Sequences and Series Arithmetic π1 = first term ππ = ππ−1 + π ππ = π1 + (π − 1) ⋅ π π ππ = (π1 + ππ ) 2 … , π, π, π, … π+π π= 2 Where do I belong? π) πΏππ π‘ π‘πππ #π,(1 π π 1 … , π, π, … π − π … , π, π, π, … π−1 π = first term 1 (π = first term 11 ππππππ π + −π1) π= = π ⋅ π π = = (π + )⋅ π 1 π 1 1 π = π + π π πΉππππ’ππ π= = ππ 2=ππ± 1π−1 − π+ πππππΈπ₯ππππππ‘ ⋅ πππ 1 π= π−1− πΉπππ π‘ π‘πππ # 2 π΄πππ‘βπππ‘ππ = πΏπππππ πΊπππππ‘πππ = πΈπ₯ππππππ‘πππ πππ‘ππ πππππ = πππ π‘ − ππππ π‘ + 1 Pg. 607 #1-32 Geometric π1 = first term ππ = ππ−1 ⋅ π ππ = π1 ⋅ π π−1 π1 (1 − π π ) ππ = 1−π π1 π= 1−π … , π, π, π, … π = ± ππ Sequence and Series Describe Arithmetic Geometric Summation Modeling 10 10 10 10 10 20 20 20 20 20 30 30 30 30 30 40 40 40 40 40 50 50 50 50 50 Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 2, 8, 14, 20, 26 Answer Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 2, 8, 14, 20, 26 Finite Arithmetic Sequence Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 2, 8, 32, 128, … Answer Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 2, 8, 32, 128, … Infinite Geometric Sequence Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 1 + 5 + 9 + βββ Answer Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 1 + 5 + 9 + βββ Infinite Arithmetic Series Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 16 + 8 + 4 + 2 + 1 Answer Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite 16 + 8 + 4 + 2 + 1 Finite Geometric Series Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite ∞ 3(0.25)π π=1 Answer Describe each using: Sequence/Series; Arithmetic/Geometric; Finite/Infinite ∞ 3(0.25)π π=1 Infinite Geometric Series Write in summation notation −31, −28, −25, −22, . . . , 2 Answer Write in summation notation −31, −28, −25, −22, . . . , 2 ππ = π1 + π − 1 ⋅ π 2 = −31 + π − 1 ⋅ 3 2 = −31 + 3π − 3 2 = −34 + 3π 36 = 3π 12 = π 12 −31 + (π − 1) ⋅ 3 π=1 Or 12 3π − 34 π=1 Write a recursive definition, explicit formula and find the 15 term for the sequence: 12, 21, 30, 39, . . . Answer Write a recursive definition, explicit formula and find the 15 term for the sequence: 12, 21, 30, 39, . . . Recursive: π1 = 12; ππ = ππ−1 + 9 Explicit: ππ = 12 + (π − 1) ⋅ 9 π15 = 12 + 15 − 1 ⋅ 9 = 138 Write a recursive definition, explicit formula and find the 18 term for the sequence: 45, 37, 29, 21, . . . Answer Write a recursive definition, explicit formula and find the 18 term for the sequence: 45, 37, 29, 21, . . . Recursive: π1 = 45; ππ = ππ−1 − 8 Explicit: ππ = 45 + (π − 1) ⋅ (−8) π18 = 45 + 18 − 1 ⋅ −8 = −91 Find the missing term of the arithmetic sequence … , −1, , 11, . . . Answer Find the missing term of the arithmetic sequence … , −1, , 11, . . . −1 + 11 = =5 2 Find the missing terms of the arithmetic sequence … , −13, , , Answer , 3, . . . Find the missing terms of the arithmetic sequence … , −13, −9, −5, , ,−1, , 3, . . . −13 + 3 = = −5 2 −13 + (−5) = = −9 2 = −5 + 4 = −1 Write in summation notation 5, 10, 20, 40, … , 640 Answer Write in summation notation 5, 10, 20, 40, … , 640 ππ = π1 ⋅ π π−1 640 = 5 ⋅ 2π−1 128 = 2π−1 π − 1 = log 2 128 π−1=7 π=8 8 5 ⋅ 2π−1 π=1 Write a recursive definition, explicit formula and find the 10 term for the sequence: −3, 6, −12, 24, . . . Answer Write a recursive definition, explicit formula and find the 10 term for the sequence: −3, 6, −12, 24, . . . Recursive: π1 = −3; ππ = ππ−1 ⋅ −2 Explicit: ππ = (−3) ⋅ (−2)π−1 π10 = (−3) ⋅ (−2)10−1 = 1536 Write a recursive definition, explicit formula and find the 9 term for the sequence: −2, −10, −50, −250, . . . Answer Write a recursive definition, explicit formula and find the 9 term for the sequence: −2, −10, −50, −250, . . . Recursive: π1 = −2; ππ = ππ−1 ⋅ 5 Explicit: ππ = (−2) ⋅ (5)π−1 π9 = −2 ⋅ 5 9−1 = −781250 Find the missing term of the geometric sequence … , 3, , 12, . . . Answer Find the missing term of the geometric sequence … , 3, , 12, . . . = ± 12 ⋅ 3 = ±6 Find the missing terms of the geometric sequence … , −20, , , Answer , −1.25, . . . Find the missing terms of the geometric sequence … , −20, ±10,, −5, ±2.5, , , −1.25, . . . = ± −20 ⋅ −1.25 = ±5 = ± −20 ⋅ −5 = ±10 1 = −5 ⋅ ± = ±2.5 2 Evaluate the sum of each series 5 + 11 + 17 + β― + 35 Answer Evaluate the sum of each series 5 + 11 + 17 + β― + 35 ππ = π1 + (π − 1) ⋅ π 35 = 5 + π − 1 ⋅ 6 35 = 5 + 6π − 6 35 = 6π − 1 36 = 6π 6=π π ππ = (π1 + ππ ) 2 6 π6 = (5 + 35) = 120 2 Evaluate the sum of each series 4 + 16 + 64 + β― + 4096 Answer Evaluate the sum of each series 4 + 16 + 64 + β― + 4096 ππ = π1 ⋅ π π−1 4096 = 4 ⋅ 4π−1 1024 = 4π−1 π − 1 = log 4 1024 π−1=5 π=6 π1 (1 − π π ) ππ = 1−π 4(1 − 46 ) π6 = = 5460 1−4 Evaluate the sum of each series 15 7π − 5 π=4 Answer Evaluate the sum of each series 15 7π − 5 π=4 π4 = 7 4 − 5 = 23 π15 = 7 15 − 5 = 100 π ππ = (π1 + ππ ) 2 π12 12 = (23 + 100) = 738 2 Evaluate the sum of each series 7 4(5)π−1 π=1 Answer Evaluate the sum of each series 7 4(5)π−1 π=1 π1 = 4(5)1−1 = 4 π1 (1 − π π ) ππ = 1−π 4(1 − 57 ) π6 = = 78124 1−5 Evaluate the sum of each series 3 3π2 π=1 Answer Evaluate the sum of each series 3 3π2 π=1 π1 = 3(1)2 = 3 π2 = 3(2)2 = 12 + π3 = 3(3)2 = 27 42 The number of toy rockets made by an assembly line for 8 hours forms an arithmetic sequence. If the line produced 40 rockets in hour one and 43 rockets in hour two, how many rockets will be produced in hour seven? How many rockets will be produced in one 8 hour day? Answer The number of toy rockets made by an assembly line for 8 hours forms an arithmetic sequence. If the line produced 40 rockets in hour one and 43 rockets in hour two, how many rockets will be produced in hour seven? How many rockets will be produced in one 8 hour day? ππ = π1 + (π − 1) ⋅ π ππ = 40 + π − 1 ⋅ 3 π7 = 40 + 7 − 1 ⋅ 3 = 58 π ππ = (π1 + ππ ) 2 8 π8 = (40 + 61) = 404 2 You invested money in a fund and each month you receive a payment for your investment. Over the first four months, you received $50, $57, $64, $71. If this pattern continues, how much will you receive in the 12th month and who much will you receive for the entire year? Write an explicit equation to model the problem. Answer You invested money in a fund and each month you receive a payment for your investment. Over the first four months, you received $50, $57, $64, $71. If this pattern continues, how much will you receive in the 12th month and who much will you receive for the entire year? Write an explicit equation to model the problem. ππ = π1 + (π − 1) ⋅ π ππ = 50 + π − 1 ⋅ 7 π12 = 50 + 12 − 1 ⋅ 7 = 127 π ππ = (π1 + ππ ) 2 12 π8 = (50 + 127) 2 = 1062 You are trying to save $1500. You begin with $5 and save $3 more than the previous week for 30 weeks. Will you meet your goal? • Write an explicit formula to model this problem • What is the amount you will save in week 30? • What is the total amount you will save over 30 weeks? Answer You are trying to save $1500. You begin with $5 and save $3 more than the previous week for 30 weeks. Will you meet your goal? No • Write an explicit formula to model this problem • What is the amount you will save in week 30? • What is the total amount you will save over 30 weeks? ππ = π1 + (π − 1) ⋅ π π ππ = (π1 + ππ ) 2 ππ = 5 + π − 1 ⋅ 3 π30 = 5 + 30 − 1 ⋅ 3 = 92 π30 30 = (5 + 92) 2 = 1455 You saved $500 this year. Each year you plan to save 5% more than the previous year. Write an explicit formula to model this situation. How much will you save in the 8 year? How much will you have saved totally over years, assume you do not spend anything? Answer You saved $500 this year. Each year you plan to save 5% more than the previous year. Write an explicit formula to model this situation. How much will you save in the 8 year? How much will you have saved totally over years, assume you do not spend anything? π1 (1 − π π ) ππ = π−1 ππ = π1 ⋅ π ππ = 500 ⋅ (1.05)π−1 π8 = 500 ⋅ (1.05)8−1 = 703.55 1−π 500(1 − 1.058 ) π8 = 1 − 1.05 = 4774.55 You drop a ball from a staircase that is 36 feet high. By the time you get down the stairs to measure the height of the bounce, the ball has bounced four times and has a height of 2.25 feet after its fourth bounce. How high did the ball bounce after it first hit the floor? (hint the bouncing ball creates a geometric sequence) Answer You drop a ball from a staircase that is 36 feet high. By the time you get down the stairs to measure the height of the bounce, the ball has bounced four times and has a height of 2.25 feet after its fourth bounce. How high did the ball bounce after it first hit the floor? 18 36, 18, , 9, , , 2.25 = ± 36 ⋅ 2.25 = 9 = ± 36 ⋅ 9 = 18