Genetics Test Check CLASS COPY. CLASS COPY. CLASS COPY. CLASS COPY.
Note: STUDY ALL MATERIALSSSS! DO NOT JUST RELY ON THIS!
MATCHING: Match the correct letter with each response. You will not use all answers.
1.
2.
3.
4.
5.
Codominance
Polygenic
Incomplete dominance
Sex-linked
Simple(dominant controlled)
a. There are only 2 phenotypes: dominant and recessive
b. There are 3 phenotypes; the heterozygous is a blend of both.
c. The trait is found either on the x or the y chromosome.
d. There is more than 1 gene that controls a single trait.
e. There are several traits controlled by only one gene.
f. There are 3 phenotypes; the heterozygous shows each
parent phenotype separately or a pattern.
MULTIPLE CHOICE: Carefully read each prompt and then choose the BEST answer.
Use the following to answer #6 and 7. Hemophiliacs have blood that does not coagulate
well, and they often die at a young age. The disease allele is recessive and X-linked.
6. What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
7. A hemophiliac male(affected) and a female who is a carrier for the disease(She does not
have the disease but can pass it down) mate. Make a Punnett square. Which of the
following is true based on your Punnett square?
a. 100% of children can be hemophiliac(affected).
b. 100% of females can be hemophiliac(affected).
c. 100% of males would be hemophiliac(affected).
d. Half of the females and half of the males could be hemophiliac(affected).
e. 100% of children will be normal(unaffected).
Use the following for #8 and 9: In dogs, D=pointed ears and d=round ears. A dog that is
homozygous dominant for pointed ears breeds with a female dog that has round ears.
8. What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
9. What are the chances of having a puppy with pointed ears?
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%
Use the following for #10 and 11. In a certain animal, B=blue allele and Y=yellow allele. The
heterozygous phenotype is green.
10. What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
11. A blue and a green parent mate. What are the chances they will have a yellow baby?
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%
Use the following for #12 and 13. In a certain animal, B=black and W=white. The heterozygous
phenotype is black and white spots.
12. What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
13. A spotted animal mates with another spotted animal. What are the chances of getting black
offspring?
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%
Use the following for #14 and 15. In dogs, D=pointed ears and d=round ears AND L=large paws and
l=small paws. Assume that we are looking at the chance of having BOTH traits.
14. A heterozygous pointed ear/heterozygous large paw male mates with a homozygous
pointed ear/homozygous small paw female. What is the female’s genotype?
a. DdLl
b. DDLL
c. DDll
d. ddll
e. ddLL
15. Using the dihybrid cross method for both traits, make your Punnett square(s). What are
they chances of having a pointed ear/small paw puppy?
a. 2/16
b. 6/16
c. 8/16
d. 12/16
e. 16/16
Use the following for #16-18. A male that has blood type O mates with a female that has blood
type A.
16. Type O is ___________ to type A.
a. Dominant
b. Incompletely dominant
c. Codominant
d. Recessive
e. None of the above
17. Type A is _________ to type B.
a. Dominant
b. Incompletely dominant
c. Codominant
d. Recessive
e. None of the above
18. The male and female mate and they have a type A child. What is the mother’s genotype
that would ensure that the child is type A?
a.
b.
c.
d.
e.
IAIB
IAIA
A
I Ai
ii
Genetics Test Check
KEY
Note: STUDY ALL MATERIALSSSS! DO NOT JUST RELY ON THIS!
MATCHING: Match the correct letter with each response. You will not use all answers.
1.
2.
3.
4.
5.
F Codominance
a. There are only 2 phenotypes: dominant and recessive
D Polygenic
b. There are 3 phenotypes; the heterozygous is a blend of both.
B Incomplete dominance
c. The trait is found either on the x or the y chromosome.
C Sex-linked
d. There is more than 1 gene that controls a single trait.
A Simple(dominant controlled)e. There are several traits controlled by only one gene.
f. There are 3 phenotypes; the heterozygous shows each
parent phenotype separately or a pattern.
MULTIPLE CHOICE: Carefully read each prompt and then choose the BEST answer.
Use the following to answer #6 and 7. Hemophiliacs have blood that does not coagulate
well, and they often die at a young age. The disease allele is recessive and X-linked.
6. D What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
7. D A hemophiliac male(affected) and a female who is a carrier for the disease(She does not
have the disease but can pass it down) mate. Make a Punnett
square. Which of the following is true based on your Punnett
square?
a. 100% of children can be hemophiliac(affected).
b. 100% of females can be hemophiliac(affected).
c. 100% of males would be hemophiliac(affected).
d. Half of the females and half of the males could be
hemophiliac(affected).
e. 100% of children will be normal(unaffected).
Use the following for #8 and 9: In dogs, D=pointed ears and d=round ears. A dog that is
homozygous dominant for pointed ears breeds with a female dog that has round ears.
8. A What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
9. E What are the chances of having a puppy with pointed ears?
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%
Use the following for #10 and 11. In a certain animal, B=blue allele and Y=yellow allele. The
heterozygous phenotype is green.
10. B What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
11. A A blue and a green parent mate. What are the chances they will have
a
yellow baby?
B Y
a. 0%
BY
b. 25%
c. 50%
BY
d. 75%
e. 100%
Use the following for #12 and 13. In a certain animal, B=black and W=white. The heterozygous
phenotype is black and white spots.
12. C What type of inheritance is this?
a. Simple dominance
b. Incomplete
c. Codominance
d. Sex-linked
e. None of the above
13. B A spotted animal mates with another spotted animal. What are the chances of getting
black offspring?
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%
Use the following for #14 and 15. In dogs, D=pointed ears and d=round ears AND L=large paws and
l=small paws. Assume that we are looking at the chance of having BOTH traits.
14. C A heterozygous pointed ear/heterozygous large paw male mates with a homozygous
pointed ear/homozygous small paw female. What is the female’s genotype?
a. DdLl
Ear D
d
b. DDLL
D
DD Dd c. DDll
D
DD Dd d. ddll
e. ddLL
15. C Using the dihybrid cross method for both traits, make your Punnett square(s). What are
they chances of having a pointed ear/small paw puppy? (4/4 pointed x 2/4 small =8/16)
a. 2/16
Paw L l
l
Ll ll b. 6/16
c. 8/16
l
Ll ll
d. 12/16
e. 16/16
Use the following for #16-18. A male that has blood type O mates with a female that has blood
type A.
16. D Type O is ___________ to type A.
a. Dominant
b. Incompletely dominant
c. Codominant
d. Recessive
e. None of the above
17. C Type A is _________ to type B.
a. Dominant
b. Incompletely dominant
c. Codominant
d. Recessive
e. None of the above
18. B The male and female mate and they have a type A child. What is the mother’s genotype
that would ensure the offspring was type A?
a.
b.
c.
d.
e.
IAIB
IAIA(Mom has to have 2 A alleles to pass down to the child. If
the mom was AO, the child could get the O and be OO(ii). )
A
I Ai
ii