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Today Ch.36 (Diffraction)

Next week, Dec.6, Review

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Final Exam: (Ch.21-25, 27-29, 32,33,35,36)

Secs.511-515: December 9, Friday: 12:30-2:30 pm

Secs.521-525, 528: December 12, Monday, 8-10 am

Lecture 24 (Ch. 36)

Diffraction

1. Huygen’s principle, bending of the rays

2. Fraunhofer’s diffraction

3. Single slit

4.Two slits with a finite width

5. Resolution of the lens

6. Diffraction grating

7.Spectroscopy

8. x-ray diffraction

9. e diffraction

Huygen’s principle and bending of the rays

Augustin-Jean Fresnel

1788 – 1827

Joseph von Fraunhofer

(1787 – 1826)

Single slit diffraction

How to describe the real picture?

 r

 r

 a sin

Single slit diffraction a

2 sin min :

 a

  sin

2

( 1 st m

 min)

( m

 a sin

1 ,

2 ,...)

  

NB : m

( m

0

  

0 all rays

0 !

parallel to axis

 max!

) for small

; sin

  tan

  y x

, min : y m

 x

 m a

Intensity distribution

R=

1 st max

 

0

E

  k

 r

2

 a sin

E

2

R sin

2

,

 

E

0 ,

R

E

E

0

 sin

2 min max

:

:

2

 m

 a sin

( 2 m

1 )

  m

( m

2

0 )

, I

I

0

{

 sin

2

}

2

2

E

1 st min:

 

2

1 st max:

 

3

I

I

0

{

 sin

2

}

2

; min :

 

2

 m

 a sin

  m

( m

0 )

2

Narrowing of the first fringe with increase of the slit width

 

1

 a

Circular hole diffraction

The photographs of four very small sources of light taken made with a circular aperture in front of the lens

Rayleigh’s criterion for resolution of two point objects : Two objects are barely resolved if the center of one diffraction pattern coincides with the first minimum if the other.

S

L sin

 

1 .

22

D

L

For a microscop

John William Strutt, 3rd Baron Rayleigh

1842 – 1919

CD :

 

780 nm

DVD :

( 0 .

7 gigabytes )

650 nm ( 4 .

7 gigabytes )

Hubble vs Arecibo

Hubble: D=2.4m,

Arecibo: D=300m,

500 nm

75 cm

S

L

L sin

 

1 .

22

D

3 .

8

10

8 m ( to the moon )

S

H

L

77

4 ly ( m , S

A

 nearest

1000 km ( crater star ,

 size

Centaury )

)

1 ly

S

H

 c

1 year

10

7 km ,

3

10

8

D

Jupiter m

 

10

7 s s

10

5 km

10

13 km

Giant Magellan Telescope (2016)

D

1

=8.5m, D eq

=24m

 

500 nm

Interferometry:

Arrays of telescopes

Two slits with a finite width

Interefere nce

Difraction factor : factor :

E

E

0

(

)

2 E

0

(

)

 cos

2 sin

E

0

2

,

 

,

  kd sin ka sin

2

I

4 I

0

{

 sin

2

}

2 cos

2

2

2

Diffraction grating max :

 

2

 m

 d sin

  m

E

0 t

E ot

NE

0

I ot

N 2 I

0

!

N-1 minima

With increase of N principal maxima becomes narrower and their amplitude grows as N

2

Grating spectroscopy

Spectrum of sunlight produced by a diffraction grating has dark absorption lines due to absorption of the corresponding wavelength by the solar atmosphere. It allows to find out a chemical composition of the solar atmosphere.

x-ray diffraction

~ 0 .

1

10 nm

Wilhelm Röntgen (1845 – 1923)

The 1 st Nobel Prize,1901

Bragg condition

2 d sin

  n

An x-ray scattering pattern of DNA recorded by

Rosalind Franklin led Watson and Crick to discovery of the DNA double helix structure

Louis de Broglie (1892 – 1987)

Electromagnetically induced transparency (EIT)

Two undistinguishable absorption passes for light result in cancellation of absorption (transparency ).

An electron has the wave property. It may be in a superposition of states 1 and 1’.

Monohromatic light with a frequency resonant either to one or another atomic transition is absorbed.

Bichromatic light containing two resonant frequencies goes through.

1

2

1’

1

O.K., Y.I.Khanin, JETP, 1986; O.K., P. Mandel, Phys. Rev. A. 1990. theory

S.E. Harris, PRL, 1991. experiment

Electromagnetically induced transparency (EIT)

2

1

1’

Two undistinguishable absorption passes for light result in cancellation of absorption (transparency).

An electron has the wave property. It may be in a superposition of states 1 and 1’.

A circular polarized light interacts only with 1-

2 (or 1’-2) state and absorbed. A linear polarized light interacts with both 1-2 and 12’ states and goes through the medium without absorption.

To make medium transparent for light with given circular polarization send through the medium simultaneously light with another circular polarization.

1

2

The same is true for two beams of different frequencies

1’

When the frequency difference coincides with the frequency of the atomic transition 1-

1’.

1

O.K., Y.I.Khanin, JETP, 1986; O.K., P. Mandel, Phys. Rev. A. 1990. theory

S.E. Harris, PRL, 1991. experiment

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