ASTR 2310: Chapter 3

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ASTR 2310: Chapter 3

Orbital Mechanics

Newton's Laws of Motion & Gravitation

(Derivation of Kepler's Laws)

Conic Sections and other details

General Form of Kepler's 3rd Law

Orbital Energy & Speed

Virial Theorem
ASTR 2310: Chapter 3

Newton's Laws of Motion & Gravitation

Three Laws of Motion (review I hope!)
–
Velocity remains constant without outside
force
–
F = ma (simplest version)
–
Every action has an equal and opposite
reaction
ASTR 2310: Chapter 3

Newton's Laws of Motion & Gravitation

Law of Gravitation (review I hope!)
–

F = G Mm/r2
Also Optics, Calculus, Alchemy and
Preservation of Virginity Projects
ASTR 2310: Chapter 3


Kepler's Laws can be derived from Newton
Takes Vector Calculus, Differential Eq.,
generally speaking, which is slightly beyond
our new prerequisites

Will use some related results.

If you have the math, please read

Will see a lot of this in Upper-Level
Mechanics
ASTR 2310: Chapter 3

Concept of Angular Momentum, L
–
Linear version: L = rmv
–
Vector version: L is the cross product of r and
p
–
Angular momentum is a conserved quantity
ASTR 2310: Chapter 3

Orbit Equations
–
R = L2/(GMm2(1+e cos theta))
–
Circle (e=0)
–
Ellipse (0 < e < 1)
–
Parabola (e =1)
–
Hyperbola (e > 1)
ASTR 2310: Chapter 3


Some terms
–
Open orbits
–
Closed orbits
Axes and eccentricity e
–
b2=a2(1-e2)
–
e=(1-b2/a2)1/2
–
<r>=a (those brackets mean “average”)
ASTR 2310: Chapter 3

Special velocities
–
Perhelion velocities
•
–
(GM/a((1+e)/(1-e)))1/2
Aphelion velocity
•
(GM/a((1-e)/(1+e)))1/2
ASTR 2310: Chapter 3

General form of Kepler's third law

P2 = 4 pi2 a3/G(M+m)

M = 4 pi2 a3/GP2

Solar mass = 1.93 x 1030 kg
ASTR 2310: Chapter 3

Orbital Energetics
–
E = K + U = (½) mv2 – GMm/r
–
More steps...vectors
–
E = (GMm/L)2(m/2)(e2-1)
–
e = (1 + (2EL2/G2M2m3))1/2
•
•
Cases of e > 1 → hyperbolic
When e=1, parabolic
–
•
vesc(r) = (2GM/r)1/2
Then e < 1, elliptical
ASTR 2310: Chapter 3

Orbital Speed
–
Lots here, not that simple
–
Can write the “vis viva equation”
•
•
•
•
•
•
V2 = GM ( 2/r – 1/a)
Other forms possible
Can solve for angular speed with position
Concept of transfer orbits (e.g. Hohmann)
See example page 77 for Mars
Related concept of launch windows
ASTR 2310: Chapter 3

Virial Theorem
–
Again, unfortunately, advanced math
–
If you know vector calculus, check it out
–
Bound systems in equilibrium:
–
2<K> + <U> = 0
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