Molecular Composition of Gases Chapter 11 Chemistry Chapter 11 1 Gay-Lussac’s law of combining volumes of gases • At constant temperature and pressure, the volumes of gaseous reactants and products can be expressed as ratios of small whole numbers Chemistry Chapter 11 2 Example • When 2 L of hydrogen react with 1 L of oxygen 2 L of water vapor are produced. • Write the balanced chemical equation: Chemistry Chapter 11 3 You try • When 1 L of hydrogen gas reacts with 1 L of chlorine gas, 2 L of hydrogen chloride gas are produced. • Write the balanced chemical equation: Chemistry Chapter 11 4 Avogadro's Law • Equal volumes of gases at the same pressure and temperature contain the same number of molecules • Atoms can’t split diatomic molecules • Gas volume is proportional to the number of molecules V kn Chemistry Chapter 11 5 Molar Volume • 1 mole of any gas contains 6.022 x 1023 molecules. • According to Avogadro’s law, 1 mole of any gas must have the same volume. • Standard molar volume: volume of 1 mole of any gas at STP • 22.4 L Chemistry Chapter 11 6 Example • You are planning an experiment that requires 0.0580 mol of nitrogen monoxide gas. What volume in liters is occupied by this gas at STP? • 1.30 L NO Chemistry Chapter 11 7 You try • A chemical reaction produces 2.56 L of oxygen gas at STP. How many moles of oxygen are in this sample? • 0.114 mol O2 Chemistry Chapter 11 8 Example • Suppose you need 4.22 g of chlorine gas. What volume at STP would you need to use? • 1.33 L Cl2 Chemistry Chapter 11 9 You try • What is the mass of 1.33 x 104 mL of oxygen gas at STP? • 19.0 g O2 Chemistry Chapter 11 10 Discuss • Explain Gay-Lussac’s law of combining volumes • State Avogadro’s law and explain its significance. Chemistry Chapter 11 11 Review • Boyles Law: 1 V P • Charles Law: V T • Avogadro’s Law: V n Chemistry Chapter 11 12 Math • A quantity that is proportional to each of several quantities is also proportional to their product. Therefore: 1 V T n P Chemistry Chapter 11 13 More math • Convert a proportionality yx • to an equality by multiplying by a constant y kx Chemistry Chapter 11 14 Therefore • We can covert • to 1 V T n P 1 V R T n P Chemistry Chapter 11 15 More neatly nRT V P or PV nRT Chemistry Chapter 11 16 This means…. • The volume of a gas varies directly with the number of moles and the temperature in Kelvin. • The volume varies indirectly with pressure. Chemistry Chapter 11 17 What if… • n and T are constant? • nRT is a constant, k PV k • Boyle’s Law • n and P are constant? • nR/P is a constant, k V kT • Charles’s Law Chemistry Chapter 11 18 What if… • P and T are constant? • RT/P is a constant, k V kn • Avogadro’s law Chemistry Chapter 11 19 The ideal gas constant •R • Value depends on units • SI units: J R 8.314 mol K Chemistry Chapter 11 20 Other units Chemistry Chapter 11 21 Solving ideal gas problems • Make sure the R you use matches the units you have. • Make sure all your units cancel out correctly. Chemistry Chapter 11 22 Example • A 2.07 L cylinder contains 2.88 mol of helium gas at 22 °C. What is the pressure in atmospheres of the gas in the cylinder? • 33.7 atm Chemistry Chapter 11 23 You try • A tank of hydrogen gas has a volume of 22.9 L and holds 14.0 mol of the gas at 12 °C. What is the reading on the pressure gauge in atmospheres? • 14.3 atm Chemistry Chapter 11 24 Example • A reaction yields 0.00856 mol of oxygen gas. What volume in mL will the gas occupy if it is collected at 43 °C and 0.926 atm pressure? • 240. mL Chemistry Chapter 11 25 You try • A researcher collects 9.09 x 10-3 mol of an unknown gas by water displacement at a temperature of 16 °C and 0.873 atm pressure (after the partial pressure of the water vapor has been subtracted). What volume of gas in mL does the researcher have? • 247 mL Chemistry Chapter 11 26 Finding mass • Number of moles (n) equals mass (m) divided by molar mass (M). PV nRT mRT PV M mRT M PV Chemistry Chapter 11 27 Example • What mass of ethene gas, C2H4, is contained in a 15.0 L tank that has a pressure of 4.40 atm at a temperature of 305 K? • 74.0 g Chemistry Chapter 11 28 You try • NH3 gas is pumped into the reservoir of a refrigeration unit at a pressure of 4.45 atm. The capacity of the reservoir is 19.4 L. The temperature is 24 °C. What is the mass of the gas in kg? • 6.03 x 10-2 kg Chemistry Chapter 11 29 Example • A chemist determines the mass of a sample of gas to be 3.17 g. Its volume is 942 mL at a temperature of 14 °C and a pressure of 1.09 atm. What is the molar mass of the gas? • 72.7 g/mol Chemistry Chapter 11 30 Density mRT M PV m D V DRT M P Chemistry Chapter 11 31 You try • The density of dry air at sea level (1 atm) is 1.225 g/L at 15 °C. What is the average molar mass of the air? • 29.0 g/mol Chemistry Chapter 11 32 Stoichiometry • Involves mass relationships between reactants and products in a chemical reaction • For gases, the coefficients in the balanced chemical equation show volume ratios as well as mole ratios • All volumes must be measured at the same temperature and pressure Chemistry Chapter 11 33 Volume-Volume calculations • From volume of one gas to volume of another gas • Use volume ratios just like mole ratios in chapter 9 Chemistry Chapter 11 34 Example • Xenon gas reacts with fluorine gas to produce the compound xenon hexafluoride, XeF6. Write the balanced equation for this reaction. • Xe(g) + 3F2(g) XeF6(g) • If a researcher needs 3.14 L of XeF6 for an experiment, what volumes of xenon and fluorine should be reacted? • 3.14 L of Xe and 9.42 L of F2 Chemistry Chapter 11 35 Example • Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water. 3NO2(g) + H2O(l) 2HNO3(l) + NO(g) • If 708 L of NO2 gas react with water, what volume of NO gas will be produced? • 236 L Chemistry Chapter 11 36 You try • What volume of hydrogen gas is needed to react completely with 4.55 L of oxygen gas to produce water vapor? • 9.10 L Chemistry Chapter 11 37 You try • At STP, what volume of oxygen gas is needed to react completely with 2.79 x 10-2 mol of carbon monoxide gas, CO, to form gaseous carbon dioxide? • 0.312 L Chemistry Chapter 11 38 You try • Fluorine gas reacts violently with water to produce hydrogen fluoride and ozone according to the following equation: 3F2(g) + 3H2O(l) 6HF(g) + O3(g) • What volumes of O3 and HF gas would be produced by the complete reaction of 3.60 x 104 mL of fluorine gas? • 1.20 x 104 mL O3 and 7.20 x 104 mL HF Chemistry Chapter 11 39 You try • Ammonia is oxidized to make nitrogen monoxide and water 4NH3(g) + 5O2(g) 4NO(g) + 6H2O(l) • At STP, what volume of oxygen will be used in a reaction of 125 mol of NH3? What volume of NO will be produced? • 3.50 x 103 L O2 and 2.80 x 103 L NO Chemistry Chapter 11 40 Volume-mass and mass-volume • Converting from volume to mass or from mass to volume • Must convert to moles in the middle • Ideal gas law may be useful for finding standard conditions Chemistry Chapter 11 41 Example • Aluminum granules are a component of some drain cleaners because they react with sodium hydroxide to release both heat and gas bubbles, which help clear the drain clog. The reaction is: 2NaOH(aq) + 2Al(s) + 6H2O (l) 2NaAl(OH)4(aq) + 3 H2(g) • What mass of aluminum would be needed to produce 4.00 L of hydrogen gas at STP? • 3.21 g Chemistry Chapter 11 42 Example • Air bags in cars are inflated by the sudden decomposition of sodium azide, NaN3 by the following reaction: 2NaN3(s) 3N2(g) + 2Na(s) • What volume of N2 gas, measured at 1.30 atm and 87 °C, would be produced by the reaction of 70.0 g of NaN3? • 36.6 L Chemistry Chapter 11 43 You try • What volume of chlorine gas at 38°C and 1.63 atm is needed to react completely with 10.4 g of sodium to form NaCl? • 3.54 L Cl2 Chemistry Chapter 11 44 Example • A sample of ethanol burns in O2 to form CO2 and H2O according to the following reaction. C2H5OH + 3O2 2CO2 + 3H2O • If the combustion uses 55.8 mL of oxygen measured at 2.26 atm and 40.°C, what volume of CO2 is produced when measured at STP? • 73.3 mL CO2 Chemistry Chapter 11 45 You try • Dinitrogen pentoxide decomposes into nitrogen dioxide and oxygen. If 5.00 L of N2O5 reacts at STP, what volume of NO2 is produced when measured at 64.5 °C and 1.76 atm? • 7.02 L NO2 Chemistry Chapter 11 46 Review • Diffusion: the gradual mixing of gases due to their random motion • Effusion: gases in a container randomly pass through a tiny opening in the container Chemistry Chapter 11 47 Rate of effusion • Depends on relative velocities of gas molecules. • Velocity varies inversely with mass • Lighter particles move faster Chemistry Chapter 11 48 Kinetic energy • Depends only on temperature • Equals 1 2 2 mv • For two gases, A and B, at the same temperature 1 1 2 2 M Av A M B vB 2 2 • Each M stands for molar mass Chemistry Chapter 11 49 Algebra time 1 1 2 2 M Av A M B vB 2 2 M AvA M BvB 2 2 2 vA MB 2 MA vB vA vB MB MA Chemistry Chapter 11 50 Rate of effusion • Depends on relative velocities of gas molecules. rateof effusion of A rateof effusion of B Chemistry Chapter 11 MB MA 51 Graham’s law of effusion • The rates of effusion of gases at the same temperature and pressure are inversely proportional to the square roots of their molar masses. Chemistry Chapter 11 52 Graham’s law • Graham experimented with densities of gases, not molar masses. • Density and molar mass are directly proportional • So we can replace molar mass with density in the equation densityB rateof effusion of A rateof effusion of B densityA Chemistry Chapter 11 53 Use of Graham’s law • Finding the molar mass • Compare rates of effusion of a gas with known molar mass and a gas with unknown molar mass • Use Graham’s law equation to solve for the unknown M • Used to separate isotopes of uranium Chemistry Chapter 11 54 Example • Compare the rates of effusion of hydrogen and helium at the same temperature and pressure. • Hydrogen diffuses about 1.41 times faster Chemistry Chapter 11 55 Example • Nitrogen effuses through a pinhole 1.7 times as fast as another gaseous element at the same conditions. Estimate the other element’s molar mass and determine its probable identity. • 81 g/mol, krypton Chemistry Chapter 11 56 You try • Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of carbon dioxide. • 17 g/mol Chemistry Chapter 11 57