C4 – Algebra and Functions Summary Remainder Theorem: When the polynomial f(x) is divided by (ax b) b . a C4 – Algebra and Functions Summary Remainder Theorem: When the polynomial f(x) is divided by (ax b) b . a the remainder = f the remainder = f b = 0. a b = 0. a Factor Theorem: If (ax – b) is a factor of f(x) then f Factor Theorem: If (ax – b) is a factor of f(x) then f The degree of a polynomial is the highest power of x it contains. In improper algebraic fraction the degree of the numerator is greater than or equal to the degree of the denominator. To simplify an improper algebraic fraction use division. If the numerator has degree n and the denominator has degree m (n > m) then the quotient has degree n – m and the remainder is a proper fraction. A rational function is an algebraic fraction. The degree of a polynomial is the highest power of x it contains. In improper algebraic fraction the degree of the numerator is greater than or equal to the degree of the denominator. To simplify an improper algebraic fraction use division. If the numerator has degree n and the denominator has degree m (n > m) then the quotient has degree n – m and the remainder is a proper fraction. A rational function is an algebraic fraction. Partial Fractions Means writing an algebraic fraction as a sum of several fractions. If a fraction in improper always simplify first and express the remainder as partial fractions. Partial Fractions Means writing an algebraic fraction as a sum of several fractions. If a fraction in improper always simplify first and express the remainder as partial fractions. Denominator has linear factors: Denominator has linear factors: px q A B . (ax b)(cx d ) ax b cx d px q A B . (ax b)(cx d ) ax b cx d To solve, multiply everything by (ax + b)(cx + d). Denominator has repeated factor: To solve, multiply everything by (ax + b)(cx + d). Denominator has repeated factor: To solve, multiply everything by (ax + b)(cx + d)2. You may need to factorise the denominator first before proceeding. To find the numerators of the partial fractions after you multiplied up i) expand brackets and simplify. The coefficients of each power of x must be the same on both sides of the equation. OR ii) substitute values in for x to create simultaneous equations. Choosing x such that the value of a bracket becomes zero makes things considerably simpler. To solve, multiply everything by (ax + b)(cx + d)2. You may need to factorise the denominator first before proceeding. To find the numerators of the partial fractions after you multiplied up i) expand brackets and simplify. The coefficients of each power of x must be the same on both sides of the equation. OR ii) substitute values in for x to create simultaneous equations. Choosing x such that the value of a bracket becomes zero makes things considerably simpler. px q A B C 2 ax b cx d (cx d ) 2 (ax b)(cx d ) px q A B C 2 ax b cx d (cx d ) 2 (ax b)(cx d )