Worksheet on The Standard Normal Distribution (Also known as the z-distribution) The standard normal distribution is the normal distribution whose mean is 0 and the standard deviation is 1. The total area under the curve is 1, representing the fact that the sum of all probabilities is 1. The probability that a randomly selected number x is between two values (say a and b) is given by the area under the curve between a and b. With this worksheet, we will learn how to find the probability that a selected number x is between two values (i.e., finding p(a<x<b)) using a table. A. Identifying the Parts of the Curve: The Body and The Tail B = body region = 0 < z < 1.3 An interval from 0 to z is called a body region. if z is positive T = tail region = z > 1.3 region = [-z,0] if z is negative The part that is leftover on the end is called a tail region. One body region and its tail represent half of the area under the normal curve: Body + Tail = z > 0 = 50% PROBLEMS 1. Sketch the region given by the interval 0 < z <1. Is it a body region or a tail region? (0 < z < 1) = 2. Sketch the region given by the interval z > 2. Is it a body region or a tail region? (z > 2) = B. Identifying the Probability that x is in a Body Region The probability that x is in a Body region 0< z < z* is given by z* = p(0<z<z*) that can be read from the body table for the standard normal distribution. This is located in Appendix F of your book. PROBLEMS 1. What percent of the standard normal z-distribution lies between z=0.00 and z=1.10? Body Region = 0.00 < z < 1.10 p(0.00 < z < 1.10) = 2. What percent of the standard normal z-distribution lies between z=0 and z=1.12? Body Region = p(0.00 < z < 1.12) = 3. What percent of the standard normal z-distribution lies between z=0 and z=1.15? Body Region = p(0.00 < z < 1.15) = 4. What percent of the standard normal z-distribution lies between z=0 and z=1.21? Body Region = p(0.00 < z < 1.21) = 5. What percent of the standard normal z-distribution lies between z=0 and z=2.00? Body Region = p(0.00 < z < 2.00) = C. Identifying the Probability that x is in a Tail Region The probability that x is in a tail region z > z* is (.5 - z*) where z* is the probability of the body region p(0<z<z*). The probability of the body region is given in the body table for the standard normal distribution. PROBLEMS 1. What percent of the standard normal z-distribution lies in the body region between z=0.00 and z=1.00? Body Region = p(0.00 < z < 1.00) = 2. What percent of the standard normal z-distribution lies in the tail region z > 1.00? Tail Region = p(z > 1.00) = 3. What percent of the standard normal z-distribution lies in the tail region between z=1.18 and z=? Tail Region = p(z > 1.18) = Body region = D. Identifying the Probability that x is in a Composite Region The probability that x is in an interval [a,b] will be a sum of the body and tail regions contained in the interval [a,b]. Step 1: Shade in the interval on a sketch of the normal distribution curve. Step 2: Identify the body and tail regions contained in the interval. Step 3: Add the probabilities for each body and tail region contained in the interval, keeping in mind two facts: a) a region to the left of the mean will have the same probability as the region of the same width on the right hand side due to symmetry. b) A body and tail region together on one side have a probability of .5. PROBLEMS 1. What percent of the standard normal z-distribution lies in the composite region between z=-1 and z=1? p(-1<z<1) = 2. What percent of the standard normal z-distribution lies in the composite region defined by z < 2? p(z<2) =