Class_Notes_Ch.2

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16.362 Signal and System I

• The representation of discrete-time signals in terms of impulse x [ 0 ]

[ n ]

 x [ 0 ] x [ 1 ]

[ n

1 ]

 x [ 1 ] x [ k ]

[ n

 k ]

 x [ k ] x [ n ]

 k



 x [ k ]

[ n

 k ]

Example u [ n ]

 k



 u [ k ]

[ n

 k ]

 k

 

0

[ n

 k ]

16.362 Signal and System I

• The representation of discrete-time signals in terms of impulse x [ n ]

 k



 x [ k ]

[ n

 k ]

[ n ] h [ n ] x [ n ]

 k



 x [ k ]

[ n

 k ] y [ n ]

 h [ n ] y [ n ]

 k



 x [ k ] h [ n

 k ]

 k

 h [ k ] x [ n

 k ] y [ n ]

 h [ n ]

 x [ n ] y [ n ]

 x [ n ]

 h [ n ]

Convolution

16.362 Signal and System I

• The representation of continuous-time signals in terms of impulse x ( t )

 



 x ( t ' )

( t

 t ' ) dt ' y ( t )

 



 x ( t ' ) h ( t

 t ' ) dt ' y ( t )

 h ( t )

 x ( t )

• Properties of LIT systems

Commutative property y ( t )

 h ( t )

 x ( t ) y ( t )

 x ( t )

 h ( t )

Distributive property y ( t )

 h

1

( t )

 h

1

( t )

 h

2 x ( t )

( t )

 x ( t ) h

2

( t )

 x ( t )

16.362 Signal and System I

• Properties of LIT systems

Associative property y ( t )

 h

1

 h

1

( t

( t

)

 h

1

( t

 h

2

)

)

 h

2 h

2

( t

( t

( t

)

)

)

 x

( t ) x ( t x ( t )

)

Causality h ( t )

0 , for t<0.

h [ n ]

0 , for n<0.

Stability

 h ( t ) dt

  n

 h [ n ]

 

16.362 Signal and System I

• The unit step response of an LTI system

[ n ] h [ n ] y [ n ] y [ n ]

 k





[ k ] h [ n

 k ] y [ n ]

 k



 h [ k ]

[ n

 k ]

 h [ n ] u [ n ] h [ n ] s [ n ] s [ n ]

 k



 h [ k ] u [ n

 k ]

 k

 n 

 h [ k ]

16.362 Signal and System I

• The unit step response of an LTI system u [ n ] h [ n ] s

1

[ n ] s

1

[ n ]

 k

 n 

 h [ k ] u [ n

1 ] h [ n ] s

2

[ n ] s

2

[ n ]

 k



 h [ k ] u [ n k n

1 

 h [ k ]

1

 k ] s

2

[ n ]

 k n

1 

 h [ k ]

 s

1

[ n

1 ] s

1

[ n ]

 s

1

[ n

1 ]

 h [ n ]

16.362 Signal and System I

• The unit step response of an LTI system

[ n ] h [ n ] h [ n ] u [ n ] h [ n ] s [ n ] s [ n ]

 s [ n

1 ]

 h [ n ]

16.362 Signal and System I

• Linear constant-coefficient difference equations x [ n ] + y [ n ] delay y [ n ]

1

2 y [ n

1 ]

 x [ n ]

1

2 y [ n ]

?

h [ n ]

?

h [ n ] y [ n ] depends on x[n]. We don’t know y[n] unless x[n] is given.

But h[n] doesn’t depend on x[n]. We should be able to obtain h[n] without x[n].

How?

• LTI system response properties, this chapter.

• Discrete Fourier transform, --- Ch. 5.

16.362 Signal and System I

• Linear constant-coefficient difference equations

[ n ]

+

1

2 h [ n ] h [ n ]

1

2 h [ n

1 ]

 

[ n ]

When n

1, h [ n ]

1

2 h [ n

1 ] h [ n ] delay y [ n ]

1

2 y [ n

1 ]

 x [ n ] h [ n ]

1

2 h [ n

1 ]

 

[ n ] h [ n ] h [ n

1 ]

1

2 h [ n ]

A

1

2 n h [ n ]

A

1

2 n u [ n ] Causality

16.362 Signal and System I

• Linear constant-coefficient difference equations

[ n ]

+ h [ n ] y [ n ]

1

2 y [ n

1 ]

 x [ n ] delay h [ n ]

1

2 h [ n

1 ]

 

[ n ] h [ n ]

1

2 h [ n ]

A

1

2 n u [ n ]

Determine A by initial condition:

When n = 0, h [ n ]

1

2 h [ n

1 ]

 

[ n ] h [ 0 ]

 

[ 0 ]

1 h [ 0 ]

A

1

2

0 u [ 0 ] A = 1

16.362 Signal and System I

• Linear constant-coefficient difference equations

[ n

1 ] h [ n ] delay y [ n ]

1

2 y [ n

1 ]

 x [ n ] h [ n ]

1

2 h [ n

1 ]

 

[ n ]

1

2 h [ n ] y [ n ]

?

+ h [ n ]

1

2 n u [ n ]

Two ways:

(1) Repeat the procedure

(2) y [ n ]

 x [ n ]

 h [ n ] y [ n ]

 

[ n

1 ]

 h [ n ]

 h [ n

1 ]

1

2 n

1 u [ n

1 ]

16.362 Signal and System I

• The unit step response of an LTI system, continuous time

( t ) h ( t ) y ( t ) y ( t )

 h ( t )

(

) h ( n

 

) d

 u ( t ) h ( t ) s ( t ) s ( t )

  

  h (

) u ( t

 

) d

 

 t

 h (

) d

 ds ( t )

 h ( t ) dt

x ( t )

16.362 Signal and System I

• Linear constant-coefficient difference equations

1

2

+ d dt y ( t ) y ( t )

 

1

2 dy dt

1

2 x ( t ) h ( t ) y ( t )

?

1

2 h ( t )

?

dy

2 y ( t )

 x ( t ) dt y ( t ) depends on x(t). We don’t know y(t) unless x(t) is given.

But h(t) doesn’t depend on x(t). We should be able to obtain h(t) without x(t).

How?

• LTI system response properties, this chapter.

• Continuous time Fourier transform.

16.362 Signal and System I

( t )

• Linear constant-coefficient difference equations

1

2

+ d dt y ( t ) y ( t )

 

1

2 dy dt

1

2 x ( t ) h ( t ) 

1

2 y ( t )

 

1

2 dy

 dt

1

2

( t )

When t>0, y ( t )

 

1

2 dy dt

Determine A by initial condition: y ( t )

 

1

2 dy dt

1

2

( t ) y ( t )

Ae

2 t h ( t )

Ae

2 t u ( t )

Causality

16.362 Signal and System I

• Linear constant-coefficient difference equations

( t )

1

2

+ y ( t ) y ( t )

 

1

2 dy dt

1

2 x ( t ) d dt h ( t ) 

1

2

Determine A by initial condition: y ( t )

 

1

2 dy

 dt

1

2

( t ) h ( t )

Ae

2 t u ( t )

Ae

2 t u ( t )

 

1

2

(

2 ) Ae

2 t u ( t )

(

1

2

) Ae

2 t

( t )

1

2

( t )

A = 1 h ( t )

 e

2 t u ( t )

16.362 Signal and System I

• Linear constant-coefficient difference equations x ( t )

Ke 3 t u ( t ) 1

2

+ y ( t ) d dt h ( t ) 

1

2 y ( t )

 

1

2 dy dt

1

2 x ( t ) h ( t )

 e

2 t u ( t ) y ( t )

 x ( t )

 h ( t )

 

 x (

) h ( t

 

) d

 

Ke

3

 u (

)[ e

2 ( t

 

) u ( t

 

)] d

  o t

Ke 3

[ e

2 ( t

 

) ] d

Ke

2 t

 o t e

5

 d

K

[ e 3 t

5

 e

2 t ] y ( t )

K

[ e

3 t

5

 e

2 t

] u ( t )

16.362 Signal and System I

• Singularity functions

Define: u

0

( t )

 

( t ) u

1

( t )

 d

( t ) dt u n

( t )

 d n

( t ) dt n u

1

( t )

 

 t

(

) d

  u ( t ) u

2

( t )

 u

1

( t )

 u

1

( t )

 

 u (

) u ( t

 

) d

 

 t

 u (

) d

 u

 n

( t )

 u ( t )

 u ( t )

   u ( t )

 

 t

 u

( n

1 )

(

) d

16.362 Signal and System I

• Singularity functions x ( t )

 u

0

( t )

 x ( t )

 

( t )

 x ( t ) x ( t )

 u

0

( t )

 x ( t ) x ( t )

 u

1

( t )

 

  u

1

(

) x ( t

 

) d

 x ( t

 

) du

0

(

)

 x ( t

  u

0

(

) u

0

)

(

) |

 

 

 dx ( t d ( t

)

) d

 u

0

(

) dx ( t

 

)

 dx

 u

0

( t ) dt

 dx dt x ( t )

 u

1

( t )

 dx ( t ) dt x ( t )

 u n

( t )

 d n x ( t ) dt n

16.362 Signal and System I

• Singularity functions x ( t )

 u

0

( t )

 x ( t ) u

1

( t )

 u

1

( t )

 du

1

( t )

 u

2

( t ) dt x ( t )

 u

1

( t )

 dx ( t ) dt x ( t )

 u n

( t )

 d n x ( t ) dt n u

1

( t )

 u

1

( t )

    u

1

( t )

 u k

( t ) k terms

16.362 Signal and System I

• Singularity functions x ( t )

 u

1

( t )

 

 x ( t )

 u ( t ) x (

) u ( t

 

) d

 

 t

 x (

) d

 x ( t )

 u

0

( t )

 x ( t ) x ( t )

 u

1

( t )

 

 t

 x (

) d

 x ( t )

 u n

( t )

 d n x ( t ) dt n u

2

( t )

 u ( t )

 u ( t ) x ( t )

 u

2

( t )

 x ( t )

 u ( t )

 u ( t )

 

 t

 x (

) d

  u ( t )

 t   

  x (

' ) d

' d

16.362 Signal and System I

• Singularity functions --- discrete time

Define: u

1

[ n ]

 

[ n ]

 

[ n

1 ] u k

[ n ]

 u k

1

[ n ]

 u k

1

[ n

1 ] x [ n ]

 u

1

[ n ]

 x [ n ]

 x [ n

 x [ n ]

1 ]

[ n ]

 x [ n ]

 

[ n

1 ] x [ n ]

 u

1

[ n ]

 x [ n ]

 x [ n

1 ] u

1

[ n ]

 u

1

[ n ]

 u

1

[ n ]

 u

1

[ n

1 ]

16.362 Signal and System I

• Singularity functions --- discrete time

Define: u

1

[ n ]

 u [ n ] u

2

[ n ]

 u

1

[ n ]

 u

1

[ n ]

 k

 u [ k ] u [ n

 k ]

 k

 n 

 u [ k ]

 n

1 x [ n ]

 u

1

[ n ]

 x [ n ]

 u [ n ]

 x [ k ] u [ n

 k ]

 n 

 x [ k ]

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