EECE 2210: Circuits II
Homework 3
Due: February 12, 2026
1. Solve 12.44. (25 points)
Answer: 531.9 V, 0.62 lagging
2. Solve 12.31. (20 points)
Partial Answer: ZL = 3.07 + j2.30 Ω, 216.51 A, 0.414 mF
3. A balanced Y-Y system has a line voltage of 208 Vrms on the load side. The total real power absorbed
by the load is 12 kW at 0.8 pf lagging. The impedance of each line is 0.1 + j0.1 Ω. (a) Determine the
per-phase impedance of the load. (b) Determine the rms line voltage on the source side. (c) Perform a
load pf correction by connecting parallel capacitors between lines and neutral to achieve a new pf 0.98
leading. Use f = 60 Hz. (30 points)
Answers: 2.30 + j1.73 Ω, 217.96 Vrms, 0.702 mF
4. An unbalanced three-phase circuit is shown below, where ZL = 1 + j0.5 Ω, Z1 = 78 + j45 Ω, Z2 = 63 +
j37 Ω, and Z3 = 91 – j12 Ω. Find all three line currents in phasor and the total complex power
accepted by the loads. Hint: Note that the source side is still balanced. Utilize the large non-balanced
Delta to Y load conversion equations (not the easy equations: Z = 3*Z, Z = Z/3). From a Y-Y
configuration, perform mesh analysis. (25 points)
Answer: Ia = 7.91∠-11.64° A, Ib = 7.78∠-146.76° A, Ic = 6.03∠100.98° A, and Sload = 2.157 kW +
j0.726 kVAR
NOTE: Please use the file naming convention LastName_HW3.pdf, for your submission. Refer to the
course textbook to view the problem numbers called out in the HW problem statements.