Velocity
vs
time
graph
Calculating the slope
acceleration
• Calculate the
acceleration for each
segment of the graph
y 2  y1
m
x2  x1
• The slope of a v-t graph
is acceleration
• Slope is calculated by
the equation
a
v f  vi
t f  ti
• To follow along- print slides 4,9,12,15
• Answers to follow
Graph 1
+15 m/s
velocity
+10 m/s
+5m/s
0 m/s
-5 m/s
-10 m/s
0s
1s
2s
time
3s
4s
5s
6
Graph 1
From 0 s to 2 s
+15 m/s
 10m / s  0m / s
a
2s  0s
 10m / s
a
2s
2
a  5 m / s
velocity
+10 m/s
+5m/s
0 m/s
-5 m/s
-10 m/s
0s
1s
2s
time
3s
4s
5s
6
Graph 1
From 2 s to 4 s
+15 m/s
velocity
+10 m/s
 10m / s  10m / s
a
4s  2s
0m / s
a
2s
a  0m / s 2
+5m/s
0 m/s
-5 m/s
-10 m/s
0s
1s
2s
time
3s
4s
5s
6
Graph 1
From 4 s to 6 s
+15 m/s
velocity
+10 m/s

10m / s   10m / s
a
6s  4s
 20m / s
a
2s
2
a  10m / s
+5m/s
0 m/s
-5 m/s
-10 m/s
0s
1s
2s
time
3s
4s
5s
6
Graph 2
Determine the acceleration of each segment
of the line on the graph to follow.
Graph 2
+30m/s
velocity
+20 m/s
+10m/s
0 m/s
-10 m/s
-20 m/s
0s
2s
4s
time
6s
8s
10 s
12
Graph 2

30m / s   10m / s
a
12s  10s
 40m / s
a
2s
a   20m / s 2
10m / s  20m / s
a
6s  0s

30m / s
a
6s
a   5m / s 2
+30m/s
+20 m/s
velocity


+10m/s

10m / s   10m / s
a
10 s  6 s
0m / s
a
4s
a  0m / s 2
0 m/s
-10 m/s
-20 m/s
0s
2s
4s
time
6s
8s
10 s
12
Graph 3
• Determine the acceleration of each
segment of the line on the graph to follow.
Graph 3
+300m/s
velocity
+200 m/s
+100m/s
0 m/s
-100 m/s
-200 m/s
0s
5s
10 s
time
15 s
20 s
25 s
30
Graph 3
+300m/s
velocity
+200 m/s
+100m/s
0 m / s   200m / s
a
30 s  15s

200m / s
a
15s
a   13.3m / s 2

100m / s  200m / s
a
5s  0 s
300m / s
a
5s
a  60m / s 2
0 m/s
-100 m/s
-200 m/s
0s
5s
10 s
time
15 s
20 s
25 s
30
Graph 4
Determine the acceleration of each segment
of the line on the graph to follow.
Graph 4
+12m/s
velocity
+8 m/s
+4m/s
0 m/s
-4m/s
-8 m/s
0s
2s
time
4s
6
Graph 4

+12m/s
velocity
+8 m/s
+4m/s

4m / s   8 / s
a
3s  0 s
4m / s
a
3s
a  4 / 3m / s 2
0 m/s
-4m/s
-8 m/s
0s
2s
time
12m / s   4 / s
a
6 s  3s

16m / s
a
3s
a   16 / 3 m / s 2
4s
6
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