SEF1124 MATHEMATICS 2 COMPILATION OF MID-SEMESTER EXAM QUESTIONS (CHAP 1 & CHAP 2) Content Semester III 2011/2012 …pg1 Semester III 2012/2013 …pg4 Additional Exercises from Past Exams …pg6 Semester III 2011/2012 QUESTION 1 3 (a) Given that tan 𝜃 = and 𝜃 is an acute angle. Find the exact values of 5 (i) (ii) sin θ sec θ (b) Without using a calculator, find the exact value of (i) sin 383° ∙ csc 23° (ii) cos 5𝜋 3 − tan 11𝜋 4 (c) Write sin t in terms of cos t, where 𝜋 < 𝑡 < 1 11𝜋 8 SEF1124 MATHEMATICS 2 QUESTION 2 (a) Given the graph of 𝑦 = 𝐴 sin(𝑘𝑥 − 𝑏) where 𝐴 > 0 and 𝑏 < 0 as shown below. Determine the values of 𝐴, 𝑘 and 𝑏. (b) Given the function 𝑓(𝑥) = 2 cos(3𝑥 + 𝜋). (i) Determine the period. (ii) 𝜋 Sketch the graph of 𝑦 = 𝑓(𝑥)for − 6 ≤ 𝑥 ≤ Hence state the range of 𝑓(𝑥). QUESTION 3 Without using a calculator, find the exact value of: (a) cos (tan−1 (− 2 1 )) √5 𝜋 (b) sec (cot −1 (3) + 2 ) 2 5𝜋 6 . Label the x and y-intercepts. SEF1124 MATHEMATICS 2 QUESTION 4 1 (a) Given sin α = 2 and α is in the second quadrant. Find α (i) cos 2 (ii) tan 2𝛼 (b) By writing cos15°in the form cos(𝐴 − 𝐵)and cos75°in the form cos(𝐴 + 𝐵), determine the angles 𝐴 and 𝐵. Hence, without using a calculator and by using the sum and difference formula, show that cos15° − cos 75° = 2 sin 45° sin 30°. QUESTION 5 (a) Express √3 cos 2𝑥 − sin 2𝑥 in the form 𝑅 cos(2𝑥 + 𝛼) where 𝑅 > 0 𝑎𝑛𝑑 0 ≤ 𝛼 ≤ 2𝜋. Hence find all the values of 𝑥, with 0 ≤ 𝑥 < 𝜋 such that √3 cos 2𝑥 − sin 2𝑥 = √3 (b) Prove that 3 1 − (1 + 2 cos 2𝛼) cos(2𝜃 + 2𝛼) 2 2 and 0 ≤ 𝜃 ≤ 2𝜋, solve the equation sin2 𝜃 + sin2 (𝜃 + 2𝛼) + sin2 (𝜃 + 𝛼) = Hence, if 𝛼 = 𝜋 4 sin2 𝜃 + sin2 (𝜃 + 2𝛼) + sin2(𝜃 + 𝛼) = 3 7 4 SEF1124 MATHEMATICS 2 Semester III 2012/2013 QUESTION 1 Let 𝑃(𝑎, 𝑏) be the point on the terminal side of 𝜃 on the unit circle as shown above. (a) Find cos 𝜃. (b) Show the coordinates of the points for the terminal sides of the following angles (i) 𝜃+𝜋 𝜋 (ii) 𝜃−2 (iii) 𝜋 Hence find the values of sin(𝜃 + 𝜋) and sin (𝜃 − ). 2 QUESTION 2 1 (a) Given the function 𝑦 = 2 sin(2𝜋𝑥 + 𝜋) (i) Find the amplitude, period and phase shift of the function. 4 SEF1124 MATHEMATICS 2 (ii) Hence, sketch the graph over one period starting from the phase shift and label the x-intercepts. (b) Without using a calculator, find the exact value of: 2 csc(−570°) + 3 sec 4 495° − tan(−420°) QUESTION 3 (a) Prove the identity 𝛼 2(1 − cos 𝛼) sec 2 ( ) = 2 sin2 𝛼 𝑘−tan 𝐵 (b) If sin(𝐴 + 𝐵) = 𝑘 cos(𝐴 − 𝐵)where k is a constant, show that tan 𝐴 = 1−𝑘 tan 𝐵. QUESTION 4 (a) Without using a calculator, find the exact value of 3𝜋 3𝜋 tan [sin−1 (sin ) + cos−1 (cos (− ))] 5 5 𝐴 (b) Given that sin 2 = − √5 3 3 𝐴 and tan 2𝐵 = 4 where 2 and 2𝐵 are in the same quadrant. Find the exact value of: (i) sin A (ii) 𝐵 sin 2 sin 3𝐵 2 QUESTION 5 (a) Solve the equation 2 cos2 𝜃 − sin2 𝜃 = 4 sin 𝜃 − 2 for 0° < 𝜃 < 360°. (b) Express sin 3𝜃 − √3 cos 𝜃 in the form of 𝑅 sin(3𝜃 − 𝛼) where 𝑅 > 0 and 𝛼 is an acute angle. Hence solve the equationsin 3𝜃 − √3 cos 𝜃 = 1 for 0 ≤ 𝜃 ≤ 2𝜋. 5 SEF1124 MATHEMATICS 2 ADDITIONAL EXERCISES FROM PAST EXAMS 1. If cos 𝜃 = 0.3, find the value of cos 𝜃 + cos(𝜃 + 2𝜋) + cos(𝜃 − 2𝜋). 2. The point (5, −12) is on the terminal side of an angle 𝜃 in standard position. Find the exact value of sin 𝜃, cos 𝜃 and tan 𝜃. 3. Establish the identity cos 4𝜃−cos 8𝜃 cos 4𝜃+cos 8𝜃 = tan 2𝜃 tan 6𝜃. 4. Develop a formula for cos 4𝜃 as a fourth degree polynomial in the variable cos θ. 5. Find the exact value of 2 cos −1 𝑥 + 𝜋 = 4 cos −1 𝑥. 6. Establish the identity cos 𝜃+2 cos 2𝜃+cos 3𝜃 cos 𝜃−2 cos 2𝜃+cos 3𝜃 𝜃 = − cot 2 2 7. Solve the equation in [0°, 180°] sin 𝑥 + sin 3𝑥 + sin 5𝑥 = 0 8. Prove the identity cos 𝑥 1 + sin 𝑥 + = 2 sec 𝑥 1 + sin 𝑥 cos 𝑥 9. Using the sum-to-product formula, solve the equation sin 6𝑥 + sin 2𝑥 = √3 sin 4𝑥 in the interval [0, 𝜋]. 10. Without using a calculator, evaluate cos 200° csc(−70°). 11. Show that 4 sin 4𝑥 cos 2𝑥 cos 𝑥 = sin 7𝑥 + sin 5𝑥 + sin 3𝑥 + sin 𝑥. 12. Solve the equation sin3 𝑥 sec 𝑥 = 2 tan 𝑥 where 𝑥 is in the interval [0, 𝜋]. 13. Using the sum-to-product formula, find the general solution for the equation sin 4𝑥 + sin 2𝑥 = sin 3𝑥 END 6