Mini-Lab 1-01: Foiled Again Purpose: In this activity, you will discover that a few simple measurements can lead you to information about individual atoms! Think about this: Avogadro’s number: 6.022 x 1023 Density = mass/volume Aluminum weighs 26.98 g/mol The standard deviation of a group of 3 or more measurements of the same quantity will give you an estimate of the uncertainty in the average. Hint: cut a square of aluminum foil Safety 1) 2) 3) 4) Don’t eat or drink anything in the lab. Always wear eye protection. Wear protective clothing (lab coats, etc.). Don’t play around – treat the lab with respect. Questions 1) What’s the density of Aluminum? 2) How thick is a sheet of aluminum foil… a. …in centimeters? b. …in inches? 3) Estimate the volume of a single atom of aluminum. 4) How thick is a sheet of aluminum foil in numbers of atoms? 5) What assumptions do you have to make in order to come up with an answer to the above questions? 6) OPTIONAL QUESTION: How well do you really know these numbers? Pick one of your answers for questions 1), 2), 3) or 4) and calculate the uncertainty in it based on your measurements. WAIT! Do not write down an answer to the Final question until your Instructor tells you to. 7) FINAL: What’s the distance between the centers of two neighboring aluminum atoms? Instructor’s Page 1-01: Foiled Again Source: SCALE-UP Concepts: measurement, dimensional analysis, atomic-level dimensions Materials: Aluminum slugs, graduated cylinders, rulers, balances, foil, scissors (have them cut a small square of foil with the scissors) Hints: Once they determine the density of aluminum and the mass of the piece of foil, they can calculate numbers of moles. After calculating the volume (with density and mass), they can get the thickness and also calculate atoms/cm3, by assuming that the atoms are packed in some fashion. The easiest assumption is that they are cubes packed side-by-side in three dimensions. According to Webelements (http://www.webelements.com/webelements/elements/text/Al/radii.html) the internuclear distance in Aluminum is 2.86 Angstroms. Another necessary assumption is that the foil is of equal thickness, but that’s probably a pretty good assumption to make. This could be confirmed by use of a micrometer, if desired. Calculating the uncertainty in their answer should be kept at a level appropriate for the student. At the simplest level, the uncertainty in the density will be approximately equal to the uncertainty in their volume measurement (as a percentage), since most lab balances will give much less uncertainty than a graduated cylinder. Discussion Ideas: Packing of atoms, actual size of an aluminum atom – how well did they do in their estimation? What changes in their procedure, reasoning or assumptions could have led them to a better estimate? What evidence is there that there really are “atoms” in the first place (i.e. – Rutherford’s gold foil experiment)? For More Information: