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```AIR NAVIGATION
Key Revision
Chapter 1
Distance, speed and time.
Distance, Speed & Time
Pilots must make regular
checks of their Estimated
Time of Arrival (ETA) at
destination as well as
estimated times for
passing waypoints enroute.
These are necessary for ATC reports, and vital for
ensuring sufficient fuel remains to reach the destination.
Regular checks of Estimated Time of Arrival
(ETA) are important. These calculations help
the crew to determine that:
a) The aircraft has sufficient
fuel to reach the destination.
b) The wind velocity will not
change.
c) They are flying the shortest
route.
d) The drift is correct.
Regular checks of Estimated Time of Arrival
(ETA) are important. These calculations help
the crew to determine that:
a) The aircraft has sufficient
fuel to reach the destination.
b) The wind velocity will not
change.
c) They are flying the shortest
route.
d) The drift is correct.
Aircrew are always aware of their Estimated
Time of Arrival (ETA). Why is this?
a) Fuel flow rate depends on
ETA.
b) It is the easiest calculation to
do.
c) It is important for fuel
calculations and air traffic
control purposes.
d) A revised ETA tells them the
wind has changed.
Aircrew are always aware of their Estimated
Time of Arrival (ETA). Why is this?
a) Fuel flow rate depends on
ETA.
b) It is the easiest calculation to
do. .
c) It is important for fuel
calculations and air traffic
control purposes.
d) A revised ETA tells them the
wind has changed.
Distance on the Earth
Distance on the earth’s
surface is measured in
Nautical Miles.
One Nautical Mile (nm) is the equivalent to one minute
of latitude, (one sixtieth of a degree).
Distance on the Earth
Degrees of latitude and
longitude are marked
with the symbol °.
Minutes of latitude and
longitude are marked
with the symbol ’.
Distance on the earth's surface is measured in
nautical miles (nm). Which of the following is
true?
a) One nm is equal to one
minute of latitude.
c) One nm is equal to 5280 feet.
b) One nm equals 1/10,000th of
the distance from the North Pole
to the Equator.
d) One nm is equal to one
minute of longitude.
Distance on the earth's surface is measured in
nautical miles (nm). Which of the following is
true?
a) One nm is equal to one
minute of latitude.
c) One nm is equal to 5280 feet.
b) One nm equals 1/10,000th of
the distance from the North Pole
to the Equator.
d) One nm is equal to one
minute of longitude.
One degree of latitude is equal to:
a) 360 nms
b) 60 nms
c) 60 kms
d) 1 nm
One degree of latitude is equal to:
a) 360 nms
b) 60 nms
c) 60 kms
d) 1 nm
One minute of latitude on the earth's surface is
equal to:
a) 1 nautical mile.
b) 60 nautical miles.
c) 1 knot.
d) 1 km.
One minute of latitude on the earth's surface is
equal to:
a) 1 nautical mile.
b) 60 nautical miles.
c) 1 knot.
d) 1 km.
Measuring Distance
Nautical maps do not have scales on the borders.
We use the scale shown along each meridian.
If dividers are used to measure distance, the degrees
and minutes scale on the nearest meridian should be
used to convert that distance into nautical miles.
The degrees and minutes on the parallels of latitude
should not be used for measuring purposes because
convergence towards the poles shrinks the scale.
Distances should
not be measured
using parallels
as they converge
towards the
poles.
Longitude
0º
Only at the
equator does
one degree of
longitude equal
60 nm.
45ºE
30ºE
15ºE
Distances measured
using scales along
the meridians will
be accurate.
75º N
60º N
Latitude
45º N
30º N
15º N
0º
The LATITUDE of a point is its distance
measured in degrees and minutes:
a) From the Greenwich (Prime)
Meridian.
b) From the true North Pole.
c) North or South of the
Equator.
d) From the true South Pole.
The LATITUDE of a point is its distance
measured in degrees and minutes:
a) From the Greenwich (Prime)
Meridian.
b) From the true North Pole.
c) North or South of the
Equator.
d) From the true South Pole.
The distance between two points on a navigation
chart can be measured with dividers. What
scale will then be used to convert that distance
to nautical miles?
a) The minute scale along a
meridian close to the area of
interest on the chart.
c) The minute scale along a
parallel of latitude.
b) 1:50,000 scale.
d) Any meridian scale off any
chart.
The distance between two points on a navigation
chart can be measured with dividers. What
scale will then be used to convert that distance
to nautical miles?
a) The minute scale along a
meridian close to the area of
interest on the chart.
c) The minute scale along a
parallel of latitude.
b) 1:50,000 scale.
d) Any meridian scale off any
chart.
Change of Latitude
Keil 54° 20’ N
54N
53N
52N
51N
50N
If two places are on the same
meridian, it is possible to
determine how far apart they
are by calculating the
differences in Latitude.
In this example Keil is due
north of Wartzburg.
Wartzburg 49° 48’ N
Change of Latitude
Keil 54° 20’ N
54N
53N
52N
51N
50N
Remembering that one minute
of latitude is one nautical mile,
we can see that Wartzburg is
just 12 nautical miles south
of the 50° line of latitude.
49° 48’ plus 12’ = 50° 00’.
Wartzburg 49° 48’ N
Change of Latitude
Keil 54° 20’ N
54N
53N
Each degree of latitude
between 50° North and 54°
North is a further 60 nautical
miles.
52N
51N
50N
4 times 60 = 240 nautical miles.
Wartzburg 49° 48’ N
Change of Latitude
Keil 54° 20’ N
54N
53N
52N
51N
50N
Finally, we can see that Keil is
another 20’ North of latitude
54° North.
So another 20 nautical miles
must be added to our total.
Wartzburg 49° 48’ N
Change of Latitude
20’
Keil 54° 20’ N
54N
12’ + 240’ + 20’ = 272’
53N
52N
240’
Keil is therefore 272 nautical
miles due north of Wartzburg.
51N
12’
50N
Wartzburg 49° 48’ N
In Germany, Kiel is due north of Wartzburg. If
Kiel's latitude is 54 20N and Wartzburg's is 49
48N how far are they apart?
a) 272 nm
b) 2720 nm
c) 27.2 nm
d) 227 nm
In Germany, Kiel is due north of Wartzburg. If
Kiel's latitude is 54 20N and Wartzburg's is 49
48N how far are they apart?
a) 272 nm
b) 2720 nm
c) 27.2 nm
d) 227 nm
Each degree is 60 nm each minute is 1 nm.
Wartzburg is 12 minutes South of 50N, Kiel 20 minutes
North of 54N.
50N to 54N is 4 degrees. Each degree is 60 nm.
4 x 60 + 12 + 20 = 272 nm.
Oslo airport (Norway) is due north of
Braunschweig airfield near Hanover
(Germany). If their latitudes are 59 53N and 52
20N respectively, how far are they apart?
a) 453 nm
b) 454 nm
c) 554 nm
d) 445 nm
Oslo airport (Norway) is due north of
Braunschweig airfield near Hanover
(Germany). If their latitudes are 59 53N and 52
20N respectively, how far are they apart?
a) 453 nm
b) 454 nm
c) 554 nm
d) 445 nm
52 20N to 59 53N is 7 degrees and 33 minutes.
Each degree is 60 nm, each minute is 1 nm.
7 degrees x 60 nm = 420nm, plus 33nm = 453nm.
Your destination airfield is situated due south of
your departure airfield. If the two latitudes are
63 25N and 57 58N, how far are they apart?
a) 327
b) 317
c) 323
d) 333
Your destination airfield is situated due south of
your departure airfield. If the two latitudes are
63 25N and 57 58N, how far are they apart?
a) 327
b) 317
c) 323
d) 333
Dundee is due north of Abergavenny. If their
latitudes are 56 27N and 51 50N, how far are
they apart?
a) 277 kms.
b) 323 kms.
c) 323 nms.
d) 277 nms.
Dundee is due north of Abergavenny. If their
latitudes are 56 27N and 51 50N, how far are
they apart?
a) 277 kms.
b) 323 kms.
c) 323 nms.
d) 277 nms.
Aircraft Speed
On land we measure distance in miles and speed in
miles per hour (mph).
In aviation we use nautical miles (nm) to measure
distances and speed is measured in nautical miles
per hour, known as knots and abbreviated ‘kts’.
Aircraft Speed
An aircraft measures speed through the air using
an instrument called an Air Speed Indicator (ASI).
The ASI compares the pressure caused by the aircraft’s
forward motion through the air (the ‘Pitot’ pressure)
with the pressure of the air surrounding the aircraft
(the ‘Static’ pressure).
The faster the aircraft flies, the greater is the difference
between these two pressures.
In aviation, speed is measured in:
a) kilometres per hour (km/hr).
b) miles per hour (mph).
c) knots (kts).
d) metres per hour (m/hr).
In aviation, speed is measured in:
a) kilometres per hour (km/hr).
b) miles per hour (mph).
c) knots (kts).
d) metres per hour (m/hr).
The Air Speed Indicator (ASI) calculates speed
by:
a) Measuring the pressure
difference between pitot and
static pressures.
c) Measuring the static pressure.
b) Measuring the pitot pressure.
d) Multiplying pitot pressure by
static pressure.
The Air Speed Indicator (ASI) calculates speed
by:
a) Measuring the pressure
difference between pitot and
static pressures.
c) Measuring the static pressure.
b) Measuring the pitot pressure.
d) Multiplying pitot pressure by
static pressure.
Calibrated Airspeed
The indicated airspeed (IAS) is corrected for
Pressure Error and Instrument Error to give a more
accurate airspeed – Calibrated Airspeed (CAS).
IAS + Pressure Error + Instrument Error = CAS
Pressure Error is caused by the airflow around the
aircraft. Carefully positioning the pitot and static tubes
can minimise, but not eliminate completely, this error.
Calibrated Air Speed (CAS) is:
a) Pitot pressure minus static
pressure.
c) Always less than IAS.
b) IAS after correction for
pressure error and instrument
error.
d) Always greater than IAS.
Calibrated Air Speed (CAS) is:
a) Pitot pressure minus static
pressure.
c) Always less than IAS.
b) IAS after correction for
pressure error and instrument
error.
d) Always greater than IAS.
Calibrated Air Speed (CAS) equals Indicated
Air Speed (IAS) plus corrections for:
a) Altitude error.
b) Pressure error.
c) Instrument error.
d) Pressure and instrument
error.
Calibrated Air Speed (CAS) equals Indicated
Air Speed (IAS) plus corrections for:
a) Altitude error.
b) Pressure error.
c) Instrument error.
d) Pressure and instrument
error.
True Airspeed
As an aircraft flies higher the air becomes less
dense, so the aircraft flies faster through the thinner
air to achieve the same force on the pitot tube.
To find the True Airspeed (TAS) at altitude the
Calibrated Airspeed must now be corrected for air
density changes caused by temperature and
altitude.
CAS + Density Error (temperature & altitude) = TAS
True Airspeed
To summarise:
IAS + Pressure & Instrument Error = CAS
CAS + Density Error (temperature & altitude) = TAS
True Airspeed
To summarise:
IAS + Pressure & Instrument Error = CAS
CAS + Density Error (temperature & altitude) = TAS
IPICDT
When Calibrated Airspeed (CAS) is corrected
for altitude and temperature, it becomes:
a) True Air Speed (TAS).
b) Indicated Airspeed (IAS).
c) Mach Number.
d) Indicated Groundspeed.
When Calibrated Airspeed (CAS) is corrected
for altitude and temperature, it becomes:
a) True Air Speed (TAS).
b) Indicated Airspeed (IAS).
c) Mach Number.
d) Indicated Groundspeed.
Calculation of Flight Time
If a car travels 120 miles at 60 mph, it will take 2
hours to complete the journey.
Distance (D)
Speed (S)
= Time (T)
120 miles
60 mph
= 2 hours
Calculation of Flight Time
Similarly, if we know the distance and time taken,
we can calculate the speed.
Distance (D)
Time (T)
= Speed (S)
120 miles
2 hours
= 60 mph
Calculation of Flight Time
If we know the speed of the vehicle and the time
the journey has taken, then we can calculate the
distance covered.
Speed (S) x Time (T) = Distance (D)
60 mph x 2 hours = 120 miles
Calculation of Flight Time
Aircraft normally fly at faster speeds and cover
greater distances, but the principle and the
mathematics remain the same.
Speed (S) x Time (T) = Distance (D)
600 kts x 2 hours = 1200 nm
How fast must an aircraft fly to cover 1200 nm
in 3 hours?
a) 400 kts
b) 800 kts
c) 400 mph
d) 3600 kts
How fast must an aircraft fly to cover 1200 nm
in 3 hours?
a) 400 kts
b) 800 kts
c) 400 mph
d) 3600 kts
1200 nm in 3 hours requires the aircraft to cover 400 nm each hour
(1200 / 3 = 400).
400 nm per hour = 400 knots.
A Hercules is flying at a groundspeed of 210 kts.
How far will it travel in 3 hours?
a) 630 nms.
b) 70 nms
c) 630 km.
d) 210 nms.
A Hercules is flying at a groundspeed of 210 kts.
How far will it travel in 3 hours?
a) 630 nms.
b) 70 nms
c) 630 km.
d) 210 nms.
3 hours @ 210 kts (nautical miles per hour) = 630 nautical miles.
A Tornado flies from its base to a target in 30
minutes. If the distance is 250 nms, what speed
is it flying at?
a) 125 kts.
b) 500 kts.
c) 750 kts..
d) 800 kts.
A Tornado flies from its base to a target in 30
minutes. If the distance is 250 nms, what speed
is it flying at?
a) 125 kts.
b) 500 kts.
c) 750 kts.
d) 800 kts.
250 nms in 30 minutes means the aircraft would cover 500 nms in
one hour, giving a speed of 500 kts.
A Nimrod flies on patrol for nine hours at a
speed of 300 kts. How far does it travel in this
time?
a) 2400 nms.
b) 2700 nms.
c) 3000 nms.
d) 3900 nms.
A Nimrod flies on patrol for nine hours at a
speed of 300 kts. How far does it travel in this
time?
a) 2400 nms.
b) 2700 nms.
c) 3000 nms.
d) 3900 nms.
A Hercules flies from A to B, a distance of 1000 nms
at a groundspeed of 250 kts. How long does the
flight take?
a) 3 hrs 20 mins.
b) 4 hrs.
c) 3 hrs 30 ins.
d) 5 hrs.
A Hercules flies from A to B, a distance of 1000 nms
at a groundspeed of 250 kts. How long does the
flight take?
a) 3 hrs 20 mins.
b) 4 hrs.
c) 3 hrs 30 mins.
d) 5 hrs.
Units of Time
All military and commercial aviators use the same
time.
This is known as either Greenwich Mean Time
(GMT) or Universal Time (UT).
Universal Time (UT) time is used as standard in
military and commercial aviation. By what
other name is it known?
a) British Summer Time (BST).
b) European Daylight Saving
Time (EDST).
c) Greenwich Mean Time
(GMT).
d) Local Time (LT) i.e. the time
of the country over which the
aircraft is flying.
Universal Time (UT) time is used as standard in
military and commercial aviation. By what
other name is it known?
a) British Summer Time (BST).
b) European Daylight Saving
Time (EDST).
c) Greenwich Mean Time
(GMT).
d) Local Time (LT) i.e. the time
of the country over which the
aircraft is flying.
GMT is also known as Z or ZULU time, eg 0800Z is 8 a.m. GMT, or
sometimes UTC, which stands for Universal Time Constant.
Chapter 2
The triangle.
contents list
exit
Vectors and Velocity
Whenever we talk about aircraft or wind movement,
we must always give both direction and speed of
that movement.
Direction and speed together are called a velocity.
A velocity can be represented on paper by a line
called a vector.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
The length of the line represents speed.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
The length of the line represents speed.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
The length of the line represents speed.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
The length of the line represents speed.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
The length of the line represents speed.
Vectors and Velocity
The bearing of the line represents the direction of
the movement.
The length of the line represents speed.
Vectors and Velocity
Imagine trying to sail a boat across a fast flowing
river.
A
Vectors and Velocity
This line with one arrow represents the velocity of
the boat (its speed and the direction it was pointed).
A
Vectors and Velocity
If a boat is pointed directly across a river, the flow
of the river will push the boat downstream.
A
B
Vectors and Velocity
The line with three arrows represents the speed and
direction of the current.
A
B
Vectors and Velocity
Although the boat started off pointing at ‘A’ it
finished up at ‘B’ because of this current.
A
B
Vectors and Velocity
Joining the ends of these two lines with a third line
completes the ‘vector triangle’.
A
B
Vectors and Velocity
This line, with two arrows, is the resultant and
represents the actual course of the boat.
A
B
The Air Triangle
A similar triangle can represent an aircraft’s
movement through air which is itself moving (wind).
track and
groundspeed
wind speed
and direction
Note that the wind vector describes the direction the
wind is blowing from – northerly in this example.
The Air Triangle
The angle between the heading and the track,
caused by the wind, is called drift.
drift
track and
groundspeed
wind speed
and direction
Velocity consists of:
a) Speed only.
b) Direction only.
c) Speed and direction together.
d) Several speed vectors
together.
Velocity consists of:
a) Speed only.
b) Direction only.
c) Speed and direction together.
d) Several speed vectors
together.
A vector is a representation on paper of:
a) Speed.
b) Time.
c) Direction.
d) Direction and speed.
A vector is a representation on paper of:
a) Speed.
b) Time.
c) Direction.
d) Direction and speed.
A vector is a line, drawn to represent a velocity.
This is achieved by:
a) The bearing represents knots
at all times.
c) The length represents mph at
all times.
b) The bearing represents speed
and the length represents
direction.
d) The bearing represents
direction and the length
represents speed.
A vector is a line, drawn to represent a velocity.
This is achieved by:
a) The bearing represents knots
at all times.
c) The length represents mph at
all times.
b) The bearing represents speed
and the length represents
direction.
d) The bearing represents
direction and the length
represents speed.
In the diagram, vector 2 is added to vector 1.
What is vector 3 (A-C) known as?
b) Current.
c) The resultant vector.
d) Drift.
B
1
2
A
C
3
In the diagram, vector 2 is added to vector 1.
What is vector 3 (A-C) known as?
b) Current.
c) The resultant vector.
d) Drift
B
1
2
A
C
3
In the triangle of velocities, DRIFT is:
a) The bearing of the wind
vector.
b) The angle between the wind
and track vectors.
and track vectors.
and wind vectors.
In the triangle of velocities, DRIFT is:
a) The bearing of the wind
vector.
b) The angle between the wind
and track vectors.
and track vectors.
and wind vectors.
In the air triangle, the heading vector includes 2
components. They are:
d) Heading and true air speed.
In the air triangle, the heading vector includes 2
components. They are:
d) Heading and true air speed.
In the air triangle, the track vector includes 2
components. They are:
a) Track and drift.
c) Track and groundspeed.
d) Track and true air speed.
In the air triangle, the track vector includes 2
components. They are:
a) Track and drift.
c) Track and groundspeed.
d) Track and true air speed.
In the air triangle, the wind vector includes 2
components. They are:
a) Wind speed and drift.
c) Wind speed and the direction
the wind is blowing from.
d) Wind speed and track.
In the air triangle, the wind vector includes 2
components. They are:
a) Wind speed and drift.
c) Wind speed and the direction
the wind is blowing from.
d) Wind speed and track.
In the Air Triangle shown below, name the
components of the 3rd side, represented by a
dotted line:
a) Wind velocity.
c) Drift and groundspeed.
d) Track and groundspeed.
In the Air Triangle shown below, name the
components of the 3rd side, represented by a
dotted line:
a) Wind velocity.
c) Drift and groundspeed.
d) Track and groundspeed.
In the Air Triangle shown below, name the
components of the 3rd side, represented by a
dotted line:
a) Wind direction and speed.
c) Drift and groundspeed.
d) Drift.
In the Air Triangle shown below, name the
components of the 3rd side, represented by a
dotted line:
a) Wind direction and speed.
c) Drift and groundspeed.
d) Drift.
Solving the Vector Triangle
As we have demonstrated, the vector triangle
consists of 6 elements:
• windspeed and direction
• track and groundspeed
Providing we know four of the elements of the
vector triangle (any four) it is possible to calculate
the other two.
The Air Triangle of velocities can be used to
calculate flight data. There are 6 elements in
total. How many elements are needed to
calculate those missing?
a) 2
b) 4
c) 5
d) 6
The Air Triangle of velocities can be used to
calculate flight data. There are 6 elements in
total. How many elements are needed to
calculate those missing?
a) 2
b) 4
c) 5
d) 6
Any of the four elements will enable the remaining two to be found.
Mental Calculations
Despite modern equipment, pilots must still make
quick, accurate calculations in their heads.
Every pilot should know the distance his aircraft will
cover in one minute for any given groundspeed.
For instance, a Tornado flying at 420 kts groundspeed
will cover 7 nm per minute. If the next turning point is
35 nm away, dividing 35 by 7 tells him he will be there
in 5 minutes.
Mental Calculations
The table on the next page shows how many
nautical miles per minute are covered at various
groundspeeds.
Ensure you know the examples in italics.
Mental Calculations
Groundspeed (kts)
nm/minute
60
1
120
2
180
3
240
4
300
5
360
6
420
7
480
8
540
9
You are flying at 120 kts groundspeed. How
long will it take to fly 20 nms?
a) 60 minutes.
b) 10 minutes.
c) 6 minutes.
d) 2 minutes.
You are flying at 120 kts groundspeed. How
long will it take to fly 20 nms?
a) 60 minutes.
b) 10 minutes.
c) 6 minutes.
d) 2 minutes.
120 kts is 120 nms per hour or 2 nms per minute.
To fly 20 nms at 2 nms per minute would take 10 minutes.
You are flying a Tornado at 420 kts
groundspeed. How many miles do you travel
each minute?
a) 42 nm
b) 8 nm
c) 7 nm
d) 6 nm
You are flying a Tornado at 420 kts
groundspeed. How many miles do you travel
each minute?
a) 42 nm
b) 8 nm
c) 7 nm
d) 6 nm
There are 60 minutes in each hour.
420 divided by 60 is 7 nm per minute.
You fly between 2 features on the ground and
you notice it takes 3 minutes. If the features are
18 nm apart, what is your groundspeed?
a) 54 kts
b) 180 kts
c) 280 kts
d) 360 kts
You fly between 2 features on the ground and
you notice it takes 3 minutes. If the features are
18 nm apart, what is your groundspeed?
a) 54 kts
b) 180 kts
c) 280 kts
d) 360 kts
3 minutes to cover 18 nm is 6 nm per minute.
Each hour is 60 minutes, you will cover 6 x 60 = 360 nm per hour.
Estimated Time of Arrival (ETA)
Pilots are constantly calculating and updating their
ETA’s, both for turning points and final destination.
ETA’s are important for both fuel and Air Traffic
Control purposes.
If an aircraft fails to arrive at its destination on
time, then ATC will initiate ‘overdue action’.
An aircraft departs from base, but does not
arrive at the destination on its Estimated Time
of Arrival (ETA). What action will Air Traffic
Control take?
a) No immediate action is
required.
b) Close down and go home.
c) Contact the departure base.
d) Initiate overdue action.
An aircraft departs from base, but does not
arrive at the destination on its Estimated Time
of Arrival (ETA). What action will Air Traffic
Control take?
a) No immediate action is
required.
b) Close down and go home.
c) Contact the departure base.
d) Initiate overdue action.
Chapter 3
The 1 in 60 rule.
contents list
exit
The 1 in 60 rule
A
Track Required
B
A line drawn on the map between departure and
destination (or from one turning point to another) is
known as the Track Required.
The 1 in 60 rule
A
Track Required
pinpoint
B
If the aircraft drifts off track, then the line from our
departure airfield to our present position is known as
An aircraft is flying from point A to point B.
Halfway a pinpoint fix shows it to be off track. A
line between point A and the fix would be
known as:
a) Drift.
b) Revised track.
d) Track required.
An aircraft is flying from point A to point B.
Halfway a pinpoint fix shows it to be off track. A
line between point A and the fix would be
known as:
a) Drift.
b) Revised track.
d) Track required.
The 1 in 60 rule
pinpoint
A
Track Error
Track Required
B
The angle between the Track Required and the Track
Made Good (the actual track of the aircraft) is called
the Track Error (TE).
The 1 in 60 rule
pinpoint
A
Track Error
Track Required
B
The 1 in 60 rule states ‘if an aircraft flies a Track Made
Good (TMG) one degree off the Track Required, after 60
miles of flying the aircraft will be one mile off track’.
The 1 in 60 rule
60 miles
A
T E = 10 degrees
Track Required
pinpoint
10 miles
B
Similarly, if an aircraft flies a Track Made Good
(TMG) ten degrees off the Track Required, after 60
miles of flying the aircraft will be ten miles off track.
The 1 in 60 rule
60 miles
A
T E = 10 degrees
Track Required
pinpoint
10 miles
B
The pilot now has the information he requires to get
the aircraft back on track.
The 1 in 60 rule
60 miles
A
T E = 10 degrees
Track Required
pinpoint
10 miles
The rule works for track errors up to 23 degrees.
B
The 1 in 60 rule
30 miles
A
TE
Track Required
pinpoint
4 miles
B
Where the aircraft has flown less than 60 miles the
triangle has to be extended to determine how far the
aircraft would be off track after 60 miles.
The 1 in 60 rule
30 miles
A
TE
Track Required
pinpoint
4 miles
B
In this example the aircraft is 4 miles off track after
just 30 miles. After 60 miles it would be 8 miles off
track giving a Track Error (TE) of 8 degrees.
The 1 in 60 rule
40 miles
A
TE
Track Required
pinpoint
6 miles
B
Here the aircraft is 6 miles off track after 40 miles.
After 60 miles therefore, it would be 9 miles off track
giving a Track Error (TE) of 9 degrees.
Using the 1 in 60 rule, calculate how many miles
off track an aircraft will be if it flies 60 nm with
a track error of 2 degrees.
a) 60 nms
b) 6 nms
c) 4 nms
d) 2 nms
Using the 1 in 60 rule, calculate how many miles
off track an aircraft will be if it flies 60 nm with
a track error of 2 degrees.
a) 60 nms
b) 6 nms
c) 4 nms
d) 2 nms
An aircraft flies a track made good, 3 degrees in
error from the required track. Using the 1 in 60
rule, how many miles off track will the aircraft
be after 60 miles of flying?
a) 2 nms
b) 6 nms
c) 1 nm
d) 3 nms
An aircraft flies a track made good, 3 degrees in
error from the required track. Using the 1 in 60
rule, how many miles off track will the aircraft
be after 60 miles of flying?
a) 2 nms
b) 6 nms
c) 1 nm
d) 3 nms
An aircraft is flying from A to B, after 20 nms it
is found to be 3 nms off track. What is the track
error?
a) 6 degrees.
b) 2 degrees.
c) 9 degrees.
d) 4 degrees.
An aircraft is flying from A to B, after 20 nms it
is found to be 3 nms off track. What is the track
error?
a) 6 degrees.
b) 2 degrees.
c) 9 degrees.
d) 4 degrees.
If the aircraft was 3 nms off track after 20 nms, projecting ahead it
would be 9 nms off track after 60 nms, therefore 9 degrees.
The 1 in 60 rule
120 miles
A
TE
Track Required
pinpoint
6 miles
B
Where the aircraft has flown more than 60 miles
before obtaining a pinpoint, you must determine how
far the aircraft was off track back at the 60 mile point.
The 1 in 60 rule
120 miles
A
TE
Track Required
pinpoint
6 miles
B
In this example the aircraft is 6 miles off track after
120 miles, so would have been 3 miles off track after
60 miles, a 3 degree Track Error.
The 1 in 60 rule
90 miles
A
TE
Track Required
pinpoint
6 miles
B
Here the aircraft is 6 miles off track after 90 miles, so
would have been 4 miles off track after 60 miles, that’s
a 4 degree Track Error.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
Once a pilot has determined his position and therefore
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
The aircraft is to the left of the Track Required, so
must turn to the right. If the Track Error is 8 degrees,
by how many degrees should he change heading?
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
TE
Track Required
B
If he turns by only eight degrees (the Track Error) the
pilot will only parallel the Track Required.
A further eight degrees (16 degrees in all) will put him
back on track after another 60 miles.
The 1 in 60 rule
60 miles
60 miles
pinpoint
A
Revised Track
Closing Angle
TE
B
Track Required
This new track is known as the Revised Track.
The angle between the Revised Track and the original
Track Required is the Closing Angle (CA).
An aircraft is flying from point A to point B. A
pinpoint fix shows it to be off track. A line from
the pinpoint fix to point B would be known as:
b) Track required.
c) Revised track.
An aircraft is flying from point A to point B. A
pinpoint fix shows it to be off track. A line from
the pinpoint fix to point B would be known as:
b) Track required.
c) Revised track.
An aircraft is flying from A to B, a distance of
120 nm. Halfway, a fix shows the aircraft to be 4
nm right of track. What heading change does
the pilot require to reach point B?
a) 8 degrees right
b) 8 degrees left
c) 4 degrees right
d) 4 degrees left
An aircraft is flying from A to B, a distance of
120 nm. Halfway, a fix shows the aircraft to be 4
nm right of track. What heading change does
the pilot require to reach point B?
a) 8 degrees right
b) 8 degrees left
c) 4 degrees rght
d) 4 degrees left
20 nm after takeoff for a pre-planned destination,
a pilot finds that he is 3 nm off track. By how
much does the pilot need to turn to regain the
intended track after flying a further 20 nm?
a) 18 degrees
b) 9 degrees
c) 6 degrees
d) 3 degrees
20 nm after takeoff for a pre-planned destination,
a pilot finds that he is 3 nm off track. By how
much does the pilot need to turn to regain the
intended track after flying a further 20 nm?
a) 18 degrees
b) 9 degrees
c) 6 degrees
d) 3 degrees
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
B
When the pinpoint is not exactly halfway along the
track, a little more thought is required.
Each triangle must be evaluated separately.
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
4nm
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
After 30 miles the aircraft is 4 miles off track. The
Track Error is therefore 8 degrees.
Turning eight degrees to the right will parallel the
Track Required.
B
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
4 nm
CA
Track Required
B
The pilot must turn further right to get onto the
Revised Track – but by how much?
He is paralleling the Track Required, so must continue to turn
through an angle equivalent to the Closing Angle (CA).
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
4 nm
CA
Track Required
B
As the aircraft was 4 miles off track, using the 1 in 60
rule gives a Closing Angle (CA) of 4 degrees.
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
4 nm
CA
Track Required
B
As the aircraft was 4 miles off track, using the 1 in 60
rule gives a Closing Angle (CA) of 4 degrees.
The pilot must turn 12 degrees in all, 8 degrees to parallel the
Track Required and 4 degrees to get onto the Revised Track.
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
B
As the aircraft was 4 miles off track, using the 1 in 60
rule gives a Closing Angle (CA) of 4 degrees.
The pilot must turn 12 degrees in all, 8 degrees to parallel the
Track Required and 4 degrees to get onto the Revised Track.
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
B
As the aircraft was 4 miles off track, using the 1 in 60
rule gives a Closing Angle (CA) of 4 degrees.
The pilot must turn 12 degrees in all, 8 degrees to parallel the
Track Required and 4 degrees to get onto the Revised Track.
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
B
As the aircraft was 4 miles off track, using the 1 in 60
rule gives a Closing Angle (CA) of 4 degrees.
The pilot must turn 12 degrees in all, 8 degrees to parallel the
Track Required and 4 degrees to get onto the Revised Track.
The 1 in 60 rule
30 miles
60 miles
pinpoint
TMG
A
Revised Track
CA
Track Required
B
As the aircraft was 4 miles off track, using the 1 in 60
rule gives a Closing Angle (CA) of 4 degrees.
The pilot must turn 12 degrees in all, 8 degrees to parallel the
Track Required and 4 degrees to get onto the Revised Track.
An aircraft flying from A to B finds itself 6 nms
off track. It has a further 60 nms to travel.
What is the required closing angle?
a) 10 degrees
b) 6 degrees
c) 3 degrees
d) 2 degrees
An aircraft flying from A to B finds itself 6 nms
off track. It has a further 60 nms to travel.
What is the required closing angle?
a) 10 degrees
b) 6 degrees
c) 3 degrees
d) 2 degrees
An aircraft flying from A to B finds itself 4 nms
off track. It has a further 60 nms to travel.
What is the required closing angle?
a) 6 degrees
b) 4 degrees
c) 3 degrees
d) 2 degrees
An aircraft flying from A to B finds itself 4 nms
off track. It has a further 60 nms to travel.
What is the required closing angle?
a) 6 degrees
b) 4 degrees
c) 3 degrees
d) 2 degrees
An aircraft flying from A to B is found to be off track at
the pinpoint shown below. The pilot calculates the track
error as 6 degrees and the closing angle of 3 degrees. By
how much does the pilot need to turn to reach point B?
a) 9 degrees to the left
b) 9 degrees to the right
c) 2 degrees to the left
d) 2 degrees to the right
fix
TE
A
CA
B
An aircraft flying from A to B is found to be off track at
the pinpoint shown below. The pilot calculates the track
error as 6 degrees and the closing angle of 3 degrees. By
how much does the pilot need to turn to reach point B?
a) 9 degrees to the left
b) 9 degrees to the right
c) 2 degrees to the left
d) 2 degrees to the right
fix
TE
A
CA
B
An aircraft flying from A to B is found to be off track at
the pinpoint shown below. The pilot calculates the track
error as 12 degrees and the closing angle of 8 degrees. By
how much does the pilot need to turn to reach point B?
a) 20 degrees to the right
b) 12 degrees to the right
c) 8 degrees to the right
d) 4 degrees to the right
fix
TE
A
CA
B
An aircraft flying from A to B is found to be off track at
the pinpoint shown below. The pilot calculates the track
error as 12 degrees and the closing angle of 8 degrees. By
how much does the pilot need to turn to reach point B?
a) 20 degrees to the right
b) 12 degrees to the right
c) 8 degrees to the right
d) 4 degrees to the right
fix
TE
A
CA
B
The 1 in 60 rule
40 miles
30 miles
pinpoint
A
TMG
TE
6m
Track Required
Revised Track
CA
B
Here is an example of the most complex problem you
will face in the examination.
After flying for 40 miles the aircraft is 6 miles off track. It has
a further 30 miles to travel. By how much does the pilot need
to turn to regain track at B?
The 1 in 60 rule
40 miles
20 miles
pinpoint
A
TMG
TE
6m
9 miles
Track Required
B
To solve this problem you must consider the two
triangles individually.
Extend the first triangle the full 60 miles to find out how far
you would be off track there – that’s the track error in degrees.
The 1 in 60 rule
40 miles
20 miles
pinpoint
A
TMG
TE
6m
Track Required
9 miles
B
After 60 miles you would be 9 miles off track. The Track
Error is therefore 9 degrees.
This is the angle you must turn right to parallel the Track
Required. To regain track, let’s look at the second triangle.
The 1 in 60 rule
30 miles
30 miles
pinpoint
12 miles
A
6m
Track Required
Revised Track
CA
B
As you only have 30 miles to travel the Closing Angle
can be found by projecting the triangle back to 60 miles.
This gives a Closing Angle of 12 degrees and this must be
added to the 9 degrees already turned to regain track at B.
The 1 in 60 rule
40 miles
30 miles
pinpoint
A
TMG
TE
6m
Track Required
Revised Track
CA
B
The Track Error of 9 degrees plus the Closing Angle of 12
degrees requires a turn of 21 degrees to regain track at B.
In the examination always draw the triangles on scrap paper to
check the sums.
The 1 in 60 rule
40 miles
30 miles
pinpoint
A
TMG
TE
6m
Track Required
Revised Track
CA
B
For simplification, in all of these examples the aircraft has
been off track to the left.
Examination questions have Track Errors left and right.
An aircraft flying from A to B finds that after 40
nms it is 4 nms off track. It has a further 60 nms
to travel. By how much does the pilot need to
turn to regain the intended track at B?
a) 12 degrees
b) 10 degrees
c) 6 degrees
d) 4 degrees
An aircraft flying from A to B finds that after 40
nms it is 4 nms off track. It has a further 60 nms
to travel. By how much does the pilot need to
turn to regain the intended track at B?
a) 12 degrees
b) 10 degrees
c) 6 degrees
d) 4 degrees
An aircraft flying from A to B finds that after 30
nms it is 4 nms left of track. It has a further 40
nms to travel. By how much does the pilot need
to turn to regain the intended track at B?
a) 16 degrees to the right
b) 14 degrees to the right
c) 14 degrees to the left
d) 12 degrees to the left
An aircraft flying from A to B finds that after 30
nms it is 4 nms left of track. It has a further 40
nms to travel. By how much does the pilot need
to turn to regain the intended track at B?
a) 16 degrees to the right
b) 14 degrees to the right
c) 14 degrees to the left
d) 12 degrees to the left
An aircraft flying from A to B finds that after 20
nms it is 2 nms right of track. It has a further 40
nms to travel. By how much does the pilot need
to turn to regain the intended track at B?
a) 12 degrees to the left
b) 9 degrees to the left
c) 6 degrees to the left
d) 6 degrees to the right
An aircraft flying from A to B finds that after 20
nms it is 2 nms right of track. It has a further 40
nms to travel. By how much does the pilot need
to turn to regain the intended track at B?
a) 12 degrees to the left
b) 9 degrees to the left
c) 6 degrees to the left
d) 6 degrees to the right
An aircraft flying from A to B finds that after 40
nms it is 6 nms right of track. It has a further 30
nms to travel. By how much does the pilot need
to turn to regain the intended track at B?
a) 24 degrees right
b) 21 degrees left
c) 18 degrees left
d) 12 degrees left
An aircraft flying from A to B finds that after 40
nms it is 6 nms right of track. It has a further 30
nms to travel. By how much does the pilot need
to turn to regain the intended track at B?
a) 24 degrees right
b) 21 degrees left
c) 18 degrees left
d) 12 degrees left
Chapter 4
Compasses.
contents list
exit
Magnetic Variation
The earth’s molten core
creates a weak magnetic
field which resembles the
field around a bar magnet.
This ‘magnet’ inside the
earth is inclined slightly to
the earth’s axis, so true
north and magnetic north
are not in the same place.
Magnetic North
Pole
True North Pole
Magnetic Variation
The difference in direction between true and
magnetic north (variation) is at its greatest in polar
areas.
Also, just as the lines of magnetic force go into the
ends of a bar magnet, they angle steeply into the
earth in polar areas causing compass needles to
‘dip’ as they try and align themselves.
For these reasons, compasses are very inaccurate
in polar areas.
Where are variation values at their greatest?
a) In the Northern hemisphere.
b) In polar regions.
c) At the equator.
d) In the Southern hemisphere.
Where are variation values at their greatest?
a) In the Northern hemisphere.
b) In polar regions.
c) At the equator.
d) In the Southern hemisphere.
As a compass nears the Magnetic North Pole,
the compass detector will try and point at the
magnetic material inside the Earth. This tilting
is called:
a) Drip.
b) Drop.
c) Dip.
d) Variation.
As a compass nears the Magnetic North Pole,
the compass detector will try and point at the
magnetic material inside the Earth. This tilting
is called:
a) Drip.
b) Drop.
c) Dip.
d) Variation.
The Direct Indicating Compass
The Direct Indicating Compass (DIC) is a very simple
aircraft compass. Because of its limitations it is only
used as a standby on most aircraft.
Its limitations are:
• It only reads correctly in unaccelerated straight
and level flight.
• It is unreliable at high magnetic latitudes.
The Direct Indicating Compass
The Direct Indicating Compass (DIC) does, however,
• It is simple and reliable.
• It is cheap and lightweight.
• It does not require any form of power.
When would a Direct Indicating Compass (DIC)
be most accurate?
a) In unaccelerated flight.
b) In a turn.
When would a Direct Indicating Compass (DIC)
be most accurate?
a) In unaccelerated flight.
b) In a turn.
Which of the following statements is true,
concerning the Direct Indicating Compass
(DIC)?
a) The DIC gives a reading of
b) The DIC needs only a small
power supply.
c) The DIC is not affected by
turns and accelerations.
d) The DIC only reads magnetic
Which of the following statements is true,
concerning the Direct Indicating Compass
(DIC)?
a) The DIC gives a reading of
b) The DIC needs only a small
power supply.
c) The DIC is not affected by
turns and accelerations.
d) The DIC only reads magnetic
All RAF aircraft are equipped with a Direct
Indicating Compass (DIC). Why is this?
a) The DIC is the most accurate
compass available.
b) The DIC is not affected by
turns or accelerations.
c) The DIC gives a reading of
d) The DIC is reliable and needs
no power supply.
All RAF aircraft are equipped with a Direct
Indicating Compass (DIC). Why is this?
a) The DIC is the most accurate
compass available.
b) The DIC is not affected by
turns or accelerations.
c) The DIC gives a reading of
d) The DIC is reliable and needs
no power supply.
The Gyro-Magnetic Compass
The gyro-magnetic compass (GMC) was invented to
overcome the limitations of the DIC.
It has three main components:
• A magnetic detector (or flux valve).
• A turn / acceleration cut-out switch.
• A gyroscope.
It can also power various compass repeaters
around the aircraft (for navigators, WSOps etc).
The Gyro-Magnetic Compass
The magnetic detector or ‘flux valve’ is solid state
equipment (i.e. no moving parts) which electrically
senses the magnetic field. It is located in the wingtip
in order to keep deviation to a minimum.
It is, however, still subject to the same turning and
acceleration errors as the DIC.
A turn / acceleration cut-out switch prevents the
gyroscope from receiving erroneous updates during
aircraft manoeuvres.
The Gyroscope
The gyroscope continues to point to the same
direction, no matter what manoeuvres the aircraft
may make.
It is constantly being updated by signals from the
magnetic detector, but only when the aircraft is in
straight and level flight.
The turn / acceleration cut-out switch ensures that
only valid magnetic signals are used to update the
gyroscope.
The Gyroscope
Despite the fine tolerances employed in gyroscope
production, no gyroscope is completely error free
and will suffer ‘real’ errors as a result.
Gyroscopes will also tend to point to a position in
space, although the earth rotates 360° each 24
hours, creating ‘apparent’ errors.
These ‘real’ and ‘apparent’ errors increase over time
and are known as ‘gyro wander’.
Which of the following is not a component
within a Gyro-magnetic compass system?
a) A turn / acceleration cut-out
switch.
b) A gyroscope.
c) A suspended magnet.
d) A flux valve magnetic
detector.
Which of the following is not a component
within a Gyro-magnetic compass system?
a) A turn / acceleration cut-out
switch.
b) A gyroscope.
c) A suspended magnet.
d) A flux valve magnetic
detector.
Which of the following statements about the
Gyro-magnetic compass is true?
a) When the aircraft climbs or
descends, the flux valve takes
over from the gyroscope.
c) The Gyro-magnetic compass
is less accurate than the Direct
Indicating Compass.
b) The gyroscope takes over from
the flux valve whenever the
aircraft turns.
d) The flux valve controls the
speed of the gyroscope.
Which of the following statements about the
Gyro-magnetic compass is true?
a) When the aircraft climbs or
descends, the flux valve takes
over from the gyroscope.
c) The Gyro-magnetic compass
is less accurate than the Direct
Indicating Compass.
b) The gyroscope takes over from
the flux valve whenever the
aircraft turns.
d) The flux valve controls the
speed of the gyroscope.
Which of the following is one advantage of a
gyro-magnetic compass over a Direct Indicating
Compass?
a) A gyro-magnetic compass
requires no electricity.
c) A gyro-magnetic compass is
cheaper.
b) A gyro-magnetic compass can
feed repeaters around the
aircraft.
d) A gyro-magnetic compass
does not work during turns or
accelerations.
Which of the following is one advantage of a
gyro-magnetic compass over a Direct Indicating
Compass?
a) A gyro-magnetic compass
requires no electricity.
c) A gyro-magnetic compass is
cheaper.
b) A gyro-magnetic compass can
feed repeaters around the
aircraft.
d) A gyro-magnetic compass
does not work during turns or
accelerations.
A gyroscope cannot be perfect, and so over a
period of time it becomes inaccurate, this is
called:
a) Gyro wander.
b) Variation.
c) Gyro rigidity.
d) Turn / acceleration error.
A gyroscope cannot be perfect, and so over a
period of time it becomes inaccurate, this is
called:
a) Gyro wander.
b) Variation.
c) Gyro rigidity.
d) Turn / acceleration error.
Inertial navigation systems (INS) use accelerometers
(highly accurate gyroscopes) to detect rate of
change of position along three axes.
Providing your start point is accurately entered you
any time.
Combining laser gyroscope INS with satellite
accuracy in modern aircraft.
What principle does an Inertial Navigation
System (INS) use to calculate the position of the
aircraft?
a) A gyroscope feeds position to
the computer.
b) The navigator must update the
system all the time.
c) It uses compass heading and
doppler values to compute
aircraft position.
d) It is set accurately on the
ground, then measures
acceleration in the fore, aft and
lateral.
What principle does an Inertial Navigation
System (INS) use to calculate the position of the
aircraft?
a) A gyroscope feeds position to
the computer.
b) The navigator must update the
system all the time.
c) It uses compass heading and
doppler values to compute
aircraft position.
d) It is set accurately on the
ground, then measures
acceleration in the fore, aft and
lateral.
Within an Inertial Navigation System the
movement of the aircraft is measured by sensors
called:
a) Axis.
b) Accelerators.
c) Accelerometers.
d) Inertials.
Within an Inertial Navigation System the
movement of the aircraft is measured by sensors
called:
a) Axis.
b) Accelerators.
c) Accelerometers.
d) Inertials.
Chapter 5
Weather
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Meteorological Conditions
Student pilots do not have the experience, and basic
training aircraft do not have the instruments to
safely fly in cloud and fog.
Beginners may only fly in Visual Meteorological
Conditions (VMC), when visibility is good and
aircraft can remain clear of cloud.
When this is not the case, Instrument Meteorological
Conditions (IMC) apply and only pilots with
instrument ratings may fly aircraft equipped with
suitable instrumentation.
The Visual Circuit
At flying training schools and training units, special
conditions apply.
Trainee pilots will not be allowed to take off and fly
circuits unless the cloudbase and visibility meet the
aerodrome controller’s requirements.
Beginners may only fly in good weather
conditions. These conditions are called:
a) Instrument Meteorological
Conditions (IMC).
b) Runway Visual Range (RVR).
c) Visual Circuits (VC).
d) Visual Meteorological
Conditions (VMC).
Beginners may only fly in good weather
conditions. These conditions are called:
a) Instrument Meteorological
Conditions (IMC).
b) Runway Visual Range (RVR).
c) Visual Circuits (VC).
d) Visual Meteorological
Conditions (VMC).
In order to fly in Instrument Met Conditions
(IMC), which of the following are required:
a) A clear windscreen canopy.
b) No cloud in the local area.
c) An instrument rating only.
d) The correct instrumentation
and a suitable pilot instrument
rating.
In order to fly in Instrument Met Conditions
(IMC), which of the following are required:
a) A clear windscreen canopy.
b) No cloud in the local area.
c) An instrument rating only.
d) The correct instrumentation
and a suitable pilot instrument
rating.
In order to fly a visual circuit, a trainee pilot
requires:
a) No wind.
b) Good visibility and no cloud in
the sky.
c) Good visibility and no wind.
d) Visibility and cloudbase
conditions to meet the
aerodrome controller's
requirements.
In order to fly a visual circuit, a trainee pilot
requires:
a) No wind.
b) Good visibility and no cloud in
the sky.
c) Good visibility and no wind.
d) Visibility and cloudbase
conditions to meet the
aerodrome controller's
requirements.
Wind
The take off runway will normally be the one which
allows the aircraft take off to be made into wind.
Into a strong wind an aircraft reaches flying speed
quickly and needs a shorter take off run.
Crosswind
27
In this example the aircraft is
about to take off on runway 27
(runway direction 270°).
Crosswind
27
The wind is 20 kts from the
direction 300° (300/20).
Crosswind
27
This wind can be split into two
parts – the crosswind component
Crosswind
27
This wind can be split into two
parts – the crosswind component
Crosswind
27
With a wind angle 30° off the
runway direction the crosswind
component will be 50% of the
total wind speed.
Crosswind
10
10
27
10
With a wind angle 30° off the
runway direction the crosswind
component will be 50% of the
total wind speed (i.e. 10 kts
crosswind for 20 kts windspeed).
Crosswind
27
With a wind angle 30° off the
component will be 90% of the
total wind speed.
Crosswind
2
18
With a wind angle 30° off the
component will be 90% of the
total wind speed (i.e. 18 kts
27
18
Crosswind
20
27
20
If a 20 kt wind is blowing at an
angle of 90° to the runway
direction, then the whole of that
20 kts of wind will be crosswind
Crosswind
27
Similarly, if a wind is blowing
straight down the length of a
runway then the whole of that
wind will be headwind with zero
crosswind component.
Why does an aircraft take off into wind?
a) To increase the groundspeed
at take off.
b) To take off at a lower airspeed.
c) To use the full length of the
runway.
d) To decrease the length of take
off run.
Why does an aircraft take off into wind?
a) To increase the groundspeed
at take off.
b) To take off at a lower airspeed.
c) To use the full length of the
runway.
d) To decrease the length of take
off run.
A wind is blowing at 90 degrees angle off the
runway direction. If the wind speed is 20 kts,
what is the crosswind component?
a) 2 kts
b) 10 kts
c) 12 kts
d) 20 kts
A wind is blowing at 90 degrees angle off the
runway direction. If the wind speed is 20 kts,
what is the crosswind component?
a) 2 kts
b) 10 kts
c) 12 kts
d) 20 kts
The wind is blowing directly down the length of
a runway. What is the crosswind component?
a) Equal to the wind's speed.
b) Equal to 3/4 of wind speed.
c) Equal to half the wind speed.
d) Zero.
The wind is blowing directly down the length of
a runway. What is the crosswind component?
a) Equal to the wind's speed.
b) Equal to 3/4 of wind speed.
c) Equal to half the wind speed.
d) Zero.
Shallow Fog
Fog presents a unique problem for the pilot, particularly
at night when runway lights can be clearly seen from
Shallow Fog
Once on the glideslope, the pilot is looking at the fog at
a much shallower angle and the reduced visibility may
prevent the aircraft from landing.
Shallow Fog
The slant visibility can be measured using equipment
placed close to the runway touchdown zone.
Shallow Fog
These yellow installations in the foreground measure
the visibility in the direct vicinity of the runway.
Shallow Fog
This slant visibility measurement, known as the Runway
Visual Range (RVR) is passed to the pilot by ATC.
The airfield has a covering of shallow fog. A
pilot circling directly overhead sees the runway
lights clearly. However, on the approach to land
he may have great difficulty seeing any lights.
Why is this?
a) Runway lights are designed
to be seen from high level only.
b) Fog is more dense closer to the
ground.
c) Fog will appear thicker when
on the glide path because the
pilot is looking at a shallower
angle.
d) The thickest fog always settles
at the end of the runway.
The airfield has a covering of shallow fog. A
pilot circling directly overhead sees the runway
lights clearly. However, on the approach to land
he may have great difficulty seeing any lights.
Why is this?
a) Runway lights are designed
to be seen from high level only.
b) Fog is more dense closer to the
ground.
c) Fog will appear thicker when
on the glide path because the
pilot is looking at a shallower
angle.
d) The thickest fog always settles
at the end of the runway.
During periods of poor visibility due to fog,
ATC will advise the pilot of the slant visibility
along the runway. This visibility is measured
accurately and is known as:
a) Runway Range.
b) Runway Visual Range.
d) Glide Slope Visibility.
During periods of poor visibility due to fog,
ATC will advise the pilot of the slant visibility
along the runway. This visibility is measured
accurately and is known as:
a) Runway Range.
b) Runway Visual Range.
d) Glide Slope Visibility.
Precipitation
Precipitation is rain, sleet, snow or hail.
Heavy rain might restrict the visibility or even flood
the runway.
If the precipitation is frozen, or the temperature at
ground level is below zero, the precipitation may
stick to the airframe causing icing and create
serious problems during take off.
The collective noun for rain, sleet, snow and hail
is:
a) Participation.
b) VMC.
c) IMC.
d) Precipation.
The collective noun for rain, sleet, snow and hail
is:
a) Participation.
b) VMC.
c) IMC.
d) Precipitation.
What problems can be caused by heavy rain?
a) Heavy snow.
b) Runway Visual Range.
c) Thunderstorms.
d) Restricted visibility and
runway flooding.
What problems can be caused by heavy rain?
a) Heavy snow.
b) Runway Visual Range.
c) Thunderstorms.
d) Restricted visibility and
runway flooding.
Engine Icing
Both jet and piston engines are affected by icing.
Whilst large and commercial aircraft have effective
de-icing systems for engines and airframes, it is
best to avoid icing conditions if possible.
In light aircraft and high performance military
aircraft with little or no anti-icing protection it is
essential to avoid icing conditions completely.
What problems can be caused by precipitation
at freezing temperatures?
a) Crosswinds.
b) Icing.
c) Fog.
d) Thunderstorms.
What problems can be caused by precipitation
at freezing temperatures?
a) Crosswinds.
b) Icing.
c) Fog.
d) Thunderstorms.
What can be the effects of heavy icing on an
aircraft's performance?
a) Loss of aerodynamics only.
b) Loss of aerodynamics and
reduced engine performance.
c) It will fly much slower.
d) There is no adverse affect on
an aircraft's performance.
What can be the effects of heavy icing on an
aircraft's performance?
a) Loss of aerodynamics only.
b) Loss of aerodynamics and
reduced engine performance.
c) It will fly much slower.
d) There is no adverse affect on
an aircraft's performance.
What effect can icing have on the aerodynamics
of an aircraft?
a) The windscreen may freeze
over.
b) Lift will decrease and weight
will increase.
c) Ice forming on the leading
edge of the wing will increase
lift.
d) There will be no adverse
effect on the aerodynamics.
What effect can icing have on the aerodynamics
of an aircraft?
a) The windscreen may freeze
over.
b) Lift will decrease and weight
will increase.
c) Ice forming on the leading
edge of the wing will increase
lift.
d) There will be no adverse
effect on the aerodynamics.
A flight briefing indicates icing en-route. The
aircraft has no ice protection. What advice
would you give a novice pilot?
a) Fly above the cloud.
b) Fly slowly, the icing will have
less effect.
c) Fly quickly, the icing will have
less effect.
d) Plan a route avoiding icing
conditions or cancel the flight.
A flight briefing indicates icing en-route. The
aircraft has no ice protection. What advice
would you give a novice pilot?
a) Fly above the cloud.
b) Fly slowly, the icing will have
less effect.
c) Fly quickly, the icing will have
less effect.
d) Plan a route avoiding icing
conditions or cancel the flight.
Conclusion
An extra question has found its way into this
examination which is not covered in the manual:
The earth revolves from West to East on its axis.
The sun appears to rise in the East, but as the Sun
is stationary it is the earth rotating West to East.
Which way does the Earth revolve on its axis?
a) East to West.
b) West to East.
c) North to South.
d) South to North.
Which way does the Earth revolve on its axis?
a) East to West.
b) West to East.
c) North to South.
d) South to North.
The sun appears to rise in the East and set in the West.
As the sun is actually stationary, it is the Earth which is revolving
West to East.
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