NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 8 8•3 Lesson 8: Similarity Student Outcomes ο§ Students know the definition of similarity and why dilation alone is not enough to determine similarity. ο§ Given two similar figures, students describe the sequence of a dilation and a congruence that would map one figure onto the other. Lesson Notes In Module 2, students used vectors to describe the translation of the plane. Now in Topic B, figures are bound to the coordinate plane, and students describe translations in terms of units left or right and/or units up or down. When figures on the coordinate plane are rotated, the center of rotation is the origin of the graph. In most cases, students describe the rotation as having center π and degree π unless the rotation can be easily identified, that is, a rotation of 90° or 180°. Reflections remain reflections across a line, but when possible, students should identify the line of reflection as the π₯-axis or π¦-axis. It should be noted that congruence, together with similarity, is the fundamental concept in planar geometry. It is a concept defined without coordinates. In fact, it is most transparently understood when introduced without the extra conceptual baggage of a coordinate system. This is partly because a coordinate system picks out a preferred point (the origin), which then centers most discussions of rotations, reflections, and translations at or in reference to that point. They are then further restricted to only the “nice” rotations, reflections, and translations that are easy to do in a coordinate plane. Restricting to “nice” transformations is a huge mistake mathematically because it is antithetical to the main point that must be made about congruence: that rotations, translations, and reflections are abundant in the plane; that for every point in the plane, there are an infinite number of rotations up to 360°, that for every line in the plane there is a reflection and that for every directed line segment there is a translation. It is this abundance that helps students realize that every congruence transformation (i.e., the act of “picking up a figure” and moving it to another location) can be accomplished through a sequence of translations, rotations, and reflections, and further, that similarity is a sequence of dilations or congruence transformations. Classwork Concept Development (5 minutes) ο§ A dilation alone is not enough to state that two figures are similar. Consider the following pair of figures: ο§ Do these figures look similar? οΊ Yes, they look like the same shape, but they are different in size. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 111 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM ο§ How could you prove that they are similar? What would you need to do? οΊ ο§ No, a dilation alone would not map figure π onto figure π0 . What else should we do to map figure π onto figure π0 ? οΊ ο§ Yes, we could dilate to make them the same size by using the appropriate scale factor. We could make them the same size, but would a dilation alone map figure π onto figure π0 ? οΊ ο§ We would need to show that they could become the same size by dilating one of the figures. Would we be able to dilate one figure so that it was the same size as the other? οΊ ο§ 8•3 We would have to perform a translation and a rotation to map figure π onto figure π0 . That is precisely why a dilation alone is not enough to define similarity. Two figures in the plane are similar if one can be mapped onto the other using a finite sequence of dilations or basic rigid motions. This mapping is called a similarity transformation (or a similarity). In this module, we will use the fact that all similarities can be represented as a dilation followed by a congruence. Example 1 (4 minutes) Example 1 π π In the picture below, we have triangle π¨π©πͺ that has been dilated from center πΆ by a scale factor of π = . It is noted by π¨′π©′πͺ′. We also have triangle π¨′′π©′′πͺ′′, which is congruent to triangle π¨′π©′πͺ′ (i.e., β³ π¨′π©′πͺ′ ≅β³ π¨′′π©′′πͺ′′). Describe the sequence that would map triangle π¨′′π©′′πͺ′′ onto triangle π¨π©πͺ. ο§ Scaffolding: Based on the definition of similarity, how could we show that triangle π΄′′π΅′′πΆ′′ is similar to triangle π΄π΅πΆ? οΊ To show that β³ π΄′′ π΅′′ πΆ ′′ ~ β³ π΄π΅πΆ, we need to describe a dilation followed by a congruence. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 Remind students of the work they did in Lesson 3 to bring dilated figures back to their original size. 112 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM ο§ We want to describe a sequence that would map triangle π΄′′π΅′′πΆ′′ onto triangle π΄π΅πΆ. There is no clear way to do this, so let’s begin with something simpler: How can we map triangle π΄′π΅′πΆ′ onto triangle π΄π΅πΆ? That is, what is the precise dilation that would make triangle π΄′π΅′πΆ′ the same size as triangle π΄π΅πΆ? οΊ ο§ MP.6 We need to translate triangle π΄′′′π΅′′′πΆ′′′ 20 units to the left and 2 units down. Let’s use precise language to describe how to map triangle π΄′′π΅′′πΆ′′ onto triangle π΄π΅πΆ. We need information about the dilation and the translation. οΊ ο§ Problem 2 of the Problem Set from Lesson 2 was like this. That is, we had two figures dilated by the same scale factor in different locations on the plane. To get one to map to the other, we just translated along a vector. Now that we have an idea of what needs to be done, let’s describe the translation in terms of coordinates. How many units and in which direction do we need to translate so that triangle π΄′′′π΅′′′πΆ′′′ maps to triangle π΄π΅πΆ? οΊ ο§ A dilation from center π with scale factor π = 2 would make triangle π΄′′π΅′′πΆ′′ the same size as triangle π΄π΅πΆ. (Show the picture below with the dilated triangle π΄′′π΅′′πΆ′′ noted by π΄′′′π΅′′′πΆ′′′.) Now that we know how to make triangle π΄′′π΅′′πΆ′′ the same size as triangle π΄π΅πΆ, what rigid motion(s) should we use to actually map triangle π΄′′π΅′′πΆ′′ onto triangle π΄π΅πΆ? Have we done anything like this before? οΊ ο§ A dilation from center π with scale factor π = 2 Remember, our goal was to describe how to map triangle π΄′′π΅′′πΆ′′ onto triangle π΄π΅πΆ. What precise dilation would make triangle π΄′′π΅′′πΆ′′ the same size as triangle π΄π΅πΆ? οΊ ο§ 8•3 The sequence that would map triangle π΄′′π΅′′πΆ′′ onto triangle π΄π΅πΆ is as follows: Dilate triangle π΄′′π΅′′πΆ′′ from center π by scale factor π = 2. Then, translate the dilated triangle 20 units to the left and 2 units down. Since we were able to map triangle π΄′′π΅′′πΆ′′ onto triangle π΄π΅πΆ with a dilation followed by a congruence, we can write that triangle π΄′′π΅′′πΆ′′ is similar to triangle π΄π΅πΆ, in notation, β³ π΄′′ π΅′′ πΆ ′′ ~ β³ π΄π΅πΆ. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 113 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM 8•3 Example 2 (4 minutes) ο§ In the picture below, we have triangle π·πΈπΉ that has been dilated from center π, by scale factor π = 3. It is noted by π·′ πΈ ′ πΉ ′ . We also have triangle π·′′ πΈ ′′ πΉ ′′ , which is congruent to triangle π·′ πΈ ′ πΉ ′ (i.e., β³ π·′ πΈ ′ πΉ ′ ≅ β³ π·′′πΈ′′πΉ′′). ο§ We want to describe a sequence that would map triangle π·′′πΈ′′πΉ′′ onto triangle π·πΈπΉ. This is similar to what we did in the last example. Can someone summarize the work we did in the last example? οΊ ο§ What is the difference between this problem and the last? οΊ ο§ This time, the scale factor is greater than one, so we need to shrink triangle π·′′πΈ′′πΉ′′ to the size of triangle π·πΈπΉ. Also, it appears as if a translation alone does not map one triangle onto another. Now, since we want to dilate triangle π·′′πΈ′′πΉ′′ to the size of triangle π·πΈπΉ, we need to know what scale factor π to use. Since triangle π·′′πΈ′′πΉ′′ is congruent to π·′πΈ′πΉ′, then we can use those triangles to determine the scale factor needed. We need a scale factor so that |ππΉ| = π|ππΉ′|. What scale factor do you think we should use, and why? οΊ ο§ First, we figured out what scale factor π would make the triangles the same size. Then, we used a sequence of translations to map the magnified figure onto the original triangle. We need a scale factor π = 1 because we want |ππΉ| = π|ππΉ′|. 3 What precise dilation would make triangle π·′′πΈ′′πΉ′′ the same size as triangle π·πΈπΉ? οΊ A dilation from center π with scale factor π = 1 would make triangle π·′′πΈ′′πΉ′′ the same size as triangle 3 π·πΈπΉ. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 114 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 8 8•3 ο§ (Show the picture below with the dilated triangle π·′′πΈ′′πΉ′′ noted by π·′′′πΈ′′′πΉ′′′.) Now we should use what we know about rigid motions to map the dilated version of triangle π·′′πΈ′′πΉ′′ onto triangle π·πΈπΉ. What should we do first? ο§ (Show the picture below, the translated triangle noted in red.) What should we do next (refer to the translated triangle as the red triangle)? οΊ οΊ We should translate triangle π·′′′πΈ′′′πΉ′′′ 2 units to the right. Next, we should reflect the red triangle across the π₯-axis to map the red triangle onto triangle π·πΈπΉ. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 115 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM ο§ 8•3 Use precise language to describe how to map triangle π·′′πΈ′′πΉ′′ onto triangle π·πΈπΉ. οΊ The sequence that would map triangle π·′′πΈ′′πΉ′′ onto triangle π·πΈπΉ is as follows: Dilate triangle 1 3 MP.6 π·′′πΈ′′πΉ′′ from center π by scale factor π = . Then, translate the dilated image of triangle π·′′πΈ′′πΉ′′, noted by π·′′′ πΈ ′′′ πΉ ′′′ , two units to the right. Finally, reflect across the π₯-axis to map the red triangle onto triangle π·πΈπΉ. ο§ Since we were able to map triangle π·′′πΈ′′πΉ′′ onto triangle π·πΈπΉ with a dilation followed by a congruence, we can write that triangle π·′′πΈ′′πΉ′′ is similar to triangle π·πΈπΉ. (In notation: β³ π·′′πΈ′′πΉ′′~ β³ π·πΈπΉ) Example 3 (3 minutes) ο§ In the diagram below, β³ π΄π΅πΆ ~ β³ π΄′π΅′πΆ′. Describe a sequence of a dilation followed by a congruence that would prove these figures to be similar. ο§ Let’s begin with the scale factor. We know that π|π΄π΅| = |π΄′π΅′|. What scale factor π makes β³ π΄π΅πΆ the same size as β³ π΄′π΅′πΆ′? οΊ We know that π ⋅ 2 = 1; therefore, π = Lesson 8: 1 makes β³ π΄π΅πΆ the same size as β³ π΄′ π΅′ πΆ ′ . 2 Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 116 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM ο§ 8•3 1 2 If we apply a dilation from the origin of scale factor π = , then the triangles are the same size (as shown and noted by triangle π΄′′π΅′′πΆ′′). What sequence of rigid motions would map the dilated image of β³ π΄π΅πΆ onto β³ π΄′π΅′πΆ′? οΊ ο§ We could translate the dilated image of β³ π΄π΅πΆ, β³ π΄′′π΅′′πΆ′′, 3 units to the right and 4 units down and then reflect the triangle across line π΄′π΅′. The sequence that would map β³ π΄π΅πΆ onto β³ π΄′π΅′πΆ′ to prove the figures similar is a dilation from the origin by 1 2 scale factor π = , followed by the translation of the dilated version of β³ π΄π΅πΆ 3 units to the right and 4 units down, followed by the reflection across line π΄′π΅′. Example 4 (4 minutes) ο§ In the diagram below, we have two similar figures. Using the notation, we have β³ π΄π΅πΆ ~ β³ π·πΈπΉ. We want to describe a sequence of the dilation followed by a congruence that would prove these figures to be similar. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 117 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM 8•3 ο§ First, we need to describe the dilation that would make the triangles the same size. What information do we have to help us describe the dilation? Μ Μ Μ Μ , we can determine the scale factor. οΊ Since we know the length of side Μ Μ Μ Μ π΄πΆ and side π·πΉ ο§ Μ Μ Μ Μ is Can we use any two sides to calculate the scale factor? Assume, for instance, that we know that side π΄πΆ Μ Μ Μ Μ and Μ Μ Μ Μ is 2 units in length. Could we find the scale factor using those two sides, π΄πΆ 18 units in length and side πΈπΉ Μ Μ Μ Μ ? Why or why not? πΈπΉ οΊ No, we need more information about corresponding sides. Sides Μ Μ Μ Μ π΄πΆ and Μ Μ Μ Μ π·πΉ are the longest sides of each triangle (they are also opposite the obtuse angle in the triangle). Side Μ Μ Μ Μ π΄πΆ does not correspond to Μ Μ Μ Μ , we could use sides π΅πΆ Μ Μ Μ Μ and πΈπΉ Μ Μ Μ Μ . If we knew the length of side π΅πΆ Μ Μ Μ Μ . side πΈπΉ ο§ Now that we know that we can find the scale factor if we have information about corresponding sides, how would we calculate the scale factor if we were mapping β³ π΄π΅πΆ onto β³ π·πΈπΉ? οΊ ο§ If we were mapping β³ π·πΈπΉ onto β³ π΄π΅πΆ, what would the scale factor be? οΊ ο§ |π΄πΆ| = π|π·πΉ|, so 18 = π ⋅ 6, and π = 3. What is the precise dilation that would map β³ π΄π΅πΆ onto β³ π·πΈπΉ? οΊ ο§ 1 3 |π·πΉ| = π|π΄πΆ|, so 6 = π ⋅ 18, and π = . 1 3 Dilate β³ π΄π΅πΆ from center π, by scale factor π = . (Show the picture below with the dilated triangle noted as β³ π΄′π΅′πΆ′.) Now we have to describe the congruence. Work with a partner to determine the sequence of rigid motions that would map β³ π΄π΅πΆ onto β³ π·πΈπΉ. οΊ Translate the dilated version of β³ π΄π΅πΆ 7 units to the right and 2 units down. Then, rotate π degrees around point πΈ so that segment π΅′πΆ′ maps onto segment πΈπΉ. Finally, reflect across line πΈπΉ. Note that “π degrees” refers to a rotation by an appropriate number of degrees to exhibit similarity. Students may choose to describe this number of degrees in other ways. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 118 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM ο§ 8•3 The sequence of a dilation followed by a congruence that proves β³ π΄π΅πΆ ~ β³ π·πΈπΉ is as follows: Dilate β³ π΄π΅πΆ 1 3 from center π by scale factor π = . Translate the dilated version of β³ π΄π΅πΆ 7 units to the right and 2 units down. Next, rotate around point πΈ by π degrees so that segment π΅′πΆ′ maps onto segment πΈπΉ, and then reflect the triangle across line πΈπΉ. Example 5 (3 minutes) ο§ Knowing that a sequence of a dilation followed by a congruence defines similarity also helps determine if two figures are in fact similar. For example, would a dilation map triangle π΄π΅πΆ onto triangle π·πΈπΉ (i.e., is β³ π΄π΅πΆ ~ β³ π·πΈπΉ)? οΊ No. By FTS, we expect the corresponding side lengths to be in proportion and equal to the scale factor. When we compare side Μ Μ Μ Μ π΄πΆ to side Μ Μ Μ Μ π·πΉ and Μ Μ Μ Μ π΅πΆ to Μ Μ Μ Μ πΈπΉ , we get οΊ 18 6 ≠ 15 4 . Therefore, the triangles are not similar because a dilation does not map one to the other. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 119 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM 8•3 Example 6 (3 minutes) ο§ Again, knowing that a dilation followed by a congruence defines similarity also helps determine if two figures are in fact similar. For example, would a dilation map Figure π΄ onto Figure π΄′ (i.e., is Figure π΄ ~ Figure π΄′)? οΊ No. Even though we could say that the corresponding sides are in proportion, there exists no single rigid motion or sequence of rigid motions that would map a four-sided figure to a three-sided figure. Therefore, the figures do not fulfill the congruence part of the definition for similarity, and Figure π΄ is not similar to Figure π΄′. Exercises (10 minutes) Allow students to work in pairs to describe sequences that map one figure onto another. Exercises 1. π Triangle π¨π©πͺ was dilated from center πΆ by scale factor π = . The dilated triangle is noted by π¨′π©′πͺ′. Another π triangle π¨′′π©′′πͺ′′ is congruent to triangle π¨′π©′πͺ′ (i.e., β³ π¨′′π©′′πͺ′′ ≅β³ π¨′π©′πͺ′). Describe a dilation followed by the basic rigid motion that would map triangle π¨′′π©′′πͺ′′ onto triangle π¨π©πͺ. Triangle π¨′′π©′′πͺ′′ needs to be dilated from center πΆ, by scale factor π = π to bring it to the same size as triangle π¨π©πͺ. This produces a triangle noted by π¨′′′π©′′′πͺ′′′. Next, triangle π¨′′′π©′′′πͺ′′′ needs to be translated π units up and ππ units left. The dilation followed by the translation maps triangle π¨′′π©′′πͺ′′ onto triangle π¨π©πͺ. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 120 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM 2. 8•3 Describe a sequence that would show β³ π¨π©πͺ ~ β³ π¨′ π©′ πͺ′ . Since π|π¨π©| = |π¨′ π©′ |, then π ⋅ π = π, and π = π. A dilation from the origin by scale factor π = π makes β³ π¨π©πͺ the same size as β³ π¨′π©′πͺ′. Then, a translation of the dilated image of β³ π¨π©πͺ ten units right and five units down, followed by a rotation of ππ degrees around point πͺ′ , maps β³ π¨π©πͺ onto β³ π¨′ π©′ πͺ′ , proving the triangles to be similar. 3. Are the two triangles shown below similar? If so, describe a sequence that would prove β³ π¨π©πͺ ~ β³ π¨′π©′πͺ′. If not, state how you know they are not similar. Yes, β³ π¨π©πͺ ~ β³ π¨′π©′πͺ′. The corresponding sides are in proportion and equal to the scale factor: ππ π ππ π = = = =π ππ π ππ π π To map triangle π¨π©πͺ onto triangle π¨′π©′πͺ′, dilate triangle π¨π©πͺ from center πΆ, by scale factor π = . Then, translate π triangle π¨π©πͺ along vector βββββββ π¨π¨′. Next, rotate triangle π¨π©πͺ π degrees around point π¨. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 121 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM 4. Lesson 8 8•3 Are the two triangles shown below similar? If so, describe the sequence that would prove β³ π¨π©πͺ ~ β³ π¨′π©′πͺ′. If not, state how you know they are not similar. Yes, triangle β³ π¨π©πͺ ~ β³ π¨′π©′πͺ′. The corresponding sides are in proportion and equal to the scale factor: π π π ππ. ππ π Μ ; = = = π. ππ = π. πππππ; therefore, π = π. ππ which is approximately equal to π π π π π π To map triangle π¨π©πͺ onto triangle π¨′π©′πͺ′, dilate triangle π¨π©πͺ from center πΆ, by scale factor π = . Then, translate π triangle π¨π©πͺ along vector βββββββ π¨π¨′. Next, rotate triangle π¨π©πͺ πππ degrees around point π¨′. Closing (4 minutes) Summarize, or ask students to summarize, the main points from the lesson. ο§ We know that a similarity can be represented as a sequence of a dilation followed by a congruence. ο§ To show that a figure in the plane is similar to another figure of a different size, we must describe the sequence of a dilation followed by a congruence (one or more rigid motions) that maps one figure onto another. Lesson Summary A similarity transformation (or a similarity) is a sequence of a finite number of dilations or basic rigid motions. Two figures are similar if there is a similarity transformation taking one figure onto the other figure. Every similarity can be represented as a dilation followed by a congruence. The notation β³ π¨π©πͺ ~ β³ π¨′ π©′ πͺ′ means that β³ π¨π©πͺ is similar to β³ π¨′π©′πͺ′. Exit Ticket (5 minutes) Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 122 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM Name 8•3 Date Lesson 8: Similarity Exit Ticket 1 2 In the picture below, we have triangle π·πΈπΉ that has been dilated from center π by scale factor π = . The dilated triangle is noted by π·′πΈ′πΉ′. We also have a triangle π·′′πΈπΉ, which is congruent to triangle π·πΈπΉ (i.e., β³ π·πΈπΉ ≅β³ π·′′πΈπΉ). Describe the sequence of a dilation followed by a congruence (of one or more rigid motions) that would map triangle π·′πΈ′πΉ′ onto triangle π·′′πΈπΉ. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 123 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 8 8•3 Exit Ticket Sample Solutions π In the picture below, we have triangle π«π¬π that has been dilated from center πΆ by scale factor π = . The dilated π triangle is noted by π«′π¬′π′. We also have a triangle π«′′π¬π, which is congruent to triangle π«π¬π (i.e., β³ π«π¬π ≅β³ π«′′π¬π). Describe the sequence of a dilation, followed by a congruence (of one or more rigid motions), that would map triangle π«′π¬′π′ onto triangle π«′′π¬π. Triangle π«′π¬′π′ needs to be dilated from center πΆ by scale factor π = π to bring it to the same size as triangle π«π¬π. This produces the triangle noted by π«π¬π. Next, triangle π«π¬π needs to be reflected across line π¬π. The dilation followed by the reflection maps triangle π«′π¬′π′ onto triangle π«′′π¬π. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 124 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 8 8•3 Problem Set Sample Solutions Students practice dilating a curved figure and describing a sequence of a dilation followed by a congruence that maps one figure onto another. 1. In the picture below, we have triangle π«π¬π that has been dilated from center πΆ by scale factor π = π. It is noted by π«′π¬′π′. We also have triangle π«′′π¬′′π′′, which is congruent to triangle π«′π¬′π′ (i.e., β³ π«′π¬′π′ ≅β³ π«′′π¬′′π′′). Describe the sequence of a dilation, followed by a congruence (of one or more rigid motions), that would map triangle π«′′π¬′′π′′ onto triangle π«π¬π. π to shrink it to the size of triangle π«π¬π. Next, we must π translate the dilated triangle, noted by π«′′′π¬′′′π′′′, one unit up and two units to the right. This sequence of the dilation followed by the translation would map triangle π«′′π¬′′π′′ onto triangle π«π¬π. First, we must dilate triangle π«′′π¬′′π′′ by scale factor π = Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 125 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM 2. Lesson 8 8•3 π Triangle π¨π©πͺ was dilated from center πΆ by scale factor π = . The dilated triangle is noted by π¨′π©′πͺ′. Another π triangle π¨′′π©′′πͺ′′ is congruent to triangle π¨′π©′πͺ′ (i.e., β³ π¨′′π©′′πͺ′′ ≅β³ π¨′π©′πͺ′). Describe the dilation followed by the basic rigid motions that would map triangle π¨′′π©′′πͺ′′ onto triangle π¨π©πͺ. Triangle π¨′′π©′′πͺ′′ needs to be dilated from center πΆ by scale factor π = π to bring it to the same size as triangle π¨π©πͺ. This produces a triangle noted by π¨′′′π©′′′πͺ′′′. Next, triangle π¨′′′π©′′′πͺ′′′ needs to be translated ππ units to the right and two units down, producing the triangle shown in red. Next, rotate the red triangle π degrees around point π© so that one of the segments of the red triangle coincides completely with segment π©πͺ. Then, reflect the red triangle across line π©πͺ. The dilation, followed by the congruence described, maps triangle π¨′′π©′′πͺ′′ onto triangle π¨π©πͺ. 3. Are the two figures shown below similar? If so, describe a sequence that would prove the similarity. If not, state how you know they are not similar. No, these figures are not similar. There is no single rigid motion, or sequence of rigid motions, that would map Figure π¨ onto Figure π©. 4. Triangle π¨π©πͺ is similar to triangle π¨′π©′πͺ′ (i.e., β³ π¨π©πͺ ~ β³ π¨′π©′πͺ′). Prove the similarity by describing a sequence that would map triangle π¨′π©′πͺ′ onto triangle π¨π©πͺ. The scale factor that would magnify triangle π¨′π©′πͺ′ to the size of triangle π¨π©πͺ is π = π. The sequence that would prove the similarity of the triangles is a dilation from center πΆ by a scale factor of π = π, followed by a translation along vector βββββββ π¨′ π¨, and finally, a reflection across line π¨πͺ. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 126 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM 5. Lesson 8 8•3 Are the two figures shown below similar? If so, describe a sequence that would prove β³ π¨π©πͺ ~ β³ π¨′π©′πͺ′. If not, state how you know they are not similar. π Yes, the triangles are similar. The scale factor that triangle π¨π©πͺ has been dilated is π = . The sequence that π proves the triangles are similar is as follows: dilate triangle π¨′π©′πͺ′ from center πΆ by scale factor π = π; then, translate triangle π¨′π©′πͺ′ along vector ββββββ πͺ′πͺ; next, rotate triangle π¨′π©′πͺ′ π degrees around point πͺ; and finally, reflect triangle π¨′π©′πͺ′ across line π¨πͺ. 6. Describe a sequence that would show β³ π¨π©πͺ ~ β³ π¨′ π©′ πͺ′ . π π Since π|π¨π©| = |π¨′ π©′ |, then π ⋅ π = π and π = . A dilation from the origin by scale factor π = makes β³ π¨π©πͺ the π π same size as β³ π¨′π©′πͺ′. Then, a translation of the dilated image of β³ π¨π©πͺ four units down and one unit to the right, followed by a reflection across line π¨′ π©′ , maps β³ π¨π©πͺ onto β³ π¨′ π©′ πͺ′ , proving the triangles to be similar. Lesson 8: Similarity This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 127 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.