The Two-Scale Methods for Mechanics Parameter Computation of Composite Materials with Periodic Distribution J. Z. Cui and X. G. Yu Academy of Mathematics and System Sciences, Chinese Academy of Sciences, China, E-mail:cjz@lsec.cc.ac.cn Abstract: In this paper, the Two-Scale computation Method (TSM) is presented for the mechanics parameters of composite materials with small periodic configuration, including stiffness parameters and strength parameters. First the major formulation of the Two-Scale Asymptotic expressions (TSA) for composite materials with periodic configuration is briefly given. And then the two-scale computation (TSM) formulation of the strains and stresses in conventionally strength experimental components, such as the tension of the column with square cross section, the bending of the cantilever with rectangular cross section and the twist of the column with circle cross section, which are made from the composite materials with the same basic cells, is developed by means of the fundamental solutions, and the procedure of TSM computation is discussed. Finally the numerical results for both stiffness and strength parameter computation are demonstrated in three kinds of typical components. And they have been compared with the experimental those, both TSM and experimental results are very close. They show that the TSM method given in this paper is feasible and valid for both stiffness and strength parameter prediction of the composite materials with periodic configuration. Key words: Two-scale method, stiffness parameters, strength parameters, composite materials with small periodic configuration. 1. Introduction With the rapid advance of composite materials, they have been widely used to a variety of industrial fields besides high science and technology products. Therefore in order to develop new composite materials it is necessary to predict the physical and mechanical properties of the composite materials at first. In stiffness parameter prediction a variety of meso-scopic and microscopic methods in mechanics and engineering [1-13] was proposed by mechanical experts and engineers. The composite materials can be divided into two classes according to the basic configuration: the composite materials with periodic configuration, such as periodically honeycomb materials and braided composites, and the composite materials with random distribution, such as concrete, foamed plastics. Due to the difference of basic configuration it is necessary to make use of different numerical methods to evaluate the physical and mechanical properties of different materials. Based on the homogenization method proposed by J.L. Lions, O.A. Oleinik and others, the Multi-Scale Analysis (MSA) method for the structure of composite materials with periodic configuration was proposed in [8-10]. It can be applied to evaluating the macroscopic stiffness parameter of the composite materials with periodic configuration. For the physics field problems of composite materials with the stationary random distribution Jikov and Kozlov developed the homogenization method, and proved the existence of macroscopic homogenization parameters [7], however, they did not give the numerical method to compute the macroscopic homogenization parameters. One of the authors in this paper proposed a kind of Statistic Multi-Scale Analysis (SMSA) method for the macroscopic mechanics and physics parameters of the composite materials of random distribution [11, 12]. Up to now the literature pertaining to the theoretic prediction for the strength parameters of 3D braided composites is very limited [13-15]. In this paper, we are concerned with the mechanics parameter computation of the composite materials with periodic configuration, including the effectively stiffness parameter and strength parameters. A kind of two-scale method for the strength parameter computation of the composite materials with periodic configuration is developed. The remainder of this paper is outlined as follows: In section 2 the main results on the two-scale asymptotic analysis for the composite materials with small periodic configuration is briefly expressed. Section 3 is devoted to the Two-Scale Analysis (TSA) formulation for the strength parameters of the composite materials with periodicity. In section 4 the procedure based on TSA is stated for both stiffness and strength parameter computation of the composite materials with periodicity. In section 5 the numerical results for mechanical parameter computation of the composite materials with small periodicity are shown. They show that the TSM method given in this paper is feasible and valid for both stiffness and strength parameter computation of the composite materials with periodic configuration. 2. Two-Scale Approximate Formulation for Composite Materials with Periodicity Suppose that the structure or component made from the composite materials with small periodic configuration is denoted by c i , where c i denotes basic cell, and all of iT ci i T are of same configuration with size . From solid mechanics the elasticity problem for this kind of structure can be expressed as follows 1 uh ( x) uk ( x) a ( x ) x ijhk fi ( x) 2 xk xh x j u ( x) u( x) x 1 1 uh ( x) uk ( x) ( u ) a ( x ) pi ( x) x 2 j ijhk 2 xk xh 1 2 0, 1 2 where (2.1) ( x) i, j, h, k 1,, n are the elastic denotes the size of basic cell ci , aijhk coefficients of periodicity with cells, u ( x) is the solution of vector-valued displacement, and j are the normal direction cosine of 2 . From composite material science it is well known that L 1 , where L denotes the size of the structure . Since aijhk ( x) i, j, h, k 1,, n vary very sharply and periodically it is very difficult to numerically solve the problem (2.1) as the detailed configuration of materials and the structure together are considered in a macroscopic scale. From material science it has been shown that the mechanical properties of previous structure depends not only on the macroscopic conditions, such as the geometry of the structure, the macroscopic constants of materials, the loading and constraints, but also on detailed configuration. Therefore the detailed configuration of composite materials should be considered with the macroscopic conditions of structure together to investigate the mechanical properties of structure. Let x , then aijhk x aijhk aijhk , aijhk is 1-periodic function. From x [8] u ( x) can be expressed into u ( x) u( x, ) , where x denotes the global coordinates of the structure and global behaviors, and x / the local coordinates on normalized cell and the effects of cell configuration. Then u ( x) u( x, ) can be expressed formally as follows u x u 0 x l l 1 1 l 1 n N1 l l u0 , x x1 xl (2.2) 0 where u ( x) is the homogenization solution and defined on global , N12 1,2 , ,l 1, , n, l 1, 2,3, l are n-order matrix valued functions with 1-periodicity, and they will be defined on 1-square Q normalized basic cell. They can be expressed as follows N1 N1 l N 1 l 11 l n1 N1 N1 l 1n N1 l nn l 1 N1 l n (2.3) 0 In concrete, all of N 1 2 l m 1 , 2 , , l , m 1, , n, l 1,2,3, and u ( x) are determined as follows: 1) For l 1 , N 1m 1 , m 1, , n are the solutions of following problems aij1m ( ) 1 N1hm ( ) N1km ( ) Q aijhk ( ) 2 k h j j Q N1m ( ) 0 2) From N 1m 1 , m 1, , n , the homogenization elasticity parameters calculated as follows (2.4) â ijhk are 1 N hpk ( ) N hqk ( ) aˆijhk aijhk ( ) aijpq ( ) d Q 2 q p 3) (2.5) For l 2, N 1 2 m 1 , 2 , m 1, , n are the solutions of following problems 1 N1 2 hm ( ) N1 2 km ( ) aijhk ( ) aˆi 2 m1 ai 2 m1 ( ) 2 k h j Q N1hm ( ) ai 2 hk ( ) aijh 2 ( ) N1hm ( ) k j N m ( ) 0 Q 12 4) (2.6) u0 ( x) is the solution of the homogenization problem defined on global with the homogenized parameters â ijhk 1 uh0 ( x) uk0 ( x) aˆijhk fi ( x), x 2 x j xk xh u 0 ( x) u( x), x 1 0 0 x aˆ 1 uh ( x) uk ( x) p , x j ijhk i 2 i 2 xk xh 1 2 0, 1 2 5) (2.7) N 1 2 l m 1 , 2 ,, l , m 1,, n, l 3, are the solutions of following problems, 1 N1 2 ...l hm ( ) N1 2 ...l km ( ) aijhk ( ) 2 k h j ail hl 1 ( ) N1 2 ...l 2 hm ( ) Q N1 2 ...l 1hm ( ) ail hk ( ) k aijhl ( ) N1 2 ...l 1hm ( ) j Q N1 2 ...l m ( ) 0 6) Since aij1m ( ) aijm1 ( ) , then N12 l m (2.8) 1,2 , ,l , m 1, , n, l 3, satisfies symmetric relation N12 7) l m Nm 2 l1 (2.9) In practical computation of engineering problem only the sum of fore M terms in (2.2) are evaluated M u (M ) x u0 x l 1 l 1 l 1 n N1 l u0 , x l x1 xl (2.10) generally, M 1,2,3 . And then the strains and stresses are evaluated in the formulas anywhere 1 uh ( x) uk ( x) 2 xk xh hk ( x, ) 1 uh0 ( x) uk0 ( x) 2 xk xh (2.11) M 1 l N αhm ( ) Dαl k1um0 ( x) N αkm ( ) Dαl h1um0 ( x) l 1 α l 2 M l 1 l 1 where 1 N αhm ( ) N αkm ( ) l 0 Dα um ( x) k h α l 2 1, 2 ,,l , Dl u m0 x l u m0 x x1 x 2 x l ij ( x, ) aijhk ( ) hk ( x, ) u 0 ( x) uk0 ( x) 1 aijhk ( ) h 2 xh xk M l l 1 M 1 aijhk ( ) N αhm ( ) Dαl k 1um0 ( x) N αkm ( ) Dαl h1um0 ( x) 2 α l l 1 l 1 (2.12) N ( ) N αkm ( ) l 0 1 aijhk ( ) αhm Dα um ( x) h α l 2 k It has been proved that if the basic configuration of cells compounded into composite materials is constructed into symmetrical-structure for xi axis i 1, , n , then the approximate displacement (2.10), strains (2.11) and stresses (2.12) strongly converge to the true displacement, strains and stresses of problem (2.1) as 0. Figure 1. The 2-D structures with periodic configuration and their basic cell 3. The Formulation for Strains and Stresses of Some Special Structures It is well known that the strength parameters of one kind of materials are obtained by the mechanics experiment of typical components made from those. By the maximum of elasticity strains/stresses inside component the strength parameters are worked out. In this section the formulas on the strains and stresses inside the structure of composite materials with periodic configuration will be discussed by the means of simulating the mechanics experiments. From (2.11) and (2.12) it follows that the distribution of the strains and stresses inside the structure/component made from composite materials depend on both the macroscopic condition, 0 that is the homogenization displacement u ( x ) defined on global , and the detailed configuration of cells, 1 , 2 ,, l , m 1,, n, l 1,2,3 the local solutions N 1 2 l m determined on normalized cell Qcell . In the mechanics experiment three kinds of experimental components, such as tensile column, bend beam and twist column, are often adopted. The formulas on the strains and stresses inside them are discussed below, respectively. 3.1 Column tension The tensile behavior of the column with rectangular cross section shown in Figure 2, which 3 x3 T 1 o 2 x2 x1 Figure 2. Column with square section secton 矩形截面柱体的均匀拉伸 is made from composite materials with small periodicity, is investigated at first. Let A denotes the area of cross section, L length of the column, x3 0 fixed end and x3 L loading end with load T . From elasticity mechanics for the tension of the column with orthogonal-anisotropic material coefficients there exists a true displacement as follows 0 13 px1 u1 E11 0 23 px2 u2 E 22 0 p x3 u3 E33 (3.1) where p T / A , E11 , E22 , E33 , 12 and 23 are the elasticity modulus of three axis directions and Poisson ratio. From (3.1) it follows that Dl um0 x l um0 x 0, for l 2 . x1 x 2 xl Thus the displacement vector of the tension problem of the column made from composite materials with periodic configuration can be expressed as 0 x u1 ( x) u ( x) u ( x) N1 ( ) . x1 0 (3.2) And then the formulas on the strains and stresses inside previous column can be exactly written into 1 uh0 ( x) uk0 ( x ) 2 xk xh hk ( x) x x N ( ) N1km ( ) 0 1 1hm um ( x) 2 xk xh x1 (3.3) 1 x uh0 ( x) uk0 ( x) ij ( x) aijhk x hk x aijhk ( ) 2 xk xh x x N1hm ( ) N1km ( ) 0 1 x um ( x) aijhk ( ) 2 k h x1 (3.4) Substituting (3.1) into (3.3) and (3.4) one obtains the expression on each component of the strain tensor inside every cell of the column respecting the symmetry of N1 ( ) and N1 2 ( ) 11 12 13 E11 p p 1 N313 13 N111 23 N 212 1 E33 E11 E22 p 1 N 323 13 N121 23 N 222 2 1 E33 E11 E22 p 1 N 313 13 N111 23 N 212 2 2 E33 E11 E22 13 p 1 N 333 13 N131 23 N 232 2 1 E33 E11 E22 p 1 N 313 13 N111 23 N 212 2 3 E33 E11 E22 22 23 23 E22 p p 1 N323 13 N121 23 N 222 2 E33 E11 E22 p 1 N 333 13 N131 23 N 232 2 2 E33 E11 E22 p 1 N 323 13 N121 23 N 222 2 3 E33 E11 E22 (3.5.1) (3.5.2) (3.5.3) (3.5.4) (3.5.5) 33 where x p 1 p N333 13 N131 23 N 232 E33 3 E33 E11 E22 (3.5.6) . Furthermore, from above strains the stresses are evaluated anywhere inside every cell belonging to the column. Then based on the yield criterion of basic materials, such as matrix, reinforced fibers and interfaces, the critical point of tensile column of composite materials can be evaluated. 3.2 Beam bending 1 3 x1 x3 2 M h (a) M o x2 L b Figure 3. The bending of cantilever made from composite materials The bending of the cantilever with rectangular cross section, which is made from composite materials with periodic configuration, is investigated shown in Figure 3. Let x3 0 denotes fixed end and at x3 L the bend moment round x2 axis is imposed. From solid mechanics the bending problem of the cantilever with orthogonal-anisotropic material coefficients has following solution 0 M 1 2 13 2 23 2 x3 x1 x2 u1 2 I E E E x2 33 11 22 23 M 0 x1 x2 u2 E22 I x2 M u30 x1 x3 E33 I x2 (3.6) where I x2 bh3 is the moment of inertia round x2 . 12 It is easy to see that the displacements are two-order polynomial. So l um0 x D u x 0, for l 3 . x1 x 2 xl l 0 m Thus the displacement vector of the bend problem of the cantilever made from composite materials with periodic configuration can be expressed as 0 2 0 x u x 0 x u x 2 u( x) u ( x) N1 ( ) u ( x) N1 2 ( ) x1 1 x1 x2 0 (3.7) Thus the strains anywhere inside above cantilever can be approximately calculated in following formulas 1 uh0 ( x) uk0 ( x) hk ( x) 2 xk xh 2um0 ( x) 2um0 ( x) 1 N1km ( ) N1hm ( ) 2 x1 xk x1 xh 1 N1hm ( ) N1km ( ) um0 ( x) 2 k h x1 (3.8) 1 N1 2 hm ( ) N1 2 km ( ) 2um0 ( x) 2 k h x1 x 2 ij ( x) aijhk x hk x u 0 ( x) uk0 ( x) 1 aijhk ( ) h 2 xh xk 2um0 ( x) 2um0 ( x) 1 aijhk ( ) N1hm ( ) N1km ( ) 2 x1 xk x1 xh (3.9) N1hm ( ) N1km ( ) um0 ( x) 1 aijhk ( ) 2 h x1 k N1 2 hm ( ) N1 2 km ( ) 2um0 ( x) 1 aijhk ( ) 2 k h x1 x 2 Respecting the symmetry of N1 ( ) and N1 2 ( ) , the components of strain tensor inside every cell belonging to the cantilever are evaluated in following formulas: 11 M I x2 1 N 313 ( ) 13 N111 ( ) 23 N 212 ( ) E11 E22 E33 Mx1 1 N 313 ( ) 23 N 212 ( ) 13 N111 ( ) I x2 1 E33 E22 E11 M 1 N 3113 ( ) 23 N 2112 ( ) 13 N1111 ( ) I x 1 E33 E22 E11 (3.10.1) 2 13 M x1 E11 I x2 12 M 2 I x2 1 N 323 ( ) 23 N 222 ( ) 13 N121 ( ) E22 E11 E33 Mx1 1 N 323 ( ) 23 N 222 ( ) 13 N121 ( ) 2 I x2 1 E33 E22 E11 M 1 N 3123 ( ) 23 N 2122 ( ) 13 N1121 ( ) 2 I x 1 E33 E22 E11 (3.10.2) 2 Mx1 1 N 313 ( ) 23 N 212 ( ) 13 N111 ( ) 2 I x2 2 E33 E22 E11 M 1 N 3113 ( ) 23 N 2112 ( ) 13 N1111 ( ) 2 I x 2 E33 E22 E11 2 13 M 1 N 333 ( ) 23 N 232 ( ) 13 N131 ( ) 2 I x2 E33 E22 E11 Mx1 1 N 333 ( ) 23 N 232 ( ) 13 N131 ( ) 2 I x2 1 E33 E22 E11 M 1 N 3133 ( ) 23 N 2132 ( ) 13 N1131 ( ) 2 I x 1 E33 E22 E11 (3.10.3) 2 Mx1 1 N 313 ( ) 23 N 212 ( ) 13 N111 ( ) 2 I x2 3 E33 E22 E11 M 1 N 3113 ( ) 23 N 2112 ( ) 13 N1111 ( ) 2 I x 3 E33 E22 E11 2 22 Mx1 1 N323 ( ) 23 N 222 ( ) 13 N121 ( ) I x2 2 E33 E22 E11 M 1 N3123 ( ) 23 N 2122 ( ) 13 N1121 ( ) I x 2 E33 E22 E11 2 23 Mx1 E22 I x2 (3.10.4) 23 Mx1 1 N 333 ( ) 23 N 232 ( ) 13 N131 ( ) 2 I x2 2 E33 E22 E11 M 1 N 3133 ( ) 23 N 2132 ( ) 13 N1131 ( ) 2 I x 2 E33 E22 E11 2 Mx 1 1 N 323 ( ) 23 N 222 ( ) 13 N121 ( ) 2 I x2 3 E33 E22 E11 (3.10.5) M 1 N 3123 ( ) 23 N 2122 ( ) 13 N1121 ( ) 2 I x 3 E33 E22 E11 2 33 Mx1 1 N333 ( ) 23 N 232 ( ) 23 N131 ( ) I x2 3 E33 E22 E22 M 1 N3133 ( ) 23 N 2132 ( ) 23 N1131 ( ) I x 3 E33 E22 E22 (3.10.6) 2 Mx1 E33 I x2 where x . Using the stress-strain relation one can evaluate the stresses anywhere inside each cell belonging to the cantilever. From previous formulas it is easy to see that only x1 component of macroscopic coordinate appear in the strain expressions. It means that the strains do not depend on macroscopic coordinate x2 and x3 . And then the maximum strain occur in the cells located on the above or below surface of the cantilever, but it is uncertain that the maximum strain occur on the above or below surface x1 h / 2 , since the strains and stresses change very sharply inside each cell. According to maximum principal stress and principal strain one can evaluate the elasticity strength limit of the beam bending of composite materials with any periodic configuration. It is worthy of note, the basic configuration of the cells of composite materials must lead to macroscopically orthogonal-anisotropic material coefficients. If not, (3.6) does not hold, herewith, each formula of (3.10) is wrong. 3.3 Twist of column The twist of the column with circle cross section, which is made from composite materials 1 3 x3 2 T x1 (a) r T o x2 L Figure 4. Twist of the column with circle section with same periodic configuration, is investigated, shown in Figure 4. Let r denotes the radius of cross section, L the length of the column, x3 0 fixed end, and on x3 L the twist moment is imposed. If the column can be considered as that made from orthogonal-anisotropic materials, from elasticity mechanics the homogenization displacement solution can be expressed as 0 Tx2 x3 1 1 u1 r 4 G13 G23 1 0 Tx1 x3 1 u2 4 r G13 G23 u30 Tx1 x2 1 1 r 4 G13 G23 (3. 11) where G13 , G23 denote the shear modulus in x1-x3 plain and x2-x3 plain.. It is easy to see that the displacements are the 2-order polynomial under above supposition. And respecting the symmetry of N1 ( ) and N1 2 ( ) the components of strain tensor inside the column are expressed as follows 11 x 2 T 2T x1 N 213 4 N 213 ( ) 2 N113 ( ) 4 r G23 r 1 G23 G13 (3.12.1) T 12 r 4G23 N 223 ( ) N113 ( ) x T x1 N 223 ( ) 2 N123 ( ) 4 r 1 G23 G13 x T x1 4 N 213 ( ) 2 N113 ( ) r 2 G23 G13 13 T r G23 4 N 233 ( ) (3.12.2) Tx2 r 4G13 x2 T x1 N ( ) N ( ) 233 133 r 4 1 G23 G13 x T x1 4 N 213 ( ) 2 N113 ( ) r 3 G23 G13 22 23 (3.12.3) x2 2 T 2T x1 N N ( ) N ( ) 123 223 123 r 4G13 r 4 2 G23 G23 Tx1 T 4 N ( ) 4 r G23 r G13 133 x T x1 N 233 ( ) 2 N133 ( ) 4 r 2 G23 G13 x T x1 4 N 223 ( ) 2 N123 ( ) r 3 G23 G13 33 where x (3.12.4) (3.12.5) x 2T x1 N 233 ( ) 2 N133 ( ) 4 r 3 G23 G13 (3.12.6) . Using the stress-strain relation one can evaluate the stresses inside each cell belonging to the column. And then according to maximum principal stress and principal strain one can determine the elasticity critical point of the twist column of composite materials with same basic configuration. Remark: 1. It should be noticed that since the column with circle cross section includes incomplete cells around its surface, it means that c i ( c i is entire cell) iT does not hold, so the expressions (3.12) of the strain components inside the column are approximate. But if L 1 , the strain values evaluated by (3.12) are close to true values everywhere inside column except the incomplete cells around its surface. 2. The basic configuration of cells must satisfy such symmetry that it leads to orthogonal-anisotropic isotropic coefficients. If not, (3.11) does not hold, herewith, (3.12) is wrong. Similarly, one can obtain the expressions of strains and stresses for other component of composite materials with periodic configuration. 4. Two-Scale Algorithm for Mechanics Parameter Computation 4.1 Approximate formulas for stiffness coefficients 1. FE solutions for N 1m and the approximate stiffness coefficients the approximate elasticity stiffness coefficients solutions N1m 1, m 1, h aˆ h ijhk aˆ . From(2.5) h ijhk can be calculated if the approximate , n of problem (2.4) are obtained. As you have known, from PDE theory it follows that problem (2.4) is equivalent to following virtual work equation Q ij v aijhk hk N m d ij v aij m d , v H 01 Q 1 1 Q (4.1) where 1 vi v j 2 j i ij v Thus approximate N1m h 1 , m=1, 2,3 can be determined by solving following FE virtual work equation on FE space S0 Q v S h (4.2) h Q / v Q 0 v a N d = v a d ij eS h ijhk h hk1 e Actually N1m h 1 , m=1, 2,3 approximate stiffness coefficients aˆ h ijhk m ij eS e h ij 1m v S0h Q (4.3) are obtained by using general FE software. Then the can be evaluated in below formulas h aˆijhk aijhk aijlm lm Nhhk d . Q 2. FE computation of N 1 2m (4.4) N 1 l m . The FE solutions and Nh12m and Nh1l m for 3 l M are obtained by solving following FE virtual h work equations on 1-square Q corresponding to FE partition S , respectively Q ij v aijhk hk Nh m d ij v a jh Nh hm d 1 2 2 Q 1 (4.5) ai 2 m ai 2hk hk Nh m1 aˆih m2 1vi d , v S0h Q Q Q ij v aijhk hk Nh 1 ail hl 1 Nh1 Q l 2 hm d d v a N a N v d , v S Q l m Q i l hk h ijh l ij 1 l 1hm h 1 l 1m hk i (4.6) h 0 3. Homogenization Solution. From elasticity mechanics the homogenization solution u x for 0 typical structure / component can be exactly obtained, and for general structure by solving the FE virtual work equations corresponding to (2.7) on global . 4. Approximate displacement, strains and stresses. Two-scale approximate solution anywhere on structure can be evaluated in following formulas l 0 x um x u x N1lim , x x1 xl l 1 1 l 1n M u (M )h i 0 i l h l 0 M M h 1 x um 0 l 1 hk u x hk N1l m l x1 xl l 1 2 l 1 hk( M ) h x l 1u m0 l 1u m0 x x h N h N , x 1 l km 1l hm x x xk x x x h 1 l 1 l x hk( M )h x , ij( M ) x aijhk 4.2 (4.7) x (4.8) (4.9) Formulas for strength parameters 0 Once the homogenization solution u ( x ) for the component made from composite materials with small periodicity is obtained the strains and stresses everywhere inside it can be evaluated in the formulas given in previous section. Thus it is easy that through analyzing the strain and stress distribution inside each cell belonging to the component the dangerous point of the strains / or stresses can be determined according with the strength criterion of basic materials. Since there is always a great difference between the mechanics properties of reinforcement and matrix of composite materials, so it is necessary to take different strength criterions for reinforcement and matrix. The facts, which lead to the fracture of the fibers and the yield of the matrix macroscopically, are that most of fibers used today are brittle, and matrix always has the characteristic of high ductility. The strength criterions taken in this paper are as follow: 1) Reinforcement (fiber). Considering the brittle characteristic of the reinforcement (fiber), the maximum normal stress criterion is adopted. The criterion for homogenous materials says that the material collapse while one of the principal stresses exceeds the strength of the material. With respect to the fibers they are always subject to the longitudinal load and fracture along the transverse section. Thus we take the longitudinal normal stress and the two principal stresses in the transverse plane instead of the three principal stresses in conventionality. Then the criterion can be expressed as: L SL , T ST (4.10) where L is the longitudinal normal stress, T denotes the maximum normal stress in the transverse plane of the fibers. S L 、 ST denote the longitudinal and transverse limit stresses, L can be evaluated through the transformation of respectively. The longitudinal normal stress coordinates. As shown in Figure 5, the relation between the stresses vector of the local coordinates (x'1, x'2, x'3) and global coordinates (x1, x2, x3) is the following: T where T 11 22 33 12 23 13 (4.11) , the transformation matrix T can be expressed as follows: l12 2 l2 l2 T 3 l1l2 l2l3 l3l1 m12 n12 2l1m1 2m1n1 2 2 2 3 2 2 2 3 m n 2l2 m2 2m2 n2 m m1m2 n n1n2 2l3m3 2m3n3 l1m2 l2 m1 m1n2 m2 n1 m2 m3 n2 n3 l2 m3 l3m2 m2 n3 m3n2 m3m1 n3n1 l1m3 l3m1 m1n3 m3n1 2n2l2 2n3l3 n1l2 n2l1 n2l3 n3l2 n1l3 n3l1 2n1l1 where li , mi , ni (i 1, 2,3) are the direction cosine between global coordinates and local coordinates. The third component of is just the longitudinal normal stress L . The x'3 x'2 o' x'1 Fiber x1 x3 o x2 Figure 5. The global and local coordinates of a cell with one fiber maximum normal stress in the transverse plane of the fibers T is just the first principal stress in the transverse plane, which can be evaluated in following formula T 11 22 2 22 11 12 2 2 (4.12) If and only if formula (4.10) does not hold, the material begins to stat in nonlinear state. 2) Matrix. Since the matrix of composite materials is ductile, the Von Mises effective stress yield criterion is employed. The criterion is following e 1 ( 1 2 )2 ( 2 3 ) 2 ( 3 1 ) 2 S 2 (4.13) or e 1 2 ( 11 22 )2 ( 22 33 )2 ( 33 11 )2 6( 122 23 312 ) S 2 (4.14) where 1 、 2 、 3 denote the three principal stresses. S is the tensile (compressive) limit stress. e is Von Mises effective stress. ij (i, j 1, 2,3) are the components of the stress tensor, which can be obtained from (2.12). If and only if above equation does not hold, the material begins to yield. Once the basic configuration of composite materials and the load type of a component / or structure are given, the critical load of the component / or structure can be determined through the 0 criterions above (4.10) and (4.14). Then the homogenization displacement u ( x ) under the critical load can be obtained. It’s easy to get the strain and stress state under the critical load through geometrical and physical equations. 4.3 Algorithm procedure The algorithm of TSM is following: 1. Determine the composite materials, i.e. the basic configuration of cells, such as the basic composition, matrix, reinforced fiber and interface materials, and their properties, and the located position of them in cell. And then verify the distribution functions a x of the ijhk material properties of basic configuration. h 2. Solve FE virtual work equation (4.2) on 1-square Q to obtain N1m , and then evaluate the homogenized constitutive coefficients aˆ h ijhk in formula (4.4). 3. Design the topology of structure/component using verified composite materials. 4. Evaluate the FE solutions N1 2m and N1l m 3 l M by solving FE virtual h h work equation (4.5) and (4.6) on 1-square Q , using same FE meshes as in step (2) as well as the stiffness matrix and its decomposition form. 5. Obtain the homogenization displacement u x for typical structure / component, Or FE 0 displacements u 0h x for general structure by using FE software on whole structure , l u0hm x . x x 0 and then evaluate the high order partial derivatives 1 7. Compute the displacement u and stresses hk (M )h x (M )h x l (M )h at arbitrary point of structure , strains hk x in (4.7), (4.8) and (4.9). 8. Evaluate constitutive parameters of the composite materials and strength parameters of the structure / component according to the formulas of previous subsection (4.2). Remark: if the configuration of composite materials has the characteristic of multi-level and multi-scale the multi-scale computation is needed, and then above computation should be repeated. 5. Numerical Experiments In this paper the stiffness parameters and strength parameters of unidirectional fiber-reinforced and 3D orthogonal braided composite materials are predicted through two-scale method. The results are compared with some theoretical models and experimental data [15-20]. 5.1 The mechanics parameter computations of composite materials with unidirectional fiber-reinforcement 1. Computational model. There are many ways to choose the basic configuration of cell compounded into unidirectional fiber reinforced composite materials, shown in Figure 6. Three kinds of basic configuration, named C1, C2, C3 shown in Figure 7, respectively, can be chosen in computation. The computational results obtained from three kinds of basic configuration, C1, C2 Figure 6. Unidirectional fiber-reinforced composite structure and C3, respectively, are very close for the stiffness parameters and the strength parameters in the tension and bending case of column made from unidirectional fiber reinforced composite materials. Therefore only the results for the basic configuration C1 are shown below. C1 C2 C3 Figure 7. Three kinds of basic configurations for composite structure In order to compare with the experimental results of [18], two sets of composite materials with different fraction of fiber volume, respectively, 27% and 23% are investigated. The basic configuration is denoted by U11 corresponding to 27%, and U21 corresponding to 23%, respectively. The FE models of basic configuration are shown in Figure 8. The parameters of FE partition are shown in Table 1, in that tetrahedron element is denoted by “TET”. The elastic properties of the matrix and the fibers are shown in Table 2. x2 x1 U11 U12 x3 U13 Figure 8 The FE models of the cells Table 1 FE models of basic cell(mm) U11 U21 Element Type TET TET Account of elements 6400 6081 Account of nodes 1415 1355 Table 2 The elastic properties of the matrix and fibers for unidirectional fiber-reinforced composite material Matrix (Shell 862) Fibers (AS-4) Em (Gpa) Gm (GPa) Ef1 (GPa) Ef2 (GPa) Gf12 (GPa) Gf23 (GPa) 12 2.94 1.07 234.6 13.8 13.8 5.5 0.2 2. The computation for stiffness parameters. Once N1m h 1 , m=1, 2,3 are obtained by solving FE equation (4.3). Then the approximate elasticity constitutive coefficients aˆ h ijhk can be evaluated in below formula (4.4). Since the four-order tensor aijhk (i, j , h, k 1, 2,3) and the elastic matrix D have the relationship (5.1). It is easy to calculate the elastic matrix D from aˆ . h ijhk a1111 a 2211 a3311 D a2311 a3111 a1211 a1122 a1133 a2222 a2233 a3322 a3333 a2322 a2333 a3122 a3133 a1222 a1233 a1123 a1132 2 a2223 a2232 2 a3323 a3332 2 a2323 a2332 2 a3123 a3132 2 a1223 a1232 2 a1131 a1113 2 a2231 a2213 2 a3331 a3313 2 a2331 a2313 2 a3131 a3113 2 a1231 a1213 2 a1112 a1121 2 a2212 a2221 2 a3312 a3321 2 a2312 a2321 2 a3112 a3121 2 a1212 a1221 2 (5.1) As you have known that the rule of mixture give a good prediction on longitudinal elastic modulus of unidirectional composites in general case. The formula is as follow: E11 EmVm E f 1V f (5.2) where E11 denotes the macroscopic longitudinal elastic modulus of the unidirectional composite, Vm 、V f the volume fraction of matrix and fiber, Em 、E f 1 the elastic modulus of matrix and the longitudinal elastic modulus of fiber, respectively. To transverse elastic modulus there is not any effective method for unidirectional composite at all. Furthermore, the results are compared with experimental results in [18]. Table 3 shows the comparison of the longitudinal modulus calculated by using two-scale method with experimental results [18] and the results evaluated in formula (5.2). Table 4 shows the comparison of the transverse modulus calculated by using two-scale method with experimental results [18]. ELTSM and ETTSM are the results computed by two-scale method, ELMXR the results calculated from formula (5.2), and ELEXP , ETEXP are experimental results [18]. Table 3 indicates that the error in the prediction from TSM is very small, and smaller than that from the rule of mixture. The error of 9.620% indicates that TSM can be applied to engineering. All of these validate TSM proposed in this paper. Table 3 Comparison of experimental and predicted longitudinal modulus for the unidirectional composite Model Two-Scale Method Mixture Rule Exp. Name ( ELTSM ) ( ELMXR ) ( ELEXP )[18] (GPa) (GPa) (Gpa) ELTSM ELEXP ELEXP (%) U11 64.376 65.5 62.6 2.837 Table 4 Comparison of experimental and predicted transverse modulus for the unidirectional composite Model Name TSM Results Exp.[18] ( ETTSM ) ( ETEXP ) ETTSM ETEXP ETEXP (GPa) (Gpa) (%) 4.989 5.52 9.620 U21 3. The computation of strength parameters. Based on the formulas for the strains and stresses given in section 3, the tensile (compressive) and bending strength of the composite column with rectangular cross section, together with the twist strength of the composite column with circle cross section, are evaluated.. The three model U11 of the unidirectional composite with fiber volume fraction 27% are employed for the prediction of the longitudinal strength parameters, and the model U21 with fiber volume fraction 23% for the prediction of the transverse strength parameters. For the longitudinal strength parameters, three types of loads are imposed on the structure. They are tensile (compressive) load along x3 axis, bending load around x1 axis and twist load around x3 axis, while evaluating the transverse strength parameters, the loads are tensile (compressive) load along x1 axis, bending load around x3 axis and twist load around x1 axis, instead. The results are shown in Table 5 and Table 6. The compressive strength parameters are compared with the theoretical model and experimental data from [18]. The comparison with experimental results shows that the longitudinal strength of unidirectional composite predicted by TSM is very accurate. Table 5 Comparison of predicted, experimental and theoretical longitudinal strength of unidirectional composite Load Type Compressive Model U11 TSM Exp.[18] ( S LTSM ) ( S LEXP ) (GPa) (GPa) 236.2 235.0 Theoretical Model in [18] ( S LTHY )(GPa) 234.9 S LTSM S LEXP S LEXP (%) 0.664 Table 6 Comparison of predicted by TSM and experimental transverse strength of unidirectional composite Load Type Tension TSM Exp.[18] ( STTSM ) ( STEXP ) STTSM STEXP STEXP (GPa) (GPa) (%) 50.96 76.0 39.0 Model U21 Table 7 Prediction for the bending and twisting strength of unidirectional composite Load Type Bending Twisting Model U11 U11 Strength by TSM 236.2 40.98 Table 6 shows that there is a big difference between TSM and experimental results for the transverse strength of unidirectional composite. It means that the transverse strength of unidirectional composite mainly depends on the strength of matrix. We consider that the transverse strength predicted by TSM is reasonable since TSM is perfect in theory. In fact, the experimental results are decentralized for the transverse strength of unidirectional composite. The prediction for the bending and twisting strength of unidirectional composite is shown in Table 7. The bending strength indicates the maximum normal stress under critical bending moment, and the twisting strength the maximum shear stress under limit torque. The result shows that the bending strength is very close to compressive (tensile) strength. The reason is that the state of stress of the dangerous point of the structure under bending moment is similar to that under compressive (tensile) load. 5.2 The mechanics parameter computations of 3-D orthogonal braided composite 1. Computational model. The basic cell of 3-D orthogonal braided composite is chosen similar x2 x1 to that in [15] to validate the TSM method previously. The configuration of the structure in [15] is shown in Figure 9. A simplified model, where the volume fractions for x1-fiber, x2-fiber and x3-fiber are the same as that in [15], is taken Figure 9. A schematic of the top-view for 3D orthogonal woven CFRP composite in this paper. The geometric parameter of basic cell is 5mm×6mm×3mm. The overall fiber volume fraction is 43%, and the nominal proportions of the x1 fiber, x2 fiber and x3 fiber are 1:1.2:0.2. The transverse section shape of x3 fiber is regarded as circle with radius 0.585mm, and that of x1 fiber and x2 fiber is ellipse with long axial 1.6883mm and short axial 0.6078mm. There are 27298 tetrahedrons and 5490 nodes in the FE model of basic cell, see Figure 10. The elastic properties of the basic materials used are shown in Table 8. Table 8 The elastic properties of basic materials of the 3-D orthogonal braided composite cell Matrix (Epicote 828) Fibers (T-300) Em (GPa) m Ef1 (GPa) Ef2 (GPa) Gf12 (GPa) Gf23 (GPa) f 12 2.2 0.35 220 13.8 11.35 5.5 0.2 x3 x2 Matrix Fibers x1 Figure 10 The FE model of 3-D orthogonal braided composite 2. The computation for stiffness parameters. Besides (5.1), the elastic matrix D for orthogonal-anisotropic materials can be expressed with elastic constants as: ( 232 ) 2 ( 12 23 13 ) ( ) D 12 23 13 0 0 0 ( 12 23 13 ) ( 12 23 13 ) 0 0 ( ) ( 23 12 13 ) 0 0 ( 23 12 13 ) ( ) 0 0 0 0 G12 0 0 0 0 G23 0 0 0 0 2 13 2 2 12 0 0 0 (5.3) 0 0 G13 where E11 / E33 , E22 / E33 , E33 /( 23 12 2 12 23 13 13 ) , 2 2 2 2 E11 、E22 、E33 are the longitudinal modulus of three axes, respectively, and 12 、 23 、 13 are the poison-ratios, and G12 、 G23 、 G13 the shear modulus in the three coordinate planes, respectively. All the elastic constants can be obtained by comparing the formulas (5.1) and (5.3). The elastic constants of orthogonal-anisotropic composite are calculated by using two-scale method, and compared with experimental results from reference [15]. Table 9 shows the prediction results for the elastic modulus of 3D orthogonal braided composite. The comparison with experimental results indicates that the two-scale method is valid. It should be noticed that the error of physics experiment for the mechanics parameters of composite materials are unavoidable. Table 9 Comparison of experimental and TSM results for elastic coefficients of 3-D orthogonal braided composite E11 (Gpa) E22 (GPa) 12 Experimental [20] 40.97 47.3 0.0346 TSM Results 43.406 50.570 0.0390 5.95 6.91 12.7 Error (%) 3. The computation of strength parameters. The data in Table 3 show the comparison of the tensile strength parameters predicted by TSM, experimental results [20] and the data of theoretical model [15]. It is noted that there is a noticeable difference between the predicted by TSM and experimental limit stresses. The reasons are following: Firstly, the geometrical simplification of experimental model may cause the deviation of the results. Secondly, the ignoring waviness of fibers on the surface of the structure influences the critical stresses in theory. Otherwise, the limit stresses predicted by TSM are close to the maximum of the experimental results. It seems that the two-scale method gives reasonable upper bound since the experimental results are decentralized. Table 3 Comparison of predicted by TSM, experimental and theoretical model in [15] tensile strength parameters for 3D orthogonal braided composite Exp.[20] Failure strength (MPa) TSM Theoretical Model in [15] avg. min. max 11t 582.84 538.12 483.72 466.68 515.67 11t 0.013427 / 0.012281 0.011173 0.013009 22t 659.19 711.04 486.24 445.07 509.17 22t 0.013035 / 0.010249 0.007158 0.012175 The predicted bending and twisting strength of the 3D orthogonal braided composite are listed in Table 4. 11t , 22t and 33t are the maximum normal stresses under critical bending moment around x1, x2 and x3 axes, respectively. 12t , 23t and 31t are the maximum shear stresses under limit torque around x2, x3 and x1 axes, respectively. There is no experimental result, which can be compared with. Table 4 Prediction for the bending and twisting strength of 3D orthogonal braided composite Bending Load Type Predicted strength (MPa) 6. Twisting 11t 22t 33t 12t 23t 31t 583.22 659.37 179.69 129.88 129.61 69.77 Conclusions In order to develop new composite materials the mechanics parameter prediction for composite materials is necessary. In this paper, a two-scale computational method is proposed based on two-scale asymptotic expression for the displacement solution of the structure made from composite materials, and the related formulas are given. It can be used to predict the stiffness parameters and strength parameters of composite materials with small periodic configuration. The predicting results for the mechanics parameters of unidirectional and 3D orthogonal braided composites are given. The following conclusions are worked out: 1) The strength parameters of composite materials depend on the microscopic configuration of composite materials, macro geometry of the structure (test component) and the state of loadings. 2) The two-scale method proposed in this paper is valid by comparing TSM predicting results with the experimental and some theoretical model. There is a reasonable agreement in the stiffness and strength parameters of unidirectional composite between TSM and experimental results. However, in the prediction for the mechanics parameters of 3D orthogonal braided composite there are some difference from the experimental results, but it still can provide a guide for design of composites since TSM is a general and perfect method in theory. References [1] T. Iwakuma, S. Koyama, “An estimate of average elastic moduli of composites and polycrystals”. Mechanics of Materials, 37(2005), 459-472. 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