Add a slide just before efficiency that explains why Qlow exhaust is necessary Ch15 Thermodynamics Zeroth Law of Thermodynamics If two systems are in thermal equilibrium with a third system, then they are in thermal equilibrium with each other. First Law of Thermodynamics The Internal Energy of a closed system will be equal to the energy added to the system by heating minus the work done by the system to its surrounding Second Law of Thermodynamics Heat flows out from hot objects to cold; heat does NOT flow from cold to hot Thermal Energy • Thermal Energy: The total internal Energy • Internal Energy: The sum of the kinetic and potential energies of the internal motion of particles that make up an object. Internal Energy • The sum of all the energy of all the molecules in an object (thermal energy) • Internal Energy of an Ideal Gas Brass Brass KEavg kT 3 2 U 32 NKT 32 nRT Ch15 Thermodynamics • Heat – Transfer of energy due to ΔT • Work – Transfer of energy NOT due to ΔT • Q – Heat • W – Work – W done on the system is negative (Giancoli) – W done by the system is positive (AP WS) • ΔU – Change in energy Ch15 Thermodynamics First Law of Thermodynamics U Q W Heat added is Heat lost is Work on system is Work by system is + – + Ch15 Thermodynamics The distinction between work done on the gas and work done by the gas is one your equation sheet and book define differently The area under the P-V curve will always be the work done by the gas during the process First Law of Thermodynamics 2500J of heat is added to a system, and 1800J of work is done on the system. What is the changed in internal energy of the system? (Q) 2500J of heat will increase the Internal Energy (W) 1800J of work done ON the system will … U Q W Is the work positive or negative? Why? U 2500 J (1800 J ) U 4300 J Did the temperature increase or decrease? Ch15 Thermodynamics • Isothermal process: Constant temperature – The system is in contact with a heat reservoir Isothermal – Change of phase 4 Pressure U 32 nRT 0 U Q W Q W 5 3 2 1 0 0 1 2 3 Volume • The work done by the gas in an isothermal process equals the heat added to the gas 4 5 Isothermal process: Constant temperature, i.e. PV is constant Isothermal Which Isothermal process is at a higher Temperature? 5 Which Isothermal process does more work? Pressure 4 3 2 1 0 0 1 2 3 Volume 4 5 Adiabatic • Adiabatic Process: No heat in or out of the system – Well insulated (like a thermos) – The process happens very quickly (firing of a car cylinder) Adiabatic Isothermal 9 8 7 Pressure U Q W U W 10 6 5 4 3 2 1 0 0 1 2 3 4 5 Volume 6 7 8 9 10 Work Given the following two processes: Isothermal and Adiabatic. Both processes start at 10Pa and end with a volume of 10m3 During which process is more work done? Estimate the work done in each process. W PV Adiabatic Isothermal PV 5.5Pa(10m 3m ) PV 38.5 J 3 3 9 8 7 Pressure PV 6.5Pa(10m3 3m3 ) PV 45.5 J 10 6 5 4 3 2 1 0 0 1 2 3 4 5 Volume 6 7 8 9 10 Isovolumetric • Isovolumetric: (Isochoric) No change in volume – Inside a ridged container Isovolumetric 10 W PV 9 W P(0) 6 W 0 8 Pressure 7 5 4 3 2 1 0 0 1 2 3 4 5 Volume 6 7 8 9 10 Isobaric • Isobaric: No change in pressure – Movable piston W PV Isobaric 10 9 8 Pressure 7 6 5 4 3 2 1 0 0 1 2 3 4 5 Volume 6 7 8 9 10 Internal Energy ΔU U 32 nRT PV nRT U 32 PV U 32 400Pa(60m3 ) Pressure (Pa) • 1 mole of an ideal gas is brought from point a to point c by 3 different process paths. Which path has the highest change in internal energy? • 1) Uabc • 2) Uadc 400 b • 3) U ac 300 • 4) All the same • 5) Unknown c 200 100 d a 10 20 30 Volume (m3) 40 50 60 Work (W) W PV Wabc 400(50) Wadc 100(50) Wac 250(50) Pressure (Pa) • 1 mole of an ideal gas is brought from point a to point c by 3 different process paths. During which path did the gas do the most work? • 1) Wabc • 2) Wadc 400 b • 3) Wac 300 • 4) All the same • 5) Unknown c 200 100 d a 10 20 30 Volume (m3) 40 50 60 Heat (Q) U Q W Q U W Qabc U 400(50) Qadc U 100(50) Qac U 250(50) Pressure (Pa) • 1 mole of an ideal gas is brought from point a to point c by 3 different process paths. During which path was the most heat added? • 1) Qabc • 2) Qadc 400 b • 3) Qac 300 • 4) All the same • 5) Unknown c 200 100 d a 10 20 30 Volume (m3) 40 50 60 • One mole of monatomic ideal gas is enclosed under a frictionless piston. A series of processes occur, and eventually the state of the gas returns to its initial state with a P-V diagram as shown below. Answer the following in terms of P0, V0, and R. • Find the temperature at each vertex. PV o o nRTA PV TA o o nR 4 PV TB o o nR • Find the change in internal energy for each process. U nRT 3 2 U A B 32 nR ( 4 PoVo PoVo ) nR nR • Find the work done by the gas for each process. WAB PVAB Po (4Vo V0 ) • a) b) Calculate the total work done by the gas Calculate the total heat flow into the gas Pressure Pa • An ideal gas is slowly compress at constant pressure (2.0 ATM) from 10.0L to 2.0L Heat is then added to the gas holding the volume constant and the pressure and temperate are allowed to rise until the temperature reaches its original value. 2 Volume m3 10 In an engine 0.25 moles of an ideal gas in the cylinder expands rapidly against the piston. In this process, the temperature of the gas drops from 1150K to 400K. a)What type of process is this? b) How much work does the gas do? U Q W U W 3 U nRT 2 U 32 (0.25moles)(8.314 molJ K (400K 1150K ) 2300J Is the work done by the gas positive or negative? W 2300 J Efficiency • Efficiency (e): the ratio of work W done by the system to the input heat QH W e QH W e QH QH W QL QH QL QH QL 1 QH TL 1 TH An automobile engine has an efficiency of 20% and produces an average of 23,000J of mechanical work per second. a) How much input heat is required? b) How much heat is discharged as wasted per second? b) a) W e QH QL 1 e QH W QH e QL (1 e)QH .8(115kJ ) 23, 000 J QH 0.20 QH 1.15x105 J QL 92kJ When a gas is taken from a to c along the curved path shown, the work done by the gas is W = -35 J and the heat added to the gas is Q = -62 J. Along path abc, the work done is W = -51J. a) What is Q for path abc? b) If Pc = 1/2 Pb, what is W for path cda? c) What is Q for path cda? d) What is Ua - Uc? e) If Ud - Uc = 4 J, what is Q for path da? When a gas is taken from a to c along the curved path in shown, the work done by the gas is W = -35 J and the heat added to the gas is Q = -62 J. Along path abc, the work done is W = -51J. a) What is Q for path abc? b) If Pc = 1/2 Pb, what is W for path cda? c) What is Q for path cda? d) What is Ua - Uc? e) If Ud - Uc = 4 J, what is Q for path da? -78J 25.5J 52.5J 27J 23J • Is the car’s efficiency higher or lower as the car warms up?