G.CO.C.11 STUDENT NOTES WS #2 – geometrycommoncore.com 1 Using the informal method of putting congruent triangles together to form different quadrilaterals we learned a lot about their characteristics and properties. These properties are critical to solving problems about the parallelogram family. Let us summarize those properties and discuss how these shapes relate to each other. PARALLELOGRAM Definition: RECTANGLE Definition: RHOMBUS Definition: SQUARE Definition: A quadrilateral with 2 sets of opposite sides that are parallel. A parallelogram with 4 congruent angles. A parallelogram with 4 congruent sides. A rectangle and a rhombus. Notice that the rectangle, rhombus and ultimately the square are define as special types of parallelograms. In other words all of these quadrilaterals are parallelograms. Because of this they share all of the parallelogram properties and then have some unique ones from their definition or structure. PARALLELOGRAM Properties: RECTANGLE Properties: RHOMBUS Properties: SQUARE Properties: Opposite Sides are Opposite Sides are Opposite Sides are Opposite Sides are Opposite ’s are Opposite ’s are Opposite ’s are Opposite ’s are Consecutive ’s are supplementary Consecutive ’s are supplementary Consecutive ’s are supplementary Consecutive ’s are supplementary Diagonals bisect each other Diagonals bisect each other Diagonals bisect each other Diagonals bisect each other 4 Right Angles (Def.) 4 Right Angles Diagonals Diagonals 4 Sides (Def.) 4 Sides Diagonals Diagonals Diagonals bisect ’s Diagonals bisect ’s The square is the regular quadrilateral which means that it has 4 equal sides, 4 equal angles and has 4 lines of symmetry. Notice that it has all of the properties from the parallelogram, rectangle and rhombus making it the most restricted (specific) parallelogram. Knowing the characteristics of each type of parallelogram is critical to solving problems in this objective. G.CO.C.11 STUDENT NOTES WS #2 – geometrycommoncore.com 2 Let’s apply some of these properties to solve problems. Determine the missing information. a) Parallelogram ABCD b) Rhombus ABCD c) Square ABCD C C x B 3.2 cm B y E 13° x B 12 cm y 68° D C y E x A D A x = 13 because alternate angles are equal when lines are parallel. x = 12 cm because in a rhombus all four sides are . D 15 cm A x = 15 because all 4 sides are . y = 90 because diagonals are . y = 3.2 cm because in a parallelogram diagonals bisect each other. d) Rectangle ABCD e) Rhombus ABCD 12 cm B 71° y = 68 because diagonals bisect angles. x f) Parallelogram ABCD B 5 cm x x D AC = y C 62° C E A B AC = 12 cm mBCD = 68° C 36° A E y D E y A x = 19 because mABC = 90. y = 13 cm because ABC is a right with a hypotenuse of AC so 52 + 122 = 132 (Pythagorean Theorem) D y = 34 because the diagonals bisect the angles and alt. interior ’s are with parallel lines. x = 6 cm because diagonals bisect each other. x = 36 because alternate interior ’s are with parallel lines. y = 82 because the angles of a sum to 180.