Lesson 22: Congruence Criteria for Triangles—SAS

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NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 22
M1
GEOMETRY
Lesson 22: Congruence Criteria for Triangles—SAS
Student Outcomes
๏‚ง
Students learn why any two triangles that satisfy the SAS congruence criterion must be congruent.
Lesson Notes
Lesson 22 begins to investigate criteria, or the indicators, of triangle congruence. Students are introduced to the
concept in Grade 8 but justified the criteria of triangle congruence (i.e., ASA, SAS, and SSS) in a more hands-on manner,
manipulating physical forms of triangles through rigid motions to determine whether or not a pair of triangles is
congruent. In this lesson, students formally prove the triangle congruency criteria.
Note that in the exercises that follow, proofs may employ both statements of equality of measure of angles and lengths
of segments and statements of congruence of angles and segments. While not introduced formally, it is intuitively clear
that two segments are congruent if and only if they are equal in length; similarly, two angles are equal in measure if and
only if they are congruent. That is, a segment can be mapped onto another if and only if they are equal in length, and an
angle can be mapped onto another if and only if they are equal in measure. Another implication is that some of our key
facts and discoveries may also be stated in terms of congruence, such as “Vertical angles are congruent.” Or, “If two
lines are cut by a transversal such that a pair of alternate interior angles are congruent, then the lines are parallel.”
Discuss these results with your students. Exercise 4 of this lesson should help students understand the logical
equivalency of these statements.
Classwork
Opening Exercise (4 minutes)
Opening Exercise
Answer the following question. Then discuss your answer with a partner.
Do you think it is possible to know whether there is a rigid motion that takes one triangle to another without actually
showing the particular rigid motion? Why or why not?
Answers may vary. Some students may think it is not possible because it is necessary to show the transformation as proof
of its existence. Others may think it is possible by examining the triangles carefully.
It is common for curricula to take indicators of triangle congruence such as SAS and ASA as axiomatic, but this curriculum
defines congruence in terms of rigid motions (as defined in the G-CO domain). However, it can be shown that these
commonly used statements (SAS, ASA, etc.) follow from this definition of congruence and the properties of basic rigid
motions (G-CO.B.8). Thus, these statements are indicators of whether rigid motions exist to take one triangle to the
other. In other words, we have agreed to use the word congruent to mean there exists a composition of basic rigid
motion of the plane that maps one figure to the other. We see that SAS, ASA, and SSS imply the existence of the rigid
motion needed, but precision demands that we explain how and why.
Lesson 22:
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
While there are multiple proofs that show that SAS follows from the definition of congruence in terms of rigid motions
and the properties of basic rigid motions, the one that appears in this lesson is one of the versions most accessible for
students.
Discussion (20 minutes)
Discussion
It is true that we do not need to show the rigid motion to be able to know that there is one. We are going to show that
there are criteria that refer to a few parts of the two triangles and a correspondence between them that guarantee
congruency (i.e., existence of rigid motion). We start with the Side-Angle-Side (SAS) criteria.
SIDE-ANGLE-SIDE TRIANGLE CONGRUENCE CRITERIA (SAS): Given two triangles โ–ณ ๐‘จ๐‘ฉ๐‘ช and โ–ณ ๐‘จ′๐‘ฉ′๐‘ช′ so that ๐‘จ๐‘ฉ = ๐‘จ′๐‘ฉ′ (Side),
๐’Ž∠๐‘จ = ๐’Ž∠๐‘จ′ (Angle), and ๐‘จ๐‘ช = ๐‘จ′ ๐‘ช′ (Side). Then the triangles are congruent.
The steps below show the most general case for determining a congruence between two triangles that satisfy the SAS
criteria. Note that not all steps are needed for every pair of triangles. For example, sometimes the triangles already
share a vertex. Sometimes a reflection is needed, sometimes not. It is important to understand that we can always use
some or all of the steps below to determine a congruence between the two triangles that satisfies the SAS criteria.
PROOF: Provided the two distinct triangles below, assume ๐‘จ๐‘ฉ = ๐‘จ′๐‘ฉ′ (Side), ๐’Ž∠๐‘จ = ๐’Ž∠๐‘จ′ (Angle), and
๐‘จ๐‘ช = ๐‘จ′๐‘ช′ (Side).
A
B
B'
C
A'
C'
By our definition of congruence, we have to find a composition of rigid motions that maps โ–ณ ๐‘จ′๐‘ฉ′๐‘ช′ to โ–ณ ๐‘จ๐‘ฉ๐‘ช. We must
find a congruence ๐‘ญ so that (โ–ณ ๐‘จ′ ๐‘ฉ′ ๐‘ช′ ) = โ–ณ ๐‘จ๐‘ฉ๐‘ช. First, use a translation ๐‘ป to map a common vertex.
Which two points determine the appropriate vector?
๐‘จ′, ๐‘จ
Can any other pair of points be used? Why or why not?
No. We use ๐‘จ′ and ๐‘จ because only these angles are congruent by assumption.
Lesson 22:
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
State the vector in the picture below that can be used to translate โ–ณ ๐‘จ′๐‘ฉ′๐‘ช′.
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘จ′๐‘จ
Using a dotted line, draw an intermediate position of โ–ณ ๐‘จ′๐‘ฉ′๐‘ช′ as it moves along the vector:
A
B
B'
A'
C
C'
′ ′ ′
After the translation (below), ๐‘ป๐‘จ′๐‘จ
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ— (โ–ณ ๐‘จ ๐‘ฉ ๐‘ช ) shares one vertex with โ–ณ ๐‘จ๐‘ฉ๐‘ช, ๐‘จ. In fact, we can say
′ ′ ′
๐‘ป๐‘จ′๐‘จ
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ— (โ–ณ ๐‘จ ๐‘ฉ ๐‘ช ) = โ–ณ ๐‘จ๐‘ฉ′′๐‘ช′′.
B"
A
B
C"
C
ฬ…ฬ…ฬ…ฬ…ฬ…ฬ… to ๐‘จ๐‘ช
ฬ…ฬ…ฬ…ฬ…ฬ…ฬ… to ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ… (or a counterclockwise rotation to bring ๐‘จ๐‘ฉ′′
ฬ…ฬ…ฬ…ฬ…).
Next, use a clockwise rotation ๐‘น∠๐‘ช๐‘จ๐‘ช′′ to bring the side ๐‘จ๐‘ช′′
B"
A
B
C
C"
A rotation of appropriate measure maps โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘จ๐‘ช′′ to โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘จ๐‘ช, but how can we be sure that vertex ๐‘ช′′ maps to ๐‘ช? Recall that part
of our assumption is that the lengths of sides in question are equal, ensuring that the rotation maps ๐‘ช′′ to ๐‘ช.
ฬ…ฬ…ฬ…ฬ…ฬ… became ฬ…ฬ…ฬ…ฬ…ฬ…ฬ…
(๐‘จ๐‘ช = ๐‘จ๐‘ช′′ ; the translation performed is a rigid motion, and thereby did not alter the length when ๐‘จ๐‘ช′
๐‘จ๐‘ช′′ .)
A
B
B'''
C
After the rotation ๐‘น∠๐‘ช๐‘จ๐‘ช′′ (โ–ณ ๐‘จ๐‘ฉ′′๐‘ช′′), a total of two vertices are shared with โ–ณ ๐‘จ๐‘ฉ๐‘ช, ๐‘จ and ๐‘ช. Therefore,
๐‘น∠๐‘ช๐‘จ๐‘ช′′ (โ–ณ ๐‘จ๐‘ฉ′′๐‘ช′′) = โ–ณ ๐‘จ๐‘ฉ′′′๐‘ช.
Lesson 22:
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Finally, if ๐‘ฉ′′′ and ๐‘ฉ are on opposite sides of the line that joins ๐‘จ๐‘ช, a
reflection ๐’“๐‘จ๐‘ช
ฬ…ฬ…ฬ…ฬ… brings ๐‘ฉ′′′ to the same side as ๐‘ฉ.
A
Since a reflection is a rigid motion and it preserves angle measures, we
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ— . If, however,
know that ๐’Ž∠๐‘ฉ′′′ ๐‘จ๐‘ช = ๐’Ž∠๐‘ฉ๐‘จ๐‘ช and so โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘จ๐‘ฉ′′′ maps to ๐‘จ๐‘ฉ
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ— , can we be certain that ๐‘ฉ′′′ actually maps to ๐‘ฉ?
๐‘จ๐‘ฉ′′′ coincides with ๐‘จ๐‘ฉ
B
B'''
We can, because not only are we certain that the rays coincide but also by
our assumption that ๐‘จ๐‘ฉ = ๐‘จ๐‘ฉ′′′. (Our assumption began as ๐‘จ๐‘ฉ = ๐‘จ′ ๐‘ฉ′ ,
but the translation and rotation have preserved this length now as ๐‘จ๐‘ฉ′′′.)
Taken together, these two pieces of information ensure that the reflection
ฬ…ฬ…ฬ…ฬ… brings ๐‘ฉ′′′ to ๐‘ฉ.
over ๐‘จ๐‘ช
C
ฬ…ฬ…ฬ…ฬ….
Another way to visually confirm this is to draw the marks of the __ perpendicular bisector _ construction for ๐‘จ๐‘ช
Write the transformations used to correctly notate the congruence (the composition of transformations) that take
โ–ณ ๐‘จ′ ๐‘ฉ′ ๐‘ช′ ≅ โ–ณ ๐‘จ๐‘ฉ๐‘ช:
A
๐‘ญ
Translation
๐‘ฎ
Rotation
๐‘ฏ
Reflection
′
′ ′ )))
๐‘ฏ (๐‘ฎ(๐‘ญ(โ–ณ ๐‘จ ๐‘ฉ ๐‘ช
B
B'
_
A'
C
= โ–ณ ๐‘จ๐‘ฉ๐‘ช
C'
We have now shown a sequence of rigid motions that takes โ–ณ ๐‘จ′๐‘ฉ′๐‘ช′ to โ–ณ ๐‘จ๐‘ฉ๐‘ช with the use of just three criteria from
each triangle: two sides and an included angle. Given any two distinct triangles, we could perform a similar proof.
There is another situation when the triangles are not distinct, where a modified proof is needed to show that the
triangles map onto each other. Examine these below. Note that when using the Side-Angle-Side triangle congruence
criteria as a reason in a proof, you need only state the congruence and SAS.
Example (5 minutes)
Students try an example based on the Discussion.
Example
What if we had the SAS criteria for two triangles that were not distinct? Consider the following two cases. How would
the transformations needed to demonstrate congruence change?
Case
Transformations
Needed
Diagram
A
Shared Side
B
B'''
reflection
C
B"
A
Shared Vertex
C
Lesson 22:
rotation,
reflection
B
C"
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Exercises (7 minutes)
Exercises
1.
Given: Triangles with a pair of corresponding sides of equal length and a pair of included angles of equal measure.
Sketch and label three phases of the sequence of rigid motions that prove the two triangles to be congruent.
Translation
Rotation
Reflection
Justify whether the triangles meet the SAS congruence criteria; explicitly state which pairs of sides or angles are
congruent and why. If the triangles do meet the SAS congruence criteria, describe the rigid motion(s) that would
map one triangle onto the other.
2.
Given: ๐’Ž∠๐‘ณ๐‘ต๐‘ด = ๐’Ž∠๐‘ณ๐‘ต๐‘ถ, ๐‘ด๐‘ต = ๐‘ถ๐‘ต
Do โ–ณ ๐‘ณ๐‘ต๐‘ด and โ–ณ ๐‘ณ๐‘ต๐‘ถ meet the SAS criteria?
๐’Ž∠๐‘ณ๐‘ต๐‘ด = ๐’Ž∠๐‘ณ๐‘ต๐‘ถ
Given
๐‘ด๐‘ต = ๐‘ถ๐‘ต
Given
๐‘ณ๐‘ต = ๐‘ณ๐‘ต
Reflexive property
โ–ณ ๐‘ณ๐‘ต๐‘ด ≅โ–ณ ๐‘ณ๐‘ต๐‘ถ
SAS
ฬ…ฬ…ฬ…ฬ….
The triangles map onto one another with a reflection over ๐‘ณ๐‘ต
3.
Given: ๐’Ž∠๐‘ฏ๐‘ฎ๐‘ฐ = ๐’Ž∠๐‘ฑ๐‘ฐ๐‘ฎ, ๐‘ฏ๐‘ฎ = ๐‘ฑ๐‘ฐ
Do โ–ณ ๐‘ฏ๐‘ฎ๐‘ฐ and โ–ณ ๐‘ฑ๐‘ฐ๐‘ฎ meet the SAS criteria?
๐’Ž∠๐‘ฏ๐‘ฎ๐‘ฐ = ๐’Ž∠๐‘ฑ๐‘ฐ๐‘ฎ
Given
๐‘ฏ๐‘ฎ = ๐‘ฑ๐‘ฐ
Given
๐‘ฎ๐‘ฐ = ๐‘ฐ๐‘ฎ
Reflexive property
โ–ณ ๐‘ฏ๐‘ฎ๐‘ฐ ≅โ–ณ ๐‘ฑ๐‘ฐ๐‘ฎ
SAS
The triangles map onto one another with a ๐Ÿ๐Ÿ–๐ŸŽ° rotation about the midpoint of the diagonal.
Lesson 22:
Congruence Criteria for Triangles—SAS
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NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 22
M1
GEOMETRY
4.
Is it true that we could also have proved โ–ณ ๐‘ฏ๐‘ฎ๐‘ฐ and โ–ณ ๐‘ฑ๐‘ฐ๐‘ฎ meet the SAS criteria if we had been given that ∠๐‘ฏ๐‘ฎ๐‘ฐ ≅
ฬ…ฬ…ฬ…ฬ…ฬ… ≅ ๐‘ฑ๐‘ฐ
ฬ… ? Explain why or why not.
∠๐‘ฑ๐‘ฐ๐‘ฎ and ๐‘ฏ๐‘ฎ
Yes, this is true. Whenever angles are equal, they can also be described as congruent. Since rigid motions preserve
angle measure, for two angles of equal measure, there always exists a sequence of rigid motions that will carry one
onto the other. Additionally, since rigid motions preserve distance, for two segments of equal length, there always
exists a sequence of rigid motions that carries one onto the other.
Closing (1 minute)
๏‚ง
Two triangles, โ–ณ ๐ด๐ต๐ถ and โ–ณ ๐ด′๐ต′๐ถ′, meet the Side-Angle-Side criteria when ๐ด๐ต = ๐ด′๐ต′ (Side),
๐‘š∠๐ด = ๐‘š∠๐ด′ (Angle), and ๐ด๐ถ = ๐ด′ ๐ถ ′ (Side). The SAS criteria implies the existence of a congruence that maps
one triangle onto the other.
Exit Ticket (8 minutes)
Lesson 22:
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Name
Date
Lesson 22: Congruence Criteria for Triangles—SAS
Exit Ticket
If two triangles satisfy the SAS criteria, describe the rigid motion(s) that would map one onto the other in the following
cases.
1.
The two triangles share a single common vertex.
2.
The two triangles are distinct from each other.
3.
The two triangles share a common side.
Lesson 22:
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Exit Ticket Sample Solutions
If two triangles satisfy the SAS criteria, describe the rigid motion(s) that would map one onto the other in the following
cases.
1.
The two triangles share a single common vertex.
Rotation, reflection
2.
The two triangles are distinct from each other.
Translation, rotation, reflection
3.
The two triangles share a common side.
Reflection
Problem Set Sample Solutions
Justify whether the triangles meet the SAS congruence criteria; explicitly state which pairs of sides or angles are congruent
and why. If the triangles do meet the SAS congruence criteria, describe the rigid motion(s) that would
map one triangle onto the other.
1.
ฬ…ฬ…ฬ…ฬ…, and ๐‘จ๐‘ฉ = ๐‘ช๐‘ซ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ช๐‘ซ
Given: ๐‘จ๐‘ฉ
Do โ–ณ ๐‘จ๐‘ฉ๐‘ซ and โ–ณ ๐‘ช๐‘ซ๐‘ฉ meet the SAS criteria?
๐‘จ๐‘ฉ = ๐‘ช๐‘ซ, ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ฉ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ช๐‘ซ
Given
๐‘ฉ๐‘ซ = ๐‘ซ๐‘ฉ
Reflexive property
๐’Ž∠๐‘จ๐‘ฉ๐‘ช = ๐’Ž∠๐‘ช๐‘ซ๐‘ฉ
If a transversal intersects two parallel lines,
then the measures of the alternate interior
angles are equal in measure.
โ–ณ ๐‘จ๐‘ฉ๐‘ซ ≅ โ–ณ ๐‘ช๐‘ซ๐‘ฉ
SAS
The triangles map onto one another with a ๐Ÿ๐Ÿ–๐ŸŽ° rotation about the midpoint of the diagonal.
2.
Given: ๐’Ž∠๐‘น = ๐Ÿ๐Ÿ“°, ๐‘น๐‘ป = ๐Ÿ•", ๐‘บ๐‘ผ = 5", and ๐‘บ๐‘ป = ๐Ÿ“"
Do โ–ณ ๐‘น๐‘บ๐‘ผ and โ–ณ ๐‘น๐‘บ๐‘ป meet the SAS criteria?
There is not enough information given.
3.
ฬ…ฬ…ฬ…ฬ…ฬ… and ๐‘ฑ๐‘ต
ฬ…ฬ…ฬ…ฬ… bisect each other
Given: ๐‘ฒ๐‘ด
Do โ–ณ ๐‘ฑ๐‘ฒ๐‘ณ and โ–ณ ๐‘ต๐‘ด๐‘ณ meet the SAS criteria?
ฬ…ฬ…ฬ…ฬ…ฬ… and ๐‘ฑ๐‘ต
ฬ…ฬ…ฬ…ฬ… bisect each other
๐‘ฒ๐‘ด
Given
๐’Ž∠๐‘ฒ๐‘ณ๐‘ฑ = ๐’Ž∠๐‘ด๐‘ณ๐‘ต
Vertical angles are equal in measure
๐‘ฒ๐‘ณ = ๐‘ด๐‘ณ
Definition of a segment bisector
๐‘ฑ๐‘ณ = ๐‘ต๐‘ณ
Definition of a segment bisector
โ–ณ ๐‘ฑ๐‘ฒ๐‘ณ ≅ โ–ณ ๐‘ต๐‘ด๐‘ณ
SAS
The triangles map onto one another with a ๐Ÿ๐Ÿ–๐ŸŽ° rotation about ๐‘ณ.
Lesson 22:
Congruence Criteria for Triangles—SAS
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Lesson 22
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
4.
Given: ๐’Ž∠๐Ÿ = ๐’Ž∠๐Ÿ, and ๐‘ฉ๐‘ช = ๐‘ซ๐‘ช
Do โ–ณ ๐‘จ๐‘ฉ๐‘ช and โ–ณ ๐‘จ๐‘ซ๐‘ช meet the SAS criteria?
๐’Ž∠๐Ÿ = ๐’Ž∠๐Ÿ
Given
๐‘ฉ๐‘ช = ๐‘ซ๐‘ช
Given
๐‘จ๐‘ช = ๐‘จ๐‘ช
Reflexive property
โ–ณ ๐‘จ๐‘ฉ๐‘ช ≅ โ–ณ ๐‘จ๐‘ซ๐‘ช
SAS
โƒกโƒ—โƒ—โƒ—โƒ— .
The triangles map onto one another with a reflection over ๐‘จ๐‘ช
5.
ฬ…ฬ…ฬ…ฬ… bisects angle ∠๐‘ฉ๐‘ช๐‘ซ, and ๐‘ฉ๐‘ช = ๐‘ซ๐‘ช
Given: ๐‘จ๐‘ฌ
Do โ–ณ ๐‘ช๐‘จ๐‘ฉ and โ–ณ ๐‘ช๐‘จ๐‘ซ meet the SAS criteria?
ฬ…ฬ…ฬ…ฬ… bisects angle ∠๐‘ฉ๐‘ช๐‘ซ
๐‘จ๐‘ฌ
Given
๐’Ž∠๐‘ฉ๐‘ช๐‘จ = ๐’Ž∠๐‘ซ๐‘ช๐‘จ
Definition of an angle bisector
๐‘ฉ๐‘ช = ๐‘ซ๐‘ช
Given
๐‘จ๐‘ช = ๐‘จ๐‘ช
Reflexive property
โ–ณ ๐‘ช๐‘จ๐‘ซ ≅ โ–ณ ๐‘ช๐‘จ๐‘ฉ
SAS
โƒกโƒ—โƒ—โƒ—โƒ— .
The triangles map onto one another with a reflection over ๐‘จ๐‘ช
6.
ฬ…ฬ…ฬ…ฬ…ฬ…and ๐‘น๐‘ป
ฬ…ฬ…ฬ…ฬ…ฬ…bisect each other
Given: ๐‘บ๐‘ผ
Do โ–ณ ๐‘บ๐‘ฝ๐‘น and โ–ณ ๐‘ผ๐‘ฝ๐‘ป meet the SAS criteria?
ฬ…ฬ…ฬ…ฬ…ฬ…and ๐‘น๐‘ป
ฬ…ฬ…ฬ…ฬ…ฬ…bisect each other Given
๐‘บ๐‘ผ
๐‘บ๐‘ฝ = ๐‘ผ๐‘ฝ
Definition of a segment bisector
๐‘น๐‘ฝ = ๐‘ฝ๐‘ป
Definition of a segment bisector
๐’Ž∠๐‘บ๐‘ฝ๐‘น = ๐’Ž∠๐‘ผ๐‘ฝ๐‘ป
Vertical angles are equal in measure
โ–ณ ๐‘บ๐‘ฝ๐‘น ≅ โ–ณ ๐‘ผ๐‘ฝ๐‘ป
SAS
The triangles map onto one another with a ๐Ÿ๐Ÿ–๐ŸŽ° rotation about ๐‘ฝ.
7.
ฬ…ฬ…ฬ…ฬ… ⊥ ๐‘ด๐‘ณ
ฬ…ฬ…ฬ…ฬ…ฬ…, and ๐‘ฒ๐‘ณ
ฬ…ฬ…ฬ…ฬ… ⊥ ๐‘ด๐‘ณ
ฬ…ฬ…ฬ…ฬ…ฬ…
Given: ๐‘ฑ๐‘ด = ๐‘ฒ๐‘ณ, ๐‘ฑ๐‘ด
Do โ–ณ ๐‘ฑ๐‘ด๐‘ณ and โ–ณ ๐‘ฒ๐‘ณ๐‘ด meet the SAS criteria?
๐‘ฑ๐‘ด = ๐‘ฒ๐‘ณ
ฬ…ฬ…ฬ…ฬ… ⊥ ๐‘ด๐‘ณ
ฬ…ฬ…ฬ…ฬ…ฬ…, ๐‘ฒ๐‘ด
ฬ…ฬ…ฬ…ฬ…ฬ… ⊥ ๐‘ด๐‘ณ
ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘ฑ๐‘ด
Given
๐’Ž∠๐‘ฑ๐‘ด๐‘ณ = ๐Ÿ—๐ŸŽ°, ๐’Ž∠๐‘ฒ๐‘ณ๐‘ด = ๐Ÿ—๐ŸŽ°
Definition of perpendicular lines
๐’Ž∠๐‘ฑ๐‘ด๐‘ณ = ๐’Ž∠๐‘ฒ๐‘ณ๐‘ด
Transitive property
๐‘ด๐‘ณ = ๐‘ณ๐‘ด
Reflexive property
โ–ณ ๐‘ฑ๐‘ด๐‘ณ ≅ โ–ณ ๐‘ฒ๐‘ณ๐‘ด
SAS
Given
The triangles map onto one another with a reflection over the perpendicular bisector of ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘ด๐‘ณ.
8.
ฬ…ฬ…ฬ…ฬ…, and ๐‘ช๐‘ฌ
ฬ…ฬ…ฬ…ฬ… ⊥ ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ… ⊥ ๐‘จ๐‘ช
ฬ…ฬ…ฬ…ฬ…
Given: ๐‘ฉ๐‘ญ
Do โ–ณ ๐‘ฉ๐‘ฌ๐‘ซ and โ–ณ ๐‘ช๐‘ญ๐‘ซ meet the SAS criteria?
There is not enough information given.
Lesson 22:
Congruence Criteria for Triangles—SAS
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
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This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 22
M1
GEOMETRY
9.
Given: ๐’Ž∠๐‘ฝ๐‘ฟ๐’€ = ๐’Ž∠๐‘ฝ๐’€๐‘ฟ
Do โ–ณ ๐‘ฝ๐‘ฟ๐‘พ and โ–ณ ๐‘ฝ๐’€๐’ meet the SAS criteria?
There is not enough information given.
10.
Given: โ–ณ ๐‘น๐‘บ๐‘ป is isosceles, with ๐‘น๐‘บ = ๐‘น๐‘ป, and ๐‘บ๐’€ = ๐‘ป๐’
Do โ–ณ ๐‘น๐‘บ๐’€ and โ–ณ ๐‘น๐‘ป๐’ meet the SAS criteria?
โ–ณ ๐‘น๐‘บ๐‘ป is isosceles with ๐‘น๐‘บ = ๐‘น๐‘ป
Given
๐’Ž∠๐‘บ = ๐’Ž∠๐‘ป
Base angles of an isosceles triangle
are equal in measure.
๐‘บ๐’€ = ๐‘ป๐’
Given
โ–ณ ๐‘น๐‘บ๐’€ ≅ โ–ณ ๐‘น๐‘ป๐’
SAS
Lesson 22:
Congruence Criteria for Triangles—SAS
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
199
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
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