NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 4 8•3 Lesson 4: Fundamental Theorem of Similarity (FTS) Student Outcomes ο§ Students experimentally verify the properties related to the fundamental theorem of similarity (FTS). Lesson Notes The goal of this activity is to show students the properties of the fundamental theorem of similarity (FTS) in terms of dilation. FTS states that given a dilation from center π and points π and π (points π, π, π are not collinear), the segments formed when π is connected to π and π′ is connected to π′ are parallel. More surprising is that |π′π′| = π|ππ|. That is, the segment ππ, even though it was not dilated as points π and π were, dilates to segment π′ π′ , and the length of segment π′π′ is the length of segment ππ multiplied by the scale factor. The following picture refers to the activity suggested in the Classwork Discussion below. Also, consider showing the diagram (without the lengths of segments), and ask students to make conjectures about the relationships between the lengths of segments ππ and π′π′. Classwork Discussion (30 minutes) For this Discussion, students need a piece of lined paper, a centimeter ruler, a protractor, and a four-function (or scientific) calculator. ο§ The last few days, we have focused on dilation. We now want to use what we know about dilation to come to some conclusions about the concept of similarity in general. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 44 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM ο§ 8•3 A regular piece of notebook paper can be a great tool for discussing similarity. What do you notice about the lines on the notebook paper? οΊ The lines on the notebook paper are parallel; that is, they never intersect. ο§ Keep that information in mind as we proceed through this activity. On the first line of your paper, mark a point π. This is our center. ο§ Mark the point π a few lines down from the center π. From point π, draw a ray βββββ ππ . Now, choose a π′ farther down the ray, also on one of the lines of the notebook paper. For example, you may have placed point π three lines down from the center and point π′ five lines down from the center. ο§ Use the definition of dilation to describe the lengths along this ray. οΊ ο§ By the definition of dilation, |ππ′| = π|ππ|. Recall that we can calculate the scale factor using the following computation: using the lines on the paper as our unit, the scale factor is π = |ππ′ | |ππ| = π. In my example, 5 because point π′ is five lines down from the 3 center, and point π is three lines down from the center. On the top of your paper, write the scale factor that you have obtained. ο§ Now draw another ray, ββββββ ππ . Use the same scale factor to mark points π and π′. In my example, I would place π three lines down and π′ five lines down from the center. ο§ Now connect point π to point π and point π′ to point π′. What do you notice about lines ππ and π′π′? οΊ ο§ Use your protractor to measure ∠πππ and ∠ππ′π′. What do you notice, and why is it so? οΊ ο§ ∠πππ and ∠ππ′π′ are equal in measure. They must be equal in measure because they are corresponding angles of parallel lines (lines ππ and π′π′) cut by a transversal (ray βββββ ππ ). (Consider asking students to write their answers to the following question in their notebooks and to justify their answers.) Now, without using your protractor, what can you say about ∠πππ and ∠ππ′π′? οΊ ο§ The lines ππ and π′π′ fall on the notebook lines, which means that lines ππ and π′π′ are parallel lines. These angles are also equal for the same reason; they are corresponding angles of parallel lines (lines ββββββ ). ππ and π′π′) cut by a transversal (ray ππ Use your centimeter ruler to measure the lengths of segments ππ and ππ′. By the definition of dilation, we expect |ππ′| = π|ππ| (i.e., we expect the length of segment ππ′ to be equal to the scale factor times the length of segment ππ). Verify that this is true. Do the same for lengths of segments ππ and ππ′. οΊ Sample of what student work may look like: Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 Note to Teacher: Using a centimeter ruler makes it easier for students to come up with a precise measurement. Also, let students know that it is okay if their measurements are off by a tenth of a centimeter, because that difference can be attributed to human error. 45 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM ο§ Lesson 4 8•3 Bear in mind that we have dilated points π and π from center π along their respective rays. Do you expect the segments ππ and π′π′ to have the relationship |π′π′| = π|ππ|? οΊ (Some students may say yes. If they do, ask for a convincing argument. At this point, they have knowledge of dilating segments, but that is not what we have done here. We have dilated points and then connected them to draw the segments.) ο§ Measure the segments ππ and π′π′ to see if they have the relationship |π′π′| = π|ππ|. ο§ It should be somewhat surprising that, in fact, segments ππ and π′π′ enjoy the same properties as the segments that we actually dilated. ο§ Now mark a point π΄ on line ππ between points π and π. Draw a ray from center π through point π΄, and then mark point π΄′ on the line π′π′. Do you think |π′π΄′| = π|ππ΄|? Measure the segments, and use your calculator to check. οΊ ο§ Now mark a point π΅ on the line ππ but this time not on the segment ππ (i.e., not between points π and π). Again, draw the ray from center π through point π΅, and mark the point π΅′ on the line π′π′. Select any of the Μ Μ Μ Μ , and verify that it has the same property as the others. Μ Μ Μ Μ , or ππ΅ segments, Μ Μ Μ Μ π΄π΅ , ππ΅ οΊ ο§ Sample of what student work may look like: Does this always happen, no matter the scale factor or placement of points π, π, π΄, and π΅? οΊ ο§ Students should notice that these new segments also have the same properties as the dilated segments. Yes, I believe this is true. One main reason is that everyone in class probably picked different points, and I’m sure many of us used different scale factors. In your own words, describe the rule or pattern that we have discovered. MP.8 Encourage students to write and collaborate with a partner to answer this question. Once students have finished their work, lead a discussion that crystallizes the information in the theorem that follows. ο§ We have just experimentally verified the properties of the fundamental theorem of similarity (FTS) in terms of dilation, namely, that the parallel line segments connecting dilated points are related by the same scale factor as the segments that are dilated. THEOREM: Given a dilation with center π and scale factor π, then for any two points π and π in the plane so that π, π, and π are not collinear, the lines ππ and π′π′ are parallel, where π′ = π·ππππ‘πππ(π) and π′ = π·ππππ‘πππ(π), and furthermore, |π′π′| = π|ππ|. Ask students to paraphrase the theorem in their own words, or offer them the following version of the theorem: FTS states that given a dilation from center π and points π and π (points π, π, and π are not on the same line), the segments formed when you connect π to π and π′ to π′ are parallel. More surprising is the fact that the segment ππ, even though it was not dilated as points π and π were, dilates to segment π′ π′ , and the length of segment π′π′ is the length of segment ππ multiplied by the scale factor. ο§ Now that we are more familiar with properties of dilations and FTS, we begin using these properties in the next few lessons to do things like verify similarity of figures. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 46 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 8•3 Exercise (5 minutes) Exercise In the diagram below, points πΉ and πΊ have been dilated from center πΆ by a scale factor of π = π. a. If |πΆπΉ| = π. π ππ¦, what is |πΆπΉ′ |? |πΆπΉ′ | = π(π. π ππ¦) = π. π ππ¦ b. If |πΆπΊ| = π. π ππ¦, what is |πΆπΊ′ |? |πΆπΊ′ | = π(π. π ππ¦) = ππ. π ππ¦ c. Connect the point πΉ to the point πΊ and the point πΉ′ to the point πΊ′. What do you know about the lines that contain segments πΉπΊ and πΉ′ πΊ′? The lines containing the segments πΉπΊ and πΉ′πΊ′ are parallel. d. What is the relationship between the length of segment πΉπΊ and the length of segment πΉ′ πΊ′? The length of segment πΉ′ πΊ′ is equal to the length of segment πΉπΊ, times the scale factor of π (i.e., |πΉ′ πΊ′ | = π|πΉπΊ|). e. Identify pairs of angles that are equal in measure. How do you know they are equal? |∠πΆπΉπΊ| = |∠πΆπΉ′ πΊ′ | and |∠πΆπΊπΉ| = |∠πΆπΊ′ πΉ′ | They are equal because they are corresponding angles of parallel lines cut by a transversal. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 47 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 4 8•3 Closing (5 minutes) Summarize, or ask students to summarize, the main points from the lesson. ο§ We know that the following is true: If |ππ′| = π|ππ| and |ππ′| = π|ππ|, then |π′π′| = π|ππ|. In other words, under a dilation from a center with scale factor π, a segment multiplied by the scale factor results in the length of the dilated segment. ο§ We also know that the lines ππ and π′π′ are parallel. ο§ We verified the fundamental theorem of similarity in terms of dilation using an experiment with notebook paper. Lesson Summary THEOREM: Given a dilation with center πΆ and scale factor π, then for any two points π· and πΈ in the plane so that πΆ, π·, and πΈ are not collinear, the lines π·πΈ and π·′πΈ′ are parallel, where π·′ = π«πππππππ(π·) and πΈ′ = π«πππππππ(πΈ), and furthermore, |π·′πΈ′| = π|π·πΈ|. Exit Ticket (5 minutes) Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 48 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM Name ___________________________________________________ 8•3 Date____________________ Lesson 4: Fundamental Theorem of Similarity (FTS) Exit Ticket Steven sketched the following diagram on graph paper. He dilated points π΅ and πΆ from point π. Answer the following questions based on his drawing. 1. What is the scale factor π? Show your work. 2. Verify the scale factor with a different set of segments. 3. Which segments are parallel? How do you know? 4. Are ∠ππ΅πΆ and ∠ππ΅′πΆ′ right angles? How do you know? Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 49 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 8•3 Exit Ticket Sample Solutions Steven sketched the following diagram on graph paper. He dilated points π© and πͺ from point πΆ. Answer the following questions based on his drawing. 1. What is the scale factor π? Show your work. |πΆπ©′ | = π|πΆπ©| π =π⋅π π =π π 2. Verify the scale factor with a different set of segments. |π©′ πͺ′ | = π|π©πͺ| π=π⋅π π =π π 3. Which segments are parallel? How do you know? Segments π©πͺ and π©′πͺ′ are parallel since they lie on the grid lines of the paper, which are parallel. 4. Are ∠πΆπ©πͺ and ∠πΆπ©′πͺ′ right angles? How do you know? The grid lines on graph paper are perpendicular, and since perpendicular lines form right angles, ∠πΆπ©πͺ and ∠πΆπ©′πͺ′ are right angles. Problem Set Sample Solutions Students verify that the fundamental theorem of similarity holds true when the scale factor π is 0 < π < 1. 1. Use a piece of notebook paper to verify the fundamental theorem of similarity for a scale factor π that is π < π < π. οΌ Mark a point πΆ on the first line of notebook paper. οΌ ββββββ . Mark the point π·′ on the Mark the point π· on a line several lines down from the center πΆ. Draw a ray, πΆπ· ray and on a line of the notebook paper closer to πΆ than you placed point π·. This ensures that you have a scale factor that is π < π < π. Write your scale factor at the top of the notebook paper. οΌ ββββββ , and mark the points πΈ and πΈ′ according to your scale factor. Draw another ray, πΆπΈ οΌ Connect points π· and πΈ. Then, connect points π·′ and πΈ′. οΌ ββββββ . Mark point π¨′ at Place a point, π¨, on the line containing segment π·πΈ between points π· and πΈ. Draw ray πΆπ¨ the intersection of the line containing segment π·′πΈ′ and ray ββββββ πΆπ¨. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 50 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 8•3 Sample student work is shown in the picture below: a. Are the lines containing segments π·πΈ and π·′πΈ′ parallel lines? How do you know? Yes, the lines containing segments π·πΈ and π·′πΈ′ are parallel. The notebook lines are parallel, and these lines fall on the notebook lines. b. Which, if any, of the following pairs of angles are equal in measure? Explain. i. ∠πΆπ·πΈ and ∠πΆπ·′πΈ′ ii. ∠πΆπ¨πΈ and ∠πΆπ¨′πΈ′ iii. ∠πΆπ¨π· and ∠πΆπ¨′π·′ iv. ∠πΆπΈπ· and ∠πΆπΈ′π·′ All four pairs of angles are equal in measure because each pair of angles are corresponding angles of parallel lines cut by a transversal. In each case, the parallel lines are line π·πΈ and line π·′ πΈ′ , and the transversal is the respective ray. c. Which, if any, of the following statements are true? Show your work to verify or dispute each statement. i. |πΆπ·′| = π|πΆπ·| ii. |πΆπΈ′| = π|πΆπΈ| iii. |π·′π¨′| = π|π·π¨| iv. |π¨′πΈ′| = π|π¨πΈ| All four of the statements are true. Verify that students have shown that the length of the dilated segment was equal to the scale factor multiplied by the original segment length. d. Do you believe that the fundamental theorem of similarity (FTS) is true even when the scale factor is π < π < π? Explain. Yes, because I just experimentally verified the properties of FTS for when the scale factor is π < π < π. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 51 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 2. 8•3 Caleb sketched the following diagram on graph paper. He dilated points π© and πͺ from center πΆ. a. What is the scale factor π? Show your work. |πΆπ©′ | = π|πΆπ©| π =π⋅π π =π π π =π π b. Verify the scale factor with a different set of segments. |π©′ πͺ′ | = π|π©πͺ| π =π⋅π π =π π π =π π c. Which segments are parallel? How do you know? Segment π©πͺ and π©′πͺ′ are parallel. They lie on the lines of the graph paper, which are parallel. d. Which angles are equal in measure? How do you know? |∠πΆπ©′ πͺ′ | = |∠πΆπ©πͺ|, and |∠πΆπͺ′ π©′ | = |∠πΆπͺπ©| because they are corresponding angles of parallel lines cut by a transversal. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 52 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 3. 8•3 Points π© and πͺ were dilated from center πΆ. a. What is the scale factor π? Show your work. |πΆπͺ′ | = π|πΆπͺ| π= π⋅π π =π π π=π b. If |πΆπ©| = π, what is |πΆπ©′ |? |πΆπ©′ | = π|πΆπ©| |πΆπ©′ | = π ⋅ π |πΆπ©′ | = ππ c. How does the perimeter of triangle πΆπ©πͺ compare to the perimeter of triangle πΆπ©′πͺ′? The perimeter of triangle πΆπ©πͺ is ππ units, and the perimeter of triangle πΆπ©′πͺ′ is ππ units. d. Did the perimeter of triangle πΆπ©′πͺ′ = π × (perimeter of triangle πΆπ©πͺ)? Explain. Yes, the perimeter of triangle πΆπ©′πͺ′ was twice the perimeter of triangle πΆπ©πͺ, which makes sense because the dilation increased the length of each segment by a scale factor of π. That means that each side of triangle πΆπ©′πͺ′ was twice as long as each side of triangle πΆπ©πͺ. Lesson 4: Fundamental Theorem of Similarity (FTS) This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M3-TE-1.3.0-08.2015 53 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.