TT03 ECE LAB ONLINE 5 – BJT APPLICATIONS
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ECE LAB ONLINE 5
DIODE APPLICATIONS
STUDENT INFORMATION
CLASS: TT01
STUDENT ID:
FULL NAME:
Note: name the file according to the syntax
CLASS_ID_FullName_Session_[Offset at class?]
Eg: T01_1812466_NguyenVanB_Day_1
T01_1812466_NguyenVanB_Day_1_Offset at class T04 (T01 is the student class,
T04 is the class that makes up)
OBJECTIVES
 Know how to use Analog Discovery Studio Kit and Software, Lab Instrument.
 Understand voltage and current properties in series and parallel circuit.
 Understand I-V characteristic of BJT.
PREPARATION
 Install Proteus version 8.8 or above before coming to the LAB session.
TT03 ECE LAB ONLINE 5 – BJT APPLICATIONS
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1. EXPERIMENT 1
OBJECTIVES:
In this lab assignment, we examine input I-V characteristics IB = f(VBE) of BJT, sketch
the shape of IB = f(VBE) characteristic and determine open voltage of BJT.
CIRCUIT:
Given the circuit as shown below. In this circuit:
- Q2 is a transistor with product number is 2N5551.
- Vo = 5V DC.
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THEORY:
What does I-V characteristics IB = f(VBE) of BJT look like?
It has no current running through until the voltage reach the point that it able to
penetrate the BJT
SIMULATION:
Draw a simulation of the given circuit on Proteus.
(Picture of simulation circuit on Proteus)
1.4.1. Using TRANSFER GRAPHS to draw IB = f(VBE). (Vo = 5V).
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(Picture of running TRANSFER GRAPHS)
Find the opening voltage of the BE junction.
1.4.2. Using TRANSFER GRAPHS to draw IB = f(VBE). (Vo = 1V and Vo = 10V)
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(Picture of running TRANSFER GRAPHS)
Explain the reason why there is such a GRAPHS.
It has no current running through until the voltage reach the point that it able to
penetrate the BJT
1.4.3. Using TRANSFER GRAPHS to draw IB = f(VBE). (Vo = 1V to Vo = 10V, 10 steps)
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(Picture of running TRANSFER GRAPHS)
Comment on the characteristic shape as Vo increases.
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2. EXPERIMENT 2
OBJECTIVES:
In this lab assignment, we examine IC = f(VCE) characteristics of BJT, draw IC = f(VCE)
characteristic of BJT.
CIRCUIT:
Given the circuit as shown below. In this circuit:
- Q2 is a transistor with product number is 2N5551.
- Ib is a 10uA-DC-current source.
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THEORY:
How do you understand the graph below?
despite how high the current is, all have the same active region
SIMULATION:
Draw a simulation of the given circuit on Proteus.
(Picture of simulation circuit on Proteus)
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2.4.1. Using TRANSFER GRAPHS to draw IC = f(VCE). (Ib = 10uA).
(Picture of running TRANSFER GRAPHS)
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From the graph, students make calculations to derive the saturation voltage (điện áp bảo
hòa) VCE-sat (approximate value) and gain β (hệ số khuếch đại). Explain how.
2.4.2. Using TRANSFER GRAPHS to draw IC = f(VCE). (Ib = 10uA and Ib = 50uA)
(Picture of running TRANSFER GRAPHS)
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Explain the reason why there is such a GRAPHS.
It has no current running through until the voltage reach the point that it able to
penetrate the BJT
2.4.3. Using TRANSFER GRAPHS draw IC = f(VCE). (Ib=10uA to Ib=100uA, 10 steps)
(Picture of running TRANSFER GRAPHS)
Comment on the characteristic shape as Ib increases.
As Ib increase the amplitude of Ic also increase.
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3. EXPERIMENT 3
OBJECTIVES:
Understand the schematic diagram of amplifier circuit using BJT.
CIRCUIT:
Given the circuit as shown below. In this circuit:
- BJT is a transistor with product number is 2N5551.
- Rc is a 10-Kilo-Ohm resistor.
- The resistance of Re is 100 Ohm.
- R1 has a resistance of 44 Kilo-Ohm.
- R2 is a potentiometer with a resistance of 10 Kilo-Ohm at MAX.
- Vcc is a 12V-DC source.
- Using DC Voltmeter, Ammeter to find VCE, IC.
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SIMULATION:
Draw a simulation of the given circuit on Proteus.
(Picture of simulation circuit on Proteus)
Adjust rheostat R2 to VCE=6V, then how much is R2 and Ic?.
(Picture of simulation circuit on Proteus)
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R2 =2800Ohm
Ic =0.56mA
Add 3 1uF-capacitors as the below picture. Vi is a sine waveform with an amplitude of
100mV, frequency at 100Hz and offset = 0V. Using SIGNAL GENERATE to create Vi.
Using Oscilloscope to observe Vin and Vo (Note that in this lab, it is no need to adjust
the scale for the 2 channels to be the same).
(Picture of simulation circuit on Proteus)
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Find the amplitude of Vi and Vo.
Vi=100mV
Vo =2.4V
How many times is Vo amplified?
It amplified 24 times
What if we increase or decrease Vi, how does the voltage waveform of Vo change?
It will decrease its amplitude, because the Vo waveform is depended on the Vi
amplitude
What if we increase or decrease R2, how does the voltage waveform of Vo change?
If we increase R2 the amplitude of Vo waveform will decrease. And the opposite with
when we decrease R2.
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