Name: Date: ______________ Algebra 2 Quadratic Functions: Putting it all Together page 1 Quadratic Functions: Putting it all Together We’ve learned about three forms for quadratic functions, and we’ve covered all of the skills needed to convert between the forms (distributing, factoring, and completing the square). You can find enough information about a quadratic function (vertex, zeros, y-intercept) to be able to sketch the graph without a calculator. Three forms for quadratic functions Here are three general forms that can be used for writing formulas for quadratic functions. Each has its advantages. form standard factored vertex function formula f(x) = ax2 + bx + c f(x) = (px + q)(rx + s) main advantage ready for using the Quadratic Formula Find zeros by solving the equations px + q = 0 and rx + s = 0. OR OR f (x) a(x x1)(x x2 ) x1 and x2 are the zeros f(x) = a(x – h)2 + k The vertex is (h, k). Converting between the forms You’ve already learned all of the skills needed to change a quadratic function from any of the forms to another form. Specifically here’s what’s needed in each case: conversion standard to factored standard to vertex factored to standard vertex to standard how to do it factoring, and maybe some extra steps completing the square distributing (mult. table or “FOIL”) and simplifying (combine like terms) distributing (mult. table or “FOIL”) and simplifying (combine like terms) To get back and forth between factored and vertex forms, use standard form as an in-between step. Example: Convert f(x) = 3(x – 6)(x – 2) into vertex form. Steps to get from factored to standard form First multiply (x – 6)(x – 2): f(x) = 3(x2 – 8x + 12) Distribute the 3: f(x) = 3x2 – 24x + 36 Steps to get from standard to vertex form Factor out 3 from first two terms: Calculate: –8/2 = –4, (–4)2 = 16 Complete the square: Write perfect square and simplify: f(x) = 3(x2 – 8x ) + 36 f(x) = 3(x2 – 8x + 16) + 36 – 48 f(x) = 3 (x – 4)2 – 12 Name: Date: ______________ Algebra 2 Quadratic Functions: Putting it all Together page 2 Problems: Converting 1. Change each function into the form specified. If you’re not sure what to do, see the chart on page 1. a. f(x) = x2 – 4x – 96 into factored form. b. f(x) = 4x2 – 4x – 3 into factored form. c. f(x) = 3(x – 4)(x + 2) into standard form. Hint: First do (x – 4)(x + 2) then use the 3. d. f(x) = –2 (x + 5)2 + 6 into standard form. Hint: First do (x + 5)2, then use the –2, then the 6. Name: Date: ______________ Algebra 2 Quadratic Functions: Putting it all Together page 3 e. f(x) = 2x2 + 16x + 28 into vertex form. f. f(x) = (x + 3)(x – 5) into vertex form. Hint: First distribute, then completing-the-square. g. f(x) = (x – 1)2 – 1 into factored form. Hint: Distribute, then simplify, then factor. h. f(x) = 3(x – 4)(x + 2) into vertex form. Name: Date: ______________ i. f(x) = 2(x – 3)2 – 8 into factored form. j. f(x) = –(x – 5)2 – 3 into standard form. k. f(x) = –2x2 – 12x – 18 into factored form. l. f(x) = –2x2 – 12x – 18 into vertex form. Algebra 2 Quadratic Functions: Putting it all Together page 4 Name: Date: ______________ Algebra 2 Quadratic Functions: Putting it all Together page 5 Making Graphs by Hand If you’re asked to graph of a quadratic function by hand, here’s a set of steps that will produce a reasonably accurate graph: Use the a value (from any of the three forms) to get the shape: if a > 0, if a < 0. Find the zeros using the easiest method (factoring, square roots, completing the square, quadratic formula). Provided that there are two zeros, this will give you two points to draw. Find the vertex (using vertex form or –b/2a or averaging the zeros). This usually gives a third point to draw. Find the y-intercept (evaluate f(0), or just take the c value from ax2 + bx + c form). This usually gives a fourth point to draw. Draw a dotted line for the axis of symmetry (vertical line through the vertex). Then you can often get a fifth point by drawing the reflected image of the y-intercept point. Make sure that all the points you’ve found fit with the shape that you anticipated ( or ). If everything looks OK, draw a parabola shape passing through the points you have. Example: Make a graph of f(x) = x2 + 6x + 8. The a value is 1, so expect the shape. Factoring gives the zeros: f(x) = (x + 2)(x + 4) so there are points (–2, 0) and (–4, 0). Completing-the-square leads to vertex form: f(x) = (x + 3)2 – 1 so the vertex is (–3, –1). f(0) = 8 so the y-intercept is at (0, 8). The axis of symmetry x = –3 shows that there’s a reflected image point at (–6, 8). Draw a graph using the five known points: Name: Date: ______________ Algebra 2 Quadratic Functions: Putting it all Together page 6 2. Do all of the following for the function f(x) = 2x2 – 8x + 6, without using a calculator. a. Using factoring, find the zeros. b. Using completing-the-square, find the vertex. c. Find the y-intercept. d. Draw the 4 points found so far, use the axis of symmetry to find a 5th point, then sketch the graph of f(x). Name: Date: ______________ Algebra 2 Quadratic Functions: Putting it all Together page 7 3. Using the same sequence of steps as in problem 2, find five points then draw the graph for f(x) = –x2 + 6x – 8, without using a calculator. Name: Date: ______________ 4. Do all of the following for the function f(x) = Algebra 2 Quadratic Functions: Putting it all Together page 8 1 2 x2 + 2x – 4, without using a calculator. a. Using the Quadratic Formula, find the zeros. b. Using a formula for the x-coordinate of the vertex, find the vertex. c. Find the y-intercept. d. Draw the 4 points found so far (some of them will involve non-whole numbers but put them in approximately the correct place). Use the axis of symmetry to find a 5th point, then sketch the graph of f(x).