P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> i ESSENTIAL E Further Mathematics PL Third edition SA M PETER JONES MICHAEL EVANS KAY LIPSON TI-Nspire and Casio ClassPad material prepared in collaboration with Russell Brown Kevin McMenamin Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> CAMBRIDGE UNIVERSITY PRESS Cambridge, New York, Melbourne, Madrid, Cape Town, Singapore, São Paulo Cambridge University Press 477 Williamstown Road, Port Melbourne, VIC 3207, Australia www.cambridge.edu.au Information on this title: www.cambridge.edu.au/0521613280 Peter Jones, Michael Evans & Kay Lipson 2005 First published 1998 Reprinted 1998 Second edition 1999 Reprinted 2000, 2001, 2002, 2003, 2005 Third edition 2005 Reprinted 2006 E C PL Cover designed by Modern Art Production Group Text designed by Sylvia Witte Typeset in India by Techbooks Printed in China through Everbest Printing Company Pty Ltd National Library of Australia Cataloguing in Publication data Jones, Peter, 1943-. Essential further mathematics. 3rd ed. ISBN-13 978-0-521-74051-7 paperback ISBN-10 0-521-61328-0 paperback 1. Mathematics – Problems, exercises, etc. I. Evans, Michael (Michael Wyndham). II. Lipson, Kay. III. Title 510.76 SA M ISBN-13 978-0-521-74051-7 paperback ISBN-10 0-521-61328-0 paperback Reproduction and communication for educational purposes The Australian Copyright Act 1968 (the Act) allows a maximum of one chapter or 10% of the pages of this publication, whichever is the greater, to be reproduced and/or communicated by any educational institution for its educational purposes provided that the educational institution (or the body that administers it) has given a remuneration notice to Copyright Agency Limited (CAL) under the Act. 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P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> PL E Contents Acknowledgements xiv CORE CHAPTER 1 — Organising and displaying data Classifying data 1 Organising and displaying categorical data Organising and displaying numerical data What to look for in a histogram 20 Stem-and-leaf plots and dot plots 26 Key ideas and chapter summary 34 Skills check 35 Multiple-choice questions 35 Extended-response questions 37 SA M 1.1 1.2 1.3 1.4 1.5 1 3 8 CHAPTER 2 — Summarising numerical data: the median, range, IQR and box plots 2.1 2.2 2.3 2.4 2.5 40 Will less than the whole picture do? 40 The median, range and interquartile range (IQR) 41 The five-number summary and the box plot 45 Relating a box plot to distribution shape 52 Interpreting box plots: describing and comparing distributions 54 Key ideas and chapter summary 57 Skills check 58 Multiple-choice questions 59 Extended-response questions 60 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents CHAPTER 3 — Summarising numerical data: the mean and the standard deviation 3.3 The mean 63 Measuring the spread around the mean: the standard deviation 67 The normal distribution and the 68–95–99.7% rule: giving meaning to the standard deviation 73 Standard scores 79 Populations and samples 83 Key ideas and chapter summary 88 Skills check 90 Multiple-choice questions 91 Extended-response questions 92 PL 3.4 3.5 63 E 3.1 3.2 CHAPTER 4 — Displaying and describing relationships between two variables 4.1 4.2 4.3 4.4 4.5 4.6 4.7 4.8 4.9 95 Investigating the relationship between two categorical variables 95 Using a segmented bar chart to identify relationships in tabulated data 99 Investigating the relationship between a numerical and a categorical variable 102 Investigating the relationship between two numerical variables 104 How to interpret a scatterplot 107 Calculating Pearson’s correlation coefficient r 112 The coefficient of determination 118 Correlation and causality 121 Which graph? 122 Key ideas and chapter summary 123 Skills check 124 Multiple-choice questions 125 Extended-response questions 128 SA M iv CHAPTER 5 — Regression: fitting lines to data 5.1 5.2 5.3 5.4 5.5 131 Least squares regression line: the theory 131 Calculating the equation of the least squares regression line 133 Performing a regression analysis 140 A graphical approach to regression: the three median line 153 Extrapolation and interpolation 157 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents v Key ideas and chapter summary 159 Skills check 160 Multiple-choice questions 160 Extended-response questions 162 CHAPTER 6 — Data transformation E Data transformation 166 Transforming the x axis 169 183 Transforming the y axis Choosing and applying the appropriate transformation 189 Key ideas and chapter summary 197 Skills check 197 Multiple-choice questions 197 Extended-response questions 200 PL 6.1 6.2 6.3 6.4 CHAPTER 7 — Time series 7.1 7.2 7.3 204 Time series data 204 Smoothing a time series plot (moving means) 210 Smoothing a time series plot (moving medians) 215 Seasonal indices 220 Fitting a trend line and forecasting 207 Key ideas and chapter summary 233 Skills check 234 Multiple-choice questions 235 Extended-response questions 237 SA M 7.4 7.5 CHAPTER 8 — Revision of the core 8.1 8.2 8.3 8.4 8.5 166 239 Displaying, summarising and describing univariate data 239 Displaying, summarising and describing relationships in bivariate data 243 Regression and data transformation 245 Time series 249 Extended-response questions 253 MODULE 1 — Number patterns and applications CHAPTER 9 — Arithmetic and geometric sequences 259 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents 9.4 9.5 9.6 9.7 9.8 297 PL 9.9 9.10 Sequences 259 Arithmetic sequences 260 The nth term of an arithmetic sequence and its applications 264 The sum of an arithmetic sequence and its applications 274 Geometric sequences 281 The nth term of a geometric sequence 285 Applications modelled by geometric sequences 289 The sum of the terms in a geometric sequence 294 The sum of an infinite geometric sequence Rates of growth of arithmetic and geometric sequences 302 Key ideas and chapter summary 307 Skills check 308 Multiple-choice questions 309 Extended-response questions 310 E 9.1 9.2 9.3 CHAPTER 10 — Difference equations 10.1 10.2 312 Introduction 312 The relationship between arithmetic and geometric sequences and difference equations 320 First-order difference equations 322 Solving first-order difference equations that generate arithmetic sequences 324 Solving difference equations that generate geometric sequences 325 Solution of general first-order difference equations (optional) 327 Summary of first-order difference equations 328 Applications of first-order difference equations 329 The Fibonacci sequence 338 Key ideas and chapter summary 345 Skills check 346 Multiple-choice questions 346 Extended-response questions 348 SA M vi 10.3 10.4 10.5 10.6 10.7 10.8 10.9 CHAPTER 11 — Revision: Number patterns and applications 11.1 11.2 350 Multiple-choice questions 350 Extended-response questions 355 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents vii MODULE 2 — Geometry and trigonometry CHAPTER 12 — Geometry E Properties of parallel lines – a review 360 Properties of triangles – a review 362 Properties of regular polygons – a review 364 Pythagoras’ theorem 367 Similar figures 371 Volumes and surface areas 375 Areas, volumes and similarity 382 387 Key ideas and chapter summary Skills check 389 Multiple-choice questions 390 PL 12.1 12.2 12.3 12.4 12.5 12.6 12.7 CHAPTER 13 — Trigonometry 392 Defining sine, cosine and tangent The sine rule 396 The cosine rule 401 Area of a triangle 404 Key ideas and chapter summary Skills check 407 Multiple-choice questions 408 SA M 13.1 13.2 13.3 13.4 360 392 406 CHAPTER 14 — Applications of geometry and trigonometry 14.1 14.2 14.3 410 Angles of elevation and depression, bearings, and triangulation 410 Problems in three dimensions 417 Contour maps 421 Key ideas and chapter summary 424 Skills check 424 Multiple-choice questions 424 Extended-response questions 426 CHAPTER 15 — Revision: Geometry and trigonometry 15.1 15.2 431 Multiple-choice questions 431 Extended-response questions 438 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents MODULE 3 — Graphs and relations CHAPTER 16 — Constructing and interpreting linear graphs The gradient of a straight line 441 The general equation of a straight line 443 Finding the equation of a straight line 445 Equation of a straight line in intercept form 449 Linear models 450 Simultaneous equations 452 Problems involving simultaneous linear equations 456 Break-even analysis 458 Key ideas and chapter summary 460 Skills check 461 Multiple-choice questions 461 PL 16.8 441 E 16.1 16.2 16.3 16.4 16.5 16.6 16.7 CHAPTER 17 — Graphs 17.1 17.2 17.3 17.4 17.5 465 Line segment graphs 465 Step graphs 468 Non-linear graphs 470 Relations of the form y = kxn for n = 1, 2, 3, −1, −1, − −2 2 472 Linear representation of non-linear relations Key ideas and chapter summary 482 Skills check 483 Multiple-choice questions 483 Extended-response questions 486 SA M viii CHAPTER 18 — Linear programming 18.1 18.2 18.3 18.4 488 Regions defined by an inequality 488 Regions defined by two inequalities 490 Feasible regions 492 Objective functions 493 Key ideas and chapter summary 503 Skills check 504 Multiple-choice questions 505 Extended-response questions 507 CHAPTER 19 — Revision: Graphs and relations 19.1 19.2 475 510 Multiple-choice questions 510 Extended-response questions 514 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents ix MODULE 4 — Business related mathematics CHAPTER 20 — Principles of financial mathematics Percentage change 521 Simple interest 526 Compound interest 534 Reducing balance loans 546 548 Key ideas and chapter summary Skills check 549 Multiple-choice questions 549 Extended-response questions 551 E 20.1 20.2 20.3 20.4 521 CHAPTER 21 — Applications of financial Percentage changes and charges 553 Bank account balances 558 Hire purchase 561 Inflation 567 Depreciation 571 Applications of Finance Solvers 581 Key ideas and chapter summary 597 Skills check 599 Multiple-choice questions 600 Extended-response questions 602 SA M 21.1 21.2 21.3 21.4 21.5 21.6 553 PL mathematics CHAPTER 22 — Revision: Business-related mathematics 22.1 22.2 606 Multiple-choice questions 606 Extended-response questions 610 MODULE 5 — Networks and decision mathematics CHAPTER 23 — Undirected graphs 23.1 23.2 23.3 23.4 23.5 614 Introduction and definitions 614 Planar graphs and Euler’s formula 619 Complete graphs 622 Euler and Hamilton paths 623 Weighted graphs 626 Key ideas and chapter summary 630 Skills check 632 Multiple-choice questions 632 Extended-response questions 636 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents CHAPTER 24 — Directed graphs 639 Introduction, reachability and dominance Network flows 645 The critical path problem 649 Allocation problems 656 Key ideas and chapter summary 662 Skills check 663 Multiple-choice questions 663 Extended-response questions 667 639 E 24.1 24.2 24.3 24.4 CHAPTER 25 — Revision: Networks and decision mathematics 671 Multiple-choice questions 671 Extended-response questions 677 PL 25.1 25.2 MODULE 6 — Matrices and applications CHAPTER 26 — Matrices and applications 1 26.1 26.2 26.3 26.4 CHAPTER 27 — Matrices and applications II 27.1 27.2 27.3 27.4 690 What is a matrix? 690 Using matrices to represent information 696 Matrix arithmetic: addition, subtraction and scalar multiplication 699 Matrix arithmetic: the product of two matrices 706 Key ideas and chapter summary 715 Skills check 717 Multiple-choice questions 717 Extended-response questions 720 SA M x 722 The inverse matrix 722 Applications of the inverse matrix: solving simultaneous linear equations 729 Matrix powers 737 Transition matrices and their applications 739 Key ideas and chapter summary 749 Skills check 751 Multiple-choice questions 751 Extended-response questions 754 Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> Contents xi CHAPTER 28 — Revision: Matrices and applications 756 Multiple-choice questions 756 Extended-response questions 760 Appendix TI-nspire 763 Appendix ClassPad 768 771 SA M PL E Answers Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin Ess Maths IN-BOOK BROCHUR.qxd 11/3/05 7:37 PM Page xii Quark08 Quark08:Books:CUAT006_From Pooja:CUAT013: The new Essential series for the 2006 study design 1 CORE Organising and displaying data What is the difference between categorical and numerical data? What is a frequency table, how is it constructed and when is it used? What is the mode and how do we determine its value? What are bar charts, histograms, stem plots and dot plots? How are they constructed and when are they used? How do you describe the features of bar charts, histograms and stem plots when In each chapter you will find … writing a statistical report? 1.1 Classifying data Statistics is a science concerned with understanding the world through data. The first step in this process is to put the data into a form that makes it easier to see patterns or trends. Some data The data contained in Table 1.1 is part of a larger set of data collected from a group of university students. Chapter 9 – Arithmetic and geometric sequences 237 data Table 1.1 Student Height (cm) How to use a graphics calculator to generate the terms of an arithmetic sequence on the Home screen Weight (kg) Age (years) Sex M male F female female 57 58 62 84 64 74 60 50 18 19 18 18 18 22 19 34 M M M F M F F M Plays sport 1 regularly 2 sometimes 3 rarely rarely 2 2 1 1 3 3 3 3 Pulse rate (beats/min) 86 82 96 71 90 78 88 70 E 173 Generate the first five terms of the arithmetic sequence: 2, 7, 12, 17, 22, . . . 179 167 Steps 195 173 1 Start on the Home screen. Clear. Enter the value of the 184 first term 2. Press Í. 175 140 Source: www.statsci.org/data/oz/ms212.html. Used with permission. 2 The common difference for this sequence is 5. So, type in + 5. Press Í.. The second term in the sequence, 7, is generated. 3 Pressing Í again generates the next term, 12. 4 Pressing Í again generates the next term, 17. Keep pressing Í until the required number of terms is generated. Being able to recognise an arithmetic sequence is another skill that you need to develop. The key idea here is that the successive terms in an arithmetic sequence differ by a constant amount (the common difference). PL a vibrant full colour text with a clear layout that makes maths more accessible for students 1 ‘Using a graphics calculator’ boxes within chapters explain how to do problems using the TI-83/Plus and TI-84 graphics calculators, and include screen shots to further assist students Example 1 Testing for an arithmetic sequence 20, 17 17,, 14, 14, 11 11,, 8, 8, . . . arithmetic? a Is the sequence 20, Chapterr 4 — Displaying and describing relationships between two variables Chapte 107 Solution Clearly, traffic volume is a very good predictor of carbon monoxide levels in the air. Knowing Strategy:: Subtract successive terms in the sequence to see whether they differ by a constant Strategy the traffic volume will enable us to predict carbon monoxide levels with a high degree of amount. If they do, the sequence is arithmetic. accuracy. This contrasts with the next example, which concerns the ability to predict 20,, 17, 20 17, 14, 14, 11, 11, 8, 8, . . . 1 Write down the terms of the sequence. mathematical ability from verbal ability. 17 − 20 = −3 −3 2 Subtract successive terms. 14 − 17 = −3 −3 Example 3 Calculating and interpreting the coefficient of determination 11 − 14 = −3 −3 and so on Sequence Sequ ence is arithmetic as terms differ by a Scores on tests of verbal and mathematical ability are linearly related with: constant amount. 3 Write down your conclusion rmathematical, verbal = +0.275 Determine the value of the coefficient of determination, write it in percentage terms, and interpret. In this relationship, mathematical ability is the DV. Solution SA M a wealth of worked examples that support theory explanations within chapters carefully graduated exercises that include a number of easier lead-in questions to provide students with a greater opportunity for immediate success chapter summaries at the end of each chapter provide students with a coherent overview chapter reviews that include key ideas and chapter summary and skills check lists, and multiplechoice and extended-response questions Appendices that include a TIAppendices 83/84 Plus help guide and stepby-step worked examples using TI-89 Graphics Calculators revision chapters to help consolidate student knowledge The coefficient of determination is: r 2 = (0.275)2 = 0.0756 . . . or 0.076 × 100 = 7.6% Therefore, only 7.6% of the variation observed in scores on the test of mathematical ability can be explained by the variation in scores obtained on the test of verbal ability. Clearly, scores on the verbal ability test are not good predictors of the scores on the mathematical ability test; 92.4% of the variation in mathematical ability is explained by other factors. Exercise 4G 1 For each of the following values of r, calculate the value of the coefficient of determination and convert to a percentage (correct to one decimal place). a r = 0.675 b r = 0.345 c r = −0.567 d r = −0.673 e r = 0.124 2 a For the relationship described by the scatterplot 173 shown opposite, the coefficient of determination = 0.8215. Determine the value of the correlation coefficient r (correct to three decimal places). Chapter 6 — Data transformation Review New Essential Mathematics Series Back to Menu >>> C H A P T E R Key ideas and chapter summary Data transformation This means changing the scale on either the x or y axis. It is performed when a residual plot shows that the underlying b For the relationship described by the scatterplot shown relationship in a set of bivariate data is clearly non-linear. opposite, the coefficient of determination = 0.1243. x2 or y2 transformation the value of the correlation coefficient r The square transformation stretches out the upper end Determine of the scale on an axis. (correct to three decimal places). The log transformation compresses the upper end of the scale on an axis. log x or log y transformation 1 1 or transformation x y The reciprocal transformation compresses the upper end of the scale on an axis to a greater extent than the log transformation. Residual plots Residual plots are used to assess the effectiveness of each data transformation. Coefficient of determination (r2 ) The transformation which results in a linear relationship and which has the highest value of the coefficient of determination is considered to be the best transformation. The circle of transformations The circle of transformations provides guidance in choosing the transformations that can be used to linearise various types of scatterplots. See page 166. Skills check Having completed this chapter you should be able to: 1 1 recognise which of the x 2 , log x, , y 2 , log y or transformations might be used to x y linearise a bivariate relationship apply each of these transformations to a data set use residual plots and the coefficient of determination r 2 to decide which transformation gives the best model for the relationship use the transformed variable as part of a regression analysis to give a model for the relationship Multiple-choice questions 1 The missing data values, a and b, in the table are: value (value)2 log(value) 1 a 0 A a = 0, b = 0.5 D a = 1, b = 0.602 2 4 b 3 4 9 16 0.477 0.602 B a = 1, b = 0.5 E a = 1, b = 0.693 Glossary C a = 1, b = 0.301 Assignment problem: [p. 602] See allocation problem. A B Activity (CPA): [p. 595] A task to be completed as part of a project. Activities are represented by the edges in the project diagram. Acute angle: An angle less than 90◦ . Bar chart: [p. 4] A statistical graph used to display the frequency distribution of categorical data. Bearing: [p. 371] See true bearing. Adjacency matrix: [pp. 561, 586] A square matrix showing the number of edges joining each pair of vertices in a graph. Algorithm: A step-by-step procedure for solving a particular problem that involves applying the same process repeatedly. Examples include Prim’s algorithm and the Hungarian algorithm. Allocation problem: [p. 602] A problem that involves finding the best way to match a given number of objects (people, machines, etc.) to a given number of activities. Alternate angles: [p. 320] Angle of depression: [p. 371] The angle between the horizontal and a direction below the horizontal. Angle of elevation: [p. 371] The angle between the horizontal and a direction above the horizontal. Angle sum of a triangle: [p. 322] In triangle ABC, <A + <B + <C = 180◦ . Annuity equation: [pp. 531, 534] The equation: A = PRn − Q(R n − 1) r , where R = 1 + . R−1 100 The annuity equation can be used to determine either the amount owed on a reducing balance loan with regular repayments, or the value of an investment (annuity) with regular payments or withdrawals. Area of a triangle: [p. 364] See also Heron’s formula. Arithmetic sequence: [p. 236] A sequence whose successive terms differ by a constant amount (d) called the common difference. Given the value of the first term in an arithmetic sequence (a), there are rules for finding the nth term and the sum of the first n terms. Bipartite graph (bigraph): [p. 562] A graph whose set of vertices can be split into two subsets, X and Y, in such a way that each edge of the graph joins a vertex in X and a vertex in Y. Bivariate data: [p. 85] Data associated with two related variables. Book value: [p. 526] The value of an item after depreciation. Box plot (standard): [p. 41] A graphical representation of a five number summary. Box plot (with outliers): [p. 42] A modified form of the standard box plot in which possible outliers are shown. Possible outliers are defined as data values greater than Q 3 + 1.5 × IQR and less than Q 1 − 1.5 × IQR. Break-even analysis: [p. 418] Finding the point where the revenue of a business first equals the costs of running the business. Past this point, the business is running at a profit: profit = revenue − costs. C Capacity of a cut: [p. 592] The sum of the capacities (weights) of the edges directed from X to Y that the cut passes through. Categorical data: [p. 2] Data obtained when classifying or naming some quality or attribute, for example: place of birth, hair colour. Causal relationship: [p. 108] When the change in one variable in a relationship can be said to be the direct result of a change in a second variable, the relationship is said to be causal. A high correlation between two variables does not necessarily mean that the variables are causally related. a comprehensive glossary of mathematical terms with page . assist¥• Uncorrected in the ‘open Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson Cambridge references University to Press TI-Nspire &book’ Casioexam ClassPad material in collaboration with Brown and McMenamin 705 Ess Maths IN-BOOK BROCHUR.qxd 11/3/05 7:37 PM Page xiii Quark08 Quark08:Books:CUAT006_From Pooja:CUAT013: Back to Menu >>> Explaining icons in the book ... Links to Teacher CD-ROM Gives an extra hint in extended-response questions that a numerical approach is required Indicates that there is an explanation in Appendix B as to how this example may be done using TI-89 Graphics Calculators Indicates that a skillsheet is available to provide further practice and examples in this area. If students are having difficulty they can approach pproach their teacher who can access this material on the Teacher CD-ROM. Links to Student CD-ROM E Calculator icons PL Live links to interactive files on the Student CD-ROM. What teachers and students will find on the CD-ROMs ... Teacher CD-ROM The Essential Further Mathematics Teacher CD-ROM contains a wealth of time-saving assessment and classroom resources including: SA M modifiable chapter tests and answers containing multiple-choice and short-answer questions chapter review assignments with extended problems that can be given to students in class or can be completed at home printable versions of the multiple-choice questions from the Student CD-ROM print-ready skillsheets to revise the prerequisite knowledge and skills required for the chapter editable Exam Question Sets from which teachers can create their own exams. Student CD-ROM The textbook includes a Student CD-ROM that contains a PDF of the book, interactive multiple-choice questions and unique drag-and-drop activities. Technology aapplets pplets such as PowerPoint and Excel activites are also included. Additional resources ... Solutions Supplements Websites The Essential Further Mathematics Third Edition Solutions Supplement book provides solutions to the extended-response questions, highlighting the process as well as the answer. Teacher Website This dynamic website enables teachers to interact with each other through teacher forums, to send questions to the authors and to obtain updates. www.essentialmaths.com.au Student Website This free student website contains a student forum allowing keen mathematics students to interact with each other, as well as interactive tests and links to other useful sites. Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517agg.xml CUAT013-EVANS September 7, 2008 11:27 Back to Menu >>> E Acknowledgements SA M PL Cambridge University Press and the authors would like to acknowledge all the reviewers who provided invaluable feedback throughout the development of this text. In particular we would like to thank Cathy Ashworth (Sandringham Secondary College), Anthony Gale (Catholic Regional College, Sydenham), Tim Grant (St Bernard’s College, Essendon), David Greenwood (Trinity Grammar School, Kew), Fran Petrie (Melbourne High School), Paul Rice (St Bernard’s College, Essendon), Inna Smith (St Michael’s Grammar School, St Kilda), Kyle Staggard (Bendigo Senior Secondary College), Leah Whiffin (Bendigo Senior Secondary College), and Joe Wilson (Mill Park Secondary College). We also acknowledge the work of James Wan and James Hillis who checked all of the answers in this book. Cambridge University Press ¥• Uncorrected Sample pages ¥• 978-0-521-61328-6 •¥ 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> C H A P T E R 1 CORE PL E Organising and displaying data What is the difference between categorical and numerical data? What is a frequency table, how is it constructed and when is it used? What is the mode and how do we determine its value? What are bar charts, histograms, stem plots and dot plots? How are they constructed and when are they used? How do you describe the features of bar charts, histograms and stem plots when SA M writing a statistical report? 1.1 Classifying data Statistics is a science concerned with understanding the world through data. The first step in this process is to put the data into a form that makes it easier to see patterns or trends. Some data The data contained in Table 1.1 is part of a larger set of data collected from a group of university students. Table 1.1 Student data Height (cm) Weight (kg) Age (years) Sex M male F female 173 179 167 195 173 184 175 140 57 58 62 84 64 74 60 50 18 19 18 18 18 22 19 34 M M M F M F F M Plays sport 1 regularly 2 sometimes 3 rarely 2 2 1 1 3 3 3 3 Pulse rate (beats/min) 86 82 96 71 90 78 88 70 Source: www.statsci.org/data/oz/ms212.html. Used with permission. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson 1 and McMenamin TI-Nspire & Casio ClassPad material in collaboration with Brown P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core E Variables In a data set, we call the things about which we record information variables. An important first step in analysing any set of data is to identify the variables involved, their units of measurement (where appropriate) and the values they take. In this particular data set there are six variables: height (in centimetres) sex (M = male, F = female) weight (in kilograms) plays sport (1 = regularly, 2 = sometimes, 3 = rarely) age (in years) pulse rate (beats/minute) Types of variables: categorical and numerical PL Having identified the variables we are working with, the next step is to decide the variable type. Some variables represent qualities or attributes. For example, ‘F’ in the Sex column indicates that the person is a female, while a ‘2’ in the Plays sport column indicates that the person is someone who plays sport sometimes. Variables that represent qualities are called categorical variables. Other variables represent quantities. For example, a ‘179’ in the Height column indicates that the person is 179 cm tall, while an ‘82’ in the Pulse rate column indicates that they have a pulse rate of 82 beats/minute. Variables that represent quantities are called numerical variables. Numerical variables come in two types, discrete and continuous. Discrete numerical variables represent quantities that are counted. The number of mobile phones in a house is an example. Counting leads to discrete data values because it results in values like 0, 1, 2, 3 etc. There can be nothing in between. As a guide, discrete numerical variables arise when we ask the question ‘How many?’ Continuous numerical variables represent quantities that are measured rather than counted. Thus, even though we might record a person’s height as 179 cm, in reality that could be any value between 178.5 and 179.4 cm. We have just rounded off the height to 179 cm for convenience, or to match the accuracy of the measuring device. SA M 2 Warning!! It is not the variable name itself that determines whether the data is numerical or categorical, it is the way the data for the variable is recorded. For example: ‘weight’ recorded in kilograms, is a numerical variable ‘weight’ recorded as 1 = underweight, 2 = normal weight, 3 = overweight, is a categorical variable Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 3 Exercise 1A 1 What is: a a numerical variable? Give an example. b a categorical variable? Give an example. 2 There are two types of numerical variables. Name them. length of bananas (in centimetres) h number of cars in a supermarket car park i daily temperature in ◦ C j eye colour (brown, blue, . . . ) k shoe size (6, 8, 10, . . . ) l the number of children in a family m city of residence (NY, London, . . . ) n number of people who live in your city/area time spent watching TV (hours) the TV channel most watched by students salary (high, medium, low) salary (in dollars) whether a person smokes (yes, no) the number of cigarettes smoked per day PL a b c d e f g E 3 Classify each of the following variables as numerical or categorical. If the variable is numerical, further classify the variable as discrete or continuous. Recording information on: 4 Classify the data for each of the variables in Table 1.1 as numerical or categorical. Organising and displaying categorical data SA M 1.2 The frequency table With a large number of data values, it is difficult to identify any patterns or trends in the raw data. We first need to organise the data into a more manageable form. A statistical tool we use for this purpose is the frequency table. The frequency table A frequency table is a listing of the values a variable takes in a data set, along with how often (frequently) each value occurs. Frequency can be recorded as a count: the number of times a value occurs, or percent: the percentage of times a value occurs count × 100% total count A listing of the values a variable takes, along with how frequently each of these values occurs in a data set, is called a frequency distribution. percent = Example 1 Frequency table for a categorical variable The sex of 11 preschool children is as shown (F = female, M = male): F M M F F M F F F M M Construct a frequency table to display the data. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Solution Frequency Sex Count Percent Female Male 6 5 54.5 45.5 Total 11 100.0 E 1 Set up a table as shown. The variable Sex has two categories, ‘Male’ and ‘Female’. 2 Count up the number of females (6) and males (5). Record in the ‘Count’ column. 3 Add the counts to find the total count, 11 (6+5). Record in the ‘Count’ column opposite ‘Total’. 4 Convert the counts into percentages. Record in the ‘Percent’ column. For example: 6 × 100% = 54.5% 11 5 Finally, total the percentages and record. PL percentage of females = There are two things to note in constructing the frequency table in Example 1. 1 In setting up this frequency table, the order in which we have listed the categories ‘Female’ and ‘Male’ is quite arbitrary; there is no natural order. However, if the categories had been, for example, ‘First’, ‘Second’ and ‘Third’, then it would make sense to list the categories in that order. 2 The Total count should always equal the total number of observations, in this case 11. The percentages should add to 100%. However, if percentages are rounded to one decimal place a total of 99.9 or 100.1 is sometimes obtained. This is due to rounding error. Totalling the count and percentages helps check on your counting and percentaging. SA M 4 How has forming a frequency table helped? The process of forming a frequency table for a categorical variable: displays the data in a compact form tells us something about the way the data values are distributed (the pattern of the data) The bar chart Once categorical data has been organised into a frequency table, it is common practice to display the information graphically to help identify any features that stand out in the data. A statistical tool we use for this purpose is the bar chart. The bar chart pictures the key information in a frequency table. It is designed for categorical data. In a bar chart: frequency (or percentage frequency) is shown on the vertical axis the variable being displayed is plotted on the horizontal axis the height of the bar (column) gives the frequency (count or percentage) the bars are drawn with gaps between them to indicate that each value is a separate category there is one bar for each category Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 5 Example 2 Constructing a bar chart from a frequency table Construct a bar chart for this frequency table. 3 14 6 23 13.0 60.9 26.1 100.0 15 SA M PL 1 Label the horizontal axis with the variable name, ‘Climate type’. Mark the scale off into three equal intervals and label, ‘Cold’, Moderate’ and ‘Hot’. 2 Label the vertical axis ‘Frequency’. Scale allowing for the maximum frequency, 14. Fifteen would be appropriate. Mark the scale off in fives. 3 For each interval, draw in a bar. There are gaps between the bars to show that the categories are separate. The height of the bar is made equal to the frequency. Cold Moderate Hot Total E Solution Climate type Frequency Count Percent Frequency 10 5 0 Cold Moderate Climate type Hot The mode One of the features of a data set that is quickly revealed with a bar chart is the mode or modal category. This is the most frequently occurring value or category. This is given by the category with the tallest bar. For the bar chart above, the modal category is clearly ‘Moderate’. That is, for the countries considered, the most frequently occurring climate type is ‘Moderate’. However, the mode is only of interest when a single value or category in the frequency table occurs much more often than the others. Modes are of particular importance in ‘popularity’ polls. For example, in answering questions like ‘Which is the most frequently watched TV station between the hours of 6.00 and 8.00 p.m.?’ or ‘What are the times when a supermarket is in peak demand, ‘morning’, ‘afternoon’ or ‘night’?’ What to look for in a frequency distribution of a categorical variable: writing a report A bar chart, in combination with a frequency table, is useful for gaining an overall view of a frequency distribution of a categorical variable, the so-called ‘big picture’. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Describing a bar chart In describing a bar chart, we focus on two things: the presence of a dominant category (or group of categories) in the distribution. This is given by the mode. If there is no dominant category, then this should be stated. the order of occurrence of each category and its relative importance E In commenting on these features, it is usual to support your conclusions with percentages. When quoting percentages, it is also advisable to indicate at the beginning the total number of cases involved. Using the information in Example 2 to describe the distribution of climate type, you might write as follows: Report PL The climate types of 23 countries were classified as being, `cold', `moderate' or `hot'. The majority of the countries, 60.9%, were found to have a moderate climate. Of the remaining countries, 26.1% were found to have a hot climate while 13.0% were found to have a cold climate. Stacked or segmented bar charts Percentage Frequency 25 A variation on the standard bar chart is the Climate Hot segmented or stacked bar chart. In a Moderate 20 segmented bar chart, the bars are stacked Cold on one another to give a single bar with 15 several components. The lengths of the 10 segments are determined by the frequencies. When this is done, the height of the bar gives 5 the total frequency. Segmented bar charts should only be used when there are 0 a relatively small number of components, usually no more than four or five, because it becomes difficult to distinguish the components. The segmented bar chart above was formed from the climate data used in Example 2. Note that a legend has been included to identify the segments. In a percentage segmented bar chart, 100 Climate the lengths of each of the segments in the 90 Hot bar are determined by the percentages. 80 Moderate 70 When this is done, the height of the bar is Cold 60 100. The percentage segmented bar chart 50 opposite was formed from the climate data 40 used in Example 2. 30 Percentage segmented bar charts are most 20 10 useful when we come to analyse the 0 relationship between two categorical variables, as we will see in Chapter 4. SA M 6 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 7 Exercise 1B 1 a In a frequency table, what is the mode? b Identify the mode in the following data sets: i Grades: A A C B A B B B ii Shoe size: 8 9 9 10 8 8 7 9 8 B 10 D C 12 8 10 E 2 The following data; 2 1 1 1 3 1 3 1 1 3 3 identifies the state of residence of a group of people, where 1 = Victoria, 2 = SA and 3 = WA. PL a Form a frequency table (with both counts and percentages) to show the distribution of state of residence for this group of people. Use the table in Example 1 as a model. b Construct a bar chart using Example 2 as a model. 3 The size (S = small, M = medium, L = large) of 20 cars was recorded as follows: S M S S L L M S M M M M L M S S S S M M SA M a Form a frequency table (with both counts and percentages) to show the distribution of size for these cars. Use the table in Example 1 as a model. b Construct a bar chart using Example 2 as a model. 4 The table shows the frequency distribution of School type for a number of schools. The table is incomplete. a Write down the information missing from the table. b How many schools are categorised as ‘Independent’? c How many schools are there in total? d What percentage of schools are categorised as ‘Government’? e Use the information in the frequency table to complete the following report. School type Catholic Government Independent Total Frequency Count Percent 4 11 5 20 25 100 Report schools were classified according to school type. The majority of these schools, %, schools. Of the remaining schools, were while were found to be schools. 20% were Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> 8 Essential Further Mathematics – Core 5 The table shows the frequency distribution of the place of birth for 500 Australians. a Is Place of birth a categorical or a numerical variable? b Display the data in the form of a percentage segmented bar chart. c Use the information in the frequency table to write a brief report. Place of birth Percent Australia Overseas Total 78.3 21.8 100.1 Type of vehicle Private Commercial Total Frequency Count Percent 132 736 49 109 PL a Copy and complete the table giving the percentages correct to the nearest whole number. b Display the data in the form of a percentage segmented bar chart. E 6 The table records the number of new cars sold in Australia during the first quarter of 2005 categorised by type (private vehicle or commercial vehicle). 7 The table shows the frequency distribution of eye colour of 11 preschool children. SA M a Use the information in the table to construct a bar chart. Place the columns in order of decreasing frequency. b Use the information in the table to construct a percentage segmented bar chart. c Use the information in the table to write a brief report. 8 Twenty-two students were asked the question, ‘How often do you play sport?’ with the possible response: ‘Regularly’, ‘Sometimes’ or ‘Rarely’. The distribution of responses is summarised in the frequency table. a Write down the information missing from the table. b Use the information in the frequency table to complete the following report. Frequency Eye colour Count Percentage Brown Hazel Blue Total 6 2 3 11 Plays sport Frequency Count Percent Regularly Sometimes Rarely Total 54.5 18.2 27.3 100.0 5 10 22.7 31.8 22 Report When students were asked the question, `How often do you play sport', the dominant % of the students. Of the remaining students, response was `Sometimes', given by % of the students responded that they played sport while % said they that . they played sport 1.3 Organising and displaying numerical data Frequency tables can also be used to organise numerical data. For discrete numerical data, the process exactly mirrors that for categorical data. For continuous data, some modifications need to be made because groups of data values, rather than individual values are listed. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 9 Example 3 Frequency table for discrete numerical data The family size of 11 preschool children (including the child itself) is as follows: 3 3 4 4 5 3 2 4 3 5 3 Display the data in the form of a frequency table. Solution E Frequency Family size Count Percent 2 3 4 5 1 5 3 2 9.1 45.5 27.3 18.2 Total 11 100.1 PL 1 Set up a table as shown. In the data set, the variable family size takes the values 2, 3, 4 and 5. List these values under ‘Family size’ in some order, here increasing. 2 Count up the number of 2s, 3s, 4s and 5s in the dataset. For example, there are five 3s. Record these values in the ‘Count’ column. 3 Add the counts to find the total count, 11. Record this value in the ‘Count’ column opposite ‘Total’. 4 Convert the counts into percents. Record in the ‘Percent’ column. For example, 5 × 100% = 45.5% 11 5 Finally, total the percentages and record. SA M percentage of 3s = Grouping data Some variables can only take on a limited range of values, for example, the number of children in a family. Here, it makes sense to list each of these values individually when forming a frequency distribution. In other cases, the variable can take a large range of values, for example age (0–100). Listing all possible ages would be tedious and would produce a large and unwieldy display. To solve this problem, we group the data into a small number of convenient intervals. There are no hard and fast rules for the number of intervals but, normally, between five and fifteen intervals are used. Usually, the smaller the number of data values, the smaller the number of intervals. Note that the intervals are defined so that it is quite clear into which interval each data value falls. For example, you cannot define intervals as, 1–5, 5–10, 10–15, 15–20, . . . etc, as you would not know into which interval to put the values, 5, 10, 15, etc. Guideline for choosing the number of intervals There are no hard and fast rules for the number of intervals to use but, normally, between five and fifteen intervals are used. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Example 4 Grouping data The ages of a sample of 200 people aged from 16 to 72 years are to be recorded. Group the ages into six equal-sized categories that will cover all of these ages. Solution E Number of intervals: 6 57 Interval width = = 9.5: use 10 6 PL 1 Write down the required number of intervals. 2 Determine interval width. Ages range from 16 to 72, which covers 57 years. Six intervals will give intervals 57 = 9.5. of width 6 Set the interval width to 10, the nearest whole number above 9.5. 3 Choose a starting point that ensures that the intervals cover the full range of values. 15 would be a suitable starting point. 4 Write down the intervals. Starting point: 15 Intervals: 15−24, 25−34, . . . , 65−74 Once we know how to group data, we can form a frequency distribution for grouped data. Example 5 A grouped frequency distribution for a continuous numerical variable SA M 10 The data below gives the average hours worked per week in 23 countries. 35.0, 48.0, 45.0, 43.0, 38.2, 50.0, 39.8, 40.7, 40.0, 50.0, 35.4, 38.8, 40.2, 45.0, 45.0, 40.0, 43.0, 48.8, 43.3, 53.1, 35.6, 44.1, 34.8 Form a grouped frequency table with five intervals. Solution 1 Set up a table as shown. For five intervals and data values ranging between 34.8 and 53.1, use the intervals: 30.0–34.9, 35.0–39.9, . . . , 50.0–54.9. 2 List these intervals, in ascending order, under ‘Average hours worked’. 3 Count the number of countries whose average working hours fall into each of the intervals. For example, six countries have average working hours between 35.0 and 39.9. Record these values in the ‘Count’ column. 4 Add the counts to find the total count, 23. Record this value in the ‘Count’ column opposite ‘Total’. Average hours worked 30.0−34.9 35.0−39.9 40.0−44.9 45.0−49.9 50.0−54.9 Total Frequency Count Percent 1 6 8 5 3 4.3 26.1 34.8 21.7 13.0 23 99.9 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 11 5 Convert the counts into percentages. Record in the ‘Percent’ column. For example, for 35.0–39.9 hours, 6 × 100% = 26.1% percentage = 23 6 Finally, total the percentages and record. E There are two things to note in the frequency table in Example 5. 1 The intervals in this example are of width five. For example, the interval 35.0–39.9, is an interval of width 5.0 because it contains all values from 34.9500 . . . to 39.9499. 2 The modal interval is 40.0–44.9 hours; eight (34.8%) of the countries have working hours that fall into this interval. The histogram PL How has forming a frequency table helped? The process of forming a frequency table for a numerical variable: orders the data displays the data in a compact form tells us something about the way the data values are distributed (the pattern of the data) helps us identify the mode (the most frequently occurring value or interval of values) SA M The frequency histogram, or histogram for short, is a graphical way of presenting the information in a frequency table for numerical data. Later in the chapter, you will learn about two other graphical displays for numerical data, the stem plot and the dot plot. Constructing a histogram from a frequency table In a frequency histogram: frequency (count or percent) is shown on the vertical axis the values of the variable being displayed are plotted on the horizontal axis for continuous data, each bar in a histogram corresponds to a data interval. For discrete data, where there are gaps between values, the intervals start and end halfway between values. Empty classes or missing discrete values have bars of zero height. the height of the bar gives the frequency (usually the count, but it can equally well be the percentage) Example 6 Constructing a histogram from a frequency table: continuous numerical variable Construct a histogram for this frequency table. Average hours worked 30.0–34.9 35.0–39.9 40.0–44.9 45.0–49.9 50.0–54.9 Total Frequency (count) 1 6 8 5 3 23 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Solution Example 7 9 8 Frequency 7 6 5 4 E 3 2 1 0 25 30 35 40 45 50 55 Average hours worked 60 PL 1 Label the horizontal axis with the variable name, ‘Average hours worked’. Mark in the scale using the beginning of each interval as the scale points: that is 30, 35, . . . 2 Label the vertical axis ‘Frequency’. Scale allowing for the maximum frequency, 8. Ten would be appropriate. Mark in the scale in units. 3 Finally, for each interval, 30.0–34.9, 35.0–39.9, . . . , draw in a bar with the base starting at the beginning of each interval and finishing at the beginning of the next. The height of the bar is made equal to the frequency. Constructing a histogram from a frequency table: discrete numerical variable Construct a histogram for this frequency table. SA M Family size 2 3 4 5 Total Frequency (count) 1 5 3 2 11 Solution 1 Label the horizontal axis with the variable name, ‘Family size’. Mark the scale in units, so that it includes all possible values. 2 Label the vertical axis ‘Frequency’. Scale to allow for the maximum frequency, 5. Five would be appropriate. Mark the scale in units. 3 Draw in a bar for each data value. The width of each bar is 1, starting and ending halfway between data values. For example, the base of the bar representing a family size of 2 starts at 1.5 and ends at 2.5. The height of the bar is made equal to the frequency. 5 4 Frequency 12 3 2 1 0 1 2 3 4 Family size 5 6 Constructing a histogram from raw data It is relatively quick to construct a histogram from a preprepared frequency table. However, if you only have raw data (as you mostly do), it is a very slow process because you have to construct the frequency table first. Fortunately, a graphics calculator do this forLipson us. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 will © Jones, Evans, TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 13 How to construct a histogram using the TI-Nspire CAS Display the following set of 27 marks in the form of a histogram. 11 12 4 18 25 22 15 17 7 18 14 23 13 15 12 17 15 18 13 22 16 23 14 PL Steps 1 Start a new document: Press c and select 6:New Document (or press / + N ). If prompted to save an existing document move cursor to No and press enter . 14 13 E 16 15 SA M 2 Select 3:Add Lists & Spreadsheet. Enter the data into a list named marks. a Move the cursor to the name space of column A (or any other column) and type in marks as the list name. Press enter . b Move the cursor down to row 1, type in the first data value and press enter . Continue until all the data has been entered. Press enter after each entry. 3 Statistical graphing is done through the Data & Statistics application. Press c and select 5:Data & Statistics. A random display of dots will appear – this is to indicate list data are available for plotting. It is not a statistical plot. a Move cursor to the text box area below the horizontal axis. Press x (click) when prompted and select the variable marks. Press enter to paste the variable marks to that axis. Note: Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Note: PL Your screen should now look like that shown opposite. This histogram has a column (or bin) width of 2 and a starting point of 3. E b A dot plot is displayed as the default plot. To change the plot to a histogram press b /1:Plot Type/3:Histogram. Keystrokes: b 1 3 Count is the same as frequency. To change the count axis to a percentage axis, press / + b /4:Scale/1:Percent Hint: Pressing / + b gives you a contextual menu that enables you to do things that relate only to histograms. 1 2 4 Data analysis a Move the cursor onto any column and a will show and the column will become highlighted. Holding down the centre mouse button x until a appears displays the end points of the selected column (here 11 to < 13) and its frequency or count (i.e. 3). b Press x to change the hand back to . To view other column data values move the cursor to another column and repeat the steps in 4a above. SA M 14 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 15 PL E Hint: To unshade previously selected columns move the cursor to the open area and press x . to undo the Hint: If you accidentally move a column or data point, press / + move. 5 Change the histogram column (bin) width to 4 and the starting point to 2. a Press / + b to get the contextual menu as shown (below left). b Select 5:Bin Settings. c In the settings menu (below right) change the Width to 4 and the Starting Point (Alignment) to 2 as shown. Press enter . SA M d A new histogram is displayed with column width of 4 and a starting point of 2 but it no longer fits the viewing window (below left). To solve this problem press / + b /6:Zoom/2:Zoom-Data to obtain the histogram shown below right. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core How to construct a histogram using the ClassPad Display the following set of 27 marks in the form of a histogram. 11 12 4 18 25 22 15 17 7 18 14 23 13 15 Steps 1 From the application menu screen, locate the built-in Statistics application. 12 17 15 18 13 22 16 23 14 PL to open. Tap from the icon panel (just Tapping below the touch screen) will display the application menu if it is not already visible. 14 13 E 16 15 2 Enter the data into a list named marks. To name the list: a Highlight the heading of the first list by tapping it. b Press k on the front of the tab. calculator and tap the c Type the word marks and press E. To enter the data: d Type in each data value and press E or (which is found on the cursor button on the front of the calculator) to move down to the next cell. The screen should look like the one shown below (left). SA M 16 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 PL 3 Set up the calculator to plot a statistical graph. from the toolbar at a Tap the top of the screen. This opens the Set StatGraphs dialog box. b Complete the dialog box as given below. For • Draw: select On • Type: select Histogram ( ) • XList: select main \ marks ( ) • Freq: leave as 1 c Tap h to confirm your selections. Note: To make sure only this graph is drawn, select SetGraph from the menu bar at the top and confirm there is a tick only beside StatGraph1 and no others. E Back to Menu >>> Chapter 1 — Organising and displaying data 17 SA M 4 To plot the graph: in the toolbar at the a Tap top of the screen. b Complete the Set Interval dialog box for the histogram as given below. For • HStart: type in 2 (i.e. the starting point of the first interval) • HStep: type in 4 (i.e. the interval width) Tap OK. The screen is split into two halves, with the graph displayed in the bottom half, as shown opposite. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> PL Tapping r from the icon panel will allow the graph to fill the entire screen. The graph is drawn in an automatically scaled window. Tap r again to return to half-screen size. from the toolbar places Tapping a marker at the top of the first column of the histogram (see opposite) and tells us that a the first interval begins at 2 (xc = 2) b for this interval, the frequency is 1(Fc = 1) To find the frequencies and starting points of the other intervals, use the arrow ( ) to move from interval to interval. E Essential Further Mathematics – Core SA M 18 Exercise 1C 1 The number of occupants in nine cars stopped at a traffic light was: 1 1 2 1 3 1 2 1 3 What is the mode of this data set? What does this tell us? 2 The number of surviving grandparents for 11 preschool children is listed below. 0 4 4 3 2 3 4 4 4 3 3 Form a frequency table to show the distribution of the number of surviving grandparents. 3 a Write down the missing information in the frequency table. b How many families had only one child? c How many families had more than one child? d What percentage of families had no children? e What percentage of families had fewer than three children? No. of children in family 0 1 2 3 4 Total Frequency Count % 3 10 6 2 21 47.6 28.6 9.5 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 19 4 a Salaries of women teaching in a school range from $20 106 to $63 579. Group the salaries into five equal-sized categories that cover all teaching salaries. b The number of students in VCE Further Mathematics classes ranges from 6 to 33. Group class size into six equal-sized categories that cover all Further Mathematics class sizes. c The amount of money carried by a sample of 23 students ranges from nothing to $8.75. Group the amount of money carried by the students into five equal-sized categories that cover all amounts of money carried by the students. 5 The histogram opposite was formed by recording the number of words in 30 randomly selected sentences. E Frequency (%) 30 25 20 15 10 PL a What percentage of these sentences contained: ii 25–29 words? i 5–9 words? iv fewer than 15 words? iii 10–19 words? Give answers correct to the nearest per cent. b How many of these sentences contained: ii more than 25 words? i 20–24 words? c What is the mode (modal interval)? 35 5 0 5 10 15 20 25 30 Number of words in sentence Population density 0–199 200–399 400–599 600–799 800–999 Total Frequency (count) 11 4 4 2 1 22 7 Use the information in the table opposite to help you construct a histogram to display the distribution of the number of rooms in the houses of 11 preschool children. Use the histogram in Example 7 as a model. Label axes and mark in scales. Number of rooms 4 5 6 7 8 Total Frequency (count) 3 0 1 3 4 11 SA M 6 Use the information in the table opposite to help you construct a histogram to display population density. Use the histogram in Example 6 as a model. Label axes and mark in scales. 8 The pulse rates of 23 students are given below. 86 70 82 78 96 69 71 77 90 64 78 80 68 83 71 78 68 88 88 70 76 86 74 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> 20 Essential Further Mathematics – Core E a Use a graphics calculator to construct a histogram. So that the first column starts at 63 and the column width is two. b For this histogram: i what is the starting point of the third column? ii what is the ‘count’ for the third interval? What actual data column width is five values does this include? c Use the window menu to redraw the histogram so that the first starts at 60. d For this histogram, what is the count in the interval ‘65 to <70’? 9 The following data values are the number of children in the families of 25 VCE students: 1 6 2 5 5 3 4 1 2 7 3 4 5 3 1 3 2 1 4 4 3 9 4 3 3 What to look for in a histogram SA M 1.4 PL a Use a graphics calculator to construct a histogram. So that the first column width is one and starts at 0.5. b For this histogram; what is the starting point for the fourth column and what is the count? c Use the window menu to redraw the histogram so that the first interval width is two and starts at 0. d For this histogram: i what is the count in the interval from 6 to less than 8? ii what actual data value(s) does this interval include? Histograms are useful for gaining an overall view of a frequency distribution of a numerical variable, the so-called ‘big picture’. Describing a histogram In describing a histogram, we focus on three things: shape and outliers (values in the data set that appear to stand out from the rest) centre spread Shape How is the data distributed? Is the histogram peaked, that is, do some data values tend to occur much more frequently than others, or is it relatively flat, showing that all values in the distribution occur with approximately the same frequency? Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 21 lower tail peak upper tail 10 8 6 4 2 0 Histogram 1 peak peak E 10 8 6 4 2 0 Frequency Frequency Symmetric distributions If a histogram is single-peaked, does the histogram region tail off evenly on either side of the peak? If so, the distribution is said to be symmetric (see Histogram 1). Histogram 2 SA M PL A single-peaked symmetric distribution is characteristic of the data that derives from measuring variables such as people’s heights, intelligence test scores, weights of oranges in a storage bin, or any other data for which the values vary evenly around some central value. The histogram for average hours worked (see Example 6) would be classified as approximately symmetric. The double-peaked distribution (Histogram 2) is symmetric about the dip between the two peaks. A histogram which has two distinct peaks indicates a bimodal (two modes) distribution. A bimodal distribution often indicates that the data has come from two different populations. For example, if we were studying the distance the discus is thrown by Olympic level discus throwers, we would expect a bimodal distribution if both male and female throwers were included in the study. Skewed distributions Sometimes a histogram tails off primarily in one direction. Such distributions are said to be skewed. If a histogram tails off to the right we say that it is positively skewed (Histogram 3). The distribution of salaries of workers in a large organisation tends to be positively skewed. Most workers earn a similar salary with some variation above or below this amount, but a few earn more and even fewer, like the senior manager, earn even more. The distribution of house prices also tends to be positively skewed. long upper tail +ve skew Histogram 3 10 Frequency Frequency peak 10 8 6 4 2 0 8 long lower tail peak –ve skew 6 4 2 0 Histogram 4 If a histogram tails off to the left we say that it is negatively skewed (Histogram 4). The distribution of age at death tends to be negatively skewed. Most people die in old age, a few in middle age and even fewer in childhood. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Outliers Centre E PL Frequency Outliers are any data values that stand out from the main body of data. These are data values that are atypically high or low. See for example, Histogram 5, which shows an outlier. In this case it is a data value which is atypically low compared to the rest of the data values. outlier main body of data Outliers can indicate errors made collecting 10 or processing data, for example a person’s 8 age recorded as 365. Alternatively, they may 6 indicate data values that are very different 4 2 from the rest of the values. For example, 0 compared to her students’ ages, a teacher’s Histogram 5 age is an outlier. Frequency Histograms 6 to 8 display the distribution 8 of test scores for three different classes 7 6 taking the same subject. They are identical 5 in shape, but differ in where they are 4 located along the axis. In statistical terms 3 we say that the distributions are ‘centred’ 2 at different points along the axis. 1 But what do we mean by the centre of a 0 50 60 70 80 90 100 110 120 130 140 150 distribution? This is an issue we will return Histograms 6 to 8 to in more detail later. For the present we will take centre to be the middle of the distribution. The middle of a symmetric distribution is reasonably easy to locate by eye. Looking at Histograms 6 to 8, it would be reasonable to say that the centre or middle of each distribution lies roughly halfway between the extremes; half the observations would lie above this point and half below. Thus we might estimate that Histogram 6 (yellow) is centred at about 60, Histogram 7 (light blue) at about 100, and Histogram 8 (dark blue) at about 140. SA M 22 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 23 E Frequency For skewed distributions, it is more difficult to estimate the middle of a distribution by eye. The middle is not halfway between the extremes because, in a skewed distribution, the scores tend to bunch up at one end. However, if we 5 line that divides imagine a cardboard cut-out of the histogram, the area of the 4 the midpoint lies on the line that divides the histogram in half histogram into two equal areas (Histogram 9). 3 Using this method, we would estimate the 2 centre of the distribution to lie somewhere between 35 and 40, but closer to 35, so we 1 might opt for 37. However, remember this is 0 15 20 25 30 35 40 45 50 only an estimate. PL Histogram 9 Spread If the histogram is single peaked, is it narrow? This would indicate that most of the data values in the distribution are tightly clustered in a small region. Or is the peak broad? This would indicate that the data values are more widely spread out. Histograms 10 and 11 are both single peaked. Histogram 10 has a broad peak indicating that the data values are not very tightly clustered about the centre of the distribution. In contrast, Histogram 11 has a narrow peak, indicating that the data values are tightly clustered around the centre of the distribution. 2 4 6 8 10 12 14 16 18 20 22 Histogram 10 Frequency Frequency SA M wide central region 10 8 6 4 2 0 narrow central region 20 16 12 8 4 0 2 4 6 8 10 12 14 16 18 20 22 Histogram 11 But what do we mean by the spread of a distribution? We will return to this in more detail later. For a histogram we will take it to be the maximum range of the distribution. Range Range = largest value − smallest value For example, Histogram 10, has a spread (maximum range) of 22 (22 − 0) units, which is considerably greater than the spread of Histogram 11, which has a spread of 12 (18 − 6) units. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Example 8 Describing a histogram in terms of shape, centre and spread 35 30 25 20 15 10 E Frequency (count) The histogram opposite shows the distribution of the number of phones per 1000 people in 85 countries. a Describe its shape and note outliers (if any). b Locate the centre of the distribution. c Estimate the spread of the distribution. 5 0 170 340 510 680 850 1020 Number of phones (per 1000 people) Solution The distribution is positively skewed. There are no outliers. The distribution is centred in the interval 170−340 phones/1000 people. Spread = 1020 − 0 = 1020 phones/1000 people PL a Shape and outliers b Centre Count up the frequencies from either end to find the middle interval. c Spread Use the maximum range to estimate the spread. It should be noted that with grouped data, it is difficult to precisely determine the location of the centre of a distribution from a histogram. So, when working with grouped data, it is acceptable to state that the centre of a distribution lies in the interval 170–340. We will learn how to solve this problem later in the chapter. If you were using the histogram above to describe the distribution in a form suitable for a statistical report, you might write as follows. SA M Report For the 85 countries, the distribution of the number of phones per 1000 people is positively skewed. The centre of the distribution lies somewhere in the interval 170−340 phones/1000 people. The spread of the distribution is 1020 phones/1000 people. There are no outliers. Exercise 1D 1 Label each of the following histograms as approximately symmetric, positively skewed or negatively skewed, and identify the following: i the mode a Frequency 20 15 10 ii any potential outliers iii the approximate location of the centre b 80 Frequency 24 60 40 5 20 0 0 Cambridge University Press Histogram • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Histogram B Evans, Lipson A TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 25 c d 15 20 Frequency Frequency 20 10 5 15 10 5 0 0 Histogram D Histogram C SA M E PL Frequency 10 2 These three histograms show the marks obtained by a group 9 8 of students in three subjects. 7 a Are each of the distributions 6 approximately symmetric or 5 skewed? 4 b Are there any clear outliers? 3 c Determine the interval 2 containing the central mark 1 for each of the three subjects. 0 d In which subject was the 2 6 10 14 18 22 26 30 34 38 42 46 50 spread of marks the least? Use Subject A Subject B Subject C Marks the range to estimate the spread. e In which subject did the marks vary most? Use the range to estimate the spread. 3 Label each of the following histograms as approximately symmetric, positively skewed or negatively skewed, and identify the following: ii any potential outliers iii the approximate location of the centre b 20 Frequency Frequency i the mode(s) a 15 10 5 0 80 60 40 20 0 Histogram B Histogram A 20 15 10 5 0 d Frequency Frequency c 20 15 10 5 0 Histogram D Histogram C 20 15 f Frequency Frequency e 10 5 0 80 60 40 20 0 Histogram E Histogram F Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> 26 Essential Further Mathematics – Core Use the histogram to complete the report below describing the distribution of pulse rate in terms of shape, centre, spread and outliers (if any). 6 5 Frequency (count) 4 This histogram shows the distribution of pulse rate (in beats per minute) for 28 students. 4 3 2 1 E 0 60 65 70 75 80 85 90 95 100 105 110 115 Pulse rate (beats per minute) Report 1.5 PL For the students, the distribution of pulse rates is with an outlier. The beats per minute and the spread of the centre of the distribution lies in the interval beats per minute. The outlier lies in the interval beats per minute. distribution is Stem-and-leaf plots and dot plots Stem plots SA M A stem-and-leaf plot, or stem plot for short, is an alternative to the histogram. It is particularly useful for displaying small to medium sized sets of data (up to about 50 data values) and has the advantage of retaining all the original data values. This makes it useful for further computations. A stem plot is also a very quick and easy way to order and display a set of data by hand. Like a histogram, the stem plot gives information about the shape, outliers, centre and spread of the distribution. One of the stem plot’s advantages over a histogram in describing distributions is being able to see all the actual data values. This enables the centre and the range of the distribution to be located more precisely. It also enables the clear identification of outliers. Constructing a stem plot In a stem-and-leaf plot, each data value is separated into two parts: the leading digit(s) form the stem, and the trailing digit becomes the leaf. For example, in a stem-and-leaf plot, the data values 25 and 132 are represented as follows: 25 is represented by 132 is represented by Stem Leaf 2 5 13 2 and so on. To construct a stem plot, enter the stems to the left of a vertical dividing line, and the leaves for each data point to the right. Usually we first construct an unordered stem plot by systematically plotting each data point as listed in the data set. From the unordered stem-and-leaf plot an ordered stem plot is then easily obtained. In an ordered stem plot the Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 27 leaves increase in value as they move away from the stem. It is usually the ordered stem plot that we want, because an ordered stem plot makes it easy to find the key values. Example 9 Constructing an ordered stem plot Solution 0 1 2 3 4 5 PL 1 The data set has values in the units, tens, twenties, thirties, forties and fifties. Thus, appropriate stems are 0, 1, 2, 3, 4, and 5. Write these down in ascending order, followed by a vertical line. E University participation rates (%) in 23 countries are given below. 26 3 12 20 36 1 25 26 13 9 26 27 30 1 15 21 7 8 22 3 37 17 55 Display the data in the form of an ordered stem plot. SA M 2 Now attach the leaves. The first data value is ‘26’. The stem is ‘2’ and the leaf is ‘6’. Opposite the 2 in the stem write down the number 6, as shown. The second data value is ‘3’ or ‘03’. The stem is ‘0’ and the leaf is ‘3’. Opposite the 0 in the stem, now write down the number 3, as shown. Continue systematically working through the data following the same procedure until all points have been plotted. You will then have the unordered stemplot as shown. 3 Ordering the leaves in increasing value as they move away from the stem gives the ordered stem plot as shown. 0 1 2 3 4 5 0 1 2 3 4 5 6 3 6 0 3 1 9 1 7 1 2 3 5 7 2 6 0 5 6 6 3 6 0 7 4 5 5 unordered stemplot 0 1 1 3 3 7 1 2 3 5 7 2 0 1 2 5 6 3 0 6 7 4 5 5 ordered stemplot 8 3 7 1 2 8 9 6 6 7 Using a stem plot to describe a distribution Stem plots are just like histograms, except that you can see all the data values. This enables more precise estimates to be madeSample of thepages centre and spread. Cambridge University Press • Uncorrected • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Spread (range) E Methods for determining the centre, spread and outliers from a stem plot Centre (middle) Count up from either end of the distribution until you find the middle value; the value which has an equal number of data values either side. n+1 th For an odd number of data values, n, the middle value is the 2 value. Thus, the median will be an actual data value. n+1 th For an even number of data values, n, the middle value is the 2 value. Thus, the median will lie between two data values. Subtract the smallest data value from the largest data value. Range = largest value − smallest value Example 10 Data values that stand out from the main body of data are called outliers. Their values can be read directly from the stem plot. PL Outliers Describing a stem plot in terms of shape, centre and spread Test marks The ordered stem plot opposite shows the 0 distribution of test marks of 23 students: 1 5 9 9 9 a Name its shape and note outliers (if any). 2 0 4 5 7 8 8 8 b Locate the centre of the distribution. 3 0 3 5 5 6 8 c Estimate the spread of the distribution. 4 1 2 3 3 5 d Write down the values of any outliers. 5 6 0 Solution SA M 28 a Shape b Centre There are 23 data values, the middle value is the 12th value. Check by counting. c Spread Use the range to estimate the spread. d Outlier Read off the value of the outlier The distribution is approximately symmetric with one outlier. The distribution is centred at 30 marks. Spread = 60 − 15 = 45 marks Outlier = 60 marks If you were using the stem plot to describe the distribution in a form suitable for a statistical report, you might write as follows. Report For the 23 students, the distribution of marks is approximately symmetric with an outlier. The centre of the distribution is at 30 marks and the distribution has a spread of 45 marks. The outlier is a mark of 60. Split stems In some instances, using the simple process outlined above produces a stem plot that is too bunched up to give us a good overall picture of the variation in the data. This is often the case Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 29 when the data values all have the same first digit or the same one or two first digits. For example, a group of 17 VCE students recently sat for a statistics test marked out of 20. The results are as shown below. 2 12 13 9 18 17 7 16 12 10 16 14 11 15 16 15 17 0 1 2 0 7 1 9 2 2 3 4 5 5 6 6 6 7 E Using the above process to form a stem plot we end up with a bunched-up plot like the one below: 7 8 1 (10−19) Single stem PL When this happens, the stem plot scale can be stretched out by ‘splitting’ the stems. Generally the stem is split into halves or fifths. For example, for the interval 10–19, the split stem system works as follows. 1 (10−14) 1 (15−19) 1 (10−11) 1 (12−13) 1 (14−15) 1 (16−17) 1 (18−19) Stem split into halves Stem split into fifths SA M In a stem plot with a single stem, the ‘1’ represents the interval 10–19. In a stem plot with its stem split into halves, the top ‘1’ represents the interval 10–14, while the bottom ‘1’ represents the interval 15–19. In a stem plot with its stem split into fifths, the top ‘1’ represents the interval 10–11, the second ‘1’ represents the interval 12–13, the third ‘1’ represents the interval 14–15, the fourth ‘1’ represents the interval 16–17, while the bottom ‘1’ represents the interval 18–19. Comparison of stem plots with different split stems Using a split stem plot to display the test marks can show features not revealed by a standard plot. This can be seen in the next plot with the stem split into fifths, indicating that a mark of 2 is an outlier. 0 2 7 9 1 0 1 2 2 3 4 5 5 6 6 6 7 7 8 Single stem 0 0 1 1 2 7 9 0 1 2 2 3 4 5 5 6 6 6 7 7 8 Stem split into halves 0 0 0 0 0 1 1 1 1 1 2 7 9 0 2 4 6 8 1 2 3 5 5 6 6 7 7 Stem split into fifths Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Back-to-back stem plots A back-to-back plot has a single stem with 8 6 4 2 1 1 1 5 6 8 9 8 two sets of leaves as shown. 1 0 2 1 1 1 4 The real value of back-to-back plots is 3 2 2 3 1 1 5 that they are a useful tool for comparing the distribution of two sets of data values for the same variable. Using a back-to-back stem plot to compare two distributions Solution Report Test 1 Test 2 9 8 6 6 5 9 8 7 6 5 5 7 5 3 3 2 2 9 0 0 0 0 1 2 3 4 5 8 9 0 0 1 0 4 3 2 5 7 8 8 5 5 6 8 9 3 3 4 5 PL Use the back-to-back stem plot to write a report comparing the distribution of the two sets of test marks in terms of shape, centre, spread and outliers. E Example 11 8 The distribution of the Test 1 marks is negatively skewed while the distribution of the Test 2 marks is approximately symmetric. The two distributions have similar centres, 36.5 and 35. The spread of the Test 1 marks is less than the Test 2 marks, 29 compared to 42. There are no outliers. SA M 30 Dot plots The simplest way to display numerical data is to form a dot plot. A dot plot consists of a number line with each data point marked by a dot. When several data points have the same value, the points are stacked on top of each other. Like stem plots, dot plots are a great way for displaying small data sets and have the advantage of being very quick to construct by hand. They are best when the data values are relatively close together. Example 12 Constructing a dot plot The ages (in years) of the 13 members of a sporting team are: 22 19 18 19 23 25 22 29 18 22 23 24 22 Construct a dot plot. Solution 1 Draw in a number line, scaled to include all data values. Label the line with the variable being displayed. 17 18 19 20 21 22 23 24 25 26 27 28 29 30 Age (years) Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 31 2 Plot each data value by marking in a dot above the corresponding value on the number line. 17 18 19 20 21 22 23 24 25 26 27 28 29 30 Age (years) E Interpreting a dot plot Dot plots are interpreted in much the same way as stem plots. However, usually there is little we can say about the shape of the distribution from the dot plot because there are not sufficient data points for any pattern to be revealed. From the dot plot in Example 12, we see that the distribution of ages is centred at 22 years (the middle value) with a spread of 11 years (29 − 18 = 11). Which graph? PL One of the issues that you will face is choosing a suitable graph to display a distribution. The following guidelines might help you in your decision making. They are guidelines only, because in some instances, there may be more than one suitable graph. Type of data Graph Qualifications on use Categorical Bar chart Segmented bar chart Not too many categories (4 or 5 maximum) Histogram Stem plot Dot plot Best for medium to large data sets (n ≥ 40) Best for small to medium sized data sets (n ≤ 50) Only suitable for small data sets (n ≤ 20) SA M Numerical Exercise 1E 1 The data below gives the urbanisation rates (%) in 23 countries. 54 99 22 20 31 3 22 9 25 3 56 12 16 9 29 6 28 100 17 9 35 27 12 a Construct an ordered stem plot. b What advantage does a stem plot have over a histogram? 2 For each of the following stem plots (A, B and C): a name its shape and note outliers (if any) b locate the centre of the distribution c determine the spread of the distribution d write down the values of outliers (if any) Stem plot A Stem plot B Stem plot C 0 1 2 3 4 5 6 0 1 2 3 4 5 6 0 1 2 3 4 5 6 0 2 0 2 0 2 0 1 1 2 6 7 7 9 2 3 5 5 5 5 6 1 4 7 2 0 1 0 2 1 2 2 3 0 2 2 3 6 1 2 4 9 5 6 8 8 4 5 9 9 9 4 6 1 3 2 0 2 4 1 1 3 5 8 8 0 0 4 4 4 7 7 8 9 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core 3 The data below gives the wrist circumference (in cm) of 15 men. 16.9 17.3 19.3 18.5 18.2 18.4 19.9 16.7 17.1 17.6 17.7 16.5 17.0 17.2 17.6 a Construct a stem plot for wrist circumference using: i stems 16, 17, 18, 19 ii these stems split into halves b Which stem plot appears to be more appropriate for this data? c Use the stem plot with split stems to help you complete the report below E Report For the men, the distribution of their wrist circumference is . The centre of cm and it has a spread of cm. There are no outliers. the distribution is at PL 4 The data below gives the weight (in kg) of 22 students. 57 58 62 84 64 74 57 55 56 60 75 68 59 72 110 56 69 56 50 60 75 58 a Construct a stem plot for weight using: i stems 5, 6, 7, 8, 9, 10 and 11 ii these stems split into halves b Use the stem plot with a split stem to write a brief report on the distribution of the weights of the students in terms of shape (and outliers), centre and spread. Use the report from Question 3 as a model. 5 The number of possessions (kicks, mark, handballs, knockouts, etc.) recorded for players in a football game between Carlton and Essendon is shown below. SA M 32 Carlton Essendon 10 44 32 44 19 35 11 5 24 28 21 32 21 59 21 12 19 26 23 22 29 34 22 34 36 20 14 25 16 19 32 32 14 29 8 22 21 26 44 19 21 22 a Display the data in the form of an ordered back-to-back stem plot. b Complete the following report comparing the two distributions in terms of shape (and outliers), centre and spread. Report The distribution of the number of possessions is for both teams. The two and possessions respectively. The spread of distributions have similar centres, at possessions, compared to possessions for the distribution is less for Carlton, Essendon. 6 The following data gives the number of children in the families of 14 VCE students: 1 6 2 5 5 3 4 4 2 7 3 4 3 4 a Construct a dot plot. b What is the mode? c What is: i the centre? ii the spread? Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 33 7 The following data gives the life expectancies in years of 13 countries: 76 75 74 74 73 73 75 71 72 75 75 78 72 a Construct a dot plot. b What is the mode? c What is: i the centre? ii the spread? PL number of passengers in a bus — 1000 buses in sample amount of petrol purchased (in litres) — 30 petrol purchases type of petrol purchased (super, unleaded, premium) prices of houses sold in Melbourne over a weekend the number of medals won by countries winning medals at the Olympics state of residence of a sample of 200 Australians number of cigarettes smoked in a day (a sample of 120 people) resting pulse rates of 7 students SA M a b c d e f g h E 8 Data has been collected for each of the following variables. The data is to be displayed graphically. In each case, decide which is the most appropriate graph. Select from bar chart, histogram, stem plot or dot plot. Sometimes more than one sort of graph is suitable. Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core Key ideas and chapter summary Data can be classified as numerical or categorical. Frequency table A frequency table is a listing of the values a variable takes in a data set, along with how often (frequently) each value occurs. Frequency can be recorded as a: r count: the number of times a value occurs; for example, the number of females in the data set is 32 r percent: the percentage of times a value occurs; for example, the percentage of females in the data set is 45.5% Categorical data Categorical data arises when classifying or naming some quality or attribute; for example, place of birth, hair colour. Bar chart Bar charts are used to display the frequency distribution of categorical data. PL E Types of data For a small number of categories, the distribution of a categorical Describing variable is described in terms of the dominant category (if any), the distributions of categorical variables order of occurrence of each category and its relative importance. Mode The mode is the value or group of values that occurs most often (frequently) in a data set. For example, for the data 2 1 1 3 3 2 5 1 6 1 1 2 1 1, the mode is 1, because it is the data value that occurs most often. SA M Review 34 Numerical data Numerical data arises from measuring or counting some quantity; for example, height, number of people, etc. Numerical data can be discrete or continuous. Discrete data arises when you count. Continuous data arises when you measure. Histogram A histogram is used to display the frequency distribution of a numerical variable: suitable for medium to large sized data sets. Stem plot A stem plot is an alternative graphical display to the histogram: suitable for small to medium sized data sets. The advantage of the stem plot over the histogram is that it shows the value of each data point. Dot plot A dot plot consists of a number line with each data point marked by a dot: suitable for small sets of data only. Describing the distribution of a numerical variable The distribution of a numerical variable can described in terms of: r shape: symmetric or skewed (positive or negative)? r outliers: values that appear to stand out r centre: the midpoint of the distribution (median) r spread: one measure is the range of values covered (Range = largest value − smallest value) Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 35 SA M PL E Having completed this chapter you should be able to: differentiate between numerical and categorical data interpret the information contained in a frequency table identify and interpret the mode construct a bar chart or histogram from a frequency table decide when it is appropriate to use a histogram rather than a bar chart and vice versa construct a histogram from raw data, using a graphics calculator construct a dot plot and a stem plot from raw data, using split stems if required locate the mode of a distribution from a histogram, stem plot, dot plot or bar chart recognise a symmetric, positively skewed and negatively skewed histogram or stem plot identify potential outliers in a distribution from its histogram or stem plot write a brief report to describe the distribution of a numerical variable in terms of shape, centre, spread and outliers (if any) write a brief report to describe the distribution of a categorical variable in terms of the dominant category (if any), the order of occurrence of each category and their relative importance Multiple-choice questions The following information relates to Questions 1 to 3 A survey collected information about the number of cars owned by a family and the car size (small, medium, large). 1 The variables Number of cars owned and car Size are: A both categorical variables B both numerical variables C a categorical and a numerical variable respectively D a numerical and a categorical variable respectively E neither numerical nor categorical variables 2 To graphically display the information about car size you could use a: A dot plot B stem plot C histogram D segmented bar chart E back-to-back stemplot 3 The Number of cars owned is: A a continuous numerical variable C a continuous categorical variable E none of the above B a discrete numerical variable D a discrete categorical variable Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin Review Skills check P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core The following information relates to Questions 4 to 6 A group of teenagers were asked to nominate their favourite leisure Leisure activity activity. Their responses have been Sport organised into a frequency table as Listening to music shown. Some information is missing. Watching TV Other Total Frequency Count Percentage 73 70 29.2 19.2 23.6 E 59 250 PL 4 The percentage of students who said that listening to music was their favourite leisure activity is: A 17.5 B 28.0 C 29.2 D 50.0 E 70.0 5 The number of students who said watching TV was their favourite leisure activity is: A 19 B 48 C 62 D 125 E 70.0 6 For these students, the most popular leisure activity is: A sport B listening to music C watching TV D other E can’t tell 7 The total number of students in the class is: A 6 B 18 C 20 D 21 E 22 8 The number of students in the class who obtained a test score less then 14 is: A 4 B 10 C 14 Frequency Questions 7 to 11 relate to the histogram shown below This histogram displays the test scores of a class 6 of Further Mathematics students. 5 SA M Review 36 4 3 2 1 0 6 8 10 12 14 16 18 20 22 24 26 28 Test score D 17 E 28 9 The histogram is best described as: A negatively skewed B negatively skewed with an outlier C approximately symmetric D approximately symmetric with outliers E positively skewed 10 The centre of the distribution lies in the interval: A 8–10 B 10–12 C 12–14 D 14–16 11 The spread of the students’ marks is: A 8 B 10 C 12 D 20 E 22 12 For the stem plot shown opposite, the modal interval is: A 20–24 B 25–29 C 20–29 D 25 E 29 E 18–20 1 1 2 2 3 0 5 3 5 0 2 5 3 7 1 6 9 4 9 9 9 2 4 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 37 60 50 40 30 20 10 0 Red Black Brown Blonde E 14 For these students, the most common hair colour is: A black B blonde C brown Percentage 13 The number of students with brown hair is closest to: A 4 B 34 C 57 D 68 E 114 Other D red E other PL 15 The ages of 11 primary school children were collected. The best graph to display the distribution of ages of these children would be a: A bar chart B dot plot C histogram D segment bar chart E stem plot Extended-response questions 1 One hundred and twenty-one students were asked to identify their preferred leisure activity. The results of the survey are displayed in a bar chart. 30 Percentage SA M 25 a What percentage of students nominated watching TV as their preferred leisure activity? b What percentage of students in total nominated either going to the movies or reading as their preferred leisure activity? c What is the most popular leisure activity for these students? How many students rated this activity as their preferred leisure activity? 20 15 10 5 TV M us i M c ov i Re es ad in g O th er Sp or t 0 Preferred leisue activity 2 The number of people killed in natural and non-natural disasters in 1997 by world region is shown in the table below. a Construct a bar chart. Region Number killed b In which region was the: Europe 874 i greatest number of people killed? Africa 8 327 ii least number of people killed? Asia 10 551 ∗ Oceania 457 The Americas 1 581 ∗ includes Australia (41) Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin Review The following information relates to Questions 13 and 14 This percentage segmented bar chart 100 90 shows the distribution of hair 80 70 colour for 200 students. P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Essential Further Mathematics – Core 3 A group of 52 teenagers was asked ‘Do you agree that the use of marijuana should be legalised?’ Their responses are summarised in the table opposite. Legalise Agree Disagree Don’t know Total Frequency Count Percent 18 26 8 52 E a Construct a properly labelled and scaled frequency bar chart for this data. b Complete the table by calculating the appropriate percentages correct to one decimal place. c Use the percentages to construct a percentage segmented bar chart for this data. d Use the frequency table to help you complete the following report. PL Report: In response to the question, `Do you agree that the use of marijuana . Of the remaining should be legalised?', 50% of the 52 students % agreed while % said that they . students, 4 The table below gives the distribution of the number of children in 50 families. a Is the number of children in a family a numerical or categorical variable? b Write down the missing information. c What is the mode? d Determine the number of families with: i three children ii two or three children iii less than three children e Determine the percentage of families with: i six children ii more than six children iii less than six children SA M Number of children in family 0 1 2 3 4 5 6 7 8 Total 10 5 Students were asked how much they spent on entertainment each month. The 8 results are displayed in the histogram. Use this information to answer the 6 following questions. 4 a How many students: i were surveyed? 2 ii spent $100–105 per month? 0 90 b What is the mode? c How many students spent $110 or more per month? d What percentage spent less than $100 per month? Frequency Count Percent 5 6 19 7 10 2 3 0 1 50 4 6 0 2 100 38 14 Frequency Review 38 100 110 120 Amount ($) 130 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin 140 P1: FXS/ABE P2: FXS 9780521740517c01.xml CUAT013-EVANS September 1, 2008 17:55 Back to Menu >>> Chapter 1 — Organising and displaying data 39 i Name the shape of the distribution displayed by the histogram. ii Locate the interval containing the centre of the distribution. iii Determine the spread of the distribution using the range. 6 This stem plot displays the ages (in years) of a group of women. a What was the age of the youngest woman? 2 = 17.2 years 3 4 6 6 8 8 9 9 1 3 3 3 4 5 5 5 5 5 6 7 8 8 8 9 2 2 3 3 PL E b In terms of age, one of the women is a Note: 17 possible outlier. What is her age? 17 2 c How many women were aged between 17 5 18 0 17.0 and 17.4 years, inclusive? 18 5 d How many women were 19 years old 19 1 or older? 19 8 e What is the modal age category? f What percentage of women were younger 20 20 6 than 20 years old? g i Name the shape of the distribution of ages, noting outliers. ii Locate the centre of the distribution. iii Determine the spread of the distribution. 10 8 Frequency SA M 7 The distribution of times spent by 37 cars while stopped at traffic lights is as shown in the histogram opposite. Use the histogram to write a report on the distribution of waiting times in terms of shape, centre, spread and outliers. 6 4 2 0 5 10 15 20 25 30 35 40 45 50 55 Waiting time (seconds) 8 Use a graphics calculator to construct histograms for the following sets of data: a Use intervals of width 5 starting at 90. Monthly expenditure on entertainment (in dollars) 110 115 105 98 118 114 125 112 107 135 121 95 114 104 97 130 122 94 108 118 106 121 125 107 109 93 b Use intervals of width 8 starting at 32. Life span (in years) 58 65 68 74 73 73 75 71 72 61 67 66 50 66 64 72 74 48 41 44 44 49 48 48 37 Cambridge University Press • Uncorrected Sample pages • 978-0-521-61328-6 • 2008 © Jones, Evans, Lipson TI-Nspire & Casio ClassPad material in collaboration with Brown and McMenamin Review e