √27 • √2 2. √16 • √π₯ 2 3. 643 27 2 4.( 64 )3 1 4 5. (π3 π‾¹)− 3 = 2 4 2 6. π₯ 3 (3π₯ 3 + 2π₯ −3 ) 1 7. 252 1 8.− 362 1 9. (−64)3 1 10. 814 3 11. 362 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV WORK PROJECT / LEARNING ACTIVITY NO. 2, MODULE IV Name: ___________________________________ Yr/Sec: ____________ Date: ____________ B. Addition and Subtraction of Radicals 1. 5√3π₯³ + √12π₯ 2. 4√6 − 8√6 + 9√6 − 7√6 3 4 3 4 3. 2√3 − 4√5 + 10 √3 − 8√5 4. 16√45 + 9√175 3 3 5. √27 + 5√8 6. 10√5 + 11√5 7. 5√4 − 10√36π₯ − 5√121 − 4√625π₯ 3 3 8. √40 + √320 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV WORK PROJECT / LEARNING ACTIVITY NO.3, MODULE IV Name: ___________________________________ Yr/Sec: ____________ Date: ____________ C. Multiplication and Division of Radicals 1. √5 (√80 + √20 − √45 ) 2. (√10 − √6 )(√10 + √6 ) 3. (√π2 − π 2 )(√π + π )(√π − π ) 4. (√2 + √8 ) 5. 6. 7. √2 + √3 − √5 √6 2 √2 + √3 + √5 √2 − √3 √5 + √6 − √7 3 8. 2 √64π₯β΅π¦ 3 √8π₯π¦ ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 4.3 ALGEBRAIC EQUATIONS An equation is a mathematical statement that shows two expressions are equal. The equality of such expressions is denoted by the symbol of equality ( = ). There are different types of equations: Identity, Conditional, and Equivalent equations. 1. The equation (x – 2)2 = x2 - 4x + 4 is an identity equation because the equation is satisfied for any real number of x that will be substituted in (x – 2)2. The equation (x + 3) (x – 3) = x2 – 9 is also an identity equation. 2. The equation 3x + 2 = 2x - 3 is a conditional equation because it is satisfied only when x = - 5. 3. The equations 5x + 4 = 4x -3 and 7x + 39 = 4x + 18 are equivalent equations because they have the same solution set which is {- 7}. The equations 7x – 21 = 0 and 7x = 21 are equivalent equations because the two equations are satisfied only when x = 3. Identify if the following equations are identity or conditional equations: 1. (xn - 1)2 = x2n - 2xn + 1 2. x + 10 = 5x - 16 3. x2 - 9 = (x - 3) (x + 3) 4. 5 - 3x = 7x + 9 5. x + 4 = 4 - x 6. x2 + 9 = (x - 3) (x + 2) ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 4.4 LINEAR EQUATIONS A linear equation in a single variable is a mathematical equation that involves a single variable with 1 as the highest exponent. Some examples of linear equation in the variable xare: x - 1 = 3, 3x + 2 = 4, and π₯ 2 = 5π₯ − 1 3 The value of the variable x that will satisfy the equation is called the solution set of the linear equation. In the equation x - 1 = 3, when the value of x is 4, the equation is true. Hence, x = 4 is the solution of the given equation. To solve a linear equation means to find the solution of the equation. The following are the steps in solving linear equation in one variable: 1. Transfer all terms containing variables to the left side of the equation, or transfer all constants to the right side of the equation. Example: 3x + 2 = 4 transfer 2 to the right side of the equal sign, becomes 3x = 4 – 2. 2. Simplifying the equation becomes 3x = 2. 3. Divide both sides of the equation by the coefficient {3}, 3π₯ 3 = 2 2 , therefore x = 3 3 Our solution shows that the value of x = 2 . 3 4. Check if the value of x is correct which will make the equation true. 2 Substitute x with the value in the equation, re-write the equation and 3 2 simplify 3x + 2 = 4 becomes 3(3) + 2 = 4, = 4. ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 2 + 2 = 4, then 4 Examples: 1. 2x + 3 = 4x - 5 Check: 2x - 4x = - 5 - 3 2(4) + 3 = 4(4) - 5 - 2x = - 88 + 3 = 16 - 5 -2 -2 11 = 11 x = 4 2. (n + 2)(n + 4) = n(n + 8) n2 + 6n + 8 = n2 + 8n n2 – n2 + 6n - 8n = - 8 - 2n = - 8 - 2 -2 n = 4 3π 3. ( + 4 3π 4 + π 3 π 3 = 13 = 13 3 3 )¹² 9a + 4a = 52 13a = 52 13 13 a = 4 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV Solve the following linear equations and check solution set: 1. x + 5 = 8 2. 3y + 3 = y - 4 3. (3z - 8) – 2(z + 5) = 0 4. 5. 10 4π₯ + 3 π¦ 2π¦−3 4 = π₯ 1 − 2 = 1 2π¦ + 3 6. 2x + 3 = 4x - 1 7. (x - 2) (x + 3) = (x - 3) (x + 5) 8. 9. 5π₯ + 3 2 8π₯ + 11 4 = 7π₯ − 8 3 = 3 10. 3x + 4 = 5x - 10 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 4.5 MATHEMATICAL STATEMENTS Mathematical statements are statements written in algebraic forms which are equivalent to worded statements. For examples, translate the following worded phrases into mathematical statements: 1. “The square of the sum of x and y” Written as: (x - y)2 2. “The sum of the squares of x and y” Written as: x2 + y2 3. “The sum of x and the product of 5 and y” Written as: x + 5y 4. “Five times the difference of the cubes of x and y” Written as: 5(x3 - y3) 5. “The sum of the three consecutive even integers” Written as: x + (x + 2) + (x + 4) Write a mathematical statement of the following worded problems: 6. The length of the rectangle is twice its width. The perimeter of the rectangle is 50 inches. Let x – the width of a rectangle 2x – the length of the rectangle which is twice its width. The formula for the perimeter of the rectangle: P = 2(L + W) Therefore: 50 = 2(2x + x) ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 7. A woman is nine times as old as her son and her husband is five years older than she. The sum of their ages is 81. Let x - the age of the sun 9x - the age of the woman whose age is 9 times of the age of her son 9x + 5 - the age of the husband Therefore: x + 9x + (9x + 5) = 81 8. In a group of 200 students there are 40 more boys than girls. Let x - the number of girls 40 + x - the number of boys who are 40 more than the girls. Therefore: x + (40 + x) = 200 9. The second number is two greater than the first number while the third number is three times the first number. The sum of the three numbers is 17. Let x - the first number 2 + x - the second number greater than the first number by 2 3x - the third number three times the first Therefore: x + (2 + x) + 3x = 17 10. Business Problem A man invested part of his β±5, 000 at a bank that offers 4 % interest rate and the rest is invested at 5 %. The total annual income from the two investments is β±209.00. How much was invested at each of the rates? ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV Let x - the amount invested at 4 % = 0.04x annual income (5, 000 - x) - the amount invested at 5 % = 0.05(5,000 – x) annual Therefore: 0.04x + 0.05(5,000 - x) = β±209.00 0.04x + 250 - 0.05x = β± 209. 00 250 - 0.01x = β± 209. 00 250 - 209 = 0.01x 41 = 0.01x 0.01 0.01 x = β±4, 100 amount invested at 4 % 5, 000 – 4, 100 = β± 900 amount invested at 5 % 11. The sum of three numbers is 27. The second number is 2 less than twice the first number, and the third number is 5 greater than 3 times the first number. What are the numbers? Let x - the first number (2x – 2) - the second number (3x + 5) - the third number Therefore: x + (2x - 2) + (3x + 5) = 27 x + 2x - 2 + 3x + 5 = 27 6x + 3 = 27 6x = 27 - 3 6x = 24 6 6 x = 4 ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV 12. Berto is 40 years old and his daughter, Cuartita, is 14 years old. In how many years will he be twice as old as his daughter? Let x - the number of years required 40 + x - age of Berting after x years 14 + x - age of Cuartita after x years Therefore: 40 + x = 2(14 + x) Translate the following verbal expressions into mathematical statements. 1. “Three subtracted from a number n” 2. “Five times a number t diminished by two” 3. “The price of a toy after 10 % discount if the original price is q” 4. “The average of three numbers a, b, and c” 5. “Thrice the number x increased by 5” 6. “Nine more than five times a number” 7. “The sum of three consecutive odd numbers” The second number is (x + 2) and the third is (x + 4). 8. ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV “Three consecutive even numbers whose sum is 12” Translate the following worded problem into mathematical statement and solve: 1. In a group of 300 students there are 30 more boys than girls. 2. The second number is three greater than the first number while the third number is five times the first number. The sum of the three numbers is 24. What are the three numbers/ 3. The length of the rectangle is thrice its width. The perimeter of the rectangle is 60 inches. How long are the length and the width of the rectangle? 4. A girl is two times as old as her younger sister and her eldest sister is five years older than she. If the sum of their ages is 50, how old are each of these sisters? 5. The sum of three numbers is 35. The second number is 3 less than thrice the first number, and the third number is 6 greater than 4 times the first number. What are the numbers? ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV WORK PROJECT / LEARNING ACTIVITY NO. 4, MODULE IV Name: ___________________________________ Yr/Sec: ____________ Date: ____________ A. Translate the following worded phrases into mathematical statements: 1. “The cube of the sum of x and y” 2. “The product of the squares of x and y” 3. “The sum of x and the product of 3 and y” 4. “Eight times the difference of the squares of x and y” 5. “The sum of the three consecutive odd integers” 6. 7. “Three consecutive even numbers whose sum is 42” “Twelve times a number m diminished by four” 8. “The price of a dress after 7 % discount if the original price is q” 9. “Thrice the number x increased by 5” 10. “The sum of three consecutive odd numbers whose sum is 45” ISHRM 2014 Learning Material College Algebra MT 111/MT 211 Module IV WORK PROJECT / LEARNING ACTIVITY NO. 5, MODULE IV Name: ___________________________________ Yr/Sec: ____________ Date: ____________ A. Translate the following worded phrases into mathematical statements: 1. Business Problem Miss Rivera invested a certain amount of money at a bank that offers 4 % interest per year and the rest is invested at 5 %. If her total investment is β±100,000. How much did Miss Rivera invested at each rates?