PH 401 Dr. Cecilia Vogel Review Prove the radial H-atom solution Spin evidence spin angular momentum Outline Spin spin angular momentum not really spinning simultaneous eigenstates and measurement Schrödinger's cat Spin Angular Momentum Spin is like other forms of angular momentum, in the sense that it acts like a magnet, affected by B-fields it contributes to the angular momentum, when determining conservation thereof. The eigenvalues of the magnitude of the vector are | S | s(s 1) for electron, s=1/2, so | S | 23 And the eigenvalues of the z-component are ms where ms ranges from –s to s in integer steps for electron, s=1/2, so ms =+½ “Spinning” is an imperfect model Spin is UNlike other forms of angular momentum, in the sense that nothing is physically spinning! For one thing, the electron is a point particle; how can a point spin? For another thing, assuming that there is a spin angle, fs leads to contradiction. Let’s begin by assuming that there is a physical angle of rotation, fs, corresponding to spin rotation in the same way that f corresponds to orbital angular momentum. Pf by contradiction If fs corresponds to spin rotation in the same way that f corresponds to orbital angular momentum, then g (fs ) eim f would hold true (like g (f ) eimf for orbital) s s OK, then what is the value of the function at f=0? e0=1 And what is the value of the function at f=2p? eim f ei ( )(2p ) eip 1 So, which is it? It’s the same point in space, but is the function 1 or -1? Wavefunction should be single-valued CONTRADICTION! Cross it out! s s 1 2 Spin Commutators Spin is like other forms of angular momentum, in one more way… it obeys the same type of commutation relations. [S x , S y ] iS z and similarly for cyclic permutations of x, y, z and [S 2 , Si ] 0 where i =x or y or z Spin Simultaneous Eigenstates Because [S 2 , Sz ] 0 there exists a complete set of simultaneous eigenstates of S2 and Sz, with quantum numbers s and ms. Because [S x , S y ] iS z (and similarly for cyclic permutations of x, y, z) there are NO simultaneous eigenstates of two different components of spin of electron If electron is in an eigenstate of Sz (ms=+1/2, for ex) then Sz is certain, but Sx and Sy are uncertain! Simultaneous Eigenstates Revisited Recall there exists a complete set of simultaneous eigenstates of two operators, only if they commute [Si , S j ] 0 and[Li , Lj ] 0 if i j so there is not a complete set of simultaneous eigenstates of different components of spin OR orbital angular momentum But, just because there is not a complete set, does not mean there are none. Simultaneous Eigenstates Revisited Recall there exists a simultaneous eigenstate, |ab> of two operators, A and B, if [ A, B] | ab 0 Is that possible for two components of spin? suppose [Sx , S y ] | ab 0 using the commutation relation, this means iS z | ab 0 which means |ab> is an eigenstate of Sz, with eigenvalue zero For electron, Sz has eigenvalues +½ only. CONTRADICTION again Simultaneous Eigenstates Revisited Recall there exists a simultaneous eigenstate, |ab> of two operators, A and B, if [ A, B] | ab 0 Is that possible for two components of orbital angular momentum? suppose [Lx , Ly ] | ab 0 using the commutation relation, this means iLz | ab 0 which means |ab> is an eigenstate of Lz, with eigenvalue zero That’s cool. Just means that the state is one with mℓ=0 Simultaneous Eigenstate of Ang Mom components In the previous slide, we showed that a simultaneous eigenstate of Lx and Ly could exist so long as it was also an eigenstate of Lz with Lz=0 That means it’s a simultaneous eigenstate of Lz and Lx (and Ly) thus [Lx (and Ly ), Lz ] | ab 0 which means iLy (and iLx ) | ab 0 which means |ab> is an eigenstate of Lx, Ly, and Lz, ALL with eigenvalue zero That’s cool. Then L2=0 Just means that the state is one with ℓ=mℓ=0 Simultaneous Eigenstates The punchline is there are NO simultaneous eigenstates of two different components of spin of electron but there are simultaneous eigenstates of two different components of orbital angular momentum of electron, and those are the states with ℓ=mℓ=0 Simultaneous Eigenstates & Measurement Suppose an electron is in a superposition state of spinup and spin-down it has an uncertain Sz Then we measure Sz and find Sz= - ½ now Sz is no longer uncertain the measurement collapsed the wavefunction into an eigenstate of what we were measuring. Since Sz is certain, Sx and Sy are uncertain but there is nothing to stop us from measuring Sx. What happens if we measure Sx and find +½ ? …. Simultaneous Eigenstates & Measurement We measured Sz and found Sz= - ½ Then we measured Sx and found Sx=+½ ? …. So our electron has Sz= - ½ and Sx =+½ ? NO – that would be a simultaneous eigenstate of Sx and Sz, which is impossible! When we measured Sx, we collapsed the wavefunction again it is not in the same state it was in it no longer has Sz = - ½ instead it has collapsed into an eigenstate of Sx If we measure Sz now, we have no idea what we’ll find! Review Schrödinger's Cat http://en.wikipedia.org/wiki/Schroedinger's_cat#The _thought_experiment