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Grade-9
Science-II
Chapter 16 - Heredity And Variation
ANSWERS:
Question 1:
a. Hereditary characters are transferred from parents to offsprings by gene, hence they
are said to be structural and functional units of heredity.
b. Organisms produced by asexual reproductionshow minor variations.
c. The component which is in the nuclei of cells and carries the hereditary
characteristics is called chromosome.
d. Chromosomes are mainly made up of DNA.
e. Organisms produced through sexual reproduction show major variations.
Question 2:
Explain following.
a. Monohybrid cross is a cross between two parents that have one pair of contrasting
characters; for example, if pea plant with yellow seed coat is crossed with pea plant
having green seed coat then in the F1 generation all the plants produce yellow seeds.
b. Dihybrid cross is a cross between two parents that have two pairs of contrasting
characters, for example, a plant having round and yellow seeds is crossed with a plant
having green and wrinkled seeds.
c.
Monohybrid cross
Dihybrid cross
The cross in which only one pair of
contrasting characters is involved is
known as monohybrid cross.
The cross in which only two pairs of
contrasting characters are involved is
known as dihybrid cross.
A monohybrid cross is useful in
determining the dominance of genes.
A dihybrid cross is useful in studying
the assortment of the offspring.
example- a cross between tall and dwarf
plant
example- a cross between tall plant
having red flower and a dwarf plant
having white flower
d. No, it is not right to avoid living with a person suffering from a genetic disorder.
Genetic disorders are not communicable diseases that would be transmitted to people
who come in contact with people with genetic disoders. Genetic disorders are caused
by changes in DNA sequences which can only be passed from one generation to
another under specific circumstances. Rather, we sholud support and accept people
with such disorders, so that they can live a normal life.
Question 3: Answers the following questions in your own words.
a. Chromosomes are thread-like structures found in the nucleus of all living cells.
Chromosomes are divided into four types based on the position of the centromere.
(1) Metacentric chromosomes: In these chromosomes, the centromere is present in the
middle, which gives rise to two equal arms.
(2) Sub-metacentric chromosomes: In sub-metacentric chromosomes, the centromere
lies slightly away from the middle region. As a result, it has one arm slightly longer than
the other.
(3) Acrocentric chromosomes: In acrocentric chromosomes, the centromere is located
close to the end of the chromosome. As a result, it has one arm, which is extremely
long and the other, which is extremely short.
(4) Telocentric chromosomes: In telocentric chromosomes, the centromere is present at
the terminal end. As a result, the chromosome has only one arm.b. DNA is a very large
single molecule also called as macromolecule. It has a double helix structure, similar to
a ladder, which is twisted at both ends. The DNA molecule is made up of basic materials
called nucleotides and each nucleotide is made up of three components :




Sugar
Phosphate groups
Sugar and phosphate are arranged lengthwise.
Nitrogen bases are attached sugar from inwards that extends to join
hydrogen bond and the complimentary nitrogenous base from other strand.
The nitrogen bases are :
 Adenine(A)
 Guanine(G)
 Cytosine(C)
 Thymine(T)
Adinine pairs with Thymine with two hydrogen bonds. Guanine pairs with Cytosine with
three hydrogen bonds.
During the interphase of cell cycle, DNA molecules duplicates for their equal
distribution in the daughter cells during mitosis. The double helix opens at one end,
makes the two strands free and from there new strands are formed.
c. DNA fingerprinting is a method for comparing the DNA sequences of any two
individuals. 99.9% of the base sequences in all human beings are identical. It is the
remaining 0.1% that makes every individual unique.
The applications of DNA fingerprinting are as follows:

DNA fingerprinting is widely used in forensics since DNA of every tissue from an
individual has the same degree of polymorphism.
 DNA fingerprinting forms the basis of paternity testing since a child inherits
polymorphism from both its parents.
 It can be used for studying evolution and genetic diversity in a population.
d. A RNA nucleotide has three main components − a nitrogenous base, a ribose sugar
and a phosphate group.
• The ribose sugar and the phosphates form the backbone of a polynucleotide chain
with nitrogenous bases linked to sugar moiety and projecting from the backbone.
• Two types of nitrogenous bases are present i.e. Purines (Adenine and Guanine) and
Pyrimidines (Cytosine and Uracil).
• A nitrogenous base is linked to the ribose sugar through N-glycosidic linkages to form
a nucleoside (like adenosine, guanosine or cytidine and uridine).
• A phosphate group is linked to 5'-OH of a nucleoside through phosphoester linkage to
form a corresponding nucleotide.
• Every nucleotide residue has an additional −OH group present at 2' -position in the
ribose.
• Many nucleotides are linked through 3'-5' phosphodiester linkages to each other to
form the polynucleotide chain.
• The end of the chain which has a free phosphate moiety at 5'-end of ribose sugar is
referred to as 5’-end and the other end of the chain having a free 3'-OH group at the
ribose sugar is referred to as 3' -end of the polynucleotide chain.
There are 3 types of RNA:
1. mRNA (messenger RNA) − It serves as a template for protein synthesis. DNA is
transcribed to form an mRNA, which in turn is translated to form protein.
2. tRNA (transfer RNA) − It brings amino acids during translation and reads the genetic
code.
3. rRNA (ribosomal RNA) − These are the work benches of translation. They play a
structural and catalytic role during translation.
e. It is necessary for people to have their blood examined before marriage because the
genetic disorders are transmitted only by reproduction. If a carrier/sufferer of a genetic
disorder marries a person who is also a carrier/ sufferer of the disorder, then there are
chances that disorder will be passed on to the offsprings. In order to prevent this
transmission, people should get their blood examined before marriage to know if they
are a carrier of any genetic disorder.
Question 4:
Write a brief note on each.
a. Down’s Syndrome: Down's syndrome is caused due to the presence of an additional
copy of chromosome 21 (Trisomy of 21). It was the first discovered and described
chromosomal disorder in humans. The total number of chromosomes in people affected
with Down's syndrome becomes 47. Affected individual has short stature, small, round
head, furrowed tongue, partially opened mouth, palm crease, congenital heart disease
and mental retardation.
b. Monogenic disorders: Monogenic disorders are genetic disorders which are caused
by a mutation in a single gene. This mutation may be present on one or both the
chromosomes. Some of the examples of monogenic disorders are sickle cell anemia,
cystic fibrosis, polycystic kidney etc.
c. Sickle cell anaemia: Sickle-cell anaemia is an autosome-linked recessive trait
exhibiting change in shape of the red blood cells from biconcave disk to sickle shape
under low oxygen tension. It is a result of replacement of GAG by GUG leading to the
substitution of Glu by Val at sixth position of beta globin chain of haemoglobin. It is
characterised by low haemoglobin count and other symptoms of anaemia such as
fatigue and irritability, swelling on hands and legs, pain in joints, constant low grade
fever etc.
There is no particular treatment for sickle cell anemia, the treatments which are
available provide symptomatic relief from the symptoms associated with this disorder.
Question 5:
A
B
C
Leber hereditary
optic neuropath
y
Mitochondrial
disorder
This disorder arises
during development
of zygote.
Diabetes
Polygenic
disorder
Effect on bloodglucose level
Albinism
Monogenic
disorder
Pale skin,white
hairs
Turner
syndrome
45+X
Women are sterile
Klinefelter syndr
ome
44+XXY
Men are sterile
Question 6:
Filling the blanks based on the given relationship.
a. 44+X:Turner syndrome: :44+XXY:- Klinefelter syndrome
b. 3:1 Monohybrid: : 9:3:3:1 : Dihybrid cross
c. Women : Turner syndrome : : Men : Klinefelter syndrome
Question 7:
Complete the tree diagram below based on types of hereditary disorders.
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