HYDROGEN AND METHANE STORAGE IN ADSORBENT MATERIALS FOR AUTOMOTIVE APPLICATIONS Matthew Beckner1 and Anne Dailly2 2General 1Optimal CAE, Inc. Plymouth, MI, USA Motors Global Research and Development Center, Warren, MI, USA E-mail: matthew.beckner@gm.com Supporting Information Section S1 – IRMOF-1 IRMOF-1 was synthesized as previously described in the literature [1]. Hydrogen adsorption isotherms were measured at ambient temperature up to 350 bar using a custom built manometric adsorption instrument described previously [2,3]. Excess adsorption for IRMOF-1 is found in Fig. S1. Fig. S1. Graph showing the ambient temperature hydrogen excess adsorption of IRMOF-1. Section S2 – Derivation of Equations In this section, as throughout the main paper, lower case Latin alphabet symbols indicate quantities normalized to the sample mass (or volume as appropriate). S2.1 Equations 1-4 The excess adsorption πexc is defined to be the total mass of gas in the system πst less the amount of gas that would be present if the solid was non-adsorbing πgas (π, π)π£pore so that πexc β πst − πgas (π, π)π£pore (S1) By algebraically rearranging Eq. (S1), we arrive at Eq. (1) in the main text πst = πexc + πgas (π, π)π£pore (1) The storage per volume of adsorbent, Eq. (2), is obtained from by the following steps: πst = πst ππ π£st = πst πst ππ = πtank πtank (S2) Since the tank volume is also the bulk volume as defined in Table 1 in the main text ππ π£st = ππ π‘ (S4) πb and we arrive at Eq. (2) π£st = πst πb Eq. (3) is readily obtained by substitution Eq. (1) into Eq. (2) π£st = πexc πb + πgas (π, π)π£pore πb (3) From the definitions of the volumes in Table 1, we see that the pore volume is the bulk volume minus the skeletal volume or πpore = πb − πs (S3) (2) (S5) π£pore = πpore πb − πs πb πs = = − πs πs πs πs (S6) 1 1 − πb πs (S7) It follows that and π£pore = Substituting Eq. (S7) into Eq. (3) we have 1 1 π£st = πexc πb + πgas (π, π) ( − ) πb πb πs πb ) πs (4) π£st = πexc πb + πgas (π, π)π£pore πb (3) πgas (π, π)(πb − ππ ) π£st = πexc πb + πb πs (S9) πgas (π, π) (πb − 0)πb =0+ πs (S10) πgas (π, π)πb πb πb = πgas (π, π) πs πb (S11) (empty) π£st = (empty) π£st The volumetric storage of the tank with an adsorbent is greater than the storage of an empty tank if π£st > (empty) π£st so that πb πexc πb + πgas (π, π) (1 − ) > πgas (π, π) (S13) πs πexc > πb ) πs (S15) πgas (π, π) πgas (π, π) πgas (π, π) −( − ) πb πb πs (S16) πgas (π, π) πs (S20) It follows that πpore + πs 1 = ππ πs (S21) 1 1 = π£pore + ππ πs (S22) πs π£pore 1 1 = + ππ πs πs (S23) πs π£pore + 1 1 = ππ πs (S24) and πa = πs πs π£pore + 1 (9) S2.5 Equations 10-12 We define the packing factor π to be the ratio of the apparent volume to the volume of the tank πa πβ (S25) πtank It follows that π= πa πs πtank πs (S26) πb πa (S27) π= πb = ππa (5) S2.3 Equations 6-8 Eq. (7) is an algebraic manipulation of the definition Eq. (6). From Table 1, it is clear that πs < πc ≈ πa < πb From the definitions in Table 1 πs ππ β πpore + πs and and finally we arrive at Eq. (5) πexc > S2.4 Equation 9 (S14) πgas (π, π) πgas (π, π) πb − (1 − ) πb πb πs πexc > (8) (S12) = πgas (π, π) πexc πb > πgas (π, π) − πgas (π, π) (1 − (S19) πs > πc ≈ πa > πb The volumetric storage of an empty tank is obviously the density of the gas, but this can be obtained from Eq. (3) to demonstrate the consistency of these equations. In an empty tank, πexc = 0 and πs = 0 so that, starting from Eq. (3), (empty) πs πs πs π s > ≈ > πs πc πa πb (S8) S2.2 Equation 5 π£st (S18) and finally we arrive at Eq. (8) and finally arrive at Eq. (4) π£st = πexc πb + πgas (π, π) (1 − 1 1 1 1 > ≈ > πs πc πa πb (S17) (10) We arrive at Eq. (11) and (12) by replacing the bulk density in Eqs. (1) and (4) with Eq. (10). S2.6 Equations 13 and 14 In this paper, we consider a tank without walls. The mass includes the mass of the gas and mass of material. For an 8 GGE tank, πtank β ππ + π8GGE πtank = π8GGE + π8GGE πst (S28) πtank = πtank (13) πtank = The quantity π8GGE /πst is the total mass of the sample, keeping in mind that πst is normalized to the sample mass. This ratio is the total mass required to store 8GGE of gas. Since we are neglecting the walls of the container, the volume of the tank is simply the volume that the material occupies. πtank = πs πs (S29) πs πb (S30) π8GGE πst πb (S31) And finally using Eq. (10) πtank = π8GGE πst ππa (14) Section S3 – Table 1 for Reference Table 1. Definitions of different derived volumes. Corresponding densities are found by dividing the sample mass by the appropriate volume. Inter-particle Void Volume Solid Volume Closed Pore Volume Open Pore Volume Volume Skeletal X X Crystal* X X X Apparent X X X Bulk X X X X *Only includes closed pores that exist because of the theoretical structure or the structure surmised from x-ray scattering. References [1] Chae HK, Siberio-Pérez DY, Kim J, Go Y, Eddaoudi M, Matzger AJ, et al. A route to high surface area, porosity and inclusion of large molecules in crystals. Nature 2004;427:523–7. [2] Voskuilen T, Zheng Y, Pourpoint T. Development of a Sievert apparatus for characterization of high pressure hydrogen sorption materials. Int J Hydrogen Energy 2010;35:10387–95. [3] Beckner M, Dailly A. Adsorption Enthalpy Calculations of Hydrogen Adsorption at Ambient Temperature and Pressures Exceeding 300 bar. Am J Anal Chem 2013;04:8–16.