1 HORT6033 Molecular Plant Breeding Quiz 2 Sept. 17, 2014 Name: 1. What is called for the below procedure? Answer: (http://users.ugent.be/~avierstr/principles/pcr.html) 2. What type of marker for below figure? Answer: (Below image from http://www.cdfd.org.in/) In above image, if the size of band ‘1/1’ is 100bp, what are the sizes of these bands? (1) ‘1/1’: (2) ‘2/2’: (3) ‘3/3’: (4) ‘1/2’: (5) ‘1/3’: (6) ‘2/3’: 2 3. Below is a type of molecular marker. What is called? Answer: 4. Suppose: Bacterial blight resistance in cowpea is controlled by a major gene ‘B1’. Resistance is dominant and susceptible is recessive. Parent 1 is resistance (B1B1) and Parent 2 susceptible (b1b1). Questions: (1) If we make a cross between the two parents, F1 is resistant or susceptible? Answer: (2) If the F1 self-pollinated, what is the expected ratio between resistant to susceptible plants in the F2 population? Resistant: susceptible = (3) If F1 is backcrossed to Parent 1, what is the expected ratio between resistant to susceptible plants in BC1F1(P1) population? Resistant: susceptible = (4) If F1 is backcrossed to Parent 2, what is the expected ratio between resistant to susceptible plants in BC1F1(P2) population? Resistant: susceptible = 3 5. Below is a phylogenetic tree among 26 spinach genotypes: Hellcat Unipack 277 Hector Lion Crocodile Spinner Cheetah Polar Bear T-Bird Indian Summer Megaton Alrite Tyee Melody Samish Unipack 151 Lazio Tarpy Whale Unipack 12 Eagle Bolero Denali Cherokee Vancouver Regal Questions: (1) What tools (software) can create above genetic diversity tree? Answer: (2) See the bottom spinach line Regal, which spinach line is the closest one according the genetic diversity? Answer: (3) From the top two lines, which one, Hellcat or Unipack 277 is closer to Regal (bottom)? Answer: 4 6. Supposed: One SNP [T/G] shows 101 plants with [TT], 200 plants with [GT] and 99 plants with [GG] in an F2 population derived from P1 [TT] x P2 [GG], the goodness-of-fit and independence using a chi-square test is shown below Table. Please fill the blank in the table and explain whether the SNP actions like a gene! F2 Total [TT] Total [GT] Total [GG] Total Obs 101 200 99 400 Exp value exp ratio Chi Square P Value There are 400 pea F2 plants consisted of 301 plants with purple flower and 99 white flower as below table. Please fill the blanks in the table! Based on the data, how many gene(s) control the flower color? F2 Purple flower White flower Total Obs 301 99 400 Exp value exp ratio Chi Square P Value 5 7. Suppose: A SNP marker M1 [A/C] is linked to the pea color gene ‘T1’ with the recombination rate r. In the BC1F1(P2) population, the genotypes and phenotypes and their count are below. To test flower color, please fill below Table Purple White Total 200 AC CC Total 200 Obs Exp Chi-sqaure P value To test SNP marker Obs Exp Chi-sqaure P value To calculate recombination rate (r ), please fill below table: female BC1F1(P2) male Ct1 100% AT1 (1-r)/2 Ct1 (1-r)/2 At1 r/2 CT1 r/2 ACT1t1 CCt1t1 ACt1t1 CCT1t1 purple flower white flower white flower purple flower genotype frequency Phenotype Obs. r recombination rate ( r) =