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Mu Alpha Theta 2012 Nationals
1. B
2. D
3. E
4. A
5. B
6. C
7. C
8. B
9. E
10. C
11. A
12. D
13. D
14. B
15. C THROWN OUT
16. E
17. A
18. A
19. C
20. D
21. B
22. E
23. D
24. A
25. A
26. B
27. C
28. C
29. E
30. E
Mathematics in Medicine
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
1. Sodium diatrizoate (SD) is a nonvolatile, water soluble X-ray contrast agent used for imaging
of the gastrointestinal tract. A 0.378 m solution is prepared by dissolving 38.4 g of SD in 160.
mL of water at 31.2 ̊C. The density of water at this temperature is 0.995 g/mL. What is the
molar mass of SD?
a. 638.1 g/mol.
38.4 g SD
mL H2O
1000 g H2O
1 kg H2O
g
(
)(
)(
)(
) = 638.1
160 mL H2O . 995g H2O
1 kg
. 378 mol SD
mol
2. Almost all drugs that are accumulated in the body do so by passive diffusion across the cell
membranes. Therefore lipid solubility is a key factor in passive movement of drugs. As a
result of this, drug companies must take this into account when manufacturing their drugs
in order to ensure that the drugs reaches the correct compartment of the body and is able
to have its desired effect. Knowing that aspirin is an acidic drug with a pK of 3.4. What
percentage will be uncharged at the pH of the blood (7.4)?
a. 0.01%
Acidic Drug: HA οƒ  A- + H+
π‘’π‘›π‘β„Žπ‘Žπ‘Ÿπ‘”π‘’π‘‘
log
= 𝑝𝐾 − 𝑝𝐻 = 3.4 − 7.4 = −4.0
π‘β„Žπ‘Žπ‘Ÿπ‘Žπ‘”π‘’π‘‘
π‘ˆπ‘›π‘β„Žπ‘Žπ‘Ÿπ‘”π‘’π‘‘
= 10−4 = 0.0001 π‘₯ 100 = .01 % π‘’π‘›π‘β„Žπ‘Žπ‘Ÿπ‘”π‘’π‘‘
πΆβ„Žπ‘Žπ‘Ÿπ‘”π‘’π‘‘
3. One of the most important factors that determines
the amount of blood flow to a particular organ is
peripheral vascular resistance. Peripheral vascular
△𝑃
resistance can be defined as πΆπ‘Žπ‘Ÿπ‘‘π‘–π‘Žπ‘ 𝑂𝑒𝑑𝑝𝑒𝑑 . Using the
picture to the right about how many times greater is
the systemic peripheral vascular resistance greater
than the pulmonary vascular resistance? Normal
cardiac output is 5 L/min.
a. 9.8 times
15 − 5
=2
5
100 − 2
π‘†π‘¦π‘ π‘‘π‘’π‘šπ‘–π‘ 𝑇𝑃𝑅 =
= 19.6
5
19.6
= 9.8 π‘‘π‘–π‘šπ‘’π‘ 
2
π‘ƒπ‘’π‘™π‘šπ‘œπ‘›π‘Žπ‘Ÿπ‘¦ 𝑇𝑃𝑅 =
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
4. In a given population, only the "A" and "B" alleles are present in the ABO system; there are
no individuals with type "O" blood or with O alleles in this particular population. If 200
people have type A blood, 75 have type AB blood, and 25 have type B blood, what are the
allelic frequencies of this population?
a. P=.79; q=.21
475
𝑝=
= .79; π‘ž = 1 − 𝑝 = 1 − .79 = .21
600
5. A standard solution is prepared for the analysis of fluoxymesterone (C20H29FO3), an anabolic
steroid. The molecular weight of fluoxymesterone is 336 g/mol. A stock solution is first
prepared by dissolving 25.0 mg of fluoxymesterone in enough water to give a total volume
of 500.0 mL. A 100.0-µL aliquot (portion) of this solution is diluted to a final volume of 100.0
mL. What is the concentration of the final solution in terms of molarity?
a. 1.49 x 10-7 M.
1𝑔
1 π‘šπ‘œπ‘™
1
25 π‘šπ‘” π‘₯ (1000 π‘šπ‘”) ( 336 𝑔 ) (0.5 𝐿) = 1.488 π‘₯ 10-4 M
1𝐿
100 µπΏ π‘₯ (106 µπΏ) (
1.488 π‘₯ 10−4 π‘šπ‘œπ‘™
1𝐿
6. In the heart, when a valve opens the two
compartments connected to that valve
should become equal in pressure. In certain
circumstances, heart valves either become
regurgitant (leaky) or stenotic (unable to
open). Looking at the hemodynamic curve to
the right, what is the most likely diagnosis?
(LVP = Left Ventricular Pressure; AP = Aortic
Pressure; LAP = Left Atrial Pressure)
a. Aortic Stenosis
1
) (0.1 𝐿) = 1.49 π‘₯ 10-7 M
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
7. Blood alcohol (C2H5OH; mw = 46 g/mol) level can be determined by titrating a sample of
blood plasma with an acidic dichromate solution. If 35.46 mL of 0.05961 M Cr2O72- solution
is required to titrate 28.00 g of blood plasma, determine the mass percent of alcohol in the
blood. The balanced redox equation is
16 H+ (aq) + 2 Cr2O72- (aq) + C2H5OH (aq) οƒ  4 Cr3+ (aq) + 2 CO2 (g) + 11 H2O (l)
a. 0.17%
0.05961 π‘šπ‘šπ‘œπ‘™ πΆπ‘Ÿ2 𝑂72− 1 π‘šπ‘šπ‘œπ‘™ 𝐢2 𝐻5 𝑂𝐻 46 π‘šπ‘” 𝐢2 𝐻5 𝑂𝐻
1𝑔
35.46 π‘šπΏ π‘₯ (
)(
)(
)(
)
2−
π‘šπΏ
π‘šπ‘šπ‘œπ‘™
1000 π‘šπ‘”
2 π‘šπ‘šπ‘œπ‘™ πΆπ‘Ÿ2 𝑂7
= 4.86 π‘₯ 10−2 𝑔 𝐢2 𝐻5 𝑂𝐻
4.86 π‘₯ 10−2 𝑔
π‘₯ 100 = 0.17%
28.00 𝑔
8. A patient comes to your office with a history of asthma. You decide to prescribe terbutaline,
a drug that opens up air passages in the lung. In order for the drug to be effective you must
have a concentration of 2 µg/L in the body. Therefore you must account for the volume of
distribution being 1.79 L/kg (volume of distribution is a theoretical volume in which the
total amount of drug would need to be uniformly distributed to produce the desired blood
concentration) and the oral bioavailability of this drug being 0.14 (bioavailability is a
measurement of the extent to which a drug reaches the systemic circulation). What would
be the appropriate loading dose for orally administered terbutaline for an 80 kg patient?
a. 2 mg
π‘‡π‘Žπ‘Ÿπ‘”π‘’π‘‘ πΆπ‘œπ‘›π‘π‘’π‘›π‘‘π‘Žπ‘‘π‘–π‘œπ‘› π‘₯ π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘’π‘π‘‘π‘–π‘œπ‘›
2 π‘₯ 1.79 π‘₯ 80
=
π‘‚π‘Ÿπ‘Žπ‘™ π΅π‘–π‘œπ‘Žπ‘£π‘Žπ‘–π‘™π‘Žπ‘π‘–π‘™π‘‘π‘¦
0.14
= 2 π‘šπ‘”
πΏπ‘œπ‘Žπ‘‘π‘–π‘›π‘” π·π‘œπ‘ π‘’ =
9. Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked condition common
among Mediterranean and African peoples. Glucose-6-phosphate dehydrogenase
deficiency is a condition in which red blood cells break down when the body is exposed to
certain drugs or the stress of an infection. If 6.7% of Turkish-Cypriot men were found to
have G6PD deficiency, what percentage of women are carriers for the abnormal gene?
a. 12.5%
𝑝 + π‘ž = 1; 1 − 0.067 = 0.933
2π‘π‘ž = 2 π‘₯ 0.067 π‘₯ 0.933 = 0.125 π‘₯ 100 = 12.5%
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
10. One of the most important things that all
doctors must be able to do is to be able to
detect abnormal heart sounds when listening
to a patient’s heart. You are in the clinic and
you think that you hear a slight murmur (a
murmur is an abnormal heart sound
produced as a result of turbulent flow over an
abnormal valve). You decide to send your
patient to get a hemodynamic workup. Based
on the curve to the right, which graph would
best represent the heart sound you would have heard? (S1 = Atrio-ventricular valves
closing; S2 = Aortic / Pulmonic Valves closing; LVP = Left Ventricular Pressure; AP = Aortic
Pressure; LAP = Left Atrial Pressure)
a.
11. One of the most important functions of our
blood is to carry oxygen to all of the organs in
the body. In the average human there is 15 g of
Hb/ dL. Using the curve to the right, what would
be the total O2 content if a person is breathing
100% O2 at 673 mmHg? (A gram of Hb can carry
about 1.34 mL of O2; dissolved O2 in blood is
0.003 mL/dL/mmHg)
a. 22.1 mL/dL
𝑂2 πΆπ‘Žπ‘Ÿπ‘Ÿπ‘–π‘’π‘‘ 𝑏𝑦 𝐻𝑏 = 100% π‘₯ 15 π‘₯ 1.34
= 20.1 π‘šπΏ/𝑑𝐿
π·π‘–π‘ π‘ π‘œπ‘™π‘£π‘’π‘‘ 𝑂2 = 0.003 π‘₯ 673 = 2.0 π‘šπΏ /𝑑𝐿
π‘‡π‘œπ‘‘π‘Žπ‘™ 𝑂2 π‘π‘œπ‘›π‘‘π‘’π‘›π‘‘ = 2 + 20.1 = 22.1 π‘šπΏ/𝑑𝐿
12. A pregnant female at 8 weeks post last menstrual period visits her OB for prenatal care. This
is her first pregnancy. She is affected with sickle cell anemia, an autosomal recessive
disorder characterized by hemolytic anemia and intermittent episodes of vascular occlusion
causing pain and swelling of the hands and feet, as well as chronic organ dysfunction. Her
partner’s hemoglobin is normal, ruling out both disease and carrier status. The offspring of
this couple are expected to be:
a. 100% carriers
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
13. The human eye is a complex sensing device for visible light. The optic nerve needs a
minimum of 2.0 x 10-17 J of energy to trigger a series of impulses that eventually reach the
brain. How many photons of red light (700 nm) are needed to stimulate an impulse?
(Planck’s Constant = 6.626 x 10-34 Js; Speed of light = 3 x 108 m/s)
a. 71 photons
(6.626 π‘₯ 10−34 )π‘₯ (3 π‘₯ 108 )
β„Žπ‘₯𝑐
𝐸=
=
= 2.84 π‘₯ 10−19 𝐽/π‘β„Žπ‘œπ‘‘π‘œπ‘›
−9
πœ†
700 π‘₯ 10
2 π‘₯ 10−17
= 70.4 π‘β„Žπ‘œπ‘‘π‘œπ‘›π‘  = 71
2.84 π‘₯ 10−19
14. During times of high strenuous exercise, the body regulates blood flow and diverts blood
and nutrients to where the body needs them. During these periods of high physical activity
the body can increase the amount of blood flow to skeletal muscles 10x more than at rest.
In order to assist the body in getting blood to the skeletal muscles, the heart contracts more
often and with greater force. Given the information in the following table, what is the end
diastolic volume during strenuous exercise (the amount of fluid in the heart after the
ventricle fills with blood)?
Cardiac Output
Heart Rate
Ejection Fraction
Arterial Pressure
Central Venous Pressure
Rest
6 L/min
70 beats per minute
60%
120/80 mmHg
2 mmHg
Strenuous Exercise
18 L / min
160 beats per minute
80%
150/80 mmHg
2 mmHg
a. 141 mL
πΆπ‘Žπ‘Ÿπ‘‘π‘–π‘Žπ‘ 𝑂𝑒𝑑𝑝𝑒𝑑
18
=
= 113 π‘šπΏ π‘π‘’π‘Ÿ π‘π‘’π‘Žπ‘‘
π»π‘’π‘Žπ‘Ÿπ‘‘ π‘…π‘Žπ‘‘π‘’
160
π‘†π‘‘π‘Ÿπ‘œπ‘˜π‘’ π‘‰π‘œπ‘™π‘’π‘šπ‘’
113
𝐸𝑛𝑑 π·π‘–π‘Žπ‘ π‘‘π‘œπ‘™π‘–π‘ π‘‰π‘œπ‘™π‘’π‘šπ‘’ =
=
= 141 π‘šπΏ
πΈπ‘—π‘’π‘π‘‘π‘–π‘œπ‘› πΉπ‘Ÿπ‘Žπ‘π‘‘π‘–π‘œπ‘›
.8
π‘†π‘‘π‘Ÿπ‘œπ‘˜π‘’ π‘‰π‘œπ‘™π‘’π‘šπ‘’ =
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
15. Ellie's daughter, Francis, has bilateral cleft lip with cleft palate. Family history reveals that
Ellie’s mother, Dina, has two pits in her lower
lip, as does his sister, Donna. A complete
Ch
physical examination of Ellie, by a clinical
Lip
geneticist, reveals a normal palate, normal
pits arl
es
teeth and no lower lip pits. Given the family
history, Francis is diagnosed with Van der
Do Lip
D
Lip
Woude Syndrome, a condition with 80%
i
pits nn pits
penetrance. What is Ellie’s chance of having
a
n
another affected child?
a
2
E
a.
5
There is a 50 % chance than Ellie
passes the gene on and there is an
80% penetrance.
1 4 2
π‘₯ =
2 5 5
Normal
ll
physical
exam,
i
but has the
affected
gene
e
Fran
?
Bilateral cleft
cis
lip/palate
16. Total blood cholesterol level, or technically
“serum” or “plasma” cholesterol, is the concentration of cholesterol in the serum or plasma
portion of the blood. Desirable levels are <200 mg/dL, borderline high is 200-239 mg/dL,
and high risk is >240 mg/dL. Consider a hypothetical male weighing 186 lbs with serum
cholesterol of 216 mg/dL. The total amount of cholesterol in this person’s blood would be
equivalent to the total amount of cholesterol in how many dozens of eggs? Serum or
plasma comprises 55% of blood by volume. (There are 4.7 L of blood per 160 lbs; average
cholesterol per egg is 215 mg).
a. 2.5 dozen eggs
4.7 𝐿
186 𝑙𝑏𝑠 π‘₯ 160 𝑙𝑏𝑠 π‘₯
2.5 π‘‘π‘œπ‘§π‘’π‘› 𝑒𝑔𝑔𝑠
.55 𝐿 π‘œπ‘“ π‘π‘™π‘Žπ‘ π‘šπ‘Ž
1 𝐿 π‘π‘™π‘œπ‘œπ‘‘
π‘₯
10 𝑑𝐿 π‘π‘™π‘Žπ‘ π‘šπ‘Ž
1 𝐿 π‘π‘™π‘Žπ‘ π‘šπ‘Ž
π‘₯
216 π‘šπ‘” π‘β„Žπ‘œπ‘™π‘’π‘ π‘‘π‘’π‘Ÿπ‘œπ‘™
1 𝑑𝐿 π‘π‘™π‘Žπ‘ π‘šπ‘Ž
π‘₯
1 𝑒𝑔𝑔
215 π‘šπ‘” π‘œπ‘“ π‘β„Žπ‘œπ‘™π‘’π‘ π‘‘π‘’π‘Ÿπ‘œπ‘™
π‘₯
1 π‘‘π‘œπ‘§π‘’π‘›
12 𝑒𝑔𝑔𝑠
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
17. One of the most concerning findings for a clinical
geneticist is to discover a high level of inbreeding
within a family. Inbreeding within a family leads to
less gene transfer and an increased chance of
recessive alleles to come together in order to cause
a genetic defect. A clinical geneticist begins to
counsel two patients, an uncle and niece who got
married and are currently pregnant. The uncle has
a sister with a recessive disorder. What is the
chance that their baby will have the same disorder?
1
a.
18
The uncle has a 66% chance of carrying the
recessive allele. The niece has a 33% chance of carrying the recessive allele. If both
parents carry the allele, then there is a 25% chance that the child will receive the
recessive alleles from both the cousin and uncle.
2 1 1
1
π‘₯ π‘₯ =
3 3 4 18
18. Hemoglobin is the protein that transports O2 through the blood from the lungs to the rest of
the body. In doing so, each molecule of hemoglobin combines with four molecules of O 2. If
1.00 g of hemoglobin combines with 1.53 mL of O2 at 37 ̊C and 0.978 atm, what is the molar
𝐿 π‘₯ π‘Žπ‘‘π‘š
mass of hemoglobin? (The gas constant is 0.08206 𝐾 π‘₯ π‘šπ‘œπ‘™).
a. 6.8 x 104 g/mol
𝑃π‘₯𝑉
. 978 π‘₯ (1.53 π‘₯ 10−3 )
𝑛=
=
= 5.88 π‘₯ 10−5 π‘šπ‘œπ‘™ 𝑂2
𝑅π‘₯𝑇
. 08206 π‘₯ 310.15
1 π‘šπ‘œπ‘™ π‘œπ‘“ β„Žπ‘’π‘šπ‘œπ‘”π‘™π‘œπ‘π‘–π‘›
= 1.47 π‘₯ 10−5 π‘šπ‘œπ‘™ β„Žπ‘’π‘šπ‘œπ‘”π‘™π‘œπ‘π‘–π‘›
4 π‘šπ‘œπ‘™ π‘œπ‘“ 𝑂2
1.00 𝑔 β„Žπ‘’π‘šπ‘œπ‘”π‘™π‘œπ‘π‘–π‘›
= 6.80 π‘₯ 104 𝑔/π‘šπ‘œπ‘™
1.47 π‘₯ 10−5
5.88 π‘₯ 10−5 π‘₯
19. The ability to taste the chemical phenylthiocarbamide is an autosomal dominant
phenotype, and the inability to taste it is recessive. If a taster woman with a nontaster
father marries a taster man who in a previous had a nontaster daughter, what is the
probability that their first child will be a taster boy?
a. 3/8
𝑝 (π‘‘π‘Žπ‘ π‘‘π‘’π‘Ÿ π‘π‘œπ‘¦) = 𝑝 (π‘‘π‘Žπ‘ π‘‘π‘’π‘Ÿ)π‘₯ 𝑝 (π‘π‘œπ‘¦) =
3 1
3
π‘₯ =
4 2
8
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
20. On the graph showing left ventricular
volume and pressure, at which point
does the aortic valve close?
a. 4
21. Edema can be caused by many things in
the human body such as: increased
hydrostatic pressure, reduced oncotic
pressure, increased tissue oncotic
pressure, increased blood vessel
permeability, and obstruction in fluid
clearance. In a capillary, the pressure is
30 mmHg and the oncotic pressure is 25 mmHg. In the surrounding interstitial space, the
pressure is -2 mmHg and the oncotic pressure is 2 mmHg. What is the direction of fluid
movement and the net driving force?
a. 9 mmHg; Filtration out of the capillary
Net Pressure = (Pc – Pi) – (πc – πi) = [(30 – (-2) – (25 – 2)] = + 9 mmHg
22. John and Martha are contemplating having children, but John’s brother has galactosemia
(an autosomal recessive disease in which the body is unable to metabolize the sugar
galactose) and Martha’s great grandmother also had galactosemia. Martha has a sister who
has three children, none of whom have galactosemia. What is the probability that John and
Martha’s first child will have galactossemia?
a. 1/24
𝑝 (π‘β„Žπ‘–π‘™π‘‘ β„Žπ‘Žπ‘  π‘”π‘Žπ‘™π‘Žπ‘π‘‘π‘œπ‘ π‘’π‘šπ‘–π‘Ž)
= 𝑝 (π½π‘œβ„Žπ‘› 𝑖𝑠 𝐺𝑔)π‘₯ 𝑝 (π‘€π‘Žπ‘Ÿπ‘‘β„Žπ‘Ž 𝑖𝑠 𝐺𝑔) π‘₯ 𝑝(π‘π‘œπ‘‘β„Ž π‘π‘Žπ‘Ÿπ‘’π‘›π‘‘π‘  π‘π‘Žπ‘ π‘  π‘œπ‘› π‘‘β„Žπ‘’ 𝑔𝑒𝑛𝑒)
2 1 1
= π‘₯ π‘₯ = 1/24
3 4 4
23. Cardiac output of the right side of the heart is what percentage of the cardiac output of the
left side of the heart?
a. 100%; Blood ejected from the left side of the heart to the systemic circulation
must be oxygenated by passage through the pulmonary circulation.
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
24. Duchenne muscular dystrophy is sex-linked and usually affects only males. Victims of the
disease become progressively weaker, starting in early life. If your father’s brother had the
disease, what is the probability that you have received the allele?
a. 0%
Because your father does not have the disease, you cannot inherit the allele from
him. Therefore, the probability of inheriting an allele will be based on the chance
that your mother is heterozygous. Since she is unrelated to the pedigree, assume
that this is zero.
25. Cardiac output, the volume of blood ejected per minute, can be measured by looking at the
oxygen content found in the venous and arterial blood. The following measurements were
obtained in a male patient:
Central Venous Pressure
Heart Rate
Pulmonary Vein [O2]
Pulmonary Artery [O2]
Whole Body O2 Consumption
10 mmHg
70 beats/min
0.24 mL O2 / mL
0.16 mL O2 / mL
500 mL / min
What is the patient’s cardiac output?
a. 6.25 L / min
πΆπ‘Žπ‘Ÿπ‘‘π‘–π‘Žπ‘ 𝑂𝑒𝑑𝑝𝑒𝑑 =
500
= 6250 π‘šπΏ/ min π‘œπ‘Ÿ 6.25 𝐿/π‘šπ‘–π‘›
. 24 − .16
26. A couple who are about to get married learn from studying their family histories that, in
both their families, their unaffected grandparents had siblings with cystic fibrosis (a rare
autosomal recessive disease that causes a sticky mucus to build up in the lungs and the
digestive tract). If they have four children, what is the chance that the children will have the
precise Mendelian ratio of 3 : 1 for normal : cystic fibrosis?
a. 3/256
If both parents are carriers, there is a ¾ chance a child will be normal and a ¼ chance
a child will have cystic fibrosis. Each child is an independent event but since birth
order is not considered, there are four ways to have the desired outcome. The child
with cystic fibrosis may be the first, second, third, or fourth so assuming the first is
affected, the specified outcome would be ¼ x ¾ x ¾ x ¾ or a 27/256 chance. Now
taking into account the four possible birth orders and the chance that both parents
are heterozygous, the chance of an exact 3 : 1 ratio becomes 4 x 1/6 x 1/6 x 27/256 =
3/256
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
27. In the body, aspirin breaks down by a first order process. 30 minutes after consuming a
standard dose of this compound, it reaches a maximum concentration of 2 mg / 100mL of
blood. If t1/2 = 90 minutes, what is the concentration (in mg / 100 mL) 2.5 hrs after it reaches
its maximum concentration? (ln 2 = .693)
a. e-0.462 mg / 100 mL
ln 2
. 693
π‘˜ =
=
= 7.7 π‘₯ 10−3 π‘šπ‘–π‘›−1
𝑑1/2
90 π‘šπ‘–π‘›
ln[𝐴] = ln[𝐴]π‘œ − π‘˜π‘‘ = 𝑙𝑛2 − (7.7 π‘₯ 10−3 π‘₯ 150) = −0.462
[A] = e-0.462 mg /100 mL
28. One of the most important ways that the body maintains blood pressure is by constricting
blood vessels and increasing the vascular resistance. Determine the vascular resistance of a
resting skeletal muscles from the following data:
Mean Arterial Pressure
100 mmHg
Mean Venous Pressure
0 mmHg
Blood flow to the muscle 5 mL/min
π‘šπ‘šπ»π‘” π‘₯ π‘šπ‘–π‘›
a. 20
π‘šπΏ
△𝑃
100
π‘šπ‘šπ»π‘” π‘₯ π‘šπ‘–π‘›
𝑅=
=
= 20
πΉπ‘™π‘œπ‘€
5
π‘šπΏ
29. Hydroxyapatite, Ca5(PO4)3(OH), is the main mineral component of dental enamel, dentin,
and bone, and thus has many medical uses. Coating it on metallic implants (such as titanium
alloys and stainless steels) helps the body accept the implant. In the form of powder and
beads, it is used to fill bone voices, which encourages natural bone to grow into the void.
Hydroxyapatite is prepared by adding aqueous phosphoric acid to a dilute slurry of calcium
hydroxide. What mass of hydroxyapatite could form from 100. g of 85% phosphoric acid and
100. g of calcium hydroxide?
3 H3PO4 + 5 Ca(OH)2 οƒ  Ca5(PO4)3(OH) + 9 H2O
MW of H3PO4 = 98 g/mol; MW of Ca(OH)2 = 74.09 g/mol; MW of Ca5(PO4)3OH = 502.31
g/mol
a. 135.6 g of hydroxyapatite
.867 mol H3PO4 reacts with 1.445 mol of Ca(OH)2, but only 1.350 mol Ca(OH)2 are
present; Ca(OH)2 is the limiting reactant.
1 π‘šπ‘œπ‘™ πΆπ‘Ž5 (𝑃𝑂4 )3 𝑂𝐻
502.319 𝑔
1.350 π‘šπ‘œπ‘™ πΆπ‘Ž(𝑂𝐻)2 π‘₯ (
)π‘₯
= 135.6 𝑔
5 π‘šπ‘œπ‘™ πΆπ‘Ž(𝑂𝐻)2
1 π‘šπ‘œπ‘™
Mu Alpha Theta 2012 Nationals
Mathematics in Medicine
30. Vitamin B12, cyanocobalamin, is essential for human nutrition. It is concentrated in animal
tissue, but not in higher plants. Although nutritional requirements are quite low, people
who abstain completely from animal products (and don’t take a vitamin supplement) may
develop a deficiency anemia. Cyanocobalamin contains 4.34% cobalt by mass. Calculate the
molar mass of cyanocobalamin, assuming that there is one atom of cobalt in every molecule
of cyanocobalamin. (MW of Co = 58.93).
a. 1358 g/mol
π‘€π‘œπ‘™π‘Žπ‘Ÿ π‘šπ‘Žπ‘ π‘  π‘œπ‘“ 𝐡12 =
58.93
= 1357.8 𝑔/π‘šπ‘œπ‘™
. 0434
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