LIST OF FORMULAS: 1. Polar unit vectors in terms of cartesian unit vectors: πΜ (π) = cos ππΜ + sin ππΜ πΜ(π) = −π ππ ππΜ + πππ ππΜ 2. Time derivative of the polar unit vectors: β πΜ = πΜ πΜ, β π‘ β πΜ = −πΜ πΜ β π‘ 3. Velocity in polar coordinates: π£β = πΜ πΜ + ππΜ πΜ 4. Acceleration in polar coordinates: πβ = (πΜ − ππΜ 2 )πΜ + (ππΜ + 2πΜ πΜ )πΜ 5. Length element in plane polar: β πβ = β ππΜ + πβ ππΜ 6. Angular momentum (a.m.) for fixed axis rotation about z: πΏπ = πΌ0 π (π. π. ππππ’π‘ πΆπ) + (π ββ × ππ£β)π (π. π. ππ π‘βπ πΆπ ππππ’π‘ π‘βπ πππ£ππ πππππ‘) 7. For a gyroscope, the torque πβ: πβ = β πΏββ ββ × ββββ =πΊ πΏπ β π‘ ββ is the precessional angular velocity and ββββ πΊ πΏπ is the spin angular momentum. 8. Moments and products of inertia: πΌπ₯π₯ = ∑ ππ (π¦π2 + π§π2 ) , π π πΌπ₯π¦ = − ∑ ππ π₯π π¦π = πΌπ¦π₯ , π πΌπ¦π¦ = ∑ ππ (π§π2 + π₯π2 ), πΌπ§π§ = ∑ ππ (π¦π2 + π₯π2 ) π πΌπ¦π§ = − ∑ ππ π¦π π§π = πΌπ§π¦ , πΌπ§π₯ = − ∑ ππ π§π π₯π = πΌπ₯π§ π π 9. Equation for a central force (with spherical symmetry): πΉβ (π) = π(π)πΜ 10. Equation for reduced mass (π ) picture in a two-body problem: ππβΜ = π(π)πΜ 11. Energy (πΈ) of a particle of mass π moving under a central force: 1 πΏ2 πΈ = ππΜ 2 + ππππ π€βπππ ππππ = + π(π) 2 2ππ 2 Angular momentum L= ππ 2 πΜ and π(π) is the potential energy. 12. Orbit equation for an object moving under a central force field: π β π π − π0 = πΏ ∫ π0 π 2 √2π(πΈ − ππππ ) 13. Taylor series expansion of the potential energy, assuming small perturbations: 1 β 2 π β 2 π π(π) ≈ π(π0 ) + (π − π0 )2 2 βπ0 anβ effective spring constant π = β 2 β π β π 2 π0 Where π(π) = π(π)πππ at π = π0 . 14. Equation of orbit of an object moving under gravity described by a conic section in polar coordinates: π= π0 πΏ2 2πΈπΏ2 π€βπππ π0 ≡ ππβ π ≡ √1 + 1 − ππππ π ππΆ ππΆ 2 Total energy πΈ, eccentricity is π and πΆ = πΊπ1 π2 where π1 ππβ π2 are the two masses and gravitational constant πΊ = 6.67 × 10−11 ππ2 /ππ2, πΏ is the angular momentum. 15. Length of major axis (π΄) and minor axis (π΅) of an elliptical orbit: π΄ = ππππ₯ + ππππ = 2π = π΅ = 2π = 2π0 √1 − π 2 2π0 πΆ = 1 − π 2 −πΈ = πΏ √−2ππΈ 16. Velocity π£ at any point π of the elliptical orbit: π£2 = 2πΆ 1 1 ( − ) π π π΄ 17. The time period of revolution π of an object in an elliptical orbit as given by Kepler’s 3rd law: π2 = π2π 3 π΄ 2πΆ where π΄ is the major axis length. ππ 18. In one dimension, for a conservative force, πΉ = − ππ where π is the potential energy.