ENGCV312-22A (HAM) Name: ID number: ENGCV312-22A Exam DEPARTMENT Engineering PAPER TITLE Structural Engineering 2 TIME ALLOWED Three hours NUMBER OF QUESTIONS IN PAPER Five NUMBER OF QUESTIONS TO BE ANSWERED Five VALUE OF EACH QUESTION 20 pts GENERAL INSTRUCTIONS Show all of your work. Work should be clear, orderly, and legible. Each question specifies a method of analysis. You must use this method to get credit for the problem. You are not permitted to use computer software programs to complete the problems. You must complete by hand and show your work. SPECIAL INSTRUCTIONS Allowed a single hand written A4 sheet of notes, both sides of the paper may be used. Allowed NZS1170.5. CALCULATORS PERMITTED Yes The calculator memory must be cleared prior to the test. THIS TEST PAPER MUST BE HANDED TURN OVER 2 ENGCV312-21A (HAM) CONTINUED ENGCV312-22A (HAM) 1 Lateral Loads from Earthquakes A developer is considering two location for a new hotel, Hanmer Springs or Paihia/Russell. The hotel will be designed to match the hotel brand, following a similar floor plan, elevation design, and structural plan to other hotels owned by the developer. As part of their decision process for selecting the location for the new hotel, the developer needs know how much the seismic loads will affect the design. A Considering the Ultimate Limit State, determine the lateral load distribution for the hotel at both sites and comment on difference between the two designs. B Provide advice on how the lateral loads will influence the final design for both locations. Building information common to both locations: A basic layout of the building is shown in Figure 1. Building is constructed out of structural steel. The lateral force resisting system is a moment frame. The dead loads from the structural weight and superimposed loads (HVAC, flooring, concrete slab, etc) are provided. The live loads should be determined based on the use of the building and the floor area. Use a uniformly distributed floor load of 2 kPa. No part of the building will be used for storage applications and there is no access to the roof. The hotel will have 12 apartments (6 on each of the upper floors) that will each be able to house 10 people at a time. The ground floor will be retail space. Importance level should be determined from the use of the structure and is given in Table 1. Estimate an initial period based on the structural material and lateral force resisting system using an appropriate equation based on the structural material and the lateral force resisting system. For the ultimate limit state, calculate the lateral loads for a seismic event. Additional information on the design criteria is provided in Table 2. Fill in Tables 1-5. TURN OVER 4 ENGCV312-21A (HAM) Figure 1 Hotel structural layout Table 1 Total dead and live loads on each floor Level Dead loads (kN) Roof 2000 Level 2 3000 Level 1 3000 Live loads (kN) Combined loads (kN) Total CONTINUED ENGCV312-22A (HAM) Table 2 Design Criteria Design Criteria Hanmer Springs Paihia/Russell Importance Level 2 2 Ductility (assume elastic) = 1.0 = 1.0 Design Life 100 years 100 years Site Class C D Estimated Period (USL) Figure 2 NZS1170.5 Supplement estimation of structural period TURN OVER 6 ENGCV312-21A (HAM) Table 3 Use this table to calculate the base shear Variable Hanmer Springs Paihia/Russell Calculations Calculations Spectral Shape Factor, 𝑪𝒉 (𝑻) Z-factor Return period factor, 𝑹𝒖 Shortest distance to fault, D Near Fault Factor, 𝑵(𝑻, 𝑫) Elastic Site Spectrum, 𝑪(𝑻) Structural performance factor, 𝑺𝒑 0.7 0.7 𝒌_𝝁 Horizontal design action coefficient, 𝑪𝒅 (𝑻) Seismic Weight (kN) Base Shear (kN) CONTINUED ENGCV312-22A (HAM) Table 4 Use this table to distribute the base shear and calculate the lateral loads - Hanmer Springs Floor ℎ𝑖 𝑊𝑖 ℎ𝑖 𝑊𝑖 𝐹𝑡 m kN kNm kN 0.92𝑉(𝑊𝑖 ℎ𝑖 ) ∑(𝑊𝑖 ℎ𝑖 ) 𝐹𝑖 kN kN First Floor Second Floor Roof Sum Table 5 Use this table to distribute the base shear and calculate the lateral loads - Paihia/Russell Floor ℎ𝑖 𝑊𝑖 ℎ𝑖 𝑊𝑖 𝐹𝑡 m kN kNm kN 0.92𝑉(𝑊𝑖 ℎ𝑖 ) ∑(𝑊𝑖 ℎ𝑖 ) 𝐹𝑖 kN kN First Floor Second Floor Roof Sum TURN OVER 8 2 ENGCV312-21A (HAM) Force Method. The rigid frame shown in Figure 3 Building layout (left) and frame for analysis (right)supports one end of simple building. The building has a depth of 10 meters. The roof beam along BC supports half of the roof load. The roof consists of dead loads from a concrete slab (200 mm thick), gypsum plaster suspended ceiling (13 mm thick), ducting and piping. The ducts and piping can be assumed to have a distribute weight of 0.15 kN/m2. The concrete slab has a unit weight of 23.6 kN/m3. The weight for the suspended ceilings should be taken from AS/NZS1170.1 table A2. Assume there is no live load for the structure. Do not factor the loads. A Determine the distributed load on frame ABCD. B Determine the vertical and horizontal reactions at A and D using the Force Method. If you cannot figure out the distributed load in part A, use a load of 10kN/m. C Draw the shear and bending moment diagrams. Given: 𝐼𝐴𝐵 = 𝐼𝐶𝐷 = 250𝑥106 𝑚𝑚4 , 𝐼𝐵𝐶 = 500𝑥106 𝑚𝑚4 , 𝐸 = 200 𝐺𝑃𝑎 for all members Figure 3 Building layout (left) and frame for analysis (right) CONTINUED ENGCV312-22A (HAM) 3 Slope Deflection. The simple frame shown in Figure 4 represents a simple one storey building. The frame supports a uniform lateral load W. The beam has a second area of moment, I, value twice that of the column. The frame is pin supported at A and D. The beams and columns have a constant E value. A Analysis: Using the slope deflection method, determine the internal moments at each of the joints. B Discussion: If the building were to have an additional lateral load applied at B, Figure 5, discuss how your analysis would change to compensate for the sway in the structure? Figure 4 Frame for analysis (left) Figure 5 Frame with lateral load TURN OVER 10 4 ENGCV312-21A (HAM) Stiffness Method A simple beam is shown in Figure 6. The beam supports a uniformly distributed load of W. The beam has rigid supports at the two ends and roller supports at B and C. The length of each beam segment is 3 meters. EI is constant for all members. A Determine the equivalent beam by transferring the distributed load to point loads at the joints, develop the Force and Displacement vectors for the structure. B Construct the 𝐾11 and the 𝐾21 sections of the stiffness matrix for the beam structure using the beam member stiffness matrix given. C Solve for the rotational displacements at B and C D Determine the vertical and moment reactions at supports A, B, C, and D. Figure 6 Structural Stiffness Matrix for Beam 𝑘𝑏𝑒𝑎𝑚 = 𝐸𝐼 4/9 2/3 −4/9 2/3 2/3 4/3 −2/3 2/3 −4/9 −2/3 4/9 −2/3 [ 2/3 2/3 −2/3 4/3 ] CONTINUED ENGCV312-22A (HAM) TURN OVER 12 5 ENGCV312-21A (HAM) Plastic Theory: The frame shown below supports a combination of lateral and horizontal loads, Figure 7. A The frame has 5 possible failure mechanisms. For each mechanism, determine the critical load W that can be applied using the plastic moment 𝑀𝑝 . Note that the columns have an 𝑀𝑝 equal to twice the beam. Beam: Hinges in beam at B, C, and E Beam: Hinge in beam at B, D, and E Sway: Hinge in column at B and E Combined: Hinge in beam at C, and hinge in column at E Combined: Hinge in beam at D, and hinge in column at E B State the critical mechanism for the frame. Figure 7 Plastic theory Frame CONTINUED ENGCV312-22A (HAM) Reference Material cos 2 𝜃 𝐴𝐸 sin 𝜃 cos 𝜃 𝑘𝑡𝑟𝑢𝑠𝑠 = [ 𝐿 − cos2 𝜃 −sin 𝜃 cos 𝜃 sin 𝜃 cos 𝜃 𝑠𝑖𝑛2 𝜃 −sin 𝜃 cos 𝜃 − 𝑠𝑖𝑛2 𝜃 12 𝐿3 6 2 𝑘𝑏𝑒𝑎𝑚 = 𝐸𝐼 𝐿 12 − 3 𝐿 6 [ 𝐿2 6 𝐿2 4 𝐿 6 − 2 𝐿 2 𝐿 −cos 2 𝜃 − sin 𝜃 cos 𝜃 cos2 𝜃 sin 𝜃 cos 𝜃 12 𝐿3 6 − 2 𝐿 12 𝐿3 6 − 2 𝐿 − − sin 𝜃 cos 𝜃 −𝑠𝑖𝑛2 𝜃 ] sin 𝜃 cos 𝜃 𝑠𝑖𝑛2 𝜃 6 𝐿2 2 𝐿 6 − 2 𝐿 4 𝐿 ] TURN OVER 14 ENGCV312-21A (HAM) CONTINUED ENGCV312-22A (HAM) TURN OVER 16 ENGCV312-21A (HAM) --END-- CONTINUED