Direct and Inverse Estimations for A Generalization of Positive Linear Operators ABDULLAH ALTIN and OGÜN DOĞRU Department of Mathematics Ankara University, Faculty of Science 06100 Tandoğan, Ankara TURKEY Abstract: - In this study, we give quantitative estimations and inverse theorems for a generalization of positive linear operators, which includes some well-known polynomials and operators. Key-Words: - Positive linear operators, the Bohman-Korovkin theorem, the Gadjiev-Ibragimov operators, first and second order modulus of continuities and Lipschitz classes. 1 Introduction Let n N and a be positive real numbers, be the sequence of functions in C[0, a] such that n (0) 0, n (t ) 0, for each t [0, a]. Let also n be a sequence of positive 1 numbers such that lim n 1, lim 0. 2 n n n n (0) n n (t ) and n (t ) Assume that a sequence of functions of three variables K n ( x, t , u ) ( x, t [0, a], u ) satisfies the following conditions : 10 . Each function of this family is an entire analytic function with respect to u for fixed x, t [0, a] , 2 0 . K n ( x,0,0) 1 for any x [0, a] and for all n N , 30. (1) K n ( x, t , u ) u u1 0 , t 0 u 4 0. 1 K ( x , t , u ) K ( x , t , u ) u u1 nx n m n 1 t 0 u u where m n N 0 , u u1 t 0 5 0. K n ( x, t , u ) u n n ( t ) t 0 x . nn n (0) K m n ( x, t , u ) u n n (t ) t 0 Consider the sequence of positive linear operators; ( Ln f )( x) f ( 2 ) K n ( x, t , u ) n n (0) u 0 u n n (t ) (1) t 0 [ n n (0)] ! where f C ([0, a], x 2 ) and C ([0, a ], x 2 ) be the space of functions defined on the entire line, continuous in the interval [a, b] and increasing to infinity not more rapidly than x 2 . By multiple application of property 4 0 , operator (1) can be reduced to the form n(n m)(n ( 1)m) ( Ln f )( x) f ( 2 ) ! n n (0) 0 [ n n (0)] K n m ( x,0, n n (0)) x . These operators are a generalization of some well-known operators and they are called as Gadjiev-Ibragimov operators [12]. Some approximation properties of these operators and their some generalizations are investigated by Radatz and Wood [17]. (see also [10]). n ux Remarks. By choosing K n ( x, t , u ) 1 , 1 t 1 n n, n (0) , we have h(n) n 1 and the n operators defined by (1) are transformed into classical Bernstein polynomials. For n n, n (0) b lim n 0), we n n polynomials. obtain 1 nbn ( lim bn , n Bernstein-Chlodovsky By choosing K n ( x, t , u ) e n(t ux) , n n, n (0) If 1 , we get Szasz-Mirakjan operators. n K n ( x, t , u ) (1 t ux ) n , n n, 1 then we obtain Baskakov operators (see n for details [1]). Therefore these operators include a large spectrum of some well-known positive linear operators. In [12], Gadjiev and Ibragimov proved the following theorem: Theorem A. The sequence of linear positive n (0) operators defined by (1) with conditions 1 5 converges uniformly to the function 0 0 f C ([0, a], x ) in [0, a]. In the proof of Theorem A, for using the wellknown Bohman-Korovkin theorem [6,14] (see also [2] ), the authors obtained x ( Ln1)( x) 1, ( Lnt )( x) n and n (2) x x m n 1 ( Lnt 2 )( x) n ( n 2 ). n n n n n (0) 2 In this study, we will give the sufficient conditions to obtain inverse estimates for the general operators defined in (1). Therefore, main purpose of this note is to obtain some direct and inverse results for the operators (1). We denote n,k ( x) : ( Ln (t x)k )( x), the k-th order central moment of the operator (1) for abbreviation. From the equalities in (2), we have mn 1 n, 2 ( x) ( ( n ) 2 2 n 1) x 2 n 2 x n n n n n n (0) (3) for the operators (1). Now, Using the some standard methods, we will give the proof of the direct estimates: Lemma 2.1. If f C[0, a] then we have ( Ln f (.) f ( x) )( x) 2( f ; n,2 ( x) ) . (4) Proof. By using the well-known technique of Popovichu [16], we have 1 ( Ln f (.) f ( x) )( x) ( f ; )1 n,2 ( x) . By choosing n,2 ( x) , we obtain the quantitative estimate in (4). Since n,2 ( x) 0 for n , the estimate in (4) gives the rate of approximation for the operators in (1). Now, we compute this rate of convergence by means of the second order modulus of continuity. To obtain this result we will benefit the following Theorem given by Gonska in [13]: Theorem B. If L : C ( K ) B( K ) is a positive linear operator then for f C ( K ), x K and each 0 the following holds 3 ( Lf )( x) f ( x) ( L 1) n,2 ( x) max 2 , I ( K ) 2 2 2 ( f ; ) 2 n,1 ( x) max 1, I ( K ) 1 ( f ; ) n,0 ( x) 1 f ( f ; ) (5) 2 Direct Results where n, k ( x) denote the k-th order central Let us recall that the first and second order modulus of continuities and Lipschitz classes: moment of operator L and B(K) denote the Banach space of bounded and real-valued functions on K, and I(K) denotes the length of the interval K. Lemma 2.2. For the operators in (1), if ( f ; ) sup f (t ) f ( x) ; t , x [0, a], t x , f ( x h) 2 f ( x) f ( x h) ; 2 ( f ; ) sup ( x h) [0, a], h , LipM () f : f (t ) f ( x) M t x , 0 1 , f : f ( x h) 2 f ( x ) f ( x h) M h , * LipM () . a x [ h , a h ], 0 h 2 f C[0, a] and n, 2 ( x ) 2 a large n then we have ( Ln f )( x) f ( x) 42 ( f ; n ) where n n, 2 ( x) 2 . for sufficiently (6) Proof. Since n large n, we get n, 2 ( x) a for sufficiently 2 max n 2 , a 2 n 2 . (7) If we use n,1( x) 0 , n,0 ( x) 1 0 and (7) in (5), the proof is completed. Lemma 2.3. If f LipM () then the sequence of ( Ln ) satisfies ( Ln f )( x) f ( x) M ( n, 2 ( x)) 2, (0 1, 0 x a). (8) Proof. Because of monotonicity of positive linear operator ( Ln ) , if f LipM () then we have ( Ln f )( x) f ( x) ( Ln f (.) f ( x) )( x) ( Ln M 2 . x )( x). By Hölder’s inequality for 2 2 1 1 p , q , ( p, q 1, 1), 2 p q we obtain (8). Lemma 2.4. If n and f n, 2 ( x ) 2 the sequence of ( Ln ) satisfies ( Ln f )( x) f ( x) 4M1 ( n, 2 ( x)) 2, (0 1, 0 x a). (9) Proof. If f Lip*M1 () then we have 2 ( f , n ) M1n / 2. n, 2 ( x) 2 proof is completed. decreasing in [0,a] according to x, (ii) n, 2 ( x) is decreasing in n and there is a positive number c satisfying the n 1,2 ( x) c n,2 ( x) for n0 n , K n m ( x,0, n n (0)) x . 3 Inverse Results The equivalence relation x(1 x) ( Bn f )( x) f ( x) K n Note that all the conditions above are satisfied for Bernstein and Bernstein-Chlodovsky polynomials, Szasz-Mirakjan operators and Baskakov operators. In this section, we will use the notation n(n m)(n ( 1)m) Pn, ( n , n (0), m, x) ! [ n n (0)] K n m ( x,0, n n (0)) x (10) and using Lemma 2.2, the 2 2 ( f ; ) O( ) was proved by Lorentz [15] and Berens and Lorentz [5] for some . Later, different proofs have been given by De Vore [7], Becker [4], Totik [18], Ditzian and Ivanov [9], Felten [11] for Bernstein polynomials. Also Ditzian [8] and Becker [3] obtained inverse estimation for Szasz-Mirakjan and Baskakov operators. inequality (iii) d 1 ( K n m ( x,0, n n (0)) x ) ( 2 x) dx n,2 ( x) n n (0) a for sufficiently large Lip*M1 () then Choosing n These results are starting point of investigations of the relation between the order of approximation of some positive linear operators and the smoothness of the functions approximated. In this section, we will give some direct and inverse theorems on the approximation of the operators in (1). The theorem, giving us the necessary conditions for a function to be in the saturation class is called as inverse theorems. Note that, in general, inverse theorems are difficult to prove. We assume the following conditions for the operators in (1): (i) n, 2 ( x) is concave or increasing or for abbreviation. Now, we can give the inverse results in the light of the conditions (i - iii). Lemma 3.1. If the operators (1) satisfies the inequality (8) then f Lip *M () . Proof. In this proof we will use the similar technique of Berens-Lorentz theorem in [5]. From (2) and (iii), we have d 1 ( Ln f )( x) ) f ( x)) (f( 2 dx n, 2 ( x) 0 n n (0) ( n 2 n (0) (11) x) Pn, ( n , n (0), m, x) . By the basic properties of modulus of continuity and Cauchy-Schwartz inequality, we have 1 ( Ln f ) / ( x) ( f ; ) x 2 ( x ) n, 2 0 n n (0) 1 1 x 2 n n (0) Pn, ( n , n (0), m, x) (12) 1 1 ( f ; ) . n, 2 ( x) n, 2 ( x) x x / / ( Ln f ) (t ) dt ( Ln f ) (t ) dt 1 1 1 y x ( f ; ) max , ( x ) ( y ) n , 2 n , 2 for x y . By using the last inequality in the formula f ( y ) f ( x) f ( y ) ( Ln f )( y ) f ( x) ( Ln f )( x) y Proof. Because of Lemma 3.1, if we have (9) then we get f Lip * () . 4 M1 Thus we can write Choosing M 2 8M1* , the proof is obvious. Theorem 3.3. For the operators (1) satisfying the conditions (i)-(iii), we have ( Ln f )( x) f ( x) C1 ( n, 2 ( x)) ( Ln f ) (t ) dt , x 2, (0 1, 0 x a) iff f LipC2 (). Theorem 3.4. For the operators (1) satisfying the conditions (i-iii) and / n, 2 ( x) 2 a for sufficiently large n, we have from (4), we get f ( y ) f ( x) 2M1 ( n, 2 ( x)) 2 y x ( f ; ) 1 1 1 max , . ( x ) ( y ) n , 2 n , 2 Because of (ii), we can choose n,2 (t ) n 1,2 (t ) c n,2 (t ) for all t [0, a] , then we have c 1 f ( y) f ( x) 2M1 y x ( f ; ) . If we take supremum over y x h , we get h ( f ; h) M ( f ; ) where M max 2M1, c 1 . Assume that inequality (9) then f Lip*M 2 () . By Lemma 2.3, Lemma 2.4, Lemma 3.1 and Lemma 3.2, we can give the following theorems including equivalence relations: we can write y If the operators (1) satisfies the f ( x ) 2 f ( x) f ( x ) 8M1* . Thus by (i) and (12), and concavity of y Lemma 3.2. A 1 such that 2M A1 . Choosing h hn A n and hn 1 , since hn hn 1 , with the similar calculation to the Berens-Lorentz Theorem in [5], we have ( f ; h) M *h where M * 2M A2 . Taking h y x in the last inequality, the proof is completed. 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