Sawado - Conferences

advertisement
VORTEX SOLUTIONS IN THE EXTENDED
SKYRME FADDEEV MODEL
NOBUYUKI SAWADO
Tokyo University of Science, Japan
sawado@ph.noda.tus.ac.jp
In collaboration with
Luiz Agostinho Ferreira, Pawel Klimas (IFSC/USP)
Masahiro Hayasaka (TUS)
Juha Jäykkä (Nordita)
Kouichi Toda (TPU)
arXiv:0908.3672 , arXiv:1112.1085, arXiv:1209.6452, arXiv:1210.7523
19 December, 2012
At Miami 2012: A topical conference on elementary particles, astrophysics, and cosmology,
13-20 December, Fort Lauderdale, Florida
Objects of Yang-Mills theory
(i)
Gauge + Higgs composite models
Abelian vortex (in U(1))
Abrikosov vortex, graphene, cosmic string, Brane world, etc.
‘tHooft Polyakov monopole
GUT, Nucleon catalysis (Callan-Rubakov effect), etc.
(ii) Pure Yang-Mills theory
Instantons
In the Cho-Faddeev-Niemi-Shabanov decomposition
Monopole loop
N.Fukui,et.al.,PRD86(2012)065020,``Magnetic monopole loops generated
from two-instanton solutions: Jackiw-Nohl-Rebbi versus 't Hooft instanton”
Condensates in a dual superconductivity
Confinement
The Skyrme-Faddeev Hopfions, vortices
Glueball?, Abrikosov vortex?, Branes?
β„’ = 𝛼(πœ•πœ‡ 𝑛)2 +𝛽(πœ•πœ‡ 𝑛 × πœ•πœˆ 𝑛)2 +𝛾(πœ•πœ‡ 𝑛)4
Exotic structures of the vortex……
Semi-local strings
M.N.Chernodub and A..S. Nedelin,
PRD81,125022(2010)
``Pipelike current-carrying vortices
in two-component condensates’’
The Ginzburg-Landau equation
P.J.Pereira,L.F.Chibotaru, V.V.Moshchalkov,
PRB84,144504 (2011)
``Vortex matter in mesoscopic two-gap
superconductor square’’
Summary
We got the integrable and also the numerical solutions
of the vortices in the extended Skyrme Faddeev Model.
A special form of potential is introduced in order to
stabilize and to obtian the integrable vortex solutions.
We begin with the basic formulation.
Cho-Faddeev-Niemi-Shabanov (CFNS) decomposition
L.D. Faddeev, A.J. Niemi, Phy.Rev.Lett.82 (1999) 1624,
``Partially dual variables in SU(2) Yang-Mills theory”
3×4 ― 6 = 6
Degrees of freedom
electric
2
magnetic
2
remaining terms
1
The Gies lagrangian
1
6
``Magnetic symmetry’’
πœ•πœ‡ 𝑛 + π΄πœ‡ × π‘› = 0
H. Gies, Phys. Rev. D63, 125023 (2001),``Wilsonian effective
action for SU(2) Yang-Mills theory with Cho-Faddeev-Niemi
-Shabanov decomposition
t = ln k/L ∈ (−∞ , 0]
``renormalization group time’’
The integrability: the analytical vortex solutions
Lagrangian (in Minkowski space)
Sterographic project
Static hamiltonian
Positive definite for
The equation of the vortex
The vortex solution in the integrable sector
L.A.Ferreira, JHEP05(2009)001,``Exact vortex solutions in an extended Skyrme-Faddeev model”
O.Alvarez,LAF,et.al,PPB529(1998)689,``A new approach to integrable theories in any dimension”
The zero curvature condition
πœ•πœ‡ 𝑒 πœ•πœ‡ 𝑒 = 0
One gets the infinite number of conserved quantity
Additional constraint
𝛽𝑒 2 = 1
πœ• 2 𝑒 = 0 or
πœ•1 + π‘–πœ•2 𝑒
The equation becomes πœ•πœ‡ πœ•πœ‡ 𝑒 = 0
πœ•1 − π‘–πœ•2 𝑒 = − πœ•3 + πœ•0 𝑒 [ πœ•3 − πœ•0 𝑒]
πœ•πœ‡ π‘’πœ•πœ‡ 𝑒 = 0 or (πœ•1 +π‘–πœ•2 )(πœ•1 − π‘–πœ•2 )𝑒 = −(πœ•3 + πœ•0 )(πœ•3 − πœ•0 )𝑒
𝑒 = 𝑣 𝑧 𝑀 𝑦 = 𝑧 𝑛 𝑒 𝑖𝑦 𝑧 = π‘₯ 1 + π‘–πœ–1 π‘₯ 2 ,
𝑦 = π‘₯ 3 − πœ–2 π‘₯ 0
𝜌 𝑛 𝑖[πœ– π‘›πœ‘+π‘˜(π‘₯ 3+πœ– π‘₯0)]
2
Traveling wave vortex
=
𝑒 1
π‘Ž
Vortex solutions in 𝛽𝑒 2 ≠ 1
Ansatz
𝑒 𝒓, 𝑑 =
1 − 𝑔(𝑦) 𝑖(π‘›πœ‘+πœ†π‘§+π‘˜πœ)
𝑒
𝑔(𝑦)
π‘₯ πœ‡ = π‘Ÿ0 (𝜏, 𝜌 cos πœ‘, 𝜌 sin πœ‘ , 𝑧)
𝜌: =
1−𝑦
𝑦
(0≤ 𝑦 ≤ 1)
The equation
The solution has of the form:
𝑓 𝜌 =
𝜌 𝑛
π‘Ž
𝑔 𝑦 = π‘Ž2𝑛 𝑦 𝑛 /(π‘Ž2𝑛 𝑦 𝑛 + (1 − 𝑦)𝑛 )
We have no solutions for πœ·π’†πŸ ≠ 𝟏. 𝟎.
Derrick’s scaling argument
G.H.Derrick, J.Math.Phys.5,1252 (1964),
``Comments on nonlinear wave equations as
models for elementary particles’’
Consider a model of scalar field:
Scaling:
𝐸2
𝐸4
πœ‡=
𝑑𝑒(πœ‡)
π‘‘πœ‡
=0
πœ‡=
4
𝐸0
𝐸4
and 𝐸0 = 0
for 𝐷 = 3
for 𝐷 = 2
We need to introduce form of a potential to stabilize the solution.
The baby-skyrmion potential
𝑉𝛼
𝛽
πœ‡2
=
1 + 𝑛3
2
𝛼
(1 − 𝑛3 )𝛾 𝛼 ≥ 0 𝛾 > 0
Assume the zero curvature condition
𝜌
𝑒 𝜌, πœ‘, 𝑧, 𝑑 =
π‘Ž
Plug into the equation
it is written as
4𝑛3
𝜌
2
0 = 𝛽𝑒 − 1 4 1 +
π‘Ž
π‘Ž
2π‘Ÿ0 2 πœ‡2
𝜌
+
1
+
𝑀2
π‘Ž
𝑁=𝑛
𝑛
𝑒 𝑖[πœ–π‘›πœ‘+π‘˜(𝑧+𝜏)]
with the potential:
we assume 𝜢 = 𝟐 − 𝟐/𝑡, 𝜸 = 𝟐 + 𝟐/𝑡
2𝑛 −3
2𝑁 −3
𝑛−1
2
2+
𝑁
and
𝜌
π‘Ž
𝜌
π‘Ž
2𝑛−4
4𝑁−4
π‘Ž= 𝑛
4
𝜌
− (𝑛 + 1)
π‘Ž
2
− 2−
𝑁
𝜌
π‘Ž
𝑀2 (𝛽𝑒 2 −1)
π‘Ÿ0 2 πœ‡2
4𝑛−4
2𝑁−4
Analytical solutions for n = 1, 2
𝑔 𝑦 =
π‘Ž2𝑛 𝑦 𝑛
π‘Ž2𝑛 𝑦 𝑛 +(1−𝑦)𝑛
and
2 2
π‘Ÿ
πœ‡
0
𝑛 = 1, π‘˜ 2 = 0.0,
= 1.0
𝑀2
π‘Ž= 𝑛
4
𝑀2 (𝛽𝑒 2 − 1)
π‘Ÿ0 2 πœ‡2
π‘Ÿ0 2 πœ‡ 2
𝑛 = 2, π‘˜ = 0.0,
= 1.0
𝑀2
2
The energy of the static/traveling wave vortex
The static energy per unit of length of the vortex with 𝑛 = 1
πΈπ‘ π‘‘π‘Žπ‘‘π‘–π‘
4πœ‹ 1
2 − 1)
= 2πœ‹ +
(𝛽𝑒
3 π‘Ž2
The energy per unit length of the traveling wave vortex with 𝑛 ≥ 2
2πœ‹ 1
2 − 1 𝑛2 − 1 𝐼 𝑛
πΈπ‘€π‘Žπ‘£π‘’ = 2πœ‹π‘› +
𝛽𝑒
3 π‘Ž2
2πœ‹
2
2
+π‘˜ 2πœ‹π‘Ž 𝐼 𝑛 +
𝛽𝑒 2 − 1 𝑛
3
The infinite number of conserved current
𝛿𝐺
𝛿𝐺
π½πœ‡ ≔ ∗ π’¦πœ‡ −
π’¦πœ‡ ∗ π‘€β„Žπ‘’π‘Ÿπ‘’ 𝐺 ≔ 𝐺 𝑒
𝛿𝑒
𝛿𝑒
2
And the equation of motion is written as
πœ•πœ‡ π’¦πœ‡ − 2𝑒∗ 1 + 𝑒
2
2
πœ‡
πœ•π‘‰
πœ‡
2
2
π’¦πœ‡ πœ• 𝑒 = − (1 + |𝑒| )
4
πœ•π‘’ ∗
The zero curvature condition πœ•πœ‡ π‘’πœ•πœ‡ 𝑒 = 0
π’¦πœ‡ πœ•πœ‡ 𝑒 = 𝒦 ∗πœ‡ πœ•πœ‡ 𝑒∗ = 0,
𝒦 ∗πœ‡ πœ•πœ‡ 𝑒 = π’¦πœ‡ πœ•πœ‡ 𝑒∗
Thus the current is always conserved:
∡
πœ•πœ‡ π½πœ‡
𝛿 2𝐺 πœ‡
𝛿𝐺 πœ‡
𝛿 2𝐺 πœ‡ ∗
𝛿 2𝐺 πœ‡ ∗ ∗
=
πœ• π‘’π’¦πœ‡ +
πœ• π’¦πœ‡ + ∗ πœ• 𝑒 π’¦πœ‡ − ∗2 πœ• 𝑒 π’¦πœ‡
2
𝛿𝑒
𝛿𝑒
𝛿𝑒 𝛿𝑒
𝛿𝑒
2
𝛿𝐺 πœ‡ ∗
𝛿 𝐺 πœ‡
∗
− ∗ πœ• π’¦πœ‡ −
πœ•
𝑒𝒦
πœ‡
𝛿𝑒
𝛿𝑒𝛿𝑒∗
2
𝛿𝐺
πœ‡2
πœ•π‘‰
𝛿𝐺
πœ‡
=
− (1 + |𝑒|2 )2 ∗ − ∗ −
1+ 𝑒
𝛿𝑒
4
πœ•π‘’
𝛿𝑒
4
2 2
πœ•π‘‰
=0
πœ•π‘’
For 𝐺 ≔ −4𝑖/(1 + |𝑒|2 )
we get Noether current with 𝑒 ↦ 𝑒 𝑖𝛼 𝑒
∗ − 𝑒∗ πœ• 𝑒
𝜈 𝑒 ∗ )(πœ• 𝑒 ∗ 𝑒 − 𝑒 ∗ πœ• 𝑒)
π‘’πœ•
𝑒
2(πœ•
π‘’πœ•
8
πœ‡
πœ‡
𝜈
πœ‡
πœ‡
2
π½πœ‡ = −4𝑖𝑀2
−
𝑖
(𝛽𝑒
−
1)
1+ 𝑒 2 2
𝑒2
(1 + |𝑒|2 )4
The components:
𝐽𝜌 = 0
The transverse spatial structure
of the polar component π½πœ‘ and
the longitudinal component 𝐽𝑧
are a pipelike structure.
The charge per unit length:
𝑄=
𝑑π‘₯1 𝑑π‘₯2 𝐽0 = −8πœ‹π‘€2 π‘˜π‘Ž2 π‘Ÿ0
𝑛 1
1
1
1
2 − 1 + Γ(1 + )Γ(1 − )
𝛽𝑒
6 π‘Ž2
𝑛
𝑛
𝑛
Broken axisymmetry of the solution
The baby-skyrmion exhibits a non-axisymmetric solution depending on
a choice of potential
I.Hen et. al, Nonlinearity 21 (2008) 399
Old baby skyrmion
potential
𝑉 01
πœ‡2
= (1 − 𝑛3 )
2
New baby skyrmion
potential
𝑉11
πœ‡2
= (1 − 𝑛3 )(1 + 𝑛3 )
2
The energy density plot of 𝑛 = 3 for old-, and new-baby potentials
Symmetric:
Nonsymmetric:
𝑛 = 1 (old)
𝑛 ≥ 2 new
𝑛 ≥ 2 old
For the potential 𝑉
2
2−𝑛
2
2+𝑛
,
the holomorphic solutions
appear as a ground state!
A sequence of the energy density plots of 𝑛 = 3 for the several 𝛽𝑒 2 for
the old-potential
𝛽𝑒 2 = 1.01
𝛽𝑒 2 = 1.1
𝛽𝑒 2 = 2.0
𝛽𝑒 2 = 20.0
A repulsive force between the core of the vortices might appear
It might be similar with the force between the Abrikosov vortex.
Erick J.Weinberg, PRD19,3008 (1979),
``Multivortex solutions of the Ginzburg-Landau equations”
The vortex matter/lattice structure is observed.
Summary
We got the integrable and the numerical solutions of the vortices
in the extended Skyrme Faddeev Model.
A special form of potential is introduced in order to stabilize and to
obtain the integrable vortex solutions.
Our integrable solution thus carries an infinite number of
conserved quantity.
The model (~two gap model) hides a SU(2) structure even if it
describes the U(1) like observation such as SC.
Outlook
What it the origin of the potential?
How can I observe our solutions in Physics?
For SC, we may introduce an external magnetic field
πœ•πœ‡ → π·πœ‡ = πœ•πœ‡ + π΄πœ‡ 𝑛 ×.
and see the structure change for the field.
Geometrical patterns appear?
Lago Mar Resort, USA, 17 Dec.,2012
Thank you!
Tanzan Jinja shrine,Japan, 16 Nov.,2012
The Skyrme-Faddeev model
L.Faddeev, A.Niemi, Nature (London) 387, 58 (1997),
``Knots and particles’’
Lagrangian
Static hamiltonian
R.A.Battye, P.M.Sutcliffe,
Phys.Rev.Lett.81,4798(1998)
Positive definite for
Hopfions(closed vortex)
Coordinates:
L.A.Ferreira, NS, et.al., JHEP11(2009)124, ``Static Hopfions in the
extended Skyrme-Faddeev model”
Axially symmetric ansatz
Non-axisymmetric case:
D.Foster, arXiv:1210.0926
Boundary conditions
Hopf charge
Hopf charge density
(m, n) = (1, 1)
(1, 2)
(m, n) = (1, 3)
(m, n) = (1, 4)
(2, 1)
(3, 1)
(2, 2)
(4, 1)
Dimensionless energy, Integrability
corresponds to the
zero curvature condition
The solution is close to
the Integrable sector,
but not exact.
𝛽𝑒 2
Download