Honors Math 3 Unit 1: Geometry Term Review Word Box: Vocabulary Definition of Linear Pair, Vertical angles, Definition If B is between A and C, then AB + BC = AC A 2x B 5 C 11 2x + 5 = 11 so 2x = 6 x= 3 PART + PART = TOTAL Name: ___________________________________________ Segment Addition postulate , Definition of midpoint, Complementary angles, Angle addition Postulate, Angle bisector, Supplementary angles Worked Out Example Practice Example Examples D is between A and M. AD = 2x + 3. P is between M and A. Y is between X and Z. DM = 3x + 4 AM = 6x +2. PA = 6x + 5 PM = 3x + 2 XY = 4x-1 ,YZ = 3x+7, and Find x and AD MA = 10x + 2. XZ = 10x -12. Find x and YZ. A D M Find x and PM AD + DM = AM 2x + 3 + 3x + 4 = 6x + 2 5x + 7 = 6x + 2 5 =x AD= 2x + 3 = 2(5) + 3 = 13 If M is the midpoint of AB, then AM = BM and AM = ½ AB If ray AP is on the interior of CAB then m CAP + m PAB = m CAB C P A M is the midpoint of AB. AB = 22. AM = 7x – 3. Find x and MB 7x – 3 AM = ½ AB A M B 7x – 3 = ½ (22) 7x – 3 = 11 22 7x = 14 x=2 MB = AM = 7(2) – 3 = 11 Ray CD is in the interior of ACB. m ACD = 3x + 5. m DCB = 4x – 2 m ACB = 8x – 3. Find x and m ACD A C m MAP = m PAT = ½ m MAT T is the midpoint of SV. ST = 3x-2 and SV = 10x-22. Find x and TV. Ray PM is in the interior of APT. m APM = 3x + 8 m APT = 10x - 3 m MPT = 5x – 3. Find x and m APT Ray BD is in the interior of <ABC. m<ABD = 5x +3, m<DBC = 18-x, and m<ABC = 2x+41. Find x and m<ABD Ray AL bisects Ray BD bisects <ABC. m<ABC = 12x -4, m<DBC = 4x +10. Find x and m<ABD. B m ACD + m DCB = m ACB 3x + 5 + 4x – 2 = 8x – 3 7x + 3 = 8x – 3 6=x m ACD = 3x+5 = 3(6)+5 = 23 B If ray AP bisects MAT, then D D is the midpoint of AM. AD = 4x + 8. AM = 12x + 8. Find x and DM. Ray PT bisects APC. m APT = 4x + 2 m APC = 6x + 20. Find x and m PTC A T m APT = ½ m APC P <multiply by 2> C 4x + 2 = ½ (6x + 20) 8x + 4 = 6x + 20 2x = 16 x = 8 so m PTC=4(8) +2 = 34o CAT. m CAT = 7x – 5 m LAT = 2x + 2. Find x and m CAL. Vocabulary Definition If two angles are complementary then the two angles add up to 90o If 1 and 2 are complementary then m 1 + m 2 = 90o If two angles are supplementary then the two angles add up to 180o . If 1 and 2 are supplementary then m 1 + m 2 = 180o Two angles that are supplementary and adjacent (ADDS UP TO 180o) Worked Out Example Practice Example Examples ABC and CBD are complementary. m ABC = 2x2 + 3. m CBD = 15o. Find x 1 and 2 are complementary. m 1 = 4x2 + 20. m 2 = x2 + 50. Find x and the measure of the larger angle. 3 and 4 are complementary. m 3 = 8x+3, m 4 = 5x+9. Find x and the smaller angle. 1 and 2 are supplementary. They are in the ratio of 1:5. Find the m2 3 and 4 are supplementary angles. They are in a ratio of 5:7. Find m 3. Two angles make a linear pair. The larger angle is 30 less than six times the smaller angle. Find the measure of the larger angle. Two angles make a linear pair. The larger is 30 more than twice the smaller. Find the measure of the smaller angle. 1 and 2 are vertical angles. m 1 = 4x2 + 10 m 2 = 110. Find x and m 1 3 and 4 are vertical angles. m 3 = 115, m 4 = 5x2-10. Find x and m 3. 2x2 + 3 + 15 = 90 2x2 + 18 = 90 2x2 = 72 x2 = 36 x = √36 = 6. ABC and CBD are supplementary and are in the ratio of 5:13. Find the measure of the largest angle. m ABC + m CBD = 180o m ABC = 5x and m CBD = 13x 5x + 13x = 180 18x = 180 x = 10 Largest=13x = 13(10) = 130o Two angles make a linear pair. The larger angle is 12 less than five times the smaller angle. Find the measure of the larger angle. Small + Large = 180 x + 5x – 12 = 180 6x – 12 = 180 6x = 192 x = 32. Large=5(32)-12 = 148o x + y = 180o m1 = m3 1 3 m2 = m4 2 4 OPPOSITE ANGLES ARE CONGRUENT Solve for x x + 16 = 4x – 5 16 = 3x – 5 21 = 3x 7=x