Honors Chemistry Chemical Reactions Review – Ch. 11
ANSWER KEY
synthesis
2Sb + 3I2  2SbI3
single replacement
2Li + 2H2O  2LiOH + H2
decomposition
2AlCl3  2Al + 3Cl2
combustion
C6H12 + 9O2  6CO2 + 6H2O
double replacement
2AlCl3 + 3Na2CO3  Al2(CO3)3 + 6NaCl
Neutralization
2HNO3 + Ba(OH)2  Ba(NO3)2 + 2H2O
single replacement
2Al + 3Pb(NO3)2  2Al(NO3)3 + 3Pb
double replacement
2NH4Cl(aq) + Pb(NO3)2(aq)  PbCl2(s) + 2NH4NO3(aq)
combustion
CS2(s) + 3O2(g)  CO2(g) + 2SO2(g)
single replacement
Fe(s) + 3AgNO3(aq)  Fe(NO3)3(aq) + 3Ag(s)
decomposition
2KNO3(s)  2KNO2(s) + O2(g)
synthesis
Ca(s) + Cl2(g)  CaCl2(s)
single replacement
F2(g) + 2KCl(aq)  2KF(aq) + Cl2(g)
comb, synthesis
P4(s) + 5O2(g)  2P2O5(s)
single replacement
3Mg(s) + Al2O3 (aq)  3MgO + 2Al
combustion
C2H4(g)+ 3O2(g)  2CO2(g) + 2H2O(g)
double replacement
FeCl2(aq)+ K2S(aq)  FeS(s) + 2KCl(aq)
Neutralization
H2S (aq) + 2KOH(aq) K2S + 2H2O
double replacement
NH4NO3(aq) + NaCl(aq)  N.R.
single replacement
Cl2(g) + MnBr4(s)  MnCl4(s) + Br2(l)
1 atom of solid magnesium reacts with 2 molecules of aqueous hydrochloric acid to form 2 units of
aqueous magnesium chloride and 1 molecule of hydrogen gas
22. 1 unit of solid iron (II) sulfide reacts with 2 molecules of aqueous hydrochloric acid to form 1 molecule
of hydrogen sulfide gas and 2 units of aqueous iron (II) chloride
23. 1 unit of aqueous potassium bromide reacts with 1 unit of aqueous silver nitrate to form 1 unit of solid
silver bromide and 1 unit of aqueous potassium nitrate
24. 1 unit of solid mercury (II) oxide breaks down 1 atom of liquid mercury and 1 molecular of
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gaseous oxygen.
25. 2 molecules of gaseous tetracarbon decahydride reacts with 13 molecules of oxygen gas to form 8
molecules of gaseous carbon dioxide and 10 molecules of water vapor.
26. 1 molecule of aqueous sulfuric acid reacts with 1 unit of aqueous calcium hydroxide to form 1 unit of
aqueous calcium sulfate and 2 molecules of liquid water
27. Cu2+ + OH- Cu(OH)2(s)
28. Ni2+ + PO43-  Ni3(PO4)2(s)
29. Zn(s) + Sn4+  Sn(s) + Zn2+
30. Cl2(g) + I-  I2(s) + Cl31. Soluble
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Insoluble
Soluble
Soluble
Insoluble
Insoluble
Insoluble
Soluble
Insoluble