The experimental probability that a customer at a restaurant qualified for
a senior discount was found to be
2/11.(simplified) The restaurant recorded 16 senior discounts on a given
day. What was the number of non-senior customers?
#𝑃𝑃 𝑃𝑃𝑃𝑃𝑃 𝑃 𝑃𝑃𝑃𝑃𝑃𝑃𝑃𝑃
𝑃𝑃𝑃𝑃𝑃 #𝑃𝑃 𝑃𝑃𝑃𝑃𝑃𝑃
16
𝑃(𝑃𝑃𝑃𝑃𝑃𝑃) =
𝑃𝑃𝑃𝑃𝑃# 𝑃𝑃 𝑃𝑃𝑃𝑃𝑃𝑃
16
0.182 =
𝑃𝑃𝑃𝑃𝑃# 𝑃𝑃 𝑃𝑃𝑃𝑃𝑃𝑃
16
𝑃𝑃𝑃𝑃𝑃# 𝑃𝑃 𝑃𝑃𝑃𝑃𝑃𝑃 =
. 182
𝑃𝑃𝑃𝑃𝑃 # 𝑃𝑃 𝑃𝑃𝑃𝑃𝑃𝑃 = 87.91~88
𝑃(𝑃) =
88 − 16 = 72
Therefore, there is 72 non-senior customers.