# Chapter 3 Study Guide Short Answer 1. The three values 10.714 m ```Chapter 3 Study Guide
1.
The three values 10.714 m, 12.821 m, and 13.646 m have the same number of ____________________.
2.
Round off the measurement 0.003 095 5 m to three significant figures.
3.
What is the sum of 2.7 g and 2.47 g expressed in the correct number of significant digits?
4.
The mass of the electron is 9.109 39
5.
Perform the following operation: 3.43 cm
6.
What is the volume of an object with a density of 7.73 g/cm3 and a mass of 5.40
7.
A cube of a gold-colored metal with a volume of 59 cm has a mass of 980 g. The density of pure gold is 19.3 g/cm . Is the metal pure gold? Show
8.
If a cube has an edge length of 2.00 centimeters and its mass is 5.00 grams, calculate its density.
9.
Ice has a density of 0.92 g/cm3. What is the volume of 1.8 kilograms of ice?
10
kg. Express the mass of the electron to 1, 2, 3, and 4 significant figures.
5.2 cm. Make sure that your answer has the correct number of significant figures.
10 g?
10.
The density of pure silver in the solid form at 20.0&deg; C is 10.5 g/cm3. Calculate the mass of a silver candlestick if it displaces 100. milliliters of water.
11.
The table below show measurements made on samples of three unknown materials. Explain how this data could be used to identify the three materials.
Material
Mass and Volume Data
Mass (g)
Volume (mL)
1
6.02
2.23
2
18.42
2.34
3
35.15
3.10
PROBLEM SOLVING
Use the skills you have developed in this chapter to solve each problem.
12.
Express 3.56 Mg in &micro;g.
13.
Calculate the volume of a rectangular pan that is 27.0 cm long, 14.55 cm wide, and 9.3 cm high. (Remember to retain only significant digits in your
14.
15.
Calculate how many meters are in one mile (39.37 inches = 1 meter, 5286 feet = 1 mile). Express your answer in scientific notation.
16.
Convert a height of 5 feet, 6 inches to meters.
17.
You are given a jar containing a mixture of three different solid substances. The particles of each substance are larger than 0.5 cm in diameter. All you
know about the substances is that each is a pure metal. Describe a method for determining the identities of the metals that make up the mixture.
Assume that each metal is a different color, so you can tell one from the others.
Chapter 3 Study Guide
1.
ANS:
significant figures
PTS:
1
ANS:
0.003 10 m
DIF:
L2
OBJ:
1.3.3
BLM:
comprehension
2.
PTS:
ANS:
5.2 g
1
DIF:
L2
REF:
p. 68
OBJ:
3.1.3
3.
PTS:
ANS:
1
DIF:
L2
REF:
p. 63 | p. 70
OBJ:
3.1.3
one: 9
10
PTS:
ANS:
1
4.
5.
3.43 cm
6.
PTS:
ANS:
kg; two: 9.1
10
PTS:
ANS:
10
kg; four: 9.109
10
kg
DIF:
L2
REF:
p. 63 | p. 71
OBJ:
3.1.3
DIF:
L2
REF:
p. 68 | p. 71
OBJ:
3.1.3
REF:
p. 91
OBJ:
3.4.1
REF:
p. 90 | p. 91
OBJ:
3.4.1
5.2 cm = 18 cm
1
Volume = mass / density = (5.40
7.
kg; three: 9.11
1
DIF:
10 g) / 7.73 g/cm = 69.9 cm
L2
No; mass/volume = 980 g/59 cm = 17 g/cm
8.
9.
10.
11.
12.
PTS:
1
DIF:
L3
ANS:
density = mass &divide; volume
density = 5.00 grams &divide; (2.00 cm 2.00 cm  2.00 cm)
density = 5.00 grams &divide; 8.00 cm3
density = 0.625 g/cm3
PTS:
1
DIF:
intermediate
REF:
chapter 17 | section 17.1
ANS:
density = mass  volume
volume = mass  density
mass = 1.8 kg, or 1,800 g
volume = 1,800 g  0.92 g/cm3
volume = 1,957 cm3 (2.0 L with correct number of significant digits)
PTS:
1
DIF:
intermediate
ANS:
density = mass &divide; volume
mass = density  volume
mass = 10.5 g/cm3  100. cm3
mass = 1050 grams or 1.05 kilograms
The mass of the silver candlestick is 1.05 kilograms.
REF:
chapter 17 | section 17.2
PTS:
1
DIF:
REF:
chapter 17 | section 17.2
ANS:
The density of each sample could be calculated. Then each value could be compared to known values to identify the substances.
PTS:
1
DIF:
III
REF:
2
OBJ:
4
ANS:
M stands for mega-, which means 1,000,000.
&micro; stands for micro-, which means 0.000001, or 10–6, so there are 1,000,000, or 106, micrograms per gram.
Converting megagrams to grams:
3.56 Mg  1,000,000 g = 3,560,000 g, or 3.56  106 g
1 Mg
Converting grams to micrograms:
3.56  106 g  106 &micro; = 3.56  1012 &micro;
1g
13.
PTS:
1
OBJ:
1A 1.d
ANS:
volume = length  width  height
= 27.0 cm  14.55 cm  9.3 cm
= 3653.505 cm3, which must be rounded to two significant digits to match the uncertainty in 9.3 cm, so the final answer should be reported,
after rounding, as 3700 cm3, or 3.7  103 cm3.
PTS:
ANS:
1
OBJ:
1A 1.g
14.
PTS:
ANS:
1
OBJ:
1A 1.j
15.
PTS:
ANS:
1
OBJ:
1A 1.j
16.
17.
PTS:
1
OBJ:
1A 1.j
ANS:
Each substance is a pure metal, so they should be identifiable by determining their densities. Separate the solids by color into three separate batches.
Determine the mass of each metal using a balance. Determine the volume of each metal as follows. Immerse each metal in a measured volume of a
suitable liquid in a graduated cylinder. Measure the volume of the liquid plus the metal. Calculate the difference between the volume of the liquid plus
the metal and the liquid by itself. To calculate the density, divide the mass of each metal by its volume. Compare the density and color of each metal to
the density and color listed in reference books.
PTS:
1
DIF:
L3
REF:
p. 90
OBJ:
3.4.1
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