MATH 203 (Fall 2023) Midterm Exam
October 12 (10:00 am) – October 15 (10:00 am), 2023
INSTRUCTIONS
1. Answer all 5 questions. Either use the template to answer your questions or
answer on a separate sheet of paper. If you answer on a separate sheet of paper,
please order your answers as follows: Question 1, Question 2, and so on.
2. Your exam must be submitted to myCourses as a single PDF (handwritten or
typed or the combination of both), no later than October 15, 2023, 10:00 am
(Montreal time). Make sure that your answers are legible.
3. Submit your exam on myCourses under the Assignments tab. Make sure that
you submit your exam to Midterm Exam and not any other folder.
4. You will be allowed multiple submissions until the deadline. We will grade the
latest submission before the deadline.
5. Make sure you receive an acknowledgement from myCourses that your
submission has been received.
6. It is recommended that you do not take the full 72 hours to complete your
midterm exam. Do not leave your submission until shortly before the deadline.
7. You must show your reasoning. An answer alone is not sufficient.
8. This is an "open book/note" exam. You are allowed to use your notes, book, slides,
and other informational materials about the course content.
9. You are not allowed to work with others, keep and/or share exam content (via
writing it down or taking pictures) with other people or online forums. All of these
practices are considered cheating and have severe consequences. Where
there is evidence of plagiarism or collaboration, the case will be forwarded to
the Disciplinary Officer in the student's faculty.
By starting to work on the exam, you confirm that you have read these
instructions and adhere to standards of academic integrity.
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i class 1 and class 3 have different centres class1 0.55
and class 3 0.3 spreads class 3 has a greaterspread thanclass 1
and shapes class I is symmetricand class 3 is rightskewed but
theyboth have outliers present
il Class I and Class 2 both have lower outliers present and similar
spreads however there are
differences
in centres class 1 0.55 and
class 2 0.757 and shapes class I is symmetricand class 2
is left skewed
Iii Class 2 and class 3 both have outliers present and have similar
centres on the contrary their spread class spread is greater
than class 2 and shape class 2 is left skewedand class 3 is
right skewed are different
In class 2 approximately 50 of scores is present in
0.3 0.4 This is shown by the location of Qa and Q3
where 501 of scores lie
No it is not appropriate to say that 951 of data fall
within the interval I 12s as this rule only applies to symmetric
and bell shaped curves and class 3 is right skewed
Class 3
Class 1
Class 2
Accordingto theempirical rule approximately 951
the interval of to
no
of the scores fall within
because the interval is equivalent to
According totheempirical rule approximately
Mt 20
681 of the scores fall within
85 115 as this is equivalent to MIO
The upper rangelimit is 1 SD away from the mean and the
lower range limit is 2 SDS away Since the distribution is symmetric
you can manipulate the percentage to be 1681
Thus 81.51 of the scores will fall in
2
951 2
70 115
81.51
81.5
of the data will be out of
the range 70 1307 Since the data is symmetric
Approx 5
you can do
70 85 100 115 130
It
2.51 to determine the probability
of choosing a scoreunder 70
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70 85 100 115 130
Approx 32
of the data will be out of the
symmetric
range 85 115 Since this data is
you can do 331 161 to calculate the probability
of scores greater than 115
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