32) Calculating mass of point-formed particles
Point-formed particles are particles with only one mass body, as to give some
examples we can mention the myon (μ) particle and the proton particle. According to
our theory, Matter Unified, such particles are created by a quantum resonance
process in vacuum space. The created particle oscillates in two modes, and these
oscillating modes interact with each other by a relation n, where n is a quantum
integer number.
The equation for calculating the created mass consists of two parts: the left part
and the right part. The left part is created by a process where the particle mass
oscillates in its own electrical field and the other part is created by an oscillating
mode in the mass in the radius direction of the particle. First we make a study of the
left part of the equation. We concentrate the mass of the particle in two points
situated in the end of a rigid axis connecting the two points. We assume this axis is in
a neutral position in regard to an outer electric field. In such a position the axis is not
activated by any torsional force. But if this axis is twisted in relation to its neutral
position, there will be a torsional momentum force round this axis. This force, or
momentum, will be approximately in proportion to the size of angular deviation. We
can apply the pendulum equation on this construction giving the pendulum time:
1)
T=2π.sqrt(M.R/F)
where:
M is equal to the particle total mass
R is equal to the particle’s radius
F is equal to the maximum force on the mass created by the electric field itself.
From our theory, Matter Unified, we know that:
2)
R=re.(M/me)1/3
where re is the electron mass radius
and Me is the electron mass
Now we will calculate the maximum force created by the electric field from the
particle itself. We start with our mass flowing formula:
3)
m=q.A.t.C
We multiply both sides of this equation with the quantity of C, giving:
4)
m.C=q.A.t.C2
But from Newton’s fundamental laws we know that:
5)
m.C=F.t
Then we can reduce the quantity of time, t, giving:
6)
F=q.A.C2
The product of A and C is the same as the unit charge of a point-formed particle,
equal for both electrons, protons and other point-formed particles. We know that:
7)
A.C = 4 .re2.Kt.c
where
Kt =5.355 and C= Kt.c
where c is equal to the light velocity.
We also know that the q value is:
8)
q=me/(Ka.Kt2.re3)
Inserting all these parametres into the force formula we have:
9)
F=me.c2/re
Now we insert the force value in the time oscillating formula, giving:
10)
T=2π.(M/me)2/3
For deriving the oscillating time of mass in the radius’ direction, you have to study this
derivation by reading the theory Matter Unified. This oscillating time is derived to:
11)
2 .2 .(M/me)1/3
Now we introduce a quantum number, n, being a stepping function of a half integer.
We assume that n numbers of oscillating periods will occur in the radius direction
during one oscillating period in the electric field, giving:
12)
2 (M/me)2/3=2 .2
(M/me)1/3.n
We reduce this formula and solve out the mass value, M, from this formula, giving:
13) M=me.(2 .n)3
We replace the half integer value of n by a real integer value, 1, 2, 3, 4, 5 and so on,
and rewrite the equation to:
14) M=me.(n. )3
In every theoretical derived calculation we know that the given value not always
exactly corresponds with the measurements values. Of that reason we introduce a
correction factor, k, in the formula, with its normal value, k =1, giving:
15) M=me.(k.n. )3
being the end formula for calculating mass of different point-formed particles
In Matter Unified we have before done a study of masses created by this formula
and compared the given mass values with known values from practical
measurements. And it seems to correspond very good. You can make a study of
these values in a table, but there are also good information to get from internet,
where registrations of different “jets” are registered from experimental platforms over
the world. By studying the number of hits you get when searching a particle with
given or assumed mass you can find a peak where the assumed particle seems to be
positioned. Performing such an investigation or searching on the internet may give
the following results:
n=22
calculated value: 168.7 Gev
hits on internet, interval 168.0>169.7 Gev:
0,1,3,2,14,4,2,3,1,0,0,4,21,16,0,1,5,2
peak value at: 160.2 Gev
Correction factor= -
n=21
calculated value: 148.6 Gev
hits on internet, interval 148.0>149.3 Gev:
1,1,0,0,0,3,0,0,0,0,1,3.0,0
peak value at: 148.5 Gev
Correction factor= -
n=20
calculated value: 126.7 Gev
hits on internet, interval 126.0>127.3 Gev:
3,1,0,1,1,5,2,0,3,0,4,75,3,1
peak value at: 127.1 Gev
Correction factor= -
n=19
calculated value: 108.7 Gev
hits on internet, interval 108.0>109.2 Gev:
23,1240,36,6,4,3,9,4,2,2,11,13,6
peak value at: 108.1 Gev
Correction factor= -
n=18
calculated mass: 92,4 Gev
correction factor: k=1
registered value: 92,4 Gev
particle name: Zeta
Nobel Prize awarded 1984, Carlo Rubbia
n=17
calculated value: 34,8 Gev
hits on internet, interval 77.0 78.0 Gev
7,16,0,2,15,172,2,3,2,4,15
peak value at: 77.5 Gev
Correction factor k= -
n=16
calculated value: 64.9 Gev
hits on internet, interval 64.0 >64.9 Gev:
4,2,7,3,4,6,2,5,7,11
peak value at: 64.9 Gev
Correction factor k= -
n=15
calculated value: 53.5 Gev
hits on internet, interval 53.0>54.3 Gev:
3,2,4,6,6,13,1,4,3,5,9,1,1,2
peak value at: 53.5 Gev
Correction factor= -
n=14
calculated mass: 43.5 Gev
correction factor: k=1
registered value: 43.5 Gev
particle name: No name, registered
n=13
calculated value: 34,8 Gev
hits on internet, interval 34,4>35,2 Gev:
69, 105, 188, 25, 18, 3, 15, 0, 1
peak value at: 34,6 Gev
Correction factor= -
n=12
calculated value: 27,4 Gev
hits on internet, interval 27,0>27,9 Gev:
12, 3, 3, 12, 265, 15100, 2640, 24, 4, 10
peak value at: 27,5 Gev
Correction factor= -
n=11
calculated : 21,1 Gev
hits on internet, interval 20,6>21,8 Gev
10, 5, 10, 4, 11, 7, 6, 8, 48, 47, 39, 64, 18,
peak value at: 21,7 Gev
Correction factor= -
n=10
calculated : 15.8 Gev
hits on internet, interval 14.9>16.2 Gev
31,153,13,16,37,31,57,17,27,17,12,52,10,21
peak value at: 15.0 Gev
Correction factor= -
n=9 redigera
calculated value: 11,5 Gev
hits on internet, interval 11,0>12.3 Gev
100,40,291,76,88,583,354,117,87,38,157,29,37,240
peak value at: 11.5 Gev
Correction factor= -
n=8
calculated value: 8,1 Gev
hits on internet, interval 7,6>8,6 Gev:
114, 118, 192, 64, 1700, 465, 119, 122, 93, 1070, 71
peak value at: 8,0 Gev
Correction factor=1
n=7
Calculated value=10635 electron masses
Calculated value=5.433 Gev
Registered value=5.26 Gev
Particle name: B-mison
Correction factor k=0.98714
n=6
Calculated value=6697 electron masses
Calculated value=3.421 Gev
Registered value=6697 electron masses
Registered value=2.976Gev
Partikle name: eta J/Psi
Correction factor k=0.95487
n=5
Calculated value=3875 electron masses
Calculated value=1.980 Gev
Registered value=1784.1Mev
Particle name: taon
Correction factor k=0.9658
n=4
Calculated value=1984 electron masses
Calculated value=1.013 Mev
Registered value=1836,12 electron masses
Registered value=938.2723 Mev
Particle name: Proton
Correction factor k=0.97
n=3
Calculated value=837 electron masses
Calculated value=4.27
Registered value=966 electron masses
Registered value=493.646 Mev
Particle name: Kaon
Correction factor k= Observe: This calculated mass value is a base of the kaon mass spectrum.
n=2
Calculated value=248 electron masses
Calculated value=1.26 Mev
Registered value=206.8 electron masses
Registered value=105.658 Mev
Particle name: Myon
Correction factor k=0.941
n=1
Calculated value=32 electron masses
Calculated value=15.8 Mev
Registered value=- electron masses
Particle name: WIMP
Correction factor k=By inserting the correction factor k as calculated here you get the exact value of the
searched particle. But we can observe that for low mass values we have an
interaction between the two oscillation modes. That may be the reason why the
correction factor k deviates from the ideal value of 1. We don’t exactly know how to
compute this exact k value for these particles, but a suggestion may be:
16) k=1-0.12/n
From my first publication “Absolute Space Theory” from 1981. The calculated formula
predict well later experimental found particle forms. Here given in multiples of the
electron’s mass 0.511 Mev and given in half integers values of the quantum number.
This table was published In my book “A new way to the physics” 1984
This table was published in Galilean Electrodynamics 1991.
n-values included is here limited to 8 but for n=9 (1/2 integers) the exact value of Z
particle (92.4 Gev), Nobel awarded discovery. The W particle is neutral 81Gev but
the spectral bas particle shall have the value of 77.8 Gev
COMMENTS OF RECEIVED RESULTS
Mass from
Value of
N
Unit
experiments or
k
predicted mass
Comment
1
16
Mev
predicted
(1)
2
105.65839
Mev
0.941
u, mu (6)
3
493.646
Mev
1.05172
k, kaon (6)
4
938.2723
Mev
0.9744
p, proton (6)
5
1784.1
Mev
0.96578
T, Tauon (6)
6
2.976
Ge v
0.95487
n, eta
7
5.26
Ge v
0.98714
B-(2)
8
8.3
Ge v
1.00765
z, zeta (3)
9
11.5
Ge v
-
JETS (5)
10
15.8
Ge v
-
JETS (5)
11
21
Gev
-
JETS (5)
12
27.4
Gev
-
JETS (5)
13
34.8
Gev
-
JETS (5)
Ove Tedenstig Sweden 2008
MATTER UNIFIED ISBN 91-973818-7-X
10-57
Xxx
14
43.4
Gev
0.9979
Reg. (4)
15
53.4
Gev
-
JETS (5)
16
64.8
Gev
-
JETS (5)
17
81.0
Gev
1.013342
W, (6)
18
92.4
Gev
0.999883
Z, (6)
19
20
21,
Xxx
1.
2.
3.
4.
5.
EE NEW SCIENTIST 11 TH FEBRUARY/P14,15 1995
B-MESON, SEE CERN DATA BOOKLET
ZETA, SEE NEW SCIENTIST 16 TH AUGUST 1984
43.4 GEV, SEE 25 TH OF MAY 1984
SEE STATISTICS FROM REPORTS PHYSICS REVIEW
LETTERS BELOW
Se CERN Particle Data Group booklet
From New Scientist 24 may 1984
Ove Tedenstig Sweden 2008
MATTER UNIFIED ISBN 91-973818-7-X
10-58
A-1040
xxx
Statistic from Swedish “KOSMOS” 1981 page 100
XA-10-25
Ove Tedenstig Sweden 2008
MATTER UNIFIED ISBN 91-973818-7-X
10-59
Xxx
Report of the “zeta 8.3 Gev” particle in a German Scientific journal. OBS! cited
text limited