Chapter 2 Learning Target 1

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Chapter 2 Learning Target Assessment: LT 1, 2, 3
Name___________________________________ period____________ date___________
LT1:____/20
1. Explain how you can use heat and cold to change the state of matter of a substance.
Give a specific example and be sure to talk about what heat and cold would do.
A liquid can be changed to a solid by freezing it. A liquid can be turned
to a gas by boiling it.
2. Name the 3 common states of matter and explain the movement of particles in each
state. The 3 states are liquid, solid and gas. In a solid, the particles only
vibrate. In a liquid they slide past each other. In a gas they go
everywhere.
3.
4. Matter is everything that has mass and takes up space..
5. Cross out everything which is not matter:
Sound glue energy water air metal gold
Thoughts coffee steam fire pickles
lead rock
snow jello soda
paper scissors heat paint
love
hair
ideas diamonds
Lt2:____/20
6. Which one of the following is not a physical property: solubility, density, color, odor,
flammability, mass? flammability
Explain your answer.
Flammability is a chemical property because you can’t tell if something will burn just
by looking at it. You have to test it.
7. Can you identify the chemical properties of substance just by observing the substance
by itself? Why or why not. You cannot observe chemical properties just by looking at
the substance because a chemical property is the potential for a substance to change.
You have to get the substance to react in order to observe chemical properties.
8. Calculate the density of the following block:
Mass = 80g Volume = l x w x h volume = 10cm x 1cm x 2cm
V= 20 cm3
Density = mass/volume D = 80g/20cm3
Density = 4g/cm3
9. Explain why the block in #7 would float or sink in the following liquids.
Fresh Water: Density = 1.0 g/cm3
The block would sink because it has a greater
density than water.
Water from the Dead Sea: Density = 124g/cm3 The block would float in the Dead Sea
because it has less density than the water there.
LT 3____/20
10. Use the following table to identify the unknown substance:
substance
state
color
density
water
liquid
clear
1.0 g/ml
Sulfuric acid
liquid
clear
1.8 g/ml
Rubbing alcohol liquid
clear
0.78 g/ml
White vinegar
liquid
clear
0.96 g/ml
unknown
liquid
clear
1.8 g/ml
volume
15 ml
10 ml
23.5 ml
6.5 ml
15 ml
The unknown liquid is sulfuric acid. My evidence is that the unknown liquid has the same
density as sulfuric acid. Since every substance has a unique density, it must be sulfuric acid.
11. Minerals can be identified by their density. Suppose you had what appeared to be a
gold nugget. The density of gold is 19.3 g/cm3. Your piece has a mass of 23 g.
Explain how you can find the volume of you nugget which looks like this:
Because the nugget has an irregular shape, you would have to use water displacement
to calculate the volume. To do this, fill a graduated cylinder to a specific amount.
drop the gold nugget into the water. Record the difference in volume. The difference
is the volume of the nugget.
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