The Fine Structure Constant, Quantum Theory, and Additional Structure of the Photon Joseph M. Brown1 The fine structure constant, alpha (α), has a value of 1/137.03599976. It first appeared as the velocity in speed of light units of the orbiting electron in its lowest energy state in a hydrogen atom. The analysis of the orbital velocity gives the equation 2 π£πππππ‘ π π2 1 βπ 137.03599976 =∝= = 0.007297352533= (1) where e is the charge of the electron Δ§ is Planck’s constant, and c is the speed of light. The fine structure constant is the ratio of electromagnetic forces to nuclear forces. Furthermore, alpha appears throughout quantum electrodynamic (QED) theory. QED physicists use the constant throughout their analyses of the interactions of charged particles and photons. However, they have not the least idea of its origin. Many physicists reading a book, when they come to page 137, will pause and wonder what the origin of α is. During the years 1967 to 1970, the McDonnell Douglas Company funded the Advanced Propulsion Research Group to develop a new physical theory which, hopefully, would lead to extremely advanced propulsion. The group consisted of Joseph M. Brown (PhD Purdue - Mechanical Engineering), Darell B. Harmon, Jr. (PhD UCLA - Physics), Leon A. Steinert (PhD Colorado - Physics), and Robert M. Wood (PhD Cornell - Physics). The research centered on developing a theory of physics based on an absolute space - separate absolute time universe filled with an ether of extremely small, smooth, elastic spheres. We President of Basic Research Press and Retired Professor of Mechanical Engineering at Mississippi State University. Paper prepared June, 2015. 2 This equation is based on a fixed proton. 1 dubbed this the kinetic particle theory of physics. Two parameters characterizing such a gas are the particle mean speed vm and the particle RMS speed vr. Toward the end of the research effort, we discovered the relation ( π£π −π£π 2 π£π ) = 1 = 0.007293481 137.108733 (2) The value 0.007293481 results since vr/vm = √3π/8. This expression, modified by the orbital analysis of the atom using the atom center of mass system, gave the factor 0.007289410. This quantity agreed with the value of the fine structure constant within one percent, see the paper by Brown, Harmon, and Wood [1]. Based upon the agreement of this arrangement of the kinetic particle gas parameters and the fine structure constant, our group felt greatly encouraged that the kinetic particle theory of physics should be developed. We assumed that nuclear particles consisted of condensations of the ether gas and that a condensation would act like a (fluid mechanic) doublet. Further, matter had to consist of mass orbiting at the speed of light. This was required to give matter energy as E=mc2. The computation of the interaction of one nucleon with another consisted of the analysis of two doublets. From this it was deduced that the strength of the strong nuclear force was proportional to the square of the mean velocity and, of course, proportional to the ether mass density. Thus, nuclear forces are proportional to ρvm2. This analysis was reported by Brown and Harmon in reference [2]. We soon concluded that these condensations moving at the speed of light in a circle making matter had been neutrinos translating in a straight line (at the speed of light, of course). For a condensation to be stable, it had to suck in gas particles, align them, and then expel them in two extremely fine streams. This required a pumping mechanism and streams that were so fine that this outflow would not interfere with the inflow. This fine stream requirement necessitated an extremely large mean free path to particle diameter β/d ratio. The β/d for the ether gas is 1018, see page 51 of [3]. It was noted that when particles were taken from a MaxwellBoltzmann gas, aligned to be parallel and directed with the same sense, then squeezed together so that they formed a solid stream without changing their energy, then the translational velocity will jump from vm to vr, an 8.5% increase in velocity. The neutrino does what is specified above. This means that the neutrino will translate at the velocity vr-vm. Therefore, the speed of light is c =vr-vm. This discovery was reported in references [4] and [5]. Knowing that the speed of light is vr-vm, we know that electromagnetic forces are the background density ρ times (vr-vm)2. With this information and knowing that the strong nuclear force is proportional to ρvm2 we now know that π(π£π −π£π )2 ππ£π 2 π£π −π£π 2 =[ π£π ] (3) is the ratio of the electromagnetic force to the strong nuclear force. The neutrino has two fine streams of ether particles exiting in opposite directions from the spherical neutrino. The stream directed forward is a solid stream translating at the velocity vr. The stream directed aft is at the velocity vm. When a neutrino is in a circular orbit, being a nuclear particle, such as the proton, then it produces a spherical wave with a velocity amplitude vr followed by a velocity amplitude vm. Thus, one of the primary characteristics of the electrostatic field is wavespaces with dimensions of 10 -16m (the orbital radius of the proton, see page 60 of [3]). The waves advance spherically symmetric from the proton at the velocity vr-vm, or c. The interactions of photons and electrostatic charge are dominated by these wavespaces. A photon consists of a string of the ether gas particles strung out uniformly over a harmonic wave. For high energy photons each wavespace has many particles and for very low energy photons many wavespaces along the harmonic curve may have no particles. The wavespaces always travel radially from the charged particle at the speed of light. Thus, the speed of light is always the same, which is vr-vm. The wavespaces encapsulate the particles making up the photon. The Bohr (i.e., Newtonian) analysis of electron orbits is based upon a smooth electrostatic field, not this bumpy field consisting of these 10-16meter sized wavespaces which actually exist. Experiments of the radiation from atoms, which are used to infer orbital velocities, could not be made to be consistent with the classical theory. Clearly any one given experimentally determined velocity could be made consistent by adjusting the values of any, or all, of the constants e, Δ§, and c. It was not possible to obtain a satisfactory analysis using the Bohr theory for all orbits. A solution to this problem was obtained by using an equation discovered by Erwin Schrödinger in the early 1920’s. The equation could be used to determine the probable location of an electron when subjected to a potential (such as that produced by a proton when interacting with an electron). The one-dimensional equation is − β2 π2 π 2π ππ₯ 2 +V(π₯, π‘)π = πβ ππ ππ‘ (4) where m is the particle mass, x and t are the space and time coordinates, V(x,t) is the potential, and ψ is the probability function. The probability function times its conjugate gives the probability density. Thus, the probability that a particle will be in a given interval x = a to x = b is π p =∫π ππ ∗ ππ₯ (5) The Schrödinger equation is the cornerstone of quantum mechanical theory. Equations of this type, i.e., Schrödinger equations, have been used for almost a century to obtain research results as well as to produce industrial and commercial products. There is no question that the equations model reality. Earlier it was noted that spectral data from which electron velocities could be determined could not be correlated using the Bohr theory. Using quantum theory, the correlations were obtained. The value of α has been determined to one part in 1010. Quantum theory reigns supreme in the world of the small. The break of quantum mechanics form Newtonian mechanics is due to the strong signal presented by the Schrödinger equation. The Schrödinger equation gives accurate predictions of the interaction of photons and charged particles. To this date (2015), no one has been able to derive the partial differential equation from physical models. The equation apparently was guessed at by Erwin Schrödinger. Just what is the physics from which this equation stems? One of the simplest applications of the Schrödinger equation is for a proton moving back and forth in a box when there is no potential, i.e., V(x,t) = 0. In this case m is the proton mass. One physical situation is for the width of the box to be a half wavelength of the proton wave. The wavelength of the proton is λ= β (6) ππ£ The velocity v is the average of the velocity from one wall to the next. At the wall, the velocity is reversed and the proton travels to the next wall. The solution of the Schrödinger equation for this case is illustrated in the Figure 1. Figure 1. Proton in a Box The parameter ψ times its conjugate ψ* gives a probability frequency of some characteristic of the proton. From our analysis of the proton-in-a-box we venture the hypothesis that ψ ψ* is the probability distribution frequency of the proton energy (i.e., its kinetic energy of its travel). In order to try and understand the physics occurring which produce the above result, let us see if we can gain some insight from the derivation of the differential equation for the free lateral vibration of an elastic beam. The deflection of a beam is related to the bending moment M in the beam by M = EI ππ ππ₯ (7) where E is the beam material modulus of elasticity, I is the area moment of inertia about the bending centroidal axis, dθ is the differential angular change of the beam longitudinal axis, and dx is the differential longitudinal length. Now θ= ππ¦ (8) ππ₯ so that M= EI π2π¦ (9) ππ₯ 2 The shear force Q in the beam is related to the moment by Q= ππ ππ₯ = El π3π¦ (10) ππ₯ 3 The load on a continually loaded beam with a load W newtons per unit length is related to the shear by W= ππ ππ₯ = El π4π¦ (11) ππ₯ 4 The vibration load is the differential mass ρAdx so that the inertial load per unit length is ρA EI π4 π¦ ππ₯ 4 = ππ΄ π2 π¦ ππ‘ 2 π2 π¦ ππ‘ 2 . From this we have (12) Equation (12) is similar to the Schrödinger equation. We can think of the right term in (12) as the driver and the response is the lateral deflection of the beam. Let us look at the electrostatic field of the proton and see if we can identify a driver and a responder. Notwithstanding this discussion of the Schrödinger equation, we still do not know how to derive it. We certainly do not think the equation comes form the magic of (non-newtonian) quantum mechanics any more than we thought that the magic of (non-newtonian) space-time mechanics of Einstein was needed to explain mass growth, matter shortening, and time dilation with velocity, see pages 98 to 107 of [3]. We want to consider the behavior of the proton without any potential, i.e., free proton traveling back and forth from one wall of a box to the other (in the special case where the wall width d = λ/2 = h/(2mv) ). First, let us look at the neutrino which became the proton. The neutrino absorbed ether particles and emitted them in two fine streams along its propagation vector -- the aft stream at velocity vm and the forward stream at velocity vr , where vm and vr are the mean and RMS velocities of the ether gas which has a Maxwell-Boltzmann distribution of speeds, see [1] or [2]. The neutrino takes random energy from the ether gas and produces organized energy. When the neutrino becomes a proton, it begins orbiting and establishes its electrostatic field which consists of three-dimensional wave spaces whose dimensions are on the order of the orbital radius of the proton (10-16m). The orbital velocity is vr–vm (i.e., the speed of light c, of course). The wave spaces all travel at the speed of light radially from the proton. Each wave space has a circulation velocity of vm where the plane of vm passes through the center of the proton, but the wave space travels at the speed vr–vm. These wave spaces characterize the electrostatic field. The ratio of the translating velocity (vr–vm) to the circulatory flow vm i.e., (vr–vm)/ vm) = (√3π/8 - 1) is 0.085401882. This is believed to be the origin of the coupling constant for electrostatic fields. The coupling force between two electrostatic fields is proportional to the square of this velocity (as are all forces in the kinetic particle universe). We also would expect the coupling to be proportional to the square of this number, although we do not understand the mechanism. If so, then the fine structure constant α is given by α =( π£π −π£π 2 (13) ) π£π Let us return now to the Schrödinger equation and perform two crude integrations of the terms in the equation. We start with − β2 π2 π 2π ππ₯ 2 = πβ ππ ππ‘ (14) Integrating each term once and ignoring the factor i since it only affects phasing. − Integrating again β2 ππ 2π ππ₯ = βπ (15) − β2 2π π = β ∫ π ππ‘ (16) The term on the right of (16) would have to be due to the continual stream of energy emitted from the proton. (Recall that the proton has to put out energy at the same rate the neutrino (making the proton) was taking in energy.) Now the term on the left of (16) is how the proton responds (presumably). Let us now discuss the details of how the proton responds. First of all we need to review how a charged particle is caused to move. Let us review the structure of the photon and how it interacts with the electrostatic field. This information is obtained from [3] and from the appendix. The photon is produced or absorbed by the change of the electron orbit in an atom or by the change of velocity of an atom. The process involved in the electron orbital energy reduction is easier to explain. Ether particles are collected uniformly from all around the orbit circle. The particles moving at the speed of light are encapsulated uniformly in the wave spaces which wave spaces move from the center of the charged particle at the speed of light. The number of ether particles is the photon energy divided by the energy of the individual ether particles (i.e., the particle mass m times c2). Some photons will have many particles in each wave space (high energy-short wave length photons) to some photons with only one particle in a large string of wave spaces. The harmonic shape of the photon is due to the emission by winding the photon mass out of a circular path. Let us return now to the proton-in-a-box. While the proton is translating, its neutrino takes a two-dimensional spiral path and the mass that caused it to translate has a translational energy of mv2 and has a large plane spiral path with an angular momentum of Δ§. When the proton meets the wall, this spiral string of ether particles is emitted and the proton stops. A photon coming from the opposite direction has a uniform distribution of the encapsulated ether particles absorbed in an elliptic path (as seen from a reference system attached to the new translating proton) or a plane spiral path seen from the box reference system. A new lower energy photon is scattered off (as proven by the Compton scattering experiments). The interaction is governed by the conservation of mass, conservation of linear momentum, and the conservation of energy, of course. Let us now examine the mechanism involved in the photon travel between the walls of the box. First we need to examine how a photon interacts with a charged particle to accelerate (and decelerate) it. We then need to see how the charged particle stops at the wall and starts from the wall. The gross characteristics of the acceleration are developed on pages 112-114 of [3]. A photon of energy E impacts a proton at a distance rc from the mass center of the proton. To satisfy energy and linear momentum conservation, and consistent with the Compton scattering experiments, part of the photon mass is captured (Mc) and part is scattered as a lower energy photon (Ms). The captured mass accelerates the photon as does the scattered mass. The scattering direction is equally likely to be in any direction over 4π steradians with its average being perpendicular to the impacting photon direction. Thus, the average momentum imparted is the scattered mass ms times c. The momentum imparted by the captured mass is the captured mass mc times c. Thus, the average momentum imparted is the impacting mass times c. The momentum imparted produces an angular momentum equal to Δ§. Thus, the proton undulates harmonically as it translates. The wavelength λ of this undulation is now computed. Δ§ = Prc = movrc, h = 2πΔ§ = 2π movrc = movλ (17) In this, P is the photon momentum which is also the proton momentum mov resulting from the impact. From this, the wavelength is λ = h/mov (18) This is the relation postulated by deBroglie for matter in motion. The wavelength is called the deBroglie wavelength. The captured mass of the photon is stored in a closed curved elliptic shape when viewed from a frame moving with the proton. At the center of the path (between the two walls) the center of the elliptic ring of (photon) mass is at the top (or bottom) of its path and is translating horizontally at its maximum horizontal speed. Figure 2 shows the horizontal component of the velocity of the charge. Figure 2. Horizontal Component of the Velocity of the Charge At the right of the path, the charge center is moving essentially vertically. The charged center then reverses and starts toward the left wall. These velocities are generated by the motion of the center of the captured mass of the photon and this captured mass carries the electrostatic field with it. As this field translates, it also rotates in a circular path so its horizontal velocity varies harmonically between the walls. If we define ψ as the probability frequency of the magnitude of horizontal velocity of the electron then ψ ψ* could be proportional to the energy probability. In this case, this classical analysis of the proton-in-a-box gives similar results to the Schrödinger equation. Schrödinger, as well as all QED researchers, almost certainly did not know of the bumpy characteristics of the electrostatic field. Nonetheless, Schrödinger did discover the equations. Further, any physicist who studies the physics chapters of reference [3] might conclude that the Schrödinger equation models the classically derived bumpy electrostatic field. However, to our knowledge, no one has proven that the Schrödinger equation can be derived from the characteristics of the 10-16 meter sized wave spaces of the electrostatic field. We present further discussion of this problem on pages 91-95 of [3]. At the end of the day, however, we still do not know why the speed of an electron in its lowest orbit is approximately [(vr–vm)/vm]2, in velocity of light units. Appendix: Structure of the Photon and How it Changes the Orbit of an Electron Introduction The gross characteristics of the photon were discovered in 2011 and reported by the author in reference [6]. The theory of the photon is based upon the postulates that identical, small, spherical, elastic particles moving at an average speed over ten times the speed of light make up a gaseous ether which pervades the universe. All neutrinos, matter, photons—everything—is made of these tiny elastic particles, which we call brutinos. The photon is a string of brutinos uniformly distributed along a complete sine wave. The brutinos move slowly compared to the average speed of the background particles. Their speed, of course, is the speed of light, c, and their total mass times the square of their speed is the energy they transport. The particles making the sine wave do not undulate as the photon travels; the photon travels like a wire bent in the shape of a sine wave. Since the publication of [6] we have made additional discoveries about the photon structure. The brutinos are encapsulated in a string of spheroidal wavespaces which have linear dimensions of 10-16 m. These wavespaces are links making up a sinuoidal chain the length of the photon. Also, we have additional insight into the mechanism by which the photon increases the orbital path of an electron in an atom. First, we describe the characteristics of the electrostatic field. The Electrostatic Field Each matter particle, such as the proton, is composed of a neutrino (moving at the speed of light) which takes a circular path. In the case of the proton, the path has a radius approximately 10 -16 m. The neutrino continually expels brutinos from its front end in a fine stream at speed vr, the RMS speed of the background gas, and another fine stream out the aft end at the mean speed, v m, of the background gas. Then two outflows from the neutrino at several diameters of distance from the orbital circle produce an oscillating, near spherical wave which advances at the speed vr-vm (i.e., the speed of light). Since π£π /π£π = √3π/8 for a Maxwell-Boltzmann gas, which the background gas is, we have π£π − π£π = √3π/8 π£π − π£π = π. Thus π£π = 2/(√3π/8 − 1) = 3 × 108 ⁄0.0854 = 3.51 × 109 π⁄π . The expanding wave consists of three-dimensional wavespaces with dimensions in all three directions in the order of 10-16 m. Each wave has a radial velocity amplitude of vr followed by a velocity amplitude vm in the same direction. The three-dimensional wavespaces have polarity. The positive electrostatic field is produced by the proton which consists of a right-handed neutrino. The negative electrostatic field is produced by an orbiting left-handed neutrino making the electron. Two charged particles produced by opposite spin attract each other while those produced by the same spin repel each other. For more background, see pages 72 - 75 of [7]. The waves progressing from a charged particles have motions like that produced by a breathing sphere immersed in a gas. When two charged particles are placed in the vicinity of each other the waves interact to produce attraction when the waves are 180° out of phase and repulsion when in phase. Phasing of the waves is controlled by the twist components of the fields produced by the neutrino spin Photon Formation and Structure A photon is formed when, for example, the electron in a 1H atom in its next lowest energy state drops to its lowest energy state. It expels brutinos (the ether particles) continually from the atom at the velocity of light, of course. The brutinos were uniformly distributed around a circle in the atom and, thus, are uniformly distributed along the photon. Once released, each brutino is confined to one of the wavespaces which wavespace is formed by the meshing of the proton and electron electrostatic fields. These fields can extend to the edge of the visible universe (Ruβ1028 m). The energy E of a photon is nmc2, where m is the mass of the brutino (β10-66 kg), and n is the number of brutinos in the photon. These brutinos are spread uniformly along the length of the photon. The energy is given by two equations π πΈ = β and πΈ = πππ 2 (1) βπ (2) π π = πππ 2 or π = β⁄(πππ) In these equations h is planck’s constant which is 6.63 × 10−34 ππ − π2 /π . The wavelength, in meters, of the photon having one brutino per wavespace is given by π1 = 10−16 π (3) Using π from the second equation in (2) and equating to π from (3) gives π1 = β⁄(πππ) = 10−16 π (4) π = √β⁄(10−16 ππ) (5) or Using the mass of the brutino from Appendix B of reference [2] gives π=√ 6×10−34 10−16 ×3×10−66 ×3×108 = 8 × 1019 particles (6) Now the wavelength π1 , of the photon with one brutino for each wavespace is π1 = 8 × 1019 × 10−16 = 8 × 103 π (7) This wavelength is the upper range of radio waves. Figure 1 shows a plot of the photon having one brutino per wavespace. a. Sine Wave of 9x103m Long Photon b. Detail of Block A in Figure a. Figure 1. Photon with One Brutino Per Wavespace it is The wavelength ππππ₯ of the photon with only one brutino in β ππππ₯ = (1)ππ = 6×10−34 3×10−66 ×3×108 = 1024 m (8) The length is approximately the radius of the observable universe. (Actually, the brutino might be smaller than 3 × 10−66 kg which would make ππππ₯ larger and more nearly equal the observable radius of 1028 m.) A photon with one brutino would not be recognizable as a photon. Figure 2 shows a photon consisting of just one brutino. Figure 2. Photon Consisting of One Brutino The one brutino is shown on the right side along with its velocity c. Obviously such a photon is unrecognizable. Since photons lose one brutino per wavelength of travel (see page 80–86 of [6], the photon shown could be a 10-7m wavelength photon which was emitted from a star 1011 light years from the earth and just now appeared here. The structure of the photon with a wavelength of 10-16 m is determined now. From equation (2) π = 10−16 = β/(πππ) (9) and π = β⁄(10−16 ππ) = 6 × 10−34 ⁄(10−16 × 3 × 10−66 × 3 × 108 ) (10) = 0.7 × 1040 The number of brutinos placed touching each other in a single row 10-16 m long is 10−16 ⁄10−34 ≈ 1018 . The number nr of these rows required for the 10-16m square cross section photon is π 2 π ≈ 1040 ⁄1018 = 1022 and ππ = 1011 (11) A square cross-section photon would require 1011 by 1011 rows. Thus, the width of a square cross-section photon with a wavelength of 10-16m is 1011 × 10−34 = 10−23 π (12) The dimensions are 10−23 π × 10−23 π × 10−16 π and the cross section is approximately 10−46 π2 . This value is near the maximum cross section of the core of a square neutrino. Since this core size is the maximum size of any neutrino and such condensations producing these cores produce the photon it is concluded that the minimum wave length of a photon must be around 10-16m. Figure 3 shows a photon with a wavelength of 10-16 m. Figure 3. Photon 10-16m Long (One Wavespace) The wavelength at the middle of the optical spectrum is 5.5 × 10−7 m. There are 5.5 × 10−7 ⁄10−16 = 5.5 × 109 wavespaces in this photon. The number of brutinos in a photon of wavelength 5.5 × 10−7 is π= β πmc = 6×10−34 5.5×10−7 ×3×10−66 ×3×108 = 1030 (13) Thus, there are 1030 ⁄(5.5 × 109 ) ≈ 2 × 1020 brutinos/wavespace. (14) There are approximately 1020 brutinos per wavespace for optical photons. Mechanism by which the Photon Changes Electron Orbits Consider a hydrogen atom having one nucleon (i.e. 1H) where the electron is in its lowest orbit. A photon can impact the atom and cause the electron to increase its orbit to the next higher energy state. In this process, the electron potential energy is increased and the electron velocity decreases to decrease the electron kinetic energy. The electron wave length is always given by π = β ⁄ (ππ£) (15) Where m is the electron mass and v is its velocity. For the lowest energy orbit the orbit circumference is this wave length which we denote by π1. Letting v1 be the orbital velocity in the state we have. π1 = β⁄(ππ£1 ) (16) Letting r1 be the orbital radius we have π1 = π1 ⁄2π = β⁄(2πππ£1 ) = β⁄(ππ£1 ) (17) For the next higher energy orbit the orbital circumference is two electron wavelengths. Thus π2 = 2β⁄(ππ£2 ) (18) and π2 = π2 ⁄2π = 2β⁄(2πππ£2 ) = 2β⁄(ππ£2 ) (19) Balancing the centrifugal force with the electrostatic attraction force we have π 2 ⁄π1 2 = ππ£1 2 ⁄π1 and π 2 ⁄π2 2 = ππ£2 2 ⁄π2 (20) π 2 ⁄π1 = ππ£1 2 and π 2 ⁄π2 = ππ£2 2 (21) or Substituting r1 and r2 from (17) and (19) goes (π 2 ⁄β) ππ£1 = ππ£1 2 and π 2 ππ£2 ⁄(2β) = ππ£2 2 (22) π£1 = π 2 ⁄β and π£2 = π 2 ⁄(2β) (23) or Using the fine structure constant πΌ where πΌ = π 2 ⁄βπ We have (24) π£1 = πΌπ and π£2 = πΌπ ⁄2 (25) The potential energy P1 for the lowest energy orbit is ∞ π2 π1 = ∫π 1 π ππ = − π2 π1 = −ππ£1 2 = −π(πΌπ)2 (26) and for the next higher orbit the potential energy P2 is ∞ π2 π2 = ∫π 2 π ππ = − π2 π2 = −ππ£2 2 = − π(πΌπ)2 4 (27) The kinetic energy K for each orbital is 1 1 2 2 πΎ1 = π(πΌπ)2 and πΎ2 = [π(πΌπ/2)2 ] (28) Let us denote π(πΌπ)2 as π΅ then 1 1 1 4 2 8 (29) π1 = −π΅, π2 = − π΅, πΎ1 = π΅, πΎ2 = π΅ we see that 3 3 4 8 Δπ = π2 − π1 = π΅, ΔK = πΎ2 − πΎ1 = − π΅ (30) We, therefore conclude that the potential energy increases from the 3 lowest to the next higher orbit by π΅ and the kinetic energy 4 decreased by half this amount. Further, the orbital velocity halved. And the orbital radius quadrupled. The energy required to change the electron orbit from the lowest energy to the next higher state is 3 3 3 3 4 8 8 8 βπΈ = π΅ − π΅ = π΅ = ππ (αc)2 (31) where ππ is the electron mass. The photon energy which must be captured for the orbit change is given by (31). Thus we have 3 πΈπΎ = β π ⁄π = ππΎ π 2 = ππ (αc)2 8 where ππΎ is the photon mass. Solves for π from (32) gives (32) π = 8β⁄(ππΌ 2 π) = 8 × 6.63 × 10−34 × (137.1)2 ⁄(9.11 × 10−31 × 3 × 108 ) (33) = 3.65 × 10−7 π Placing these in a circular pattern results in a radius r of π = π⁄(2π) = 3.65 × 10−7 ⁄(2π) = 5.81 × 10−8 π (34) The characteristics of such a photon are π = 3.65 × 10−7 ⁄10−16 = 3.65 × 109 wavespaces (35) π = β⁄πππ = 6.67 × 10−34 ⁄(2.89 × 10−66 × 3 × 108 × 3.65 × 10−7 ) = 2.11 × 1030 Brutinos (36) π⁄π = 2.11 × 1030 ⁄3.65 × 109 = 5.78 × 1020 brutinos/wavespace (37) A photon with a wavelength approximately 10−7 m (i.e., a photon) more energetic with more brutinos than those in the 3.65x10-7 photon, can impact 1H in its lowest energy state resulting in quadrupling the electron orbital radius and decreasing the orbital velocity by a factor of two. When the 10−7 m wavelength photon impacts the hydrogen atom, it must be wrapped around the atom. This process requires energy. The energy is supplied by the potential produced by the electrostatic fields of the atom. This potential is similar to the gravitational potential of a star acting on a passing photon. However the electrostatic potential is some 1039 times as strong as the gravitational potential. Remember that the photon consists of these 10-16 m wavespaces all along its sine wave structure and that the hydrogen atom also consists of these 10-16 m wavespaces. The sine wave of the photon is changed to a circle with a radius approximately a thousand times the magnitude of the electron orbital radius. The forces pulling the photon into the electron pull the electron outward. The electron must slow down so that twice its wavelength will be that of a complete circle around the proton. a. Photon Approaching a Hydrogen Atom b. Electron Capturing the Photon c. Orbit Change is Complete – Photon Mass is Captured in the Electron Orbit Circle Figure 4. A Hydrogen Atom Capturing a Photon Figure 5 shows the final orbit of the electron and shows the photon mass in its final location. Figure 5. Final Location of Electron and Photon Mass Concluding Remarks The mechanism of the photon as presented here is spectacular, to say the least. The fundamental 10-16m wavespaces formed by a charged particle always moving at the speed vr-vm (i.e., the speed of light) provide the key to the photon characteristics. Photons always move at the same speed. The mass transported is always encapsulated in the wavespaces so that the mass always consists of brutinos moving at speed c which is approximately a tenth the average speed of the background brutino gas particles. Capturing a photon by an atom is likened to a macroscopic mechanical process of taking a portion of the brutinos from each wavespace putting part into other wavespaces to make a lower energy photon which is emitted and putting the remaining brutinos into a circular ring of wavespaces surrounding the nucleus. The photon mechanism emphasizes the role of the background gas parameters vr (the background RMS speed) and vm the background particle mean speed. Even with these insights into the electrostatic field there is still much to learn about quantum electrodynamics. For example, we still do not know why the electron in its lowest energy state in 1H translates at the speed [(π£π − π£π )⁄π£π ]2 , in speed of light units. The role of the wavespaces encapsulating brutinos and requiring that they move at less than one tenth the mean speed of the background particles (i.e., at the speed of light) provides additional insight into the role of a single brutino regarding the finite life of photons and into the mechanism of gravitation. Both the electrostatic and gravitational fields consist of 10−16 π sized wavespaces. As the photon travels it loses a single brutino from its initial large number of brutinos for each wavelength of travel. The gravitational field is produced by a single brutino causing the amplitude of one spherically shaped electrostatic field to oscillate about another electrostatic field with the amplitude of the brutino diameter (see pages 90–92 of [7]). References 1. Brown, J.M., Harmon Jr., D.B., and Wood, R.M., “A Note on the Fine Structure Constant,” McDonnell Douglas Astronautics Company Paper MDAC WD 1372 Huntington Beach, CA, June 1970. Available from Basic Research Press. 2. Brown, J.M., Harmon, Jr. D.B., “A Kinetic Particle Theory of Physics,” J. Mississippi Academy of Sciences, VXVIII, Pages 126, 1972. Available from Basic Research Press. 3. Brown, J.M., The Mechanical Theory of Everything, ISBN: 978-09712944-9-3, Basic Research Press, Starkville, MS, 2015. 4. Brown, J.M., “A Counter Example to the Second Law of Thermodynamics”, Abstract p.98, Journal of the Mississippi Academy of Sciences, Vol. XXVI Supplement, 1981. Available from Basic Research Press. 5. Brown, J.M., “Force Production from Interacting Gas Flows for BMD Applications”, Final Report on U. S. Army Contract DAS6-80-C-0034 Administered by U. S. Army Ballistic Missile Defense Agency, Box 1500, Huntsville, Al. 35807, October 1, 1981. Available from Basic Research Press. 6. Brown, J.M., “Photons and the Elementary Particles,” ISBN: 978-09712944-5-5, Basic Research Press, Starkville, MS 39759, USA – 2011. 7. Brown, J.M., “Foundations of Physics,” ISBN: 978-0-9883180-0-7, Basic Research Press, kStarkville, MS 39759, USA – 2012.