Mechanical Engineering Department Birla Vishvakarma Mahavidyalaya (Engineering College) 3ME04: Computer Aided Design 2023-24 Assignment IV (Date of Submission: 23rd October 2023) 1. Consider the bar in Figure. Cross-sectional area Ae = 800 mm2, and Young’s modulus E = 200 GPA. If q1 = 0.508 mm and q2 = 0.635 mm, determine the displacement at point P. Also determine the strain ε, stress σ and the element stiffness matrix. 2. Consider the bar in Figure loaded as shown. Determine the nodal displacements, element stresses, and support reactions. Use elimination method for handling boundary conditions. 3. Consider the bar in Figure loaded as shown. Determine the nodal displacements, element stresses, and support reactions. Use elimination method for handling boundary conditions. 4. Solve and compare for the axial displacement and stress in the tapered bar shown in figure using one, two and three constant area elements. Evaluate the area at the center of each element length. Use that area for each element. Let Ao = 200 mm2. L = 300 mm. E = 200 x 109 N/m2 and P = 200 KN. Dr V J Patel, A M Thakkar and J R Koisha Page 1 of 3 Mechanical Engineering Department Birla Vishvakarma Mahavidyalaya (Engineering College) 3ME04: Computer Aided Design 2023-24 5. Consider the bar in figure. Determine the nodal displacements, element stresses and support reactions. Use penalty method for handling boundary conditions. 6. Consider the bar in figure. Determine the nodal displacements, element stresses and support reactions. Dr V J Patel, A M Thakkar and J R Koisha Page 2 of 3 Mechanical Engineering Department Birla Vishvakarma Mahavidyalaya (Engineering College) 3ME04: Computer Aided Design 2023-24 7. An axial load P= 385 KN is applied to the composite block shown in figure. Determine the stress in each material. 8. For the vertical rod shown in figure, find the deflection at end A and the stress distribution. Use E = 100 MPa and weight per unit volume = 0.06 N/cm3. Comment on the stress distribution. 9. Determine the displacements, stresses and support reactions for the structure shown in figure. (Take P1 = 60 KN and P2 = 75 KN) Dr V J Patel, A M Thakkar and J R Koisha Page 3 of 3
