Bilinear Isotropic Hardening Behavior MAE 5700 Final Project Raghavendar Ranganathan Bradly Verdant Ranny Zhao • Problem Statement • Illustration of bilinear isotropic hardening plasticity with an example of an interference fit between a shaft and a bushing assembly • Plasticity Model • Yield criterion • Flow rule • Hardening rule • Governing Equations • Numerical Implementation • FE Results Overview 2 Elastic-Plastic Analysis Elastic Analysis Quarter model-Plane Stress- interference with an outer rigid body Elastic Plastic Behavior 3 True Stress vs. True Strain curve Material Curve Bilinear: Approximation of the more realistic multi-linear stress-strain relation 4 • Determines the stress levels at which yield will be initiated • Given by ππ =f({π}) • ππ ππ <ππ , =ππ , >ππ , ππππ π‘ππ ππππ¦ ππππ π‘ππ ππππππππ‘πππ πππ‘ πππ π ππππ • Written in general as F(π, π ππΏ ) = 0 where F = ππ -ππ • ππ = • π½2 = 3π½2 for isotropic hardening (von Mises stress) 1 6 π11 − π22 2 + π22 − π33 2 + π33 − π11 2 2 2 2 + πΎ12 + πΎ23 +πΎ31 • ππ is function of accumulated plastic strain • For Bilinear: ππ = ππ + β ∗ πππΏ Yield Criterion 5 πΉ π, π ππΏ = 0 πΉ= 3π½2 − ππ = 0 (isotropic hardening) Yield Surface 6 • • ππ ππ = π{ } ππ ππ Where { } indicates ππ ππΏ the direction of plastic straining, and π is the magnitude of plastic deformation • Occurs when ππ = ππ • Plastic potential (Q) – a scalar value function of stress tensor components and is similar to yield surface F • Associative rule: F = Q Flow Rule (plastic straining) 7 • Description of changing of yield surface with progressive yielding • Allows the yield surface to expand and change shape as the material is plastically loaded Plastic Yield Surface after Loading Elastic Initial Yield Surface Hardening Rule 8 Hardening Types 1. Isotropic Hardening ο³2 Subsequent Yield Surface 2. Kinematic Hardening Subsequent Yield Surface ο³2 Initial Yield Surface Initial Yield Surface ο³1 ο³1 9 • Yield criterion changes with hardening • Yield surface will expand such that ππ = ππ • The 2 values will converge until ππ can’t be outside of ππ anymore • During hardening, stresses should always lie on the yield surface • ππΉ = 0 • ππΉ = ππΉ π ππ ππ + ππΉ π ππππΏ ππ ππΏ = 0 Consistency Condition 10 • Strong form • π»π π π + π = 0 • Weak form • πππ π=1 Ω π»π π€ π π·πΈππΏ π»π π’ πΩ = πππ π π=1 Γ π€ π‘ πΓ + π = π· πΈππΏ π • π = π»π π’ = [B]d πππ π π=1 Ω π€ π πΩ • Matrix form • π€π πππ π π=1 πΏ { Ω • πΎ = • π = π π΅ π π·πΈππΏ π΅ πΩ πΏπ − π· πΈππΏ π΅ πΩ Ω π΅ Γ π π π‘ πΓ + Ω • Where π·πΈππΏ = π· − Γ π π π‘ πΓ − Ω π π π πΩ} = 0 π π π πΩ ππ ππ π π· π· ππ ππ ππ π ππ π· ππ ππ Governing Equations 11 Stress and strain states at load step ‘n’ at disposal The material yield from previous step is used as basis Load step ‘n+1’ with ΔπΉ load increment Compute ππ‘π from Δπ’ and ππ‘π from ππ‘π Trail Displacement Δπ’ || Updated Displacement Δπ’new If ππ < ππ : ππ ππππ π‘ππππ‘π¦ Compute ππ If ππ ≥ ππ βΆ ππππ π‘ππππ‘π¦ Compute π using NRI such that dF = 0 Compute restoring forces and Residual πF Δπ ππΏ = π{ } ππ Perform Newton Rapshon iterations for equilibrium by updating Δπ’ ππΏ ππππΏ = {ππ−1 } + ππ ππΏ Update stresses and strains π ππ = {π π‘π } + ππ ππΏ Proceed to next load step π = π· π ππ Implementation ππΏ ππ = π(π ) 12 Elastic-Plastic Analysis Elastic Analysis Geometry: Quarter model- OD = 10in; ID = 6in; Boundary-Rigid- OD=9.9in Material: E=30e6psi; π=0.3; ππ = 36300psi; πΈ π = 75000psi (tangent modulus) ANSYS RESULTS- Von Mises Stress 13 Elastic-Plastic Analysis Elastic Analysis ANSYS Results- Radial Stress (X-Plot) 14 Elastic-Plastic Analysis Elastic Analysis ANSYS Results- Hoop Stress (Y-Plot) 15 Elastic-Plastic Elastic-Plastic Analysis Analysis Elastic Elastic Analysis Analysis ANSYS Results- Deformation 16 • Question? Thank You 17