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HORT6033 Molecular Plant Breeding
Quiz 2 Sept. 17, 2014
Name:
1. What is called for the below procedure? Answer:
(http://users.ugent.be/~avierstr/principles/pcr.html)
2. What type of marker for below figure? Answer:
(Below image from http://www.cdfd.org.in/)
In above image, if the size of band ‘1/1’ is 100bp, what are the sizes of these bands?
(1) ‘1/1’:
(2) ‘2/2’:
(3) ‘3/3’:
(4) ‘1/2’:
(5) ‘1/3’:
(6) ‘2/3’:
2
3. Below is a type of molecular marker. What is called? Answer:
4. Suppose:
Bacterial blight resistance in cowpea is controlled by a major gene ‘B1’. Resistance is dominant
and susceptible is recessive. Parent 1 is resistance (B1B1) and Parent 2 susceptible (b1b1).
Questions:
(1) If we make a cross between the two parents, F1 is resistant or susceptible?
Answer:
(2) If the F1 self-pollinated, what is the expected ratio between resistant to susceptible plants in
the F2 population?
Resistant: susceptible =
(3) If F1 is backcrossed to Parent 1, what is the expected ratio between resistant to susceptible
plants in BC1F1(P1) population?
Resistant: susceptible =
(4) If F1 is backcrossed to Parent 2, what is the expected ratio between resistant to susceptible
plants in BC1F1(P2) population?
Resistant: susceptible =
3
5. Below is a phylogenetic tree among 26 spinach genotypes:
Hellcat
Unipack 277
Hector
Lion
Crocodile
Spinner
Cheetah
Polar Bear
T-Bird
Indian Summer
Megaton
Alrite
Tyee
Melody
Samish
Unipack 151
Lazio
Tarpy
Whale
Unipack 12
Eagle
Bolero
Denali
Cherokee
Vancouver
Regal
Questions:
(1) What tools (software) can create above genetic diversity tree? Answer:
(2) See the bottom spinach line Regal, which spinach line is the closest one according the genetic
diversity? Answer:
(3) From the top two lines, which one, Hellcat or Unipack 277 is closer to Regal (bottom)? Answer:
4
6. Supposed:
One SNP [T/G] shows 101 plants with [TT], 200 plants with [GT] and 99 plants with [GG] in an F2
population derived from P1 [TT] x P2 [GG], the goodness-of-fit and independence using a chi-square test
is shown below Table.
Please fill the blank in the table and explain whether the SNP actions like a gene!
F2
Total
[TT]
Total
[GT]
Total
[GG]
Total
Obs
101
200
99
400
Exp value
exp ratio
Chi Square
P Value
There are 400 pea F2 plants consisted of 301 plants with purple flower and 99 white flower as below
table.
Please fill the blanks in the table! Based on the data, how many gene(s) control the flower color?
F2
Purple
flower
White
flower
Total
Obs
301
99
400
Exp value
exp ratio
Chi
Square
P Value
5
7. Suppose: A SNP marker M1 [A/C] is linked to the pea color gene ‘T1’ with the recombination
rate r. In the BC1F1(P2) population, the genotypes and phenotypes and their count are below.
To test flower color, please fill below Table
Purple
White
Total
200
AC
CC
Total
200
Obs
Exp
Chi-sqaure
P value
To test SNP marker
Obs
Exp
Chi-sqaure
P value
To calculate recombination rate (r ), please fill below table:
female
BC1F1(P2)
male
Ct1
100%
AT1
(1-r)/2
Ct1
(1-r)/2
At1
r/2
CT1
r/2
ACT1t1
CCt1t1
ACt1t1
CCT1t1
purple
flower
white
flower
white
flower
purple
flower
genotype
frequency
Phenotype
Obs.
r
recombination rate ( r) =
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