Final—Form A Summer 2002 Economics 173 Instructor: Petry Name_____________ SSN______________ Before beginning the exam, please verify that you have 11 pages with 35 questions in your exam booklet. You should also have a decision-tree and formula sheet provided by your TAs. Please include your full name, social security number and Net-ID on your bubble sheets. Good luck! Use the following data points to answer questions 1-2. 5, 6, 12, 7, 8, 2, 9. 1. The median for this data is: a. 8 b. 6.5 c. The same as the mean d. The same as the mode e. Larger than the mode ANSWER: C 2. The standard deviation for this data set is: a. half the variance b. 10 c. 3.16 d. a measure of the dispersion of the data around its mean e. both c & d ANSWER: E The “rule of thumb”, or “empirical rule, indicates that: a. Approximately 98% of the observations should lie within 2 means of the standard deviation b. Approximately 65% of the observations lie within 1 standard deviation of the mean c. Exactly 65% of the observations lie within 2 standard deviations of the mean d. Exactly 98% of the observations lie within 2 standard deviations of the mean e. None of the above ANSWER: E 3. 687272425 Page 1 of 11 Use the following information to answer questions 4-7. The following table is meant to list expected returns and standard deviations for various portfolios of stocks and bonds. You also have the following information: the historical return for bonds has been 9%, with standard deviation of 12%. Returns for the S&P 500 index has been 18%, with a standard deviation of 26%. Assume the correlation coefficient between the two assets is zero. Recall that the portfolio variance formula is: 2(Rp) =w12 21 + w22 22 +2w1w212. Benefits of Diversification Investment Proportion Bonds Stocks 0% 100% 20% 80% 40% 60% 60% 40% 80% 20% 100% 0% Portfolio Expected Return Standard Deviation Table of Correlation Coefficients GM GM 1 CATERPILLAR 0.218434 BIOGEN 0.113032 ENRON 0.341501 INTEL 0.442635 CATERPILLAR BIOGEN ENRON 1 -0.175108261 0.189219646 0.081064863 INTEL 1 0.209297 1 0.342395 0.293953 1 4. Upon completing the table, the 80% bond, 20% stock portfolio will have an expected return of: a. 16.2% b. 10.8% c. 9% d. 18% ANSWER: B 5. That same portfolio (80%bond 20% stock) will have a standard deviation of: a. 1.2% b. 4.3% c. 10.9% d. 19% ANSWER: C 6. Therefore, from the perspective of risk-management, this (80%, 20%) portfolio is: a. Better than an all bond (0% stocks) portfolio. b. Worse than an all bond portfolio. c. Same as an all bond portfolio. 687272425 Page 2 of 11 d. The worst possible ANSWER: A 7. Again, from the diversification/risk-management angle, the most lucrative combination is: a. INTEL and ENRON b. CATERPILLAR and ENRON c. BIOGEN and INTEL d. BIOGEN and CATERPILLAR. ANSWER: D Use the following two tables to answer questions 8-11. FULL MODEL Regression Statistics Multiple R 0.470948536 R Square 0.221792524 Adjusted R Square 0.213128271 Standard Error 2547.059272 Observations 1000 ANOVA df Regression Residual Total Intercept TOTAL HI_ENJOY AF_AM NAT ASIAN HISP FEMALE COLLEGE WORK WORK2 UNDER25 687272425 11 988 999 SS MS F Significance F 1826781276 166071025.1 25.59857344 4.84864E-47 6409660803 6487510.934 8236442079 Coefficients Standard Error 43700.85579 345.0928105 106.4565472 21.20842047 517.173803 178.8663012 -370.4585954 781.8900104 -211.6441279 581.352107 -831.2279845 197.9288103 -605.4712339 411.3955267 -434.709669 175.7162291 168.5104031 172.5055797 -32.00957871 64.29083108 16.26601487 4.264223537 -843.6227371 199.9255261 t Stat 126.6350804 5.019541521 2.891398768 -0.47379886 -0.364054977 -4.199631086 -1.471749678 -2.473930104 0.976840305 -0.497887151 3.814531468 -4.219684967 P-value 0 6.14146E-07 0.003919354 0.635748026 0.71589485 2.91494E-05 0.141406929 0.013530693 0.328887333 0.618674383 0.000144908 2.67156E-05 Page 3 of 11 REDUCED MODEL Regression Statistics Multiple R 0.467601243 R Square 0.218650922 Adjusted R Square 0.21392978 Standard Error 2545.761722 Observations 1000 ANOVA df Regression Residual Total Intercept TOTAL HI_ENJOY ASIAN FEMALE WORK2 UNDER25 6 993 999 SS MS 1800905655 300150942.5 6435536424 6480902.743 8236442079 Coefficients Standard Error 43731.73558 255.1951529 102.5075909 20.89307792 502.9148062 177.1019572 -787.2056854 195.3972259 -456.2025095 173.6868534 14.07788712 1.35354551 -879.7881838 193.5617931 t Stat 171.3658551 4.906294384 2.839690843 -4.028745453 -2.626580542 10.40074901 -4.545257458 F Significance F 46.3131379 3.77367E-50 P-value 0 1.08413E-06 0.004607905 6.03551E-05 0.008757564 4.04404E-24 6.1623E-06 8. Based on the FULL model given above, and using a 5% significance level, what is your conclusion for the overall significance test of the model? a. Do not reject the null, concluding that none of the variables in the model are significant. b. Reject the null, concluding that none of the variables in the model are significant. c. Do not reject the null, concluding that at least one of the variables in the model is significant. d. Reject the null, concluding that at least one of the variables in the model is significant. e. Reject the null, concluding that all of the variables in the model are significant. ANSWER: D 9. The test statistic for testing the following set of hypotheses is based principally upon: H0: β3 = β4 = β6 = β8 = β9 = 0 H1: at least one βj ≠ 0 a. The relationship between SSRr and SSRf b. The relationship between SSTr and SSTf c. The relationship between SSEr and SSTf d. The relationship between the t-distribution and the F-distribution e. None of the above 687272425 Page 4 of 11 ANSWER: A 10. Assuming the p-value of the previous test is .00486, and using a 5% significance level what is your conclusion? a. Reject the null and use the FULL model for prediction b. Do not reject the null and use the FULL model for prediction c. Reject the null and use the REDUCED model for prediction d. Do not reject the null and use the REDUCED model for prediction e. Cannot tell from the information given. ANSWER: A 11. Given a person with the following characteristics, and using the REDUCED model, predict this person’s average SALES. An Hispanic female who is 31 years old, a college graduate, has 2 years of work experience, scored a 10 on the TOTAL scale, and enjoys working with customers. a. 44,411.97 b. 44,859.83 c. 44,379.44 d. 44,831.68 e. 43,980.04 ANSWER: B 12. Suppose that we calculate the four-period moving average of the following time series t yt 1 16 2 28 3 21 4 15 5 26 6 12 The centered moving average for period 3 (that would be in the same row as) is: a. 22.5 b. 21.25 c. 20.50 d. 18.5 ANSWER: B 13. If we want to measure the seasonal variations on stock market performance by quarter, we would need: a. 4 indicator variables b. 3 indicator variables c. 2 indicator variables d. 1 indicator variable ANSWER: B 687272425 Page 5 of 11 14. If summer 1998 sales were $12,600 and the summer seasonal index was 1.20, then the deseasonalized 1998 summer sales value would be: a. $12,600 b. $12,601.2 c. $15,120 d. $10,500 ANSWER: D Use the following table to answer questions 15-16. Actual Values yt 2325 2555 2835 3185 3510 Forecast Values Ft 2330 2595 2860 3125 3390 15. The mean absolute deviation (MAD) equals: a. 55 b. 48 c. 20 d. 50 e. 60 ANSWER: D 16. The sum of squares for forecast error (SSE) equals: a. 20,200 b. 20,250 c. 19,100 d. 21,500 e. 23,200 ANSWER: B 17. The following seasonal indexes and linear trend were computed from five years of quarterly sales data. Trend line: yˆ 500 30t Quarter 1 2 3 4 (t = 1, 2, 3, ……., 20) Seasonal Index 1.4 1.2 0.9 0.5 The forecast for the 3rd quarter of the 6th year equals: 687272425 Page 6 of 11 a. 1,322 b. 1,071 c. 1,392 d. 1,200 e. None of the above Answer: B 18. The following autoregressive model was developed yˆ t 200 15 yt 1 Assuming that the values for time periods 20 and 21 were 10 and 8 respectively, what would you forecast for time-period 22? a. 240 b. 8 c. –8 d. 335 e. 320 Answer: E 19. Forecasts based on trend and seasonality are generated by: a. identifying and removing the seasonal effect b. extrapolating the linear trend c. adjusting the forecasts to the seasonal effect d. all of the above ANSWER: D 20. The mean absolute deviation (MAD) and the sum of squares for forecast error (SSE) are the most commonly used measures of forecast accuracy. The model that forecasts the data best will usually have the: a. lowest MAD and highest SSE b. highest MAD and lowest SSE c. lowest MAD and SSE d. highest MAD and SSE ANSWER: C 21. In regression analysis, indicator variables allows us to use: a. quantitative variables b. qualitative variables c. only quantitative variables that interact d. only qualitative variables that interact ANSWER: B 687272425 Page 7 of 11 22. In a regression model involving 50 observations, the following estimated regression model was obtained: yˆ 10.5 3.2 x1 5.8x2 6.5 x3 For this model, SSR = 450 and SSE = 175. The value of MSR is: a. 12.50 b. 275 c. 150 d. 3.804 ANSWER: C 23. In testing the utility of a multiple regression model, a large value of the F-test statistic indicates that: a. most of the variation in the independent variables is explained by the variation in y b. most of the variation in y is explained by the regression equation c. most of the variation in y is unexplained d. the model provides a poor fit ANSWER: B 24. If multicollinearity exists among the independent variables included in a multiple regression model, then: a. regression coefficients will be difficult to interpret b. standard errors of the regression coefficients for the correlated independent variables will increase c. multiple coefficient of determination will assume a value close to zero d. both a and b are correct statements ANSWER: D Use the following information to answer questions 25-26. Suppose that you are interested in explaining why more accidents occur on one particular stretch of highway than on a second stretch of highway. You believe that high variation in speeds of travelers on each highway is the leading cause of accidents in these areas. You are given the following information: S1 = 4 n1 = 100 S2 = 3 n2 = 50 25. In order to test whether the population variances of the speeds on the two stretches of highway are the same, what would the null hypothesis be? a. The population variance of highway 1 is greater than the population variance of highway 2. b. The population variance of highway 1 is the same as the population variance of highway 2. c. The population variance of highway 1 is smaller than the population variance of highway 2. d. The population variance of highway 1 is different than the population variance of highway 2. e. None of the above. 687272425 Page 8 of 11 ANSWER: B 26. What is the value of the test statistic for the above test? a. 1.3333 b. 0.75 c. 1.7777 d. 1.1547 e. not enough information given ANSWER: A 27. In constructing 95% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows: t0.025, 63 = 1.998 n1 50 x1 175 s1 18.5 z0.025 = 1.96 n2 42 x2 158 s2 32.4 The upper confidence limit is approximately: a. 19.123 b. 28.28 c. 24.911 d. 28.06 ANSWER: B 28. A sample of size 100 selected from one population has 60 successes, and a sample of size 150 selected from a second population has 95 successes. The test statistic for testing the equality of the population proportions equal to: a. -.5319 b. .7293 c. -.419 d. .2702 ANSWER: A 29. If some natural relationship exists between each pair of observations that provides a logical reason to compare the first observation of sample 1 with the first observation of sample 2, the second observation of sample 1 with the second observation of sample 2, and so on, the samples are referred to as: a. matched samples b. independent samples c. weighted samples d. random samples ANSWER: A 30. In testing the null hypothesis H 0 : p1 p2 0 , if H 0 is false, the test could lead to: a. a Type I error b. a Type II error 687272425 Page 9 of 11 c. either a Type I or a Type II error d. None of the above ANSWER: B 31. From a sample of 400 items, 14 are defective. The point estimate of the population proportion defective will be: a. 14 b. 0.035 c. 28.57 d. .14 e. None of the above ANSWER: B Use the following output to answer questions 32-35. SUMMARY OUTPUT Regression Statistics Multiple R R Square Adjusted R Square Standard Error Observations ANOVA df Regression Residual Total Intercept Vacancy 1 28 29 SS MS F Significance F 94.93883672 94.93884 11.50037 0.002089293 231.1480299 8.255287 326.0868667 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% 20.63970836 1.14279152 18.06078 5.78E-17 18.29880342 22.9806133 -0.303797797 0.089583649 -3.391219 0.002089 -0.487301789 -0.1202938 32. The coefficient of determination is: a. .5396 b. .2911 c. .2658 d. .304 e. none of the above ANSWER: B 33. The standard error of the regression is: a. .08958 b. -.3038 c. 2.8732 687272425 Page 10 of 11 d. 8.2553 e. Impossible to determine with the information given ANSWER: C 34. The correlation coefficient between the dependent and independent variable is: a. 20.6397 b. -.303798 c. .540 d. -.2911 e. None of the above ANSWER: E 35. In the graph provided below, it is likely that the analyst was trying to determine: Residuals Vacancy Residual Plot 10 0 -10 0 5 10 15 20 25 Vacancy a. if the error variable is normally distributed b. if the error variance is constant c. if there is multicollinearity d. if there is heteroscedasticity e. both b and d ANSWER: E 687272425 Page 11 of 11