Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS Lesson 3: Addition and Subtraction Formulas Student Outcomes ο§ Students prove the subtraction formula for cosine and use their understanding of the properties of the trigonometric functions to derive the remaining addition and subtraction formulas for the sine, cosine, and tangent functions. ο§ Students use the addition and subtraction formulas to evaluate trigonometric functions to solve problems. Lesson Notes In previous lessons, students have used the unit circle to examine the periodicity and symmetry of the sine, cosine, and tangent functions. They have also explored relationships between trigonometric functions and have derived formulas to evaluate the functions for various values of π. In Algebra II, Module 2, Lesson 17, the teacher led the students through a geometric proof that established the sum formula for sine, and the remaining sum and difference formulas followed. In this lesson, students use analytic methods to prove the subtraction formula for the cosine function and then extend the result to the remaining sum and difference formulas using their understanding of the periodicity and symmetry of the functions. Students apply the formulas to evaluate the trigonometric functions for specific values. Classwork Opening (3 minutes) Remind students that they have used the periodicity and symmetry of trigonometric functions to evaluate the sine, cosine, and tangent functions for specific values of π. Students should then respond to the following prompts. After sharing their thoughts with a partner, several students could discuss their suggestions. ο§ In the previous two lessons, we have been discussing the unit circle using a carousel model with a rider π rotating counterclockwise on the outer edge of the carousel. Suppose the carousel rotates radians from its 4 starting position and then stops. How can we determine the position of the rider when the carousel stops? οΊ ο§ π π 4 π 4 The position is determined by cos ( ) and sin ( ). Instead, suppose that the carousel rotates radians from its starting position and then stops. How can we 3 determine the position of the rider? οΊ MP.3 & MP.7 ο§ π π 3 3 The position is determined by cos ( ) and sin ( ). Now, suppose that the carousel rotates 7π 12 radians from its starting position and then stops. How could we use what we have already discovered about the sine, cosine, and tangent functions to determine the position of the rider when the carousel stops? What additional information would we need to determine the position of the rider? Share your responses with a partner. Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 46 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. M4 Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM PRECALCULUS AND ADVANCED TOPICS οΊ Answers will vary but should address rewriting know the exact sine and cosine values, e.g., 7π 12 7π 12 as a sum or difference of values of π for which we π π 4 3 = + . Additional information required might include determining a means to find the sine and cosine of a sum. Discussion (5 minutes) This discussion addresses the fact that evaluating trigonometric functions for a sum of two values πΌ + π½ is not equivalent to evaluating the trigonometric functions for each value πΌ and π½ and then finding the sum. This discussion also address the utility of having a formula to compute the trigonometric functions of any sum or difference. ο§ One way to evaluate the position of the rider at π = calculate the exact positions, e.g., 7π 12 π π 4 3 7π 12 is to rewrite 7π 12 as a sum of values for which we can = ( + ). Perhaps we could find the position of our rider at π = π π 4 3 7π 12 by adding the front/back positions and adding the right/left positions of the rider for π = and π = . Determine whether this strategy is valid, and either justify why it is valid or provide a counterexample to demonstrate that it is not valid. Share your thoughts with a partner. MP.3 οΊ π Answers will vary, but students should determine that summing the position coordinates for π = and π π = will not produce the position coordinates for = 7π 3 12 4 . Counterexamples might include: 7π π π π π √2 12 7π 4 3 4 3 2 We know that cos ( ) ≠ cos ( ) + cos ( ) because cos ( ) + cos ( ) = because rotation by 12 1 7π 2 12 + , but cos ( ) < 0 produces a terminal ray in Quadrant II where cosine is negative. We know that 7π π π π π √2 12 4 3 4 3 2 sin ( ) ≠ sin ( ) + sin ( ) because sin ( ) + sin ( ) = + √3 2 , which exceeds the maximum possible value of 1 for the sine function. ο§ Now you may remember that in Algebra II we used geometry to establish the formulas for the sums and differences of sine and cosine. Here we are going to use a different approach to prove them. Scaffolding: Example 1 (7 minutes) This example provides an analytic way to derive the formula for the cosine of a difference. The students then apply their understanding of the properties of the trigonometric functions to the cosine of a difference formula to derive the remaining addition and subtraction formulas and to solve problems. The example should be completed in a whole-class setting. Alternatively, students could complete it in pairs or small groups, and the results could be discussed in a whole-class setting. ο§ What do the points π΄ and π΅ represent? οΊ ο§ Point π΄ represents the position on the unit circle after the initial ray is rotated by the amount πΌ, and point π΅ represents the position on the unit circle after the initial ray is rotated by the amount π½. How can we find the distance between points π΄ and π΅? οΊ We can apply the distance formula. Lesson 3: Date: ο§ Provide a visual display of the distance formula. ο§ Show students the expressions for the lengths Μ Μ Μ Μ π΄π΅ and Μ Μ Μ Μ Μ Μ π΄′π΅′ and ask students what the different parts of the expression represent and where they come from in the diagram. ο§ Have advanced students derive the formula for cos(π½ − πΌ) using the same analytic method and explain why the formula is equivalent to that for cos(πΌ − π½). Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 47 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS ο§ Which gives us? 2 2 Μ Μ Μ Μ π΄π΅ = √(cos(πΌ) − cos(π½)) + (sin(πΌ) − sin(π½)) οΊ ο§ What is the expanded form of this expression? Μ Μ Μ Μ π΄π΅ = √cos 2 (πΌ) − 2cos(πΌ)cos(π½) + cos 2 (π½) + sin2 (πΌ) − 2sin(πΌ)sin(π½) + sin2 (π½) οΊ ο§ How can we simplify the expression under the radical? We can use the Pythagorean Identity: sin2 (πΌ) + cos 2 (πΌ) = 1, and sin2 (π½) + cos 2 (π½) = 1. We can also factor −2 from the terms −2cos(πΌ)cos(π½) − 2sin(πΌ)sin(π½), which results in the simplified expression Μ Μ Μ Μ π΄π΅ = √2 − 2(cos(πΌ)cos(π½) + sin(πΌ)sin(π½)). οΊ ο§ How does the procedure applied to part (b) compare to that in part (a)? οΊ ο§ The same procedure is applied but this time to the image points. Why can we set Μ Μ Μ Μ π΄π΅ equal to Μ Μ Μ Μ Μ Μ π΄′π΅′? Segment Μ Μ Μ Μ Μ Μ π΄′π΅′ is the image of Μ Μ Μ Μ π΄π΅ rotated by – π½ about the origin, and distance is preserved under rotation, so the length of the segment is the same before and after rotation. οΊ Example 1 Consider the figures below. The figure on the right is obtained from the figure on the left by rotating by – π· about the origin. a. Μ Μ Μ Μ in the figure on the left. Calculate the length of π¨π© π π Μ Μ Μ Μ π¨π© = √(ππ¨π¬(πΆ) − ππ¨π¬(π·)) + (π¬π’π§(πΆ) − π¬π’π§(π·)) = √ππ¨π¬ π (πΆ) − πππ¨π¬(πΆ)ππ¨π¬(π·) + ππ¨π¬ π (π·) + π¬π’π§π (πΆ) − ππ¬π’π§(πΆ)π¬π’π§(π·) + π¬π’π§π (π·) = √ππ¨π¬ π (πΆ) + π¬π’π§π (πΆ) + ππ¨π¬ π (π·) + π¬π’π§π (π·) − πππ¨π¬(πΆ)ππ¨π¬(π·) − ππ¬π’π§(πΆ)π¬π’π§(π·) = √π − π(ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·)) b. Μ Μ Μ Μ Μ Μ in the figure on the right. Calculate the length of π¨′π©′ Μ Μ Μ Μ Μ Μ π¨′π©′ = √(ππ¨π¬(πΆ − π·) − π)π + (π¬π’π§(πΆ − π·) − π)π = √ππ¨π¬ π (πΆ − π·) − πππ¨π¬(πΆ − π·) + ππ + π¬π’π§π (πΆ − π·) = √ππ¨π¬ π (πΆ − π·) + π¬π’π§π (πΆ − π·) + π − πππ¨π¬(πΆ − π·) = √π − πππ¨π¬(πΆ − π·) Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 48 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS c. Set Μ Μ Μ Μ π¨π© and Μ Μ Μ Μ Μ Μ π¨′π©′ equal to each other, and solve the equation for ππ¨π¬(πΆ − π·). √π − πππ¨π¬(πΆ − π·) = √π − π(ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·)) π π (√π − πππ¨π¬(πΆ − π·)) = (√π − π(ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·))) π − πππ¨π¬(πΆ − π·) = π − π(ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·)) −πππ¨π¬(πΆ − π·) = −π(ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·)) ππ¨π¬(πΆ − π·) = ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·) ο§ Μ Μ Μ Μ Μ Μ are equal, and what the formula you’ve Turn to your neighbor and explain how you know that Μ Μ Μ Μ π΄π΅ and π΄′π΅′ just derived represents. οΊ Segments Μ Μ Μ Μ π΄π΅ and Μ Μ Μ Μ Μ Μ π΄′π΅′ have the same length because they are images of each other under rotation, which preserves length. The formula just derived provides a way to calculate the cosine of a number for which the cosine is not readily known by expressing that number as a difference of two numbers for which the sine and cosine values are readily known. Exercises 1–2 (7 minutes) Students should complete the exercises in pairs. After an appropriate time, volunteers could display their solutions, and additional students could provide alternative solutions or offer counterarguments to refute a solution. Students establish the sum formula for sine in the Exit Ticket, but it is summarized here for reference. Exercises 1–2 1. Use the fact that ππ¨π¬(−π½) = ππ¨π¬(π½) to determine a formula for ππ¨π¬(πΆ + π·). ππ¨π¬(πΆ + π·) = ππ¨π¬(πΆ— π·) = ππ¨π¬(πΆ)ππ¨π¬(−π·) + π¬π’π§(πΆ)π¬π’π§(−π·) = ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)(−π¬π’π§(π·)) = ππ¨π¬(πΆ)ππ¨π¬(π·) − π¬π’π§(πΆ)π¬π’π§(π·) 2. π π Use the fact that π¬π’π§(π½) = ππ¨π¬ ( − π½) to determine a formula for π¬π’π§(πΆ − π·). Scaffolding: ο§ Prompt struggling students for Exercise 1 by rewriting cos(πΌ + π½) as cos(πΌ − (−π½)). ο§ Have advanced students determine the formulas without cueing. π π¬π’π§(πΆ − π·) = ππ¨π¬ ( − (πΆ − π·)) π π = ππ¨π¬ (( − πΆ) + π·) π π π = ππ¨π¬ ( − πΆ) ππ¨π¬(π·) − π¬π’π§ ( − πΆ) π¬π’π§(π·) π π = π¬π’π§(πΆ)ππ¨π¬(π·) − ππ¨π¬(πΆ)π¬π’π§(π·) Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 49 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. M4 Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM PRECALCULUS AND ADVANCED TOPICS Sum and Difference Formulas for the Sine and Cosine Functions For all real numbers πΌ and π½, cos(πΌ − π½) = cos(πΌ)cos(π½) + sin(πΌ)sin(π½) cos(πΌ + π½) = cos(πΌ)cos(π½) − sin(πΌ)sin(π½) sin(πΌ − π½) = sin(πΌ)cos(π½) − cos(πΌ)sin(π½) sin(πΌ + π½) = sin(πΌ)cos(π½) + cos(πΌ)sin(π½) Example 2 (5 minutes) This example demonstrates how to apply the identity of tangent π as the ratio of sine π to cosine π to derive the addition formula for tangent, which students use to evaluate the tangent function for exact values of π. The example should be completed in pairs or small groups and then discussed in a whole-class setting. ο§ How can we use the identity tan(π) = οΊ ο§ sin(π) cos(π) to help us find an addition formula for tangent? Answers will vary but might indicate that we could rewrite tan(πΌ + π½) as the quotient of sin(πΌ + π½) and cos(πΌ + π½), and we could apply the addition formulas for sine and cosine to determine a formula. If we rewrite tan(πΌ + π½) = tan(πΌ + π½) = sin(πΌ+π½) and cos(πΌ+π½) apply the addition formulas for sine and cosine, we find the formula sin(πΌ)cos(π½)+sin(π½)cos(πΌ) . How can we determine what to do next to try to find a more user- cos(πΌ)cos(π½)−sin(πΌ)sin(π½) friendly expression for a tangent addition formula? οΊ ο§ What if we divide by cos(πΌ)cos(π½)? οΊ ο§ Answers will vary but might include dividing by a common term so the expressions are written in terms of tan(πΌ) and tan(π½). If students do not suggest this tactic, then suggest it to them. Answers will vary but should address that the cosines in the numerators of each term in the expression will reduce with the cosines in πππ (πΌ)πππ (π½) so that each term can be written in terms of the tangent function or as 1. Are there any restrictions on the values of πΌ and π½ for tan(πΌ + π½)? οΊ π π 2 2 Yes – πΌ and π½ cannot sum to + ππ, where π is an integer, because this would result in π‘ππ ( + ππ), which we have previously determined to be undefined. ο§ How can we verify this? οΊ π π 2 2 Answers will vary. An example of an acceptable response is included. If πΌ + π½ = , then π½ = − πΌ π and tan(πΌ + π½) = π sin(πΌ)cos( 2 −πΌ)+sin( 2 −πΌ) cos(πΌ) π 2 π 2 cos(πΌ)cos( −πΌ)−sin(πΌ)sin( −πΌ) = sin(πΌ)sin(πΌ)+cos(πΌ) cos(πΌ) cos(πΌ)sin(πΌ)−sin(πΌ) cos(πΌ) = sin2 (πΌ)+cos2 (πΌ) 0 , which is undefined. Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 50 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS Example 2 Use the identity πππ§(π½) = π¬π’π§(π½) ππ¨π¬(π½) to show that πππ§(πΆ + π·) = πππ§(πΆ)+πππ§(π·) . π−πππ§(πΆ)πππ§(π·) π¬π’π§(πΆ + π·) ππ¨π¬(πΆ + π·) π¬π’π§(πΆ)ππ¨π¬(π·) + π¬π’π§(π·)ππ¨π¬(πΆ) = ππ¨π¬(πΆ)ππ¨π¬(π·) − π¬π’π§(πΆ)π¬π’π§(π·) πππ§(πΆ + π·) = π¬π’π§(πΆ)ππ¨π¬(π·) + π¬π’π§(π·)ππ¨π¬(πΆ) ππ¨π¬(πΆ)ππ¨π¬(π·) =( )( ) ππ¨π¬(πΆ)ππ¨π¬(π·) − π¬π’π§(πΆ)π¬π’π§(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) π¬π’π§(πΆ)ππ¨π¬(π·) π¬π’π§(π·)ππ¨π¬(πΆ) + ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) π¬π’π§(πΆ)π¬π’π§(π·) − ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) πππ§(πΆ) + πππ§(π·) = π − πππ§(πΆ)πππ§(π·) = Exercises 3–5 (10 minutes) Students should complete the exercises in pairs. After an appropriate time, volunteers could display their solutions. As time permits, students should be encouraged to show different approaches to finding the solutions. Exercises 3–5 3. Verify the identity πππ§(πΆ − π·) = πππ§(πΆ)−πππ§(π·) π for all (πΆ − π·) ≠ + π π. π+πππ§(πΆ)πππ§(π·) π πππ§(πΆ − π·) = πππ§(πΆ + (−π·)) = = = 4. MP.7 πππ§(πΆ) + πππ§(−π·) π − πππ§(πΆ)πππ§(−π·) πππ§(πΆ) + (−πππ§(π·)) π − πππ§(πΆ)(−πππ§(π·)) πππ§(πΆ) − πππ§(π·) π + πππ§(πΆ)πππ§(π·) Scaffolding: Have advanced students verify using the relationship between the sine and cosine functions that 5π 23π cos (− ) = −sin ( ). 12 12 Use the addition and subtraction formulas to evaluate the expressions shown. a. ππ¨π¬ (− ππ ) ππ ππ¨π¬ (− ππ π ππ π ππ π ππ ) = ππ¨π¬ ( − ) = ππ¨π¬ ( ) ππ¨π¬ ( ) + π¬π’π§ ( ) π¬π’π§ ( ) ππ π π π π π π = b. π¬π’π§ ( √π −π √π √π √π − √π ( )+ ( )= π π π π π πππ ) ππ πππ ππ π ππ π π ππ π¬π’π§ ( ) = π¬π’π§ ( − ) = π¬π’π§ ( ) ππ¨π¬ ( ) − π¬π’π§ ( ) ππ¨π¬ ( ) ππ π π π π π π = Lesson 3: Date: √π π √π − √π √π √π ( )− ( )= π π π π π Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 51 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS c. πππ§ ( ππ ) ππ π π πππ§ ( ) + πππ§ ( ) ππ π π π π πππ§ ( ) = πππ§ ( + ) = π π ππ π π π − πππ§ ( ) πππ§ ( ) π π √π +π √π + π ππ + π√π π = = = = π + √π π π − √π √π π − ( ) (π) π MP.3 5. Use the addition and subtraction formulas to verify these identities for all real-number values of π½. a. π¬π’π§(π − π½) = π¬π’π§(π½) π¬π’π§(π − π½) = π¬π’π§(π )ππ¨π¬(π½) − π¬π’π§(π½)ππ¨π¬(π ) = π(ππ¨π¬(π½)) − π¬π’π§(π½)(−π) = π¬π’π§(π½) b. ππ¨π¬(π + π½) = −ππ¨π¬(π½) ππ¨π¬(π + π½) = ππ¨π¬(π )ππ¨π¬(π½) − π¬π’π§(π )π¬π’π§(π½) = −π(ππ¨π¬(π½)) − π(π¬π’π§(π½)) = −ππ¨π¬(π½) Sum and Difference Formulas for the Tangent Function For all real numbers πΌ and π½ for which the expressions are defined, tan(πΌ − π½) = Lesson 3: Date: tan(πΌ) − tan(π½) tan(πΌ) + tan(π½) andβtan(πΌ + π½) = . 1 + tan(πΌ)tan(π½) 1 − tan(πΌ)tan(π½) Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 52 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS Closing (3 minutes) Have students write a response to the prompts below and share their responses with a partner. ο§ ο§ What are the sum and difference formulas for sine and cosine? οΊ cos(πΌ − π½) = cos(πΌ)cos(π½) + sin(πΌ)sin(π½) οΊ cos(πΌ + π½) = cos(πΌ)cos(π½) − sin(πΌ)sin(π½) οΊ sin(πΌ − π½) = sin(πΌ)cos(π½) − cos(πΌ)sin(π½) οΊ sin(πΌ + π½) = sin(πΌ)cos(π½) + cos(πΌ)sin(π½) How can the addition and subtraction formulas be used to find the position of the rider from the beginning of the lesson? οΊ 7π To find the front/back position of the rider, we need to find sin ( ), which we could rewrite as the 12 difference of two numbers, e.g., sin ( 3π 4 π − ) and then apply the formula sin(πΌ − π½) = 6 sin(πΌ) cos(π½) − cos(πΌ) sinβ‘(π½) to find the position. οΊ 7π To find the right/left position of the rider, we need to find cos ( ), which we could rewrite as the 12 difference of two numbers, e.g., cos ( 3π 4 π − ) and then apply the formula cos(πΌ − π½) = 6 cos(α) cos(π½) + sin(πΌ) sin(π½) to find the position. Lesson Summary The sum and difference formulas for sine, cosine, and tangent are summarized below. For all real numbers πΆ and π· for which the expressions are defined, ππ¨π¬(πΆ − π·) = ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·) ππ¨π¬(πΆ + π·) = ππ¨π¬(πΆ)ππ¨π¬(π·) − π¬π’π§(πΆ)π¬π’π§(π·) π¬π’π§(πΆ − π·) = π¬π’π§(πΆ)ππ¨π¬(π·) − ππ¨π¬(πΆ)π¬π’π§(π·) π¬π’π§(πΆ + π·) = π¬π’π§(πΆ)ππ¨π¬(π·) + ππ¨π¬(πΆ)π¬π’π§(π·) πππ§(πΆ) − πππ§(π·) π + πππ§(πΆ)πππ§(π·) πππ§(πΆ) + πππ§(π·) πππ§(πΆ + π·) = . π − πππ§(πΆ)πππ§(π·) πππ§(πΆ − π·) = Exit Ticket (5 minutes) Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 53 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS Name Date Lesson 3: Addition and Subtraction Formulas Exit Ticket 1. Prove that sin(πΌ + π½) = sin(πΌ) cos(π½) + sin(π½) cosβ‘(πΌ). 2. Use the addition and subtraction formulas to evaluate the given trigonometric expressions. π a. sin ( ) b. tan ( 12 13π 12 ) Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 54 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS Exit Ticket Sample Solutions 1. Prove that π¬π’π§(πΆ + π·) = π¬π’π§(πΆ) ππ¨π¬(π·) + π¬π’π§(π·) ππ¨π¬β‘(πΆ). π¬π’π§(πΆ + π·) = π¬π’π§(πΆ − (−π·)) = π¬π’π§(πΆ)ππ¨π¬(−π·) − π¬π’π§(−π·)ππ¨π¬(πΆ) = π¬π’π§(πΆ)ππ¨π¬(π·) − (−π¬π’π§(π·))(ππ¨π¬(πΆ)) = π¬π’π§(πΆ)ππ¨π¬(π·) + π¬π’π§(π·)ππ¨π¬(πΆ) 2. Use the addition and subtraction formulas to evaluate the given trigonometric expressions. a. π¬π’π§ ( π¬π’π§ ( π ) ππ π π π ) = π¬π’π§ ( − ) ππ π π π π π π = π¬π’π§ ( ) ππ¨π¬ ( ) − π¬π’π§ ( ) ππ¨π¬ ( ) π π π π √π π √π √π √π − √π = ( )( ) − ( )( ) = π π π π π b. πππ§ ( πππ ) ππ πππ ππ π πππ§ ( ) = πππ§ ( + ) ππ π π ππ π πππ§ ( ) + πππ§ ( ) π π = ππ π π − πππ§ ( ) πππ§ ( ) π π = −π + √π π − (−π)(√π) = −π + √π π + (√π) = −π + π√π = π − √π −π Problem Set Sample Solutions 1. Use the addition and subtraction formulas to evaluate the given trigonometric expressions. a. ππ¨π¬ ( π ) ππ π π π π π π π π π π π π π √π √π √π √π+√π β + β = π π π π π π π π π π π π π π π √π √π π π π π π π π π π π π √π √π √π √π+√π β + β = π π π π π ππ¨π¬ ( − ) = ππ¨π¬ ( ) ππ¨π¬ ( ) + π¬π’π§ ( ) π¬π’π§ ( ) = b. π¬π’π§ ( π ) ππ π π π¬π’π§ ( − ) = π¬π’π§ ( ) ππ¨π¬ ( ) − ππ¨π¬ ( ) π¬π’π§ ( ) = c. π¬π’π§ ( π β π π π − β √π π = √π−√π π ππ ) ππ π π π¬π’π§ ( + ) = π¬π’π§ ( ) ππ¨π¬ ( ) + ππ¨π¬ ( ) π¬π’π§ ( ) = Lesson 3: Date: Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 55 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS d. ππ¨π¬ (− π ) ππ π π π π π π π π π π π π √π π π π π π π π π π π π π √π ππ¨π¬ (− ππ ) ππ ππ¨π¬ (− √π π √π √π √π−√π π π π π π π − ) = ππ¨π¬ (− ) ππ¨π¬ ( ) + π¬π’π§ (− ) π¬π’π§ ( ) = β − β = π π π π π π π π π π π ππ¨π¬ ( − ) = ππ¨π¬ ( ) ππ¨π¬ ( ) + π¬π’π§ ( ) π¬π’π§ ( ) = e. π¬π’π§ ( ππ ) ππ π¬π’π§ ( + ) = π¬π’π§ ( ) ππ¨π¬ ( ) + ππ¨π¬ ( ) π¬π’π§ ( ) = f. g. h. i. πππ ) ππ π¬π’π§ ( √π π √π √π √π−√π ππ π ππ π ππ π + ) = π¬π’π§ ( ) ππ¨π¬ ( ) + ππ¨π¬ ( ) π¬π’π§ ( ) = β − β = π π π π π π π π π π π ππ¨π¬ (− πππ ) ππ ππ¨π¬ (− √π π √π √π √π−√π π π π π π π − ) = ππ¨π¬ (− ) ππ¨π¬ ( ) + π¬π’π§ (− ) π¬π’π§ ( ) = β − β = π π π π π π π π π π π π¬π’π§ ( π π π π ) ππ¨π¬ ( ) + ππ¨π¬ ( ) π¬π’π§ ( ) ππ ππ ππ ππ π π π¬π’π§ ( π π π π π π π π π π π π π π π π π √π π π π π π ππ¨π¬ ( ) ππ¨π¬ ( ) − π¬π’π§ ( ) π¬π’π§ ( ) π π ππ¨π¬ ( ) = m. √π π¬π’π§ ( ) ππ¨π¬ ( ) + π¬π’π§ ( ) π¬π’π§ ( ) π¬π’π§ ( ) = l. π π ππ π ππ π ) ππ¨π¬ ( ) − ππ¨π¬ ( ) π¬π’π§ ( ) ππ π ππ π π¬π’π§ ( ) = k. π √π √π √π+√π β + β = π π π π π π¬π’π§ ( π¬π’π§ ( ) = j. π √π √π √π+√π β + β = π π π π π √π π π π ππ¨π¬ ( ) ππ¨π¬ ( π π ππ¨π¬ ( ) = π π π ) + π¬π’π§ ( ) π¬π’π§ ( ) ππ π ππ √π Lesson 3: Date: π Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 56 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS n. π π π¬π’π§ ( ) ππ¨π¬ ( π π π¬π’π§ ( ) = 2. π π π ) − ππ¨π¬ ( ) π¬π’π§ ( ) ππ π ππ √π π The figure below and to the right is obtained from the figure on the left by rotating the angle by πΆ about the origin. Use the method shown in Example π to show that ππ¨π¬(π + π) = ππ¨π¬(π)ππ¨π¬(π) − π¬π’π§(π)π¬π’π§(π). π π Μ Μ Μ Μ π¨π© = √(ππ¨π¬(π·) − ππ¨π¬(πΆ)) + (π¬π’π§(π·) − π¬π’π§(πΆ)) Μ Μ Μ Μ Μ Μ = √(ππ¨π¬(πΆ + π·) − (−π))π + (π¬π’π§(πΆ + π·) − π)π π¨′π©′ Μ Μ Μ Μ π¨π© = Μ Μ Μ Μ Μ Μ π¨′π©′ π π (ππ¨π¬(π·) − ππ¨π¬(πΆ)) + (π¬π’π§(π·) − π¬π’π§(πΆ)) π = (ππ¨π¬(πΆ + π·) − (−π)) + (π¬π’π§(πΆ + π·) − π)π ππ¨π¬ π (π·) − πππ¨π¬(π·)ππ¨π¬(πΆ) + ππ¨π¬ π (πΆ) + π¬π’π§π (π·) − ππ¬π’π§(π·)π¬π’π§(πΆ) + π¬π’π§π (πΆ) = ππ¨π¬ π (πΆ + π·) + πππ¨π¬(πΆ + π) + π + π¬π’π§π (πΆ + π·) π − πππ¨π¬(π·)ππ¨π¬(πΆ) − ππ¬π’π§(π·)π¬π’π§(πΆ) = π + πππ¨π¬(πΆ + π·) −ππ¨π¬(π·)ππ¨π¬(πΆ) − π¬π’π§(π·)π¬π’π§(πΆ) = ππ¨π¬(πΆ + π) ππ¨π¬(πΆ)ππ¨π¬(π·) − π¬π’π§(πΆ)π¬π’π§(π·) = ππ¨π¬(πΆ + π·) 3. Use the sum formula for sine to show that π¬π’π§(πΆ − π·) = π¬π’π§(πΆ)ππ¨π¬(π·) − ππ¨π¬(πΆ)π¬π’π§(π·). π¬π’π§(πΆ − π·) = π¬π’π§(πΆ + (−π·)) = π¬π’π§(πΆ)ππ¨π¬(−π·) + ππ¨π¬(πΆ)π¬π’π§(−π·) = π¬π’π§(πΆ)ππ¨π¬(π·) − ππ¨π¬(πΆ)π¬π’π§(π·) 4. Evaluate πππ§(π + π) = πππ§(ππΆ) = π¬π’π§(π+π) πππ§(πΆ)+πππ§(π·) to show πππ§(πΆ + π·) = . Use the resulting formula to show that ππ¨π¬(π+π) π−πππ§(πΆ)πππ§(π·) ππππ§(πΆ) . π−πππ§π (πΆ) πππ§(πΆ + π·) = π¬π’π§(πΆ + π·) π¬π’π§(πΆ)ππ¨π¬(π·) + ππ¨π¬(πΆ)π¬π’π§(π·) = ππ¨π¬(πΆ + π·) ππ¨π¬(πΆ)ππ¨π¬(π·) − π¬π’π§(πΆ)π¬π’π§(π·) Dividing the numerator and denominator by ππ¨π¬(πΆ)ππ¨π¬(π·) gives π¬π’π§(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)π¬π’π§(π·) + πππ§(πΆ) + πππ§(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) πππ§(πΆ + π·) = = . ππ¨π¬(πΆ)ππ¨π¬(π·) π¬π’π§(πΆ)π¬π’π§(π·) π − πππ§(πΆ)πππ§(π·) − ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) It then follows that πππ§(ππΆ) = πππ§(πΆ + πΆ) = Lesson 3: Date: πππ§(πΆ) + πππ§(πΆ) ππππ§(πΆ) = . π − πππ§(πΆ)πππ§(πΆ) π − πππ§π (πΆ) Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 57 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS 5. Show ππ§(π − π) = πππ§(π)−πππ§(π) . π+πππ§(π)πππ§(π) πππ§(πΆ − π·) = π¬π’π§(πΆ − π·) π¬π’π§(πΆ)ππ¨π¬(π·) − ππ¨π¬(πΆ)π¬π’π§(π·) = ππ¨π¬(πΆ − π·) ππ¨π¬(πΆ)ππ¨π¬(π·) + π¬π’π§(πΆ)π¬π’π§(π·) Dividing the numerator and denominator by ππ¨π¬(πΆ)ππ¨π¬(π·) gives πππ§(πΆ − π·) = 6. π¬π’π§(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)π¬π’π§(π·) − πππ§(πΆ) − πππ§(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) = . ππ¨π¬(πΆ)ππ¨π¬(π·) π¬π’π§(πΆ)π¬π’π§(π·) π + πππ§(πΆ)πππ§(π·) + ππ¨π¬(πΆ)ππ¨π¬(π·) ππ¨π¬(πΆ)ππ¨π¬(π·) Find the exact value of the following by using addition and subtraction formulas. a. b. c. d. πππ§ ( π ) ππ πππ§ ( π ) ( ) πππ§(π π π π π −πππ§ π = √π−π = π − ) = πππ§ ( − ) = √π. π ππ π π )πππ§( ) π+πππ§(π π+√π π π πππ§ (− π ) ππ πππ§ (− π πππ§(π π π π π−√π π )−πππ§(π ) ) = πππ§ ( − ) = = = −π + √π. π ππ π π ) π+πππ§( π )πππ§(π π+√π π πππ§ ( ππ ) ππ πππ§ ( π πππ§(π ππ π π π+√π π )+πππ§( π ) ) = πππ§ ( + ) = = −π − √π. π = ππ π π )πππ§( ) π−πππ§(π π−√π π π πππ§ (− πππ ) ππ πππ§ (− ππ πππ§(π πππ π ππ π−√π π )−πππ§( π ) ) = πππ§ ( − ) = = = −π + √π. π ππ π π π+√π π+πππ§(π )πππ§(ππ ) π π π π ππ π π π−πππ§( )πππ§( ) π ππ πππ§( )+πππ§( ) e. π π π ππ π π π−πππ§( )πππ§( ) π ππ πππ§( )+πππ§( ) π π π ππ = πππ§ ( + ππ π ππ π ) = πππ§ (ππ ) = πππ§ ( π) = √π. π π π ππ π π π+πππ§( )πππ§( ) π ππ πππ§( )−πππ§( ) f. π π π ππ π π π+πππ§( )πππ§( ) π ππ πππ§( )−πππ§( ) Lesson 3: Date: π π π ππ = πππ§ ( − ) = πππ§ (ππ ) = πππ§ ( π) = π. Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 58 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3 NYS COMMON CORE MATHEMATICS CURRICULUM M4 PRECALCULUS AND ADVANCED TOPICS π ππ π ππ π π π−πππ§( )πππ§( ) ππ ππ πππ§( )+πππ§( ) g. π ππ π ππ π π π−πππ§( )πππ§( ) ππ ππ πππ§( )+πππ§( ) Lesson 3: Date: = πππ§ ( π ππ + π ππ π ) = πππ§ ( π) = π √π = √π . π Addition and Subtraction Formulas 2/8/16 © 2015 Common Core, Inc. Some rights reserved. commoncore.org 59 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.